If all methods are virtual, what's up with this?

I've got two class
Class A {
public void foo() {
System.out.println("As foo");
public void bar() {
foo();
Class B extends A{
public void foo() {
System.out.println("Bs foo");
Then in my main method
B myB = new B();
myB.foo();
the output is "As foo". Should it not be "Bs foo"? How can I make it execute Bs foo, without giving B it's own bar() method?

Ok, problem solved. My foo() type methods were
actually private. I made them protected and all is
well.And that answers your question as well. Not all methods are virtual.

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hi
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I can't figure out what's wrong with this code

First i want this program to allow me to enter a number with the EasyReader class and depending on the number entered it will show that specific line of this peom:
One two buckle your shoe
Three four shut the door
Five six pick up sticks
Seven eight lay them straight
Nine ten this is the end.
The error message i got was an illegal start of expression. I can't figure out why it is giving me this error because i have if (n = 1) || (n = 2) statements. My code is:
public class PoemSeventeen
public static void main(String[] args)
EasyReader console = new EasyReader();
System.out.println("Enter a number for the poem (0 to quit): ");
int n = console.readInt();
if (n = 1) || (n = 2)
System.out.println("One, two, buckle your shoe");
else if (n = 3) || (n = 4)
System.out.println("Three, four, shut the door");
else if (n = 5) || (n = 6)
System.out.println("Five, six, pick up sticks");
else if (n = 7) || (n = 8)
System.out.println("Seven, eight, lay them straight");
else if (n = 9) || (n = 10)
System.out.println("Nine, ten, this is the end");
else if (n = 0)
System.out.println("You may exit now");
else
System.out.println("Put in a number between 0 and 10");
I messed around with a few other thing because i had some weird errors before but now i have narrowed it down to just this 1 error.
The EasyReader class code:
// package com.skylit.io;
import java.io.*;
* @author Gary Litvin
* @version 1.2, 5/30/02
* Written as part of
* <i>Java Methods: An Introduction to Object-Oriented Programming</i>
* (Skylight Publishing 2001, ISBN 0-9654853-7-4)
* and
* <i>Java Methods AB: Data Structures</i>
* (Skylight Publishing 2003, ISBN 0-9654853-1-5)
* EasyReader provides simple methods for reading the console and
* for opening and reading text files. All exceptions are handled
* inside the class and are hidden from the user.
* <xmp>
* Example:
* =======
* EasyReader console = new EasyReader();
* System.out.print("Enter input file name: ");
* String fileName = console.readLine();
* EasyReader inFile = new EasyReader(fileName);
* if (inFile.bad())
* System.err.println("Can't open " + fileName);
* System.exit(1);
* String firstLine = inFile.readLine();
* if (!inFile.eof()) // or: if (firstLine != null)
* System.out.println("The first line is : " + firstLine);
* System.out.print("Enter the maximum number of integers to read: ");
* int maxCount = console.readInt();
* int k, count = 0;
* while (count < maxCount && !inFile.eof())
* k = inFile.readInt();
* if (!inFile.eof())
* // process or store this number
* count++;
* inFile.close(); // optional
* System.out.println(count + " numbers read");
* </xmp>
public class EasyReader
protected String myFileName;
protected BufferedReader myInFile;
protected int myErrorFlags = 0;
protected static final int OPENERROR = 0x0001;
protected static final int CLOSEERROR = 0x0002;
protected static final int READERROR = 0x0004;
protected static final int EOF = 0x0100;
* Constructor. Prepares console (System.in) for reading
public EasyReader()
myFileName = null;
myErrorFlags = 0;
myInFile = new BufferedReader(
new InputStreamReader(System.in), 128);
* Constructor. opens a file for reading
* @param fileName the name or pathname of the file
public EasyReader(String fileName)
myFileName = fileName;
myErrorFlags = 0;
try
myInFile = new BufferedReader(new FileReader(fileName), 1024);
catch (FileNotFoundException e)
myErrorFlags |= OPENERROR;
myFileName = null;
* Closes the file
public void close()
if (myFileName == null)
return;
try
myInFile.close();
catch (IOException e)
System.err.println("Error closing " + myFileName + "\n");
myErrorFlags |= CLOSEERROR;
* Checks the status of the file
* @return true if en error occurred opening or reading the file,
* false otherwise
public boolean bad()
return myErrorFlags != 0;
* Checks the EOF status of the file
* @return true if EOF was encountered in the previous read
* operation, false otherwise
public boolean eof()
return (myErrorFlags & EOF) != 0;
private boolean ready() throws IOException
return myFileName == null || myInFile.ready();
* Reads the next character from a file (any character including
* a space or a newline character).
* @return character read or <code>null</code> character
* (Unicode 0) if trying to read beyond the EOF
public char readChar()
char ch = '\u0000';
try
if (ready())
ch = (char)myInFile.read();
catch (IOException e)
if (myFileName != null)
System.err.println("Error reading " + myFileName + "\n");
myErrorFlags |= READERROR;
if (ch == '\u0000')
myErrorFlags |= EOF;
return ch;
* Reads from the current position in the file up to and including
* the next newline character. The newline character is thrown away
* @return the read string (excluding the newline character) or
* null if trying to read beyond the EOF
public String readLine()
String s = null;
try
s = myInFile.readLine();
catch (IOException e)
if (myFileName != null)
System.err.println("Error reading " + myFileName + "\n");
myErrorFlags |= READERROR;
if (s == null)
myErrorFlags |= EOF;
return s;
* Skips whitespace and reads the next word (a string of consecutive
* non-whitespace characters (up to but excluding the next space,
* newline, etc.)
* @return the read string or null if trying to read beyond the EOF
public String readWord()
StringBuffer buffer = new StringBuffer(128);
char ch = ' ';
int count = 0;
String s = null;
try
while (ready() && Character.isWhitespace(ch))
ch = (char)myInFile.read();
while (ready() && !Character.isWhitespace(ch))
count++;
buffer.append(ch);
myInFile.mark(1);
ch = (char)myInFile.read();
if (count > 0)
myInFile.reset();
s = buffer.toString();
else
myErrorFlags |= EOF;
catch (IOException e)
if (myFileName != null)
System.err.println("Error reading " + myFileName + "\n");
myErrorFlags |= READERROR;
return s;
* Reads the next integer (without validating its format)
* @return the integer read or 0 if trying to read beyond the EOF
public int readInt()
String s = readWord();
if (s != null)
return Integer.parseInt(s);
else
return 0;
* Reads the next double (without validating its format)
* @return the number read or 0 if trying to read beyond the EOF
public double readDouble()
String s = readWord();
if (s != null)
return Double.parseDouble(s);
// in Java 1, use: return Double.valueOf(s).doubleValue();
else
return 0.0;
Can anybody please tell me what's wrong with this code? Thanks

String[] message = {
    "One, two, buckle your shoe",
    "One, two, buckle your shoe",
    "Three, four, shut the door",
    "Three, four, shut the door",
    "Five, six, pick up sticks",
    "Five, six, pick up sticks",
    "Seven, eight, lay them straight",
    "Seven, eight, lay them straight",
    "Nine, ten, this is the end",
    "Nine, ten, this is the end"
if(n>0)
    System.out.println(message[n]);
else
    System.exit(0);

What's wrong with this Forum? Why does Adobe take so long to reply to posts?!

What's wrong with this Forum? Why does Adobe take so long to reply to posts?!
This is actually "specific" to this Photoshop Forum.
I typically get responses back from other Adobe forum promptly.
Chime in.

The Adobe engineering folks DO duck in here from time to time - and that's a BLESSING! Please name any other big company where you get to interact with the engineers AT ALL. I can't. But I suspect the engineers actually have a lot oof real work to do, and their time here is necessarily limited.
Your comments are more along the line of "I pay a huge amount, for that I expect better support". These are very valid comments. But reality is different from what we may expect, and this forum is not the place to expect Adobe support participation AT ALL. In fact, the technical support people at Adobe often direct users to come here (something I've always found amusing).
At the higher level, Adobe may simply not be spending enough on support for literally millions of users. Is is greed or smart business to try to minimize support cost? That's up for individuals to decide.
I suggest you write a snail-mail letter to the Adobe president if you're not getting the support you need.
-Noel

What's wrong with this simple code?

What's wrong with this simple code? Complier points out that
1. a '{' is expected at line6;
2. Statement expected at the line which PI is declared;
3. Type expected at "System.out.println("Demostrating PI");"
However, I can't figure out them. Please help. Thanks.
Here is the code:
import java.util.*;
public class DebugTwo3
// This class demonstrates some math methods
public static void main(String args[])
          public static final double PI = 3.14159;
          double radius = 2.00;
          double area;
          double roundArea;
          System.out.println("Demonstrating PI");
          area = PI * radius * radius;
          System.out.println("area is " + area);
          roundArea = Math.round(area);
          System.out.println("Rounded area is " + roundArea);

Change your code to this:
import java.util.*;
public class DebugTwo3
     public static final double PI = 3.14159;
     public static void main(String args[])
          double radius = 2.00;
          double area;
          double roundArea;
          System.out.println("Demonstrating PI");
          area = PI * radius * radius;
          System.out.println("area is " + area);
          roundArea = Math.round(area);
          System.out.println("Rounded area is " + roundArea);
Klint

What's wrong with this formula?

What's wrong with this formula? Why am I getting 0?

Mismatch in data types.
Status, "=*Book*" is fine, as the content of the status column is text, and the condition is comparing it to a text string (with wild cards)
But
Event Date, "=*2011*" compares a Date and Time value in Event Date to a text string (with wild cards).
Here's a demonstration, using COUNTIF to stand in for COUNTIFS.
Note that the "book" counts are all correct.
Note that the first Date count counts both occurrences of Jan 2, 2012 in column A, despite the difference in format used in displaying the dates, while the second counts neither, due to the wild card forcing it to look for a text string, not a Date and Time value.
For your case, you'll need a COUNTIFS formula with three test-range, condition pairs:
=COUNTIFS(Schedule :: $A,"=*book*",Schedule :: $B,">="&B2,Schedule :: B,"<="&B3)
Regards,
Barry

What's wrong with this (transparent) picture ...?

There are many posts on the issue of JPG's being converted into PNG's and a variety of replies with sympathetic suggestions for how to avoid this plague.
Many months back I also used to see recommendations of making an iWeb graphic into a very reduced opacity item that can be used as a hyper-link.
But I've yet to see any of the responders directly address the dreaded png's of transparent hyperlinks.
Why not.?
What's wrong with this picture.?
Am I, so far, only partially educated about file type as to be unreasonably anxious about transparent hyper-link png's.?
Has this graphic question just slipped through the cracks because of all the other jpg-into-png avoidance issues.?
Or perhaps, do transparent png's "work-just-fine, thank-you" on a PC's I.E...?
Is it somehow possible to reduce the opacity of an imported JPG without it converting..?
If png's are to be avoided for any of us aiming at the-world-beyond-Mac, then that ought to include the iWeb graphics used for hyper-Links, right.
What is the story..?
Any help appreciated appreciated.!

Nope… it'll more than likely be a problematic G5 software installation. My Mac mini runs a 24" display and can play 720p video just fine with it's extremely crappy Intel GMA950 integrated graphics. It does however frame drop a little with 1080i high motion video. Both Bluetooth and USB mice just work fine. The Mac Pro will have no problems doing any of this.

What's wrong with this code (in recursion there may be a problem )

// ELEMENTS OF TWO VECTORS ARE COMPARED HERE
// CHECK WHAT IS WRONG WITH THIS PGM
// there may be a problem in recursion
import java.util.*;
class Test
Vector phy,db;
public static void main(String adf[])
     Vector pp1=new Vector();
     Vector dp1=new Vector();
     //adding elements to the vector
     pp1.add("1");
     pp1.add("a");
     pp1.add("b");
     pp1.add("h");
     pp1.add("c");
     dp1.add("q");
     dp1.add("c");
     dp1.add("h");
     dp1.add("w");
     dp1.add("t");
     printVector(dp1);
     printVector(pp1);
     check2Vectors(pp1,dp1);
public static void printVector(Vector v1)
     System.out.println("Vector size "+v1.size());
     for(int i=0;i<v1.size();i++)
          System.out.println(v1.get(i).toString());
public static void check2Vectors(Vector p,Vector d)
     System.out.println("p.size() "+p.size()+" d.size() "+d.size());
     printVector(p);
     printVector(d);
     for(int i=0;i<p.size();i++)
               for(int j=0;j<d.size();j++)
                    System.out.println(" i= "+i+" j= "+j);
                    Object s1=p.elementAt(i);
                    Object s2=d.elementAt(j);
          System.out.println("Checking "+s1+" and "+s2);
                    if(s1.equals(s2))
System.out.println("Equal and Removing "+s1+" and "+s2);
                         p.remove(i);
                         d.remove(j);
                         printVector(p);
                         printVector(d);
                    check2Vectors(p,d);
               }//inner for
          }//outer for
if(p.size()==0||d.size()==0)
System.out.println("Vector checking finished and both match");
else
System.out.println("Vector checking finished and both do not match");
}//method
}

hi,
but the upper limit is changing everytime you call the function recursively
so there should not be any problem(i suppose)
my intension is to get the unmatched elements of the two vectors
suggest me changes and thanks in advancce
ashok
The problems comes from the fact that you remove
elements for a Vector while iterating in a loop where
the upper limit as been set to the initial size of the
Vector.
You should use so while loops with flexible stop
conditions that would work when the size of the Vector
changes.
Finally: why don't you use Vector.equals() ?

I just upgraded to Mavericks and now my Intel iMac is running more slowly. There have been no other changes. What's up with this???

I just upgraded to Mavericks and now my Intel iMac is running more slowly. There have been no other changes. What's up with this???

This procedure is a diagnostic test. It changes nothing, for better or worse, and therefore will not, in itself, solve your problem.
If you don't already have a current backup, back up all data before doing anything else. The backup is necessary on general principle, not because of anything in the test procedure. There are ways to back up a computer that isn't fully functional. Ask if you need guidance.
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The script is a single long line, all of which must be selected. You can accomplish this easily by triple-clicking anywhere in the line. The whole line will highlight, though you may not see all of it in your browser, and you can then copy it. If you try to select the line by dragging across the part you can see, you won't get all of it.
Triple-click anywhere in the line of text below on this page to select it:
clear; Fb='%s\n\t(%s)\n'; Fm='\n%s:\n\n%s\n'; Fs='\n%s: %s\n'; Fu='user %s%%, system %s%%'; PB="/usr/libexec/PlistBuddy -c Print"; A () { [[ a -eq 0 ]]; }; R () { o=; [[ r -eq 0 ]]; }; Pm () { [[ "$o" ]] && o=`sed 's/^ */ /' <<< "$o"` && printf "$Fm" "$1" "$o"; }; Pc () { o=`egrep -v '^[[:blank:]]*($|#)' "$2"`; Pm "$1"; }; Pp () { o=`$PB "$2" | awk -F'= ' \/$3'/{print $2}'`; Pm "$1"; }; Ps () { o="${o##+( )}"; [[ ! "$o" =~ ^0?$ ]] && printf "$Fs" "$1" "$o"; }; id | grep -qw '80(admin)'; a=$?; A && sudo true; r=$?; t=`date +%s`; clear; { A || echo $'No admin access\n'; A && ! R && echo $'No root access\n'; system_profiler SPSoftwareDataType | sed '8!d;s/^ *//'; o=`system_profiler SPHardwareDataType | awk '/Mem/{print $2}'`; o=$((o<4?o:0)); Ps "Memory (GB)"; o=`system_profiler SPDiagnosticsDataType | sed '5,6!d'`; [[ "$o" =~ Pass ]] || Pm "POST"; o=`pmset -g therm | sed 's/^.*CP/CP/'`; egrep -q 'No th|pms' <<< "$o" && o=; Pm "Thermal conditions"; o=`pmset -g sysload | grep -v :`; grep -q '= [^GO]' <<< "$o" || o=; Pm "System load advisory"; o=`nvram boot-args | awk '{$1=""; print}'`; Ps "boot-args"; d=(/ ""); D=(System User); for i in 0 1; do o=`cd ${d[$i]}L*/L*/Dia* && ls | grep -v 'ag$' | tail | awk -F_ '{$NF=a[split($NF,a,".")]; print}'`; Pm "${D[$i]} diagnostics"; done; o=`syslog -F bsd -k Sender kernel -k Message CReq 'GPU |hfs: Ru|I/O e|n Cause: -|NVDA\(|pagin|SATA W|ssert|timed? ?o' | tail -n25 | awk '/:/{$4=""; $5=""; print}'`; Pm "Kernel messages"; o=`df -m / | awk 'NR==2 {print $4}'`; o=$((o<5120?o:0)); Ps "Free space (MiB)"; o=$(($(vm_stat | awk '/eo/{sub("\\.",""); print $2}')/256)); o=$((o>=1024?o:0)); Ps "Pageouts (MiB)"; s=( `sar -u 1 10 | sed '$!d'` ); [[ s[4] -lt 85 ]] && o=`printf "$Fu" ${s[1]} ${s[3]}` || o=; Ps "Total CPU usage" && { s=(`ps acrx -o comm,ruid,%cpu | sed '2!d'`); o=${s[2]}%; Ps "CPU usage by process \"$s\" with UID ${s[1]}"; }; s=(`top -R -l1 -n1 -o prt -stats command,uid,prt | sed '$!d'`); s[2]=${s[2]%[+-]}; o=$((s[2]>=25000?s[2]:0)); Ps "Mach ports used by process \"$s\" with UID ${s[1]}"; o=`kextstat -kl | grep -v com\\.apple | cut -c53- | cut -d\< -f1`; Pm "Loaded extrinsic kernel extensions"; R && o=`sudo launchctl list | sed 1d | awk '!/0x|com\.(apple|openssh|vix\.cron)|org\.(amav|apac|calendarse|cups|dove|isc|ntp|post[fg]|x)/{print $3}'`; Pm "Extrinsic system jobs"; o=`launchctl list | sed 1d | awk '!/0x|com\.apple|org\.(x|openbsd)|\.[0-9]+$/{print $3}'`; Pm "Extrinsic agents"; o=`find -L {/,}L*/Lau* -type f -exec sh -c 'file -b "$1" | grep -qw XML' {} {} \; -print | while read f; do ID=$($PB\ :Label "$f") || ID="No job label"; printf "$Fb" "$f" "$ID"; done`; Pm "launchd items"; o=`find -L /{S*/,}L*/Star* -type f -exec sh -c 'file -b "$1" | egrep -q "XML|bin|exec"' {} {} \; -print`; Pm "StartupItems"; o=`find -L /S*/L*/E* {/,}L*/{A*d,Compon,Ex,In,Keyb,Mail,P*P,Qu,Scripti,Servi,Spo}* -type d -name Contents -prune | while read d; do ID=$($PB\ :CFBundleIdentifier "$d/Info.plist") || ID="No bundle ID"; egrep -qv "^com\.apple\.[^x]|Accusys|ArcMSR|ATTO|HDPro|HighPoint|driver\.stex|hp-fax|\.hpio|JMicron|microsoft\.MDI|print|SoftRAID" <<< $ID && printf "$Fb" "${d%/Contents}" "$ID"; done`; Pm "Extrinsic loadable bundles"; o=`find -L /u*/{,*/}lib -type f -exec sh -c 'file -b "$1" | grep -qw shared && ! codesign -v "$1"' {} {} \; -print`; Pm "Unsigned shared libraries"; o=`launchctl getenv DYLD_INSERT_LIBRARIES`; Pm "Inserted libraries"; o=`find -L {,/u*/lo*}/e*/periodic -type f -mtime -10d`; Pm "Modified periodic scripts"; o=`scutil --proxy | grep Prox`; Pm "Proxies"; o=`scutil --dns | awk '/r\[0\] /{if ($NF !~ /^1(0|72\.(1[6-9]|2[0-9]|3[0-1])|92\.168)\./) print $NF; exit}'`; Ps "DNS"; R && o=`sudo profiles -P | grep : | wc -l`; Ps "Profiles"; for f in fstab sysctl.conf crontab launchd.conf; do Pc $f /etc/$f; done; Pc "hosts" <(grep -v 'host *$' /etc/hosts); Pc "User launchd" ~/.launchd; R && Pc "Root crontab" <(sudo crontab -l); Pc "User crontab" <(crontab -l); R && o=`sudo defaults read com.apple.loginwindow LoginHook`; Pm "Login hook"; Pp "Global login items" /L*/P*/loginw* Path; Pp "User login items" L*/P*/*loginit* Name; Pp "Safari extensions" L*/Saf*/*/E*.plist Bundle | sed 's/\..*$//;s/-[1-9]$//'; o=`find ~ $TMPDIR.. $ -flags +sappnd,schg,uappnd,uchg -o ! -user $UID -o ! -perm -600 $ | wc -l`; Ps "Restricted user files"; cd; o=`system_profiler SPFontsDataType | egrep "Valid: N|Duplicate: Y" | wc -l`; Ps "Font problems"; o=`find L*/{Con,Pref}* -type f ! -size 0 -name *.plist ! -exec sh -c 'plutil -s "$1" >&-' {} {} \; -print`; Pm "Bad plists"; d=(Desktop L*/Keyc*); n=(20 7); for i in 0 1; do o=`find "${d[$i]}" -type f -maxdepth 1 | wc -l`; o=$((o<=n[$i]?0:o)); Ps "${d[$i]##*/} files"; done; o=$((`date +%s`-t)); Ps "Elapsed time (s)"; } 2>/dev/null | pbcopy; exit 2>&-
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Can someone tell me what's wrong with this LOV query please?

This query works fine..
select FILTER_NAME display_value, FILTER_ID return_value
from OTMGUI_FILTER where username = 'ADAM'
But this one..
select FILTER_NAME display_value, FILTER_ID return_value
from OTMGUI_FILTER where username = apex_application.g_user
Gives the following error.
1 error has occurred
* LOV query is invalid, a display and a return value are needed, the column names need to be different. If your query contains an in-line query, the first FROM clause in the SQL statement must not belong to the in-line query.
Thanks very much,
-Adam vonNieda

Ya know, I still don't know what's wrong with this.
declare
l_val varchar2(100) := nvl(apex_application.g_user,'ADAM');
begin
return 'select filter_name display_value, filter_id return_value
from otmgui_filter where username = '''|| l_val || '''';
end;
Gets the same error as above. All I'm trying to do is create a dropdown LOV which selects based on the apex_application.g_user.
What am I missing here?
Thanks,
-Adam

If all methods are virtual, what's up with this?

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