I need help in hierarchica tree
i need any sample form that declare how can i build a new one
this is the link using this you can apply
tree type query
http://www.adp-gmbh.ch/ora/sql/connect_by.html
i know you need form ...
what is your structure of table
Similar Messages
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Hi,
I need to build a Java Tree Table as the follwing:
the first column of the table is tree node, the rest are JTextField, Jlabel, JBottonBox etc.
I tried the example of JTreeTable for the file system to make the other columns as JTextField etc. did not work out.
Anybody how to do this?
A lof of thanks.
JaneHi,
I need to build a Java Tree Table as the follwing:
the first column of the table is tree node, the rest are JTextField, Jlabel, JBottonBox etc.
I tried the example of JTreeTable for the file system to make the other columns as JTextField etc. did not work out.
Anybody how to do this?
A lof of thanks.
Jane -
Hi,
I am writing a program and I need to dispaly two XMLs
(preferably in tree control). The leaf nodes in the two XMLs are
realted and I need to connect them with lines in the two trees. How
do I do this. Any poniters?
Regards,
RajI am tring for something like Araxis merge GUI.
-
Need help understanding spanning tree for CCNA.
I ran into a question something like this on exam, and I had no clue what to do. I ended up failing by 10% I think because I didn't understand STP well.
For some reason the book never covered what is a tiebreaker in a setting like this. I thought about it, but was like it's not in here then I don't care, you probably would not find that in a real network anyhow.
Based on default settings the root switch in my drawing would be SW#1. one of the ports on SW#3 would block the other would be root. Either path from SW#3 to SW#1(root) would be the same. I don't know what SW3 would do then if it's based on interface#, or something to do with the BPDU received from the prior switch, or some other method.
This topic first appeared in the Spiceworks CommunityI ran into a question something like this on exam, and I had no clue what to do. I ended up failing by 10% I think because I didn't understand STP well.
For some reason the book never covered what is a tiebreaker in a setting like this. I thought about it, but was like it's not in here then I don't care, you probably would not find that in a real network anyhow.
Based on default settings the root switch in my drawing would be SW#1. one of the ports on SW#3 would block the other would be root. Either path from SW#3 to SW#1(root) would be the same. I don't know what SW3 would do then if it's based on interface#, or something to do with the BPDU received from the prior switch, or some other method.
This topic first appeared in the Spiceworks Community -
Help needed in constructing a tree
Help needed in constructing a tree. I was wondering if some one can suggest me how to add messages in the second column for both the parent node and child elements.
I was able to create a tree succefully, but want to add some description in the second column for the first column elements, for both parent and child elements.
Please suggest me how to add the arrays to second column for parent and child nodes.
Solved!
Go to Solution.
Attachments:
Tree_fix.vi 15 KBThe Child Text parameter is the one you are searching for. It accepts a 1D string array for the following columns.
hope this helps,
Norbert
CEO: What exactly is stopping us from doing this?
Expert: Geometry
Marketing Manager: Just ignore it. -
Need help, MMC tree got deleted, very urgent.
Hi,
My sap MMC tree, got deleted in the server. I have been trying to restore since 2 days and couldnt succeed, please help me.
1) i have uncared the sapmmc.sar from Kernal\NT\I386\MMC\sapmmc.sar file
2) i got about 7 files, in which there is one sapmmc file i have tried to double click it, n check but no go.
3) i also tried to run the Sapstartsrv.exe file and fill in up the values in pop up window. & filled up the following values :-
SID: DEV
NR: 00
StartProfile: (entire start profile path given)
user: devadm
passwd; (given)
- but it says "the account name is invalid or does not exist or the password is invalid for account name specified"/
- no go in both the cases.
Please need help very urgent.
Regards,
Satish.siva,
I am getting same error since 2 days
SID: DEV
NR: 00
Start Profile: (entire start profile path)
User: <hostname>/devadm
passwd: ****
Error:
cannot install service
create service failed:421
The account name is invalid or doesnot exist, or the passwd is invalid for the account name specified.
Edited by: satish c on Jun 4, 2008 11:12 AM -
Newbie needs help with Flex app
Hi there. I am very new to Flex and also fairly new to
programming although I do have a little experience.
I am trying to create an app which stores code snippets or
common text I tend to use every day in my documents and emails.
So basically I need help on a design level. I can refer to
the developer's manual for exact instructions for commands, but I
need to know what to code first.
The app will consist of:
-a tree directory structure where I can create groups.
-There will be a basic text editor where I input all my data,
basic text formatting options (font, bullets etc) would be a bonus.
-A search function
-Finally it will ideally allow multiple client apps write to
a central database file over a network
Can anyone suggest how I should approach such a project?
Or are there any tutorials / source files which demonstrate
each bullet point?
thanks.Hey jono,
I'm new too. But I think I might know the right components.
If you google any of these + flex 3 you should get some
decent documentation
tree - advanced dataGrid component
basic text editor - rich text editor component
search function - well, you're gonna need to read up on
arrays, and arraycollection. Once you get that stuff working, you
can write up a function to search for a string in an array.
network functionality - HTTPService, you can dump the
datagrid into a database, and have it load the database when you
open up the application.
Give these things a shot, tutorials / sources will come with
the google searches. -
first of all, who has heard of the game called zuul? It is a very boring text based game I am currently having the pleasure of improving.
Basically, you are in a room, that is connected to a bunch of other rooms and depending on the room you are in, you have different exists and different items in the room.
The goal is to navigate through the collection of Rooms and there is no real win condition, It is more for learning then for actually playing.
You navigate by a series of commands such as: go (direction)( as in "direction of exit", NSEW), quit, a few other odd bits.
ex: go south, quit, go west etc
The game has several classes: Game, Command, CommandWords, Item, Parser, Room.
Obviously Game is the main central head conch, (it is not the super class.)
Game makes use of Item, Room, Parser, and Command.
Item is the class that deals with the number of items in the Room.
Room is the class that deals with the rooms the player will navigate to and from.
Command reads in the commands such as "go-(direction)" or "quit".
Parser makes everybody understand each other by using both Command and CommandWords.
CommandWords is a list of commands such as "go", "quit" etc.
The problem I am having right now is to allow a player to move through the rooms while holding a certain item. The item has to come from the rooms and the player should be able to drop it.
So I have to add two new commands: take and drop. The problem is that I have been asked to do this without creating a new class. Otherwise I would have just created class Player and be done with it. So I am trying to figure out whose responsibility should it be to take care of the take and drop command. I have done some preliminary work in class Game, it is the take(Command command) and drop() methods.
I have also a few questions concerning other aspects of the project, I have listed their locations here:
1. The take() method in class Game, the for-each loop, a complier error with ArrayList
2. class Parser, a general question about the string tokenzier
If you want to see how the game is suppose to run, just comment out the bodies of take() and drop(). Not the declaration. Everything else works.
I shall now provide the code to all classes. I wish there were an option to upload a zip file, then you don't have to read through all the codes and copy&paste all the codes. The complier I am using is BlueJ. And the SDK version is 1.6. With the exception of class Game, everything else can be assumed to be error free.
Thank you for your time,
Davy
class Game
import java.util.*;
* This class is the main class of the "World of Zuul" application.
* "World of Zuul" is a very simple, text based adventure game. Users
* can walk around some scenery. That's all. It should really be extended
* to make it more interesting!
* To play this game, create an instance of this class and call the "play"
* method.
* This main class creates and initialises all the others: it creates all
* rooms, creates the parser and starts the game. It also evaluates and
* executes the commands that the parser returns.
* @author Michael Kolling and David J. Barnes
* @version 2006.03.30
public class Game
private Parser parser;
private Room currentRoom;
private Room previousRoom;
private Stack<Room> previousRooms;
* Create the game and initialise its internal map.
public Game()
createRooms();
parser = new Parser();
* Create all the rooms and link their exits together.
private void createRooms()
Room outside, theatre, pub, lab, office;
// create the rooms
outside = new Room("outside the main entrance of the university");
theatre = new Room("in a lecture theatre");
pub = new Room("in the campus pub");
lab = new Room("in a computing lab");
office = new Room("in the computing admin office");
// create some items
Item desk, chair, beer, podium, tree;
desk = new Item("desk", "student desk",10);
chair = new Item("chair", "student chair",5);
beer = new Item("beer", "glass of beer", 0.5);
podium = new Item("podium", "lecture podium", 100);
tree = new Item("tree", "a tree", 500.5);
// put items in some of the rooms
outside.addItem(tree);
theatre.addItem(desk);
theatre.addItem(chair);
theatre.addItem(podium);
pub.addItem(beer);
pub.addItem(beer);
office.addItem(desk);
lab.addItem(chair);
lab.addItem(beer);
// initialise room exits
outside.setExit("east", theatre);
outside.setExit("south", lab);
outside.setExit("west", pub);
theatre.setExit("west", outside);
pub.setExit("east", outside);
lab.setExit("north", outside);
lab.setExit("east", office);
office.setExit("west", lab);
currentRoom = outside; // start game outside
previousRooms = new Stack<Room>(); // no rooms on the stack
previousRoom = null;
* Main play routine. Loops until end of play.
public void play()
printWelcome();
// Enter the main command loop. Here we repeatedly read commands and
// execute them until the game is over.
boolean finished = false;
while (! finished) {
Command command = parser.getCommand();
finished = processCommand(command);
System.out.println("Thank you for playing. Good bye.");
* Print out the opening message for the player.
private void printWelcome()
System.out.println();
System.out.println("Welcome to the World of Zuul!");
System.out.println("World of Zuul is a new, incredibly boring adventure game.");
System.out.println("Type 'help' if you need help.");
System.out.println();
System.out.println(currentRoom.getLongDescription());
* Given a command, process (that is: execute) the command.
* @param command The command to be processed.
* @return true If the command ends the game, false otherwise.
private boolean processCommand(Command command)
boolean wantToQuit = false;
if(command.isUnknown()) {
System.out.println("I don't know what you mean...");
return false;
String commandWord = command.getCommandWord();
if (commandWord.equals("help")) {
printHelp();
else if (commandWord.equals("go")) {
goRoom(command);
else if (commandWord.equals("look")) {
look(command);
else if (commandWord.equals("eat")) {
eat(command);
else if (commandWord.equals("back")) {
back(command);
else if (commandWord.equals("stackBack")) {
stackBack(command);
else if (commandWord.equals("take")){
take(command);
else if (commandWord.equals("drop")) {
drop(command);
else if (commandWord.equals("quit")) {
wantToQuit = quit(command);
// else command not recognised.
return wantToQuit;
// implementations of user commands:
* Print out some help information.
* Here we print some stupid, cryptic message and a list of the
* command words.
private void printHelp()
System.out.println("You are lost. You are alone. You wander");
System.out.println("around at the university.");
System.out.println();
System.out.println("Your command words are:");
System.out.println(parser.getCommands());
* Try to go to one direction. If there is an exit, enter the new
* room, otherwise print an error message.
* @param command The command entered.
private void goRoom(Command command)
if(!command.hasSecondWord()) {
// if there is no second word, we don't know where to go...
System.out.println("Go where?");
return;
String direction = command.getSecondWord();
// Try to leave current room.
Room nextRoom = currentRoom.getExit(direction);
if (nextRoom == null) {
System.out.println("There is no door!");
else {
previousRooms.push(currentRoom);
previousRoom = currentRoom;
currentRoom = nextRoom;
System.out.println(currentRoom.getLongDescription());
* "Look" was entered.
* @param command The command entered.
private void look(Command command)
if(command.hasSecondWord()) {
System.out.println("Look what?");
return;
System.out.println(currentRoom.getLongDescription());
* "Eat" was entered.
* @param command The command entered.
private void eat(Command command)
if(command.hasSecondWord()) {
System.out.println("Eat what?");
return;
System.out.println("You have eaten and are no longer hungry!");
* "Back" was entered.
* @param command The command entered.
private void back(Command command)
if(command.hasSecondWord()) {
System.out.println("Back what?");
return;
if (previousRoom==null) {
System.out.println("Can't go back.");
return;
// push current room on stack (for stackBack)
previousRooms.push(currentRoom);
// swap current and previous rooms (for back)
Room temp = currentRoom;
currentRoom = previousRoom;
previousRoom = temp;
// You could replace the previous three lines with the following
// which use the stack to get the previous room
// but note that this makes "back" dependent on "stackBack".
// (If you do it this way you no longer need "temp".
// currentRoom = previousRoom;
// previousRoom = previousRooms.peek();
System.out.println("You have gone back:");
System.out.println(currentRoom.getLongDescription());
* "StackBack" was entered.
* @param command The command entered.
private void stackBack(Command command)
if(command.hasSecondWord()) {
System.out.println("StackBack what?");
return;
if (previousRooms.isEmpty()) {
System.out.println("Can't go StackBack.");
return;
// set previous room (for "back")
previousRoom = currentRoom;
// set new current room (using stack)
currentRoom = previousRooms.pop();
System.out.println("You have gone StackBack:");
System.out.println(currentRoom.getLongDescription());
* allows a player to take something from the room
* @param command
private void take(Command command){
String a;
a=command.getSecondWord();
for (Item i:currentRoom.items()) { //a for each loop, since the room's items are kept in a list, but this gives a //compiler error, it doesn't work because items is an ArrayList, but I need a way to pick up the item. I thought that if //given the item's name, I could run a check through the room's ArrayList of items via a for-each loop
if (a==i.getName()) {
removeItem (i);
return;
* allows a player to drop an item in the room
* @param command
private void drop(Command command) {
if(command.hasSecondWord()) {
System.out.println("drop what?");
return;
//add item method is suppose to be used here
* "Quit" was entered. Check the rest of the command to see
* whether we really quit the game.
* @param command The command entered.
* @return true, if this command quits the game, false otherwise.
private boolean quit(Command command)
if(command.hasSecondWord()) {
System.out.println("Quit what?");
return false;
else {
return true; // signal that we want to quit
}class Room
import java.util.*;
* Class Room - a room in an adventure game.
* This class is part of the "World of Zuul" application.
* "World of Zuul" is a very simple, text based adventure game.
* A "Room" represents one location in the scenery of the game. It is
* connected to other rooms via exits. For each existing exit, the room
* stores a reference to the neighboring room.
* @author Michael Kolling and David J. Barnes
* @version 2006.03.30
* @author L.S. Marshall
* @version 1.03 October 25, 2007
public class Room
private String description;
private HashMap<String, Room> exits; // stores exits of this room.
// The items in the room
private ArrayList<Item> items;
* Create a room described "description". Initially, it has
* no exits. "description" is something like "a kitchen" or
* "an open court yard".
* @param description The room's description.
public Room(String description)
this.description = description;
exits = new HashMap<String, Room>();
items = new ArrayList<Item>();
* Define an exit from this room.
* @param direction The direction of the exit.
* @param neighbor The room to which the exit leads.
public void setExit(String direction, Room neighbor)
exits.put(direction, neighbor);
* Gives a short description of the room.
* @return The short description of the room
* (the one that was defined in the constructor).
public String getShortDescription()
return description;
* Return a description of the items in the room
* (Note that this could be combined with getLongDescription, but
* this way shows better cohesion, and could avoid code duplication
* for future enhancements.)
* @return A description of the items in this room
public String getItemsDescription()
String s = new String();
if (items.size()==0)
s += "There are no items in this room.\n";
else {
s += "The item(s) in the room are:\n";
for (Item item : items ) {
s += item.getInfo() + "\n";
return s;
* Return a description of the room in the form:
* You are in the kitchen.
* Exits: north west
* and information on the items in the room
* @return A long description of this room
public String getLongDescription()
String s = "You are " + description + ".\n" + getExitString() + "\n";
s += getItemsDescription();
return s;
* Return a string describing the room's exits, for example
* "Exits: north west".
* @return Details of the room's exits.
private String getExitString()
String returnString = "Exits:";
Set<String> keys = exits.keySet();
for(String exit : keys) {
returnString += " " + exit;
return returnString;
* Return the room that is reached if we go from this room in direction
* "direction". If there is no room in that direction, return null.
* @param direction The exit's direction.
* @return The room in the given direction.
public Room getExit(String direction)
return exits.get(direction);
* Adds the given item to the room.
* @param item The item to be added
public void addItem(Item item)
items.add(item);
* Removes an item if the person picks it up
* @param item the item to be removed
public void removeItem (Item item)
items.remove(item);
}class Item
* This represents an item in a room in zuul.
* @author L.S. Marshall
* @version 1.00 October 9, 2007
public class Item
// The description of the item
private String description;
// The weight of the item
private double weight;
private String name;
* Constructor for objects of class Item
* @param desc description of the item
* @param weight the weight of the item
public Item(String name, String desc, double weight)
description = desc;
this.weight = weight;
this.name=name;
* Returns a string representing this item
* @return string representing this item
public String getInfo()
return ("Item: " + description + ", weighs " + weight + ".");
* returns the name of the string
* @ return the name in a string
public String getName()
return ( name );
}class Command
* This class is part of the "World of Zuul" application.
* "World of Zuul" is a very simple, text based adventure game.
* This class holds information about a command that was issued by the user.
* A command currently consists of two strings: a command word and a second
* word (for example, if the command was "take map", then the two strings
* obviously are "take" and "map").
* The way this is used is: Commands are already checked for being valid
* command words. If the user entered an invalid command (a word that is not
* known) then the command word is <null>.
* If the command had only one word, then the second word is <null>.
* @author Michael Kolling and David J. Barnes
* @version 2006.03.30
public class Command
private String commandWord;
private String secondWord;
* Create a command object. First and second word must be supplied, but
* either one (or both) can be null.
* @param firstWord The first word of the command. Null if the command
* was not recognised.
* @param secondWord The second word of the command.
public Command(String firstWord, String secondWord)
commandWord = firstWord;
this.secondWord = secondWord;
* Return the command word (the first word) of this command. If the
* command was not understood, the result is null.
* @return The command word.
public String getCommandWord()
return commandWord;
* @return The second word of this command. Returns null if there was no
* second word.
public String getSecondWord()
return secondWord;
* @return true if this command was not understood.
public boolean isUnknown()
return (commandWord == null);
* @return true if the command has a second word.
public boolean hasSecondWord()
return (secondWord != null);
}class Parser
import java.util.Scanner;
import java.util.StringTokenizer;
//I read the documentation for String Tokenizer, and I have a few questions relating to a pet project of mine. The //project is to build a boolean algebra simplifer. I would give it a boolean expression and it will simplify it for me.
//Which is very similar to what this class does. The documentation mentioned a delimiter for separating the tokens.
//yet I see none here, is the delimiter at default, the space between the words? and if I were to set manually //delimiters, how do I do that?
//Once I read in the string, should it be Parser's job to execute the boolean simplification part? According the RDD,
//it shouldn't, but doing so would keep everything in fewer classes and therefore easier to manage, wouldn't it?
* This class is part of the "World of Zuul" application.
* "World of Zuul" is a very simple, text based adventure game.
* This parser reads user input and tries to interpret it as an "Adventure"
* command. Every time it is called it reads a line from the terminal and
* tries to interpret the line as a two word command. It returns the command
* as an object of class Command.
* The parser has a set of known command words. It checks user input against
* the known commands, and if the input is not one of the known commands, it
* returns a command object that is marked as an unknown command.
* @author Michael Kolling and David J. Barnes
* @version 2006.03.30
* @author L.S. Marshall
* @version 1.01 October 9, 2007
public class Parser
private CommandWords commands; // holds all valid command words
private Scanner reader; // source of command input
* Create a parser to read from the terminal window.
public Parser()
commands = new CommandWords();
reader = new Scanner(System.in);
* Command returns the command typed by the user.
* @return The next command from the user.
public Command getCommand()
String inputLine; // will hold the full input line
String word1 = null;
String word2 = null;
System.out.print("> "); // print prompt
inputLine = reader.nextLine();
// Find up to two words on the line.
Scanner tokenizer = new Scanner(inputLine);
if(tokenizer.hasNext()) {
word1 = tokenizer.next(); // get first word
if(tokenizer.hasNext()) {
word2 = tokenizer.next(); // get second word
// note: we just ignore the rest of the input line.
// Now check whether this word is known. If so, create a command
// with it. If not, create a "null" command (for unknown command).
if(commands.isCommand(word1)) {
return new Command(word1, word2);
else {
return new Command(null, word2);
* Returns a list of valid command words.
* @string list of valid command words
public String getCommands()
return commands.getCommandList();
}class CommandWords
* This class is part of the "World of Zuul" application.
* "World of Zuul" is a very simple, text based adventure game.
* This class holds an enumeration of all command words known to the game.
* It is used to recognise commands as they are typed in.
* @author Michael Kolling and David J. Barnes
* @version 2006.03.30
* @author L.S. Marshall
* @version 1.01 October 9, 2007
public class CommandWords
// a constant array that holds all valid command words
private static final String[] validCommands = {
"go", "quit", "help", "look", "eat", "back", "stackBack",
"take", "drop",
* Constructor - initialise the command words.
public CommandWords()
// nothing to do at the moment...
* Check whether a given String is a valid command word.
* @param aString the command word
* @return true if it is, false if it isn't.
public boolean isCommand(String aString)
for(int i = 0; i < validCommands.length; i++) {
if(validCommands.equals(aString))
return true;
// if we get here, the string was not found in the commands
return false;
* Return a string containing all valid commands.
* @return string of all valid commands
public String getCommandList()
String s="";
for(String command: validCommands) {
s += command + " ";
return s;
right, sorry, that was thoughtless of me.
class Parser
import java.util.Scanner;
import java.util.StringTokenizer;
//I read the documentation for String Tokenizer, and I have a few questions relating to a pet project of mine. The //project is to build a boolean algebra simplifer. I would give it a boolean expression and it will simplify it for me.
//Which is very similar to what this class does. The documentation mentioned a delimiter for separating the tokens.
//yet I see none here, is the delimiter at default, the space between the words? and if I were to set manually //delimiters, how do I do that?
//Once I read in the string, should it be Parser's job to execute the boolean simplification part? According the RDD,
//it shouldn't, but doing so would keep everything in fewer classes and therefore easier to manage, wouldn't it?
* This class is part of the "World of Zuul" application.
* "World of Zuul" is a very simple, text based adventure game.
* This parser reads user input and tries to interpret it as an "Adventure"
* command. Every time it is called it reads a line from the terminal and
* tries to interpret the line as a two word command. It returns the command
* as an object of class Command.
* The parser has a set of known command words. It checks user input against
* the known commands, and if the input is not one of the known commands, it
* returns a command object that is marked as an unknown command.
* @author Michael Kolling and David J. Barnes
* @version 2006.03.30
* @author L.S. Marshall
* @version 1.01 October 9, 2007
public class Parser
private CommandWords commands; // holds all valid command words
private Scanner reader; // source of command input
* Create a parser to read from the terminal window.
public Parser()
commands = new CommandWords();
reader = new Scanner(System.in);
* Command returns the command typed by the user.
* @return The next command from the user.
public Command getCommand()
String inputLine; // will hold the full input line
String word1 = null;
String word2 = null;
System.out.print("> "); // print prompt
inputLine = reader.nextLine();
// Find up to two words on the line.
Scanner tokenizer = new Scanner(inputLine);
if(tokenizer.hasNext()) {
word1 = tokenizer.next(); // get first word
if(tokenizer.hasNext()) {
word2 = tokenizer.next(); // get second word
// note: we just ignore the rest of the input line.
// Now check whether this word is known. If so, create a command
// with it. If not, create a "null" command (for unknown command).
if(commands.isCommand(word1)) {
return new Command(word1, word2);
else {
return new Command(null, word2);
* Returns a list of valid command words.
* @string list of valid command words
public String getCommands()
return commands.getCommandList();
} -
802.1x EAP-PEAP over Ethernet need help !!!
I am trying to get wired 802.1x EAP-PEAP to work and after spending about 8 hours
troubleshooting this, I am not sure what else to do. Need help. Here
is the scenario:
- Cisco Catalyst 3350 switch running IOS versionc3550-ipservicesk9-mz.122-44.SE6.bin,
- Steelbelted/JUniper Radius Server version 6.1.6 on a windows 2003 server
with IP address of 129.174.2.7. This device is connected to the same switch above.
Firewall is OFF on the server, allow ALL,
- Windows 2003 Enterprise Server supplicant with the latest Service pack and patches. Again,
Firewall is OFF on the server, allow ALL. Juniper has verified the configuration settings
on the Supplicant machine. The supplicant has a static IP address of 129.174.2.15, same subnet
as the radius server, I just want enable EAP-PEAP so that user is forced to authenticate before
the port is activate to be "hot".
- Juniper TAC has verified the configuration on the Steelbelted radius for eap-peap
and that everything is looking fine,
I have verified that the switch can communicate fine with the radius server.
- Configuration on the switch for 802.1x:
aaa new-model
aaa authentication dot1x default group radius
radius-server host 129.174.2.7 auth-port 1812 acct-port 1813 key 123456
interface FastEthernet0/39
description windows 2003 Supplicant
switchport access vlan 401
switchport mode access
dot1x port-control auto
no spanning-tree portfast (does not matter if this is enable or disable)
lab-sw-1#
.May 20 07:52:47.334: dot1x-packet:Received an EAP request packet from EAP for mac 0000.0000.0000
.May 20 07:52:47.338: dot1x-packet:dot1x_mgr_send_eapol :EAP code: 0x1 id: 0x2 length: 0x0005 type: 0x1 data:
.May 20 07:52:47.338: EAPOL pak dump Tx
.May 20 07:52:47.338: EAPOL Version: 0x2 type: 0x0 length: 0x0005
.May 20 07:52:47.338: EAP code: 0x1 id: 0x2 length: 0x0005 type: 0x1
.May 20 07:52:47.338: dot1x-packet:dot1x_txReq: EAPOL packet sent out for the default authenticator
lab-sw-1#
lab-sw-1#sh dot1x interface f0/39
Dot1x Info for FastEthernet0/39
PAE = AUTHENTICATOR
PortControl = AUTO
ControlDirection = Both
HostMode = SINGLE_HOST
Violation Mode = PROTECT
ReAuthentication = Disabled
QuietPeriod = 60
ServerTimeout = 30
SuppTimeout = 30
ReAuthPeriod = 3600 (Locally configured)
ReAuthMax = 2
MaxReq = 2
TxPeriod = 30
RateLimitPeriod = 0
lab-sw-1#
I am at a complete lost here. don't know what else to do. Someone with expertise in this realm please
help me how to make this work.
Many thanks in advance,#1: dot1x system-auth-control is already in the switch configuration
#2: Not sure if you're already aware, the minute I entered "dot1x port-control auto", the command "dot1x pae authenticator" automatically appears on the interface configuration
The case is being worked on by Cisco TAC. One of the issues is the windows 2003 server supplicant refuses to work. Windows XP supplicant uses machine-authentication instead of user-authentication. Cisco TAC is looking into this issue. -
Editable field with F4 help in alv tree output using cl_gui_alv_tree
HI
i need Editable field with F4 help in alv tree output using cl_gui_alv_tree
Regards
NareshHi Naresh,
Pass the field catalog with the additional parameter (ls_fcat-edit = 'X'.).
for F4 help if the data element have the search help it automatically will come. other wise include the additional parameter in the field catalog (ls_fcat-F4AVAILABL = 'X')
Reward if found helpful.
Regards,
Boobalan Suburaj -
Apple AND Microsoft techs stumped; workarounds impractical. I need help.
I've got one that techs at Apple and MS have so far been unable to resolve, except with workarounds that aren't really practical.
The problem I'm going to describe happened first in Office v.X. Not knowing where those discs were to reinstall even if I wanted to, I went out today and bought Office 2004. After installing the new software and downloading all the updates, the problem didn't go away.
Here's what happens, and it only happens with Word and Excel. I can open both programs. The menu bars for each show up across the top. However, the document or spreadsheet window is not there. It simply isn't on the desk top. It isn't "spaced" away. It's not hidden (I've tried turning on and off the hide window, and nothing happens). I can even minimize the window through the drop down menus, and a document or spreadsheet icon will show up in the dock.
What I've done with the techs:
Created a second administrator account. The programs work well in that account. The workaround would be then to migrate all of my 250 gigs of info to that new account, and discard the prior admin account. Whatever is affecting the operation of the MS programs could possibly migrate as well.
MS techs had me delete all of the preferences and the Normal template for the MS programs. Nothing changes.
Reinstall Office 2004. This was a time waster, as the problem existed before the initial installation of Office 2004. Reinstalling it didn't eliminate whatever conflict was happening.
I put an Excel file into my shared folder, and was able to open it successfully in the second admin account I created.
The MS techs had me do a Safe Boot, and that seemed to solve the problem once I restarted in a regular configuration. Except that the document and spread sheet windows disappeared after being open for about 10 minutes.
Please note: The applications are opening, and "believe" that the documents I opened are indeed there. I can even see the info in each spreadsheet cell in the menu bar. It's just that there's no document window. It's not behind my desk top. It's not hidden. It's not spaced. It just isn't there.
I need help please.
Has this happened to anyone else? Is there another place I should look for conflicting files or glitches? I really don't want a workaround. These two programs should work seamlessly with Leopard.Obviously you have an incompatibility with some previously installed software. Since Office works with a 'virgin' account the problem isn't system wide. It's likely confined to the ~/Library folder tree. So you can start the slow and tedious process of moving files from <badaccount>/Library/* to <goodaccount>/Library/* in a systematic way. After you move a folder, launch and test Word. Then move more folders over. Launch and test again.
Eventually you will break <goodaccount> and the last folder you moved is likely to be the culprit. -
Need help - Catalyst 3550 on CCM4.1 Voip
Guys.
We had a Catalyst 3550 switch fail last week, and the guy who really knows this system has left the company.
The switch has a non-free molecules error, which i believe is terminal.
I've sourced a replacement switch and need help configuring it.
I copied the running config from it's sister switch (there are only 2 switches on this ccm), however, the sister switch is a 3560.
I changed the I.P address and switch name before uploading it to the 3550 on the off chance it might just work.
Show run on the 3550 shows that it might be configured, but when i connected it, it took the gateway down.
I'm really up the creek at the moment unless i can get someone to either look at it, find an old config or get this guy back in for a few hours.
Any advice would be greatly received.
Looking at show run, i see two refernces to VLAN's
interface Vlan1
ip address 170.205.238.3 255.255.255.0
interface Vlan10
ip address 10.10.0.254 255.255.255.0
ip classless
ip route 0.0.0.0 0.0.0.0 170.205.238.1
no ip http server
The I.P address 170.205.238.1 is alien to me.. i don't know what this is. However, what i do know is that i never changed this. This IP address is the same in the 3560.
Could this cause an issue ?. I'm not aware of anything on a 170.X.X.X subnet, this could have been some legacy from the previous owners of the building.
The first 3 ports in the switch are connected to the publisher, subscriber and gateway router.
Does it matter which port is connected to which component. ?
I believe that i can't be too far away from configuring this, but without any help, i'm a bit stuck.
LEE-SW-CC_VOIP-01#show run
Building configuration...
Current configuration : 6147 bytes
version 12.1
no service pad
service timestamps debug datetime msec
service timestamps log datetime msec
service password-encryption
hostname LEE-SW-CC_VOIP-01
enable secret 5 $1$2BRP$UtiYkRMAsp7roykkfRDo3/
username cisco privilege 15 secret 5 $1$mh3w$w8H5ygAfDUOBdiE2UftB8.
ip subnet-zero
ip routing
vtp domain LEE
vtp mode transparent
mls qos map cos-dscp 0 8 16 26 32 46 48 56
mls qos
no file verify auto
spanning-tree mode pvst
spanning-tree extend system-id
vlan 10
interface FastEthernet0/1
switchport access vlan 10
switchport mode access
switchport voice vlan 10
no ip address
mls qos trust device cisco-phone
mls qos trust cos
auto qos voip cisco-phone
spanning-tree portfast
interface FastEthernet0/2
switchport access vlan 10
switchport mode access
switchport voice vlan 10
no ip address
mls qos trust device cisco-phone
mls qos trust cos
auto qos voip cisco-phone
spanning-tree portfast
interface FastEthernet0/3
switchport access vlan 10
switchport mode access
switchport voice vlan 10
no ip address
mls qos trust device cisco-phone
mls qos trust cos
auto qos voip cisco-phone
spanning-tree portfast
interface FastEthernet0/4
switchport access vlan 10
switchport mode access
switchport voice vlan 10
no ip address
mls qos trust device cisco-phone
mls qos trust cos
auto qos voip cisco-phone
spanning-tree portfast
interface FastEthernet0/5
switchport access vlan 10
switchport mode access
switchport voice vlan 10
no ip address
mls qos trust device cisco-phone
mls qos trust cos
auto qos voip cisco-phone
spanning-tree portfast
interface FastEthernet0/6
switchport mode access
switchport voice vlan 10
no ip address
mls qos trust device cisco-phone
mls qos trust cos
auto qos voip cisco-phone
spanning-tree portfast
interface FastEthernet0/7
switchport mode access
switchport voice vlan 10
no ip address
mls qos trust device cisco-phone
mls qos trust cos
auto qos voip cisco-phone
spanning-tree portfast
interface FastEthernet0/8
switchport mode access
switchport voice vlan 10
no ip address
mls qos trust device cisco-phone
mls qos trust cos
auto qos voip cisco-phone
spanning-tree portfast
interface FastEthernet0/9
switchport mode access
switchport voice vlan 10
no ip address
mls qos trust device cisco-phone
mls qos trust cos
auto qos voip cisco-phone
spanning-tree portfast
interface FastEthernet0/10
switchport mode access
switchport voice vlan 10
no ip address
mls qos trust device cisco-phone
mls qos trust cos
auto qos voip cisco-phone
spanning-tree portfast
interface FastEthernet0/11
switchport mode access
switchport voice vlan 10
no ip address
mls qos trust device cisco-phone
mls qos trust cos
auto qos voip cisco-phone
spanning-tree portfast
interface FastEthernet0/12
switchport mode access
switchport voice vlan 10
no ip address
mls qos trust device cisco-phone
mls qos trust cos
auto qos voip cisco-phone
spanning-tree portfast
interface FastEthernet0/13
switchport mode access
switchport voice vlan 10
no ip address
mls qos trust device cisco-phone
mls qos trust cos
auto qos voip cisco-phone
spanning-tree portfast
interface FastEthernet0/14
switchport mode access
switchport voice vlan 10
no ip address
mls qos trust device cisco-phone
mls qos trust cos
auto qos voip cisco-phone
spanning-tree portfast
interface FastEthernet0/15
switchport mode access
switchport voice vlan 10
no ip address
mls qos trust device cisco-phone
mls qos trust cos
auto qos voip cisco-phone
spanning-tree portfast
interface FastEthernet0/16
switchport mode access
switchport voice vlan 10
no ip address
mls qos trust device cisco-phone
mls qos trust cos
auto qos voip cisco-phone
spanning-tree portfast
interface FastEthernet0/17
switchport mode access
switchport voice vlan 10
no ip address
mls qos trust device cisco-phone
mls qos trust cos
auto qos voip cisco-phone
spanning-tree portfast
interface FastEthernet0/18
switchport mode access
switchport voice vlan 10
no ip address
mls qos trust device cisco-phone
mls qos trust cos
auto qos voip cisco-phone
spanning-tree portfast
interface FastEthernet0/19
switchport mode access
switchport voice vlan 10
no ip address
mls qos trust device cisco-phone
mls qos trust cos
auto qos voip cisco-phone
spanning-tree portfast
interface FastEthernet0/20
switchport mode access
switchport voice vlan 10
no ip address
mls qos trust device cisco-phone
mls qos trust cos
auto qos voip cisco-phone
spanning-tree portfast
interface FastEthernet0/21
switchport mode access
switchport voice vlan 10
no ip address
mls qos trust device cisco-phone
mls qos trust cos
auto qos voip cisco-phone
spanning-tree portfast
interface FastEthernet0/22
switchport mode access
switchport voice vlan 10
no ip address
mls qos trust device cisco-phone
mls qos trust cos
auto qos voip cisco-phone
spanning-tree portfast
interface FastEthernet0/23
switchport mode access
switchport voice vlan 10
no ip address
mls qos trust device cisco-phone
mls qos trust cos
auto qos voip cisco-phone
spanning-tree portfast
interface FastEthernet0/24
switchport mode access
switchport voice vlan 10
no ip address
mls qos trust device cisco-phone
mls qos trust cos
auto qos voip cisco-phone
spanning-tree portfast
interface GigabitEthernet0/1
switchport trunk encapsulation dot1q
switchport mode trunk
no ip address
mls qos trust cos
udld port aggressive
auto qos voip trust
interface GigabitEthernet0/2
switchport trunk encapsulation dot1q
switchport mode trunk
no ip address
mls qos trust cos
udld port aggressive
auto qos voip trust
priority-queue out
interface Vlan1
ip address 170.205.238.3 255.255.255.0
interface Vlan10
ip address 10.10.0.254 255.255.255.0
ip classless
ip route 0.0.0.0 0.0.0.0 170.205.238.1
no ip http server
logging trap debugging
line con 0
exec-timeout 0 0
privilege level 15
login local
line vty 0 4
privilege level 15
login local
length 0
line vty 5 15
privilege level 15
login local
length 0
end
LEE-SW-CC_VOIP-01#Always wanting to learn more, I re-instated the test config and ran those commands.
LEE-SW-CC_VOIP-01#show cdp neighbor
Capability Codes: R - Router, T - Trans Bridge, B - Source Route Bridge
S - Switch, H - Host, I - IGMP, r - Repeater, P - Phone
Device ID Local Intrfce Holdtme Capability Platform Port ID
LEE-SW-CC_VOIP-01#show ip int brief
Interface IP-Address OK? Method Status Prot
ocol
Vlan1 170.205.238.2 YES NVRAM up down
Vlan10 10.10.0.254 YES NVRAM up down
FastEthernet0/1 unassigned YES unset down down
FastEthernet0/2 unassigned YES unset down down
FastEthernet0/3 unassigned YES unset down down
FastEthernet0/4 unassigned YES unset down down
FastEthernet0/5 unassigned YES unset down down
FastEthernet0/6 unassigned YES unset down down
FastEthernet0/7 unassigned YES unset down down
FastEthernet0/8 unassigned YES unset down down
FastEthernet0/9 unassigned YES unset down down
FastEthernet0/10 unassigned YES unset down down
FastEthernet0/11 unassigned YES unset down down
FastEthernet0/12 unassigned YES unset down down
FastEthernet0/13 unassigned YES unset down down
FastEthernet0/14 unassigned YES unset down down
FastEthernet0/15 unassigned YES unset down down
FastEthernet0/16 unassigned YES unset down down
FastEthernet0/17 unassigned YES unset down down
FastEthernet0/18 unassigned YES unset down down
FastEthernet0/19 unassigned YES unset down down
FastEthernet0/20 unassigned YES unset down down
FastEthernet0/21 unassigned YES unset down down
FastEthernet0/22 unassigned YES unset down down
FastEthernet0/23 unassigned YES unset down down
FastEthernet0/24 unassigned YES unset down down
GigabitEthernet0/1 unassigned YES unset down down
GigabitEthernet0/2 unassigned YES unset down down
LEE-SW-CC_VOIP-01# -
I think I need help with driver (software) settings for D110a
I think I need help with driver (software) settings for D110a all-in-one
Product: D110a all-in-one
OS: Windows XP Professional
Error messages: None
Changes before problem appeared: None--new installation
The quality of photo images (mostly JPG files) in printouts is awful even though the files display beautifully on the PC screen. I am using
IrfanView software for displaying/printing. As far as I can tell, IrfanView is not the problem.
When I print the same images on a Deskjet 5150 attached to a different PC also running XP Pro and IrfanView, the quality of the printouts is at
least acceptable, Some would probably say good or very good.
It's dificult to explain in words the problem with the printouts. A picture of really pretty vegetables (squashes, tomatoes, watermelon, etc) comes
out much too red. Moreover, the red, which appears shaded on the screen, seems to be all one shade in the D110a printouts.
Something similar happens to a view of a huge tree in full leaf. On screen, there are subtle variations in the "greenness" of the leaves. In the
printout, all green is the same shade. In the same printout, the trunk of the tree is all a single shade of grey. It isn;t even obvious that the
trunk is a round, solid object.
I liken the effect to audio that disappears entirely when you lower the volume and gets clipped into square waves in even moderately loud passages.
I don't know whether the D110a driver software permits adjusting the parameters that appear to be set incorrectly, and if adjustments are possible,
how I would identify which parameters to adjust, how I would access them, or how I would adjust them. I'm hoping that someone can help. Thanks.
I forgot to mention that I have used the diagnostic application and it tells me that there are no problems.
e-mail me at [email protected]brazzmonkey wrote:
Hi everyone,
I noticed the following message when network starts on my gateway
Warning: This functionality is deprecated.
Please refer to /etc/rc.conf on how to define a single wired
connection, or use a utility such as netcfg.
Then I realized the way network settings should be written in rc.conf has changed. But I can't figure out how this should be done.
Currently, my set up is the following (old way):
INTERFACES=(eth0 eth1)
eth0="dhcp"
eth1="eth1 192.168.0.10 netmask 255.255.255.0 broadcast 192.168.0.255"
ROUTES=(!gateway)
eth0 is on DHCP because the IP is dynamically assigned my ISP.
eth1 has a fix IP because it's on the LAN side.
No problem to use DHCP on eth0 with the new settings.
But for eth1, I don't know what I am supposed to write for gateway.
Wiki isn't clear on that one either, and it looks like many articles still refer to the old way.
Any guidance appreciated, thanks.
brazzmonkey,
you can't define 2 interfaces the old way (even though I saw some tricky workaround somewhere in the forums).
Use, f.e., netcfg:
Comment your old lines.
In /etc/rc.conf insert:
NETWORKS=(Eth0-dhcp Eth1-static)
DAEMONS=(..... !network @net-profiles ....)
In /etc/network.d create 2 files:
First one is named Eth0-dhcp.
Contents:
CONNECTION="ethernet"
DESCRIPTION="Whatever text"
INTERFACE=eth0
HOSTNAME="your hostname"
IP="dhcp"
DHCP_TIMEOUT=15
Second one is named Eth1-static.
Contents:
CONNECTION='ethernet'
DESCRIPTION='whatver'
INTERFACE='eth1'
HOSTNAME='hname'
IP='static'
ADDR='192.168.0.10'
GATEWAY='192.168.0.1' # your gateway IP
DNS=('192.168.0.1') # your DNS server
The names Eth0-dhcp and Eth1-static are not magic. They just must be the same in rc.conf and in /etc/network.d.
Hope it helps.
mektub
PS: netcfg must be installed.
Last edited by Mektub (2011-07-20 14:07:05) -
Mac started hanging up while streamlining a kids show. Restarted and got the screen with the apple and the circle. restarted with control-option p and r. Ran disk repairitem got the following results;
invalid index key,
it rebuilds catalog b-tree,
volume repair complete,
updating boot support partitions for the volume as required,
Error disk utility can't repair disk
I'm then prompted to back up all files, reformat the disk and restore backed up files.
Obviously need help here as I think I'm in danger of losing my files, photos etc if I don't do this right.
Can anyone help
SteveYou might want to back up the disk as soon as possible, do the repair, then back it up again. First time will have the issues that Disk Utility can't fix, however, you'll have the data saved. Then, once you get things repaired, make a new backup, and go from there.
If you're going to use a hard drive directly connected to your iMac for backup, this is what I mentioned earlier: http://twelvesouth.com/products/backpack/ Great way to use space behind the iMac without adding something else to the desk top. You can buy it through Apple online/stores or Amazon, and there are probably other sources too.
For external hard drives, I like those sold by OWC at http://eshop.macsales.com/shop/firewire/ as many of them use Oxford chip sets, wihch work well with macs (I've used several for years with no issues). Most pre-packaged drive/cases have a 3 year warranty, although you can buy a case and add your own hard drive. I like Western Digital Scorpio Blacks that have a 5 year warranty. -
Need help implimenting PLUS ldf in c++ via XMP sdk
I'm apparently suffering major brainstem bitrot and generating lots of brain coredumps, and I need help.
I'm using the XMP toolkit sdk 5.1.2 in c++ under gcc on Debian to impliment embedding PLUS ldf licensing metadata (reference: http://ns.useplus.org/LDF/ldf-XMPReference ) into images.
I have no problems generating compliant plus ldf xmp in code for everything EXCEPT for single line detail entries like "<rdf:type rdf:resource="plus:LicenseeDetail"/>" in several places in the ldf specification, viz:
<plus:Licensee>
<rdf:Seq>
<rdf:li>
<rdf:type rdf:resource="plus:LicenseeDetail"/>
<plus:LicenseeID>http://plus-id.org/AAA-987</plus:LicenseeID>
<plus:LicenseeName>ABC Advertising Agency</plus:LicenseeName>
</rdf:li>
</rdf:Seq>
</plus:Licensee>
I can generate the appropriate text in memory then parse that to get an appropriate SXMPMeta and merge that, but I would really like to be able to properly generate the proper xmp in code, and would really appreciate any help preventing further brainrot!
I'm certain it's both simple and trivial, but I now can't see the trees because of the forest ... ThanksHi,
I'm not a XMP expert but I've been working for some years with Semantic Web technologies. My understanding is that XMP is a subset of RDF (one of the main pieces of the Semantic Web) so I will try to make my contribution to this problem from there.
Consequently, looking at your problematic piece of XMP:
<plus:Licensee>
<rdf:Seq>
<rdf:li>
<rdf:type rdf:resource="plus:LicenseeDetail"/>
<plus:LicenseeID>http://plus-id.org/AAA-987</plus:LicenseeID>
<plus:LicenseeName>ABC Advertising Agency</plus:LicenseeName>
</rdf:li>
</rdf:Seq>
</plus:Licensee>
I can say that it isn't valid RDF so it shouldn't be proper XMP. This can be confirmed looking at the example for the property plus:Licensee available from the specification (http://ns.useplus.org/LDF/ldf-XMPSpecification#Licensee):
<plus:Licensee>
<rdf:Seq>
<rdf:li rdf:parseType="Resource">
<rdf:type rdf:resource="plus:LicenseeDetail"/>
<plus:LicenseeID>http://plus-id.org/AAA-987</plus:LicenseeID>
<plus:LicenseeName>ABC Advertising Agency</plus:LicenseeName>
</rdf:li>
</rdf:Seq>
</plus:Licensee>
I have marked in bold where the problem is. Your piece of XML is missing the rdf:parseType="Resource" construct. I will explain why this is necessary from what I know from RDF. RDF is based on a graph model. There are resources, which correspond to graph nodes and represent the things the RDF metadata is talking about, and properties, which correspond to graph edges and represent the attributes and relations used to say things about the resources.
In RDF the convention is to use lowercase names for properties. This doesn't seem to be the convention in XMP so we must take a closer look at the XMP piece in order to identify what parts correspond to resources and to properties. From the LDF specification we know that plus:Licensee correspond to a property so it should link to a resource, in this case rdf:Seq (more specifically it is an anonymous resource (no id provided) of type rdf:Seq). Your example should have some additional markup before plus:Licensee, surely the resource that represents the licensee about which we are specifying the licensee using the plus:Licensee property.
Now, if we continue from the resource of type rdf:Seq, there is the rdf:li property (lower case as it is directly reused from the RDF specification). The problem now is that if we look directly inside rdf:li property we find rdf:type, plus:LicenseeID and plus:LicenseeName. It is clear that rdf:type (lowercase) is a property and from the LDF specification we can see that the other two also correspond to properties. Therefore, there is the problem. We have a property (rdf:li) pointing to three properties (rdf:type,...) so we are breaking the graph data model: nodes (resources) are connected through edges (properties) that link two nodes.
This is not the case for the example in the LDF specification. The rdf:parseType="Resource" constructs is a shortcut for:
<rdf:li>
<rdf:Resource>
<rdf:type rdf:resource="plus:LicenseeDetail"/>
<plus:LicenseeID>http://plus-id.org/AAA-987</plus:LicenseeID>
<plus:LicenseeName>ABC Advertising Agency</plus:LicenseeName>
</rdf:Resource>
</rdf:li>
It basically says that the following properties should be parsed as being connected to an anonymous resource. In order to make it clearer, it is helpful to look at the graph behing that markup. For instance, you can use the RDF2SVG service and render the graph behind the example from the specification (which I have make available from a custom URL):
http://rhizomik.net/redefer-services/render?rdf=http://rhizomik.net:8080/html/~roberto/tmp /ldf-simple-example.rdf&format=RDF/XML&mode=svg&rules=http://rhizomik.net:8080/html/redefe r/rdf2svg/showgraph.jrule
I hope all this makes it clearer.
Best,
Roberto García
http://rhizomik.net/~roberto/
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Mail app won't switch to landscape mode?
Hi all, As of this morning my Mail app seems to be stuck in portrait mode. Any clues on how I can resolve this problem? Thanks in advance, Tom.
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I have a SQL 2008 R2 system (10.50.4000) where I'm having problems connecting any user that is not a SysAdmin. Example: I setup a new SQL Login to use Windows Authentication and grant that user db_datareader on the target database. The user attempt
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Search using Metadata & Synonyms
In a document library I've added a metadata column, so tagging information with synonyms can occur. However, I'm not able to search the document library with the tagged metadata or synonym terms. I've created a new managed property within search,
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hi gurus,.. i need a urgent help ...its on information on DELETING AND ARCHIEVING MATERIAL..