Illegal access of database

Dear All,
How to know who has accessed my Production database illegally? There has been a small change on my one table (this table is not under audit) data. Can any one tell the way how to check the users with their machine names are logged on the Database? This will help us to find out the unauthorized user in Oracle RDBMS?
Thanks,

How do you know the access was "illegal"? In order for someone to update the table in question the end user will have had to have access to an Oracle username with the necessary object privileges. SB has identified how you can find the statement that made the change in question. Log miner also has the ability to generate the DML to undo the change.
But why the change was made may come down to an application coding error like an update or delete statement whose where clause fails to properly restrict the target rows for the statement to the correct rows, or you may have a general failing in security practice. This last would include a developer accidentally applying a change intended for test to production because there is too little control over who has access to the production IDs. Pretty much no one should have direct access to the object owners in production.
HTH -- Mark D Powell --

Similar Messages

I m using ms access as database and i want to create a login page in java

hye frnz... plz help me m new to java
m using ms access as database and try to create a login page where user type username and pw
i had enter valid user entries in database i checked connectivity is working i want as user login the main window must open after checking username and pw field to database but
now there is an error class not found exception sun:jdbc...... error
plz help me i had stuck frm 4 days */
import java.sql.DriverManager;
import java.sql.Connection;
import java.sql.Statement;
import java.sql.ResultSet;
import javax.swing.*;
import java.awt.*;
import java.awt.event.*;
class Login extends JFrame
//Component Declarations
JLabel jlb1,jlb2;
     JTextField jtf1;
     JPasswordField jpf1;
     JButton jb1,jb2;
     //Constructor
     Login()
     //frame settings
          setTitle("Login Dialog");
          setLayout(new GridBagLayout());
          GridBagConstraints gbc = new GridBagConstraints();
          setDefaultCloseOperation(JFrame.DISPOSE_ON_CLOSE);
          Dimension d= Toolkit.getDefaultToolkit().getScreenSize();
          setBounds(d.width/2-175,d.height/2-100,350,200);
          gbc.insets=new Insets(7,7,7,7);
     //adding components
          jlb1=new JLabel("User ID");
          gbc.gridx=0;
          gbc.gridy=0;
          add(jlb1,gbc);
          jlb2=new JLabel("Password");
          gbc.gridx=0;
          gbc.gridy=1;
          add(jlb2,gbc);
          jtf1=new JTextField(10);
          gbc.gridx=1;
          gbc.gridy=0;
          add(jtf1,gbc);
          jpf1=new JPasswordField(10);
          gbc.gridx=1;
          gbc.gridy=1;
          add(jpf1,gbc);
          jb1=new JButton("Login");
          gbc.gridx=0;
          gbc.gridy=2;
          add(jb1,gbc);
          jb1.addActionListener(new ActionListener()
               public void actionPerformed(ActionEvent ae)
               Connection conn=null;
                    Statement stmt=null;
                    boolean found=false;
               try
                         Class.forName("sun.jdbc.driver.JdbcOdbcDriver");
                         String dataSourceName = "Inventory";
                         String dbURL = "jdbc:odbc:" + dataSourceName;
                         conn=DriverManager.getConnection(dbURL, "","");
                         stmt=conn.createStatement();
                         ResultSet rst=stmt.executeQuery("Select * from User");
                         System.out.println(jtf1.getText()+"/t"+jpf1.getPassword());
                         while(rst.next())
                              System.out.println( rst.getString(1) +"/t"+ rst.getString(2));
          if(jtf1.getText().equals(rst.getString(1).trim()) && new String(jpf1.getPassword()).equals(rst.getString(2).trim()))
                                   found=true;
                                   rst.close();
                                   dispose();
                                   MainWindow mw= new MainWindow();     /*created min window object created to be opend after login but not working*/
                                   break;
                         rst.close();
                         stmt.close();
                         conn.close();
                    catch(ClassNotFoundException e){System.out.print(e);}
                    catch(Exception e){System.out.print(e);}
                    if(found==false) /*this portion is executing and dialog box appears invalid name and pw with class not found exception sun:jdbc.......on console */
                         JOptionPane.showMessageDialog(null,"Invalid username or password",
                              "Error Message",JOptionPane.ERROR_MESSAGE);
          jb2=new JButton("Clear");
          gbc.gridx=1;
          gbc.gridy=2;
          add(jb2,gbc);
          jb2.addActionListener(new ActionListener()
               public void actionPerformed(ActionEvent ae)
                    jtf1.setText("");
                    jpf1.setText("");
                    jtf1.requestFocus();
          setSize(350,200);
          setVisible(true);
          jtf1.requestFocus();
     public static void main(String args[])
Login l=new Login();
}

http://forums.oracle.com/forums/ann.jspa?annID=599
Oh, and by the way, your keyboard seems to be broken as your words are not getting spelled correctly.

Plz help using ms access as database,i want to create a login page in java

hye frnz... plz help me m new to java
m using ms access as database and try to create a login page where user type username and pw
i had enter valid user entries in database i checked connectivity is working i want as user login the main window must open after checking username and pw field to database but
now there is an error class not found exception sun:jdbc...... error
plz help me i had stuck frm 4 days */
import java.sql.DriverManager;
import java.sql.Connection;
import java.sql.Statement;
import java.sql.ResultSet;
import javax.swing.*;
import java.awt.*;
import java.awt.event.*;
class Login extends JFrame
//Component Declarations
JLabel jlb1,jlb2;
     JTextField jtf1;
     JPasswordField jpf1;
     JButton jb1,jb2;
     //Constructor
     Login()
     //frame settings
          setTitle("Login Dialog");
          setLayout(new GridBagLayout());
          GridBagConstraints gbc = new GridBagConstraints();
          setDefaultCloseOperation(JFrame.DISPOSE_ON_CLOSE);
          Dimension d= Toolkit.getDefaultToolkit().getScreenSize();
          setBounds(d.width/2-175,d.height/2-100,350,200);
          gbc.insets=new Insets(7,7,7,7);
     //adding components
          jlb1=new JLabel("User ID");
          gbc.gridx=0;
          gbc.gridy=0;
          add(jlb1,gbc);
          jlb2=new JLabel("Password");
          gbc.gridx=0;
          gbc.gridy=1;
          add(jlb2,gbc);
          jtf1=new JTextField(10);
          gbc.gridx=1;
          gbc.gridy=0;
          add(jtf1,gbc);
          jpf1=new JPasswordField(10);
          gbc.gridx=1;
          gbc.gridy=1;
          add(jpf1,gbc);
          jb1=new JButton("Login");
          gbc.gridx=0;
          gbc.gridy=2;
          add(jb1,gbc);
          jb1.addActionListener(new ActionListener()
               public void actionPerformed(ActionEvent ae)
               Connection conn=null;
                    Statement stmt=null;
                    boolean found=false;
               try
                         Class.forName("sun.jdbc.driver.JdbcOdbcDriver");
                         String dataSourceName = "Inventory";
                         String dbURL = "jdbc:odbc:" + dataSourceName;
                         conn=DriverManager.getConnection(dbURL, "","");
                         stmt=conn.createStatement();
                         ResultSet rst=stmt.executeQuery("Select * from User");
                         System.out.println(jtf1.getText()+"/t"+jpf1.getPassword());
                         while(rst.next())
                              System.out.println( rst.getString(1) +"/t"+ rst.getString(2));
          if(jtf1.getText().equals(rst.getString(1).trim()) && new String(jpf1.getPassword()).equals(rst.getString(2).trim()))
                                   found=true;
                                   rst.close();
                                   dispose();
                                   MainWindow mw= new MainWindow();     /*created min window object created to be opend after login but not working*/
                                   break;
                         rst.close();
                         stmt.close();
                         conn.close();
                    catch(ClassNotFoundException e){System.out.print(e);}
                    catch(Exception e){System.out.print(e);}
                    if(found==false) /*this portion is executing and dialog box appears invalid name and pw with class not found exception sun:jdbc.......on console */
                         JOptionPane.showMessageDialog(null,"Invalid username or password",
                              "Error Message",JOptionPane.ERROR_MESSAGE);
          jb2=new JButton("Clear");
          gbc.gridx=1;
          gbc.gridy=2;
          add(jb2,gbc);
          jb2.addActionListener(new ActionListener()
               public void actionPerformed(ActionEvent ae)
                    jtf1.setText("");
                    jpf1.setText("");
                    jtf1.requestFocus();
          setSize(350,200);
          setVisible(true);
          jtf1.requestFocus();
     public static void main(String args[])
Login l=new Login();
Edited by: 795772 on Sep 19, 2010 4:44 AM

795772 wrote:
hye frnz... plz help me m new to java
m using ms access as database and try to create a login page where user type username and pw
i had enter valid user entries in database i checked connectivity is working i want as user login the main window must open after checking username and pw field to database but
now there is an error class not found exception sun:jdbc...... error
plz help me i had stuck frm 4 days */
<snip>The subject of this forum is Oracle databases. How does your problem relate to that subject?
Two bits of advice:
1) Make sure you ask questions in a forum related to your problem.
2) If you want to be taken seriously as a professional, drop the MS IM Speak and use the language of the forum. In this forum it is English, which is successfully used by many people for whom English is far from their native language.

An error has occurred while accessing SQL database or system resources. If this is the first time you have seen this message, please try again later. If this problem persists, please contact your administrator.

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is the first time you have seen this message, please try again later. If this
problem persists, please contact your administrator." When I try to "MODIFY" the rule I get this error, "One or more values typed on this page are not valid. Check the text for the indicated fields."
The last time I checked it was working, I'm not aware of any new updates installed recently? I did a full Profile Synchronization as well, but still not working, please advise? -- Evenstarline

Hi Sara,
First of all thank you very much for your prompt responses. Here are my comments to each of your suggestions below, and just to let you know I am using a Farm Admin account.  I
was able to do this way after we upgraded from SP 2007 to SP 2010 as well.   I would like to mention I'm not a SP expert, just been given the responsibility due to another person handling it just left, so apologize with some of
my novice questions below?
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2. We have a 3-server-tier topology (SPWeb, SPDB, and SPFarm). Does the updates only apply to where the Central Admin is installed, which is the "SPFarm"? I checked all
3 servers, and NONE of the updates (KB2899494, KB2889845, and KB2883055) you'd mentioned are installed.
3. I'm new to IISRET, I need to be extra cautious of what I run in production, is this safe to run with no problem? What does it do? And How do I run it?
4. I'm also new to viewing the ULS log. I'd just downloaded a viewer for it. I'm assuming the only logs I need to be concern with viewing are within the SPAdmin (where Central
Admin is installed)? There's so many of them, what should I be looking for exactly?
Evenstarline

How to access multiple database present in single instance

Hi Team,
In oracle 11.2, can there be multiple databases in an instance??? In one of our environment, I could see multiple databases in an instance. Could you please help me in giving the data dictionary or query to access those databases?
Actually, querying v$database, I could see only one database which is same as instance name. But in inventory, there are multiple database in an instance?
I am still not exactly clear about this. Can someone help me with this?
Thanks!
Vidhya

In Oracle one instance manages one (1) database. A database consists of multiple *schemas*.
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There is also one datadictionary, consisting of a set of views.
All views beginning with dba_ list the entire database, all schemas.
All views beginning with all_ list the objects you have access to.
All views beginning with user_ list your own objects.
The view DICT show you the contents of the datadictionary.
Oracle also has online documentation at http://docs.oracle.com
From your question it is clear you should read the document called the 'Oracle Concepts Manual'.
You can find all documentation for 11gR2 here Oracle Database Online Documentation 11g Release 2 (11.2)
Too many people here don't make any effort to read it. This is probably the reason why you got no response.
Sybrand Bakker
Senior Oracle DBA

Illegal access error at runtime

Hi,
I am getting an illegal access error while trying to call a method.
- Class1 tries to call method on Class2.
- Method has package visibility
- Both classes are in same package.
- Class1 is being invoked by a class in a Web Application which is
in a completely different package. Class1 gets invoked properly
and then instantiates Class2. It then tries to call the method on
Class2.
- Compiler is compiling successfully i.e. no compile time errors
Any clues?
Env:
JDK 1.4.2_01
App Server Tomcat 4.0.6
Thanks
Reg
Aashish

Hi,
I am getting an illegal access error while trying to
call a method.
- Class1 tries to call method on Class2.
- Method has package visibility
- Both classes are in same package.
- Class1 is being invoked by a class in a Web
Application which is
in a completely different package. Class1 gets
s invoked properly
and then instantiates Class2. It then tries to call
l the method on
Class2.
- Compiler is compiling successfully i.e. no compile
time errors
Any clues?
Env:
JDK 1.4.2_01
App Server Tomcat 4.0.6
Thanks
Reg
AashishThe problem is the Class1 and Class2 are being loaded by different classloaders. Because of this, they are considered to be in different packages by the VM, and hence the IllegalAccessError.
To correct this, make sure both classes are only available in a single classloader context. So if these classes are only used by the WebApp, include them in a jar in WEB-INF/lib or WEB-INF/classes..
If yyou need access to these across multiple webapps, or by some other non-webapp classes, place them in the /common/lib directory for Tomcat.
Whatever you do, MAKE SURE THEY AREN'T avaialble in BOTH! Which is what appears to be the problem now.

Not able to access the Database & Clusterware from OEM Console.

hi,
I had installed Oracle RAC 11g R2 in RHEL 5.3 Operating environment. I had installed my Oracle RAC with Enterprise Manager Console.
Its with the defailt port 1158. After the installation when i try to access my EM Console, i was not able to access the Database and Clusterware from EM Console.
When i access the EM console with url, I found with Startup and Perform Recovery option. But whereas my database is already startup and running.
So when i click startup its saying database is already started. Since it is a prodution environment i dont want to go with Perform recovery option.
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Edited by: 795847 on Sep 21, 2010 10:40 PM

hi,
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2. After I logged in, I clicked on the Databases to expand the node. However, an error prompt says,
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I had the same problem , this one resolved the problem , thank you deshmukhsdineshd
Best
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Trying to access 10gr2 database from sqlplus utility but it connects to 11g

Hi All,
I am facing below issue while access 10gr2 database from sqlplus.
I am having two oracle homes on one server one belongs to 11gr2 and another belongs to 10gr2.
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thank you so much for responding.
hope I am clear with my reply.
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The server principal "XYuser" is not able to access the database "Ydb" under the current security context

SQL2005 on winserver 2003. I have a view in Xdb that accesses tables in 2 different databases (Xdb and Ydb) on the same server. I have mixed mode security. I have a SQL user (XYuser) that has read access to all tables and views on both databases, yet when I try to access the view using a C# windows application I get the following error:
The server principal "XYuser" is not able to access the database "Ydb" under the current security context
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In order to ‘Map’ the Login, the Login must not already be as User on the database, so you may have to go to the database security (ServerName -> Databases -> DatabaseName -> Security -> Users) and delete the Login from the list of database Users before mapping the Login to the database.

How to use PDA module to access the database of PDA?

I want to develop a program which can access the database of PDA by the pda module. give me some advice!
thanks!

It may help you to know how I add JARs
1. I open my Project (myProject)
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Mac being unable to sever connections and I can't access secure databases

Recently my university library underwent a security rehaul, since then I have been unable to access secure databases to do research for papers and the like. After resetting my browser, emptying my cache, and shutting down my computer, I am unable to sever my old connection to the library page.
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This will tell you if your apps are compatible:
http://roaringapps.com/apps:table
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SQL Developer 1.5.4 failed to migrate MS Access 2002 database

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I tried to migrate a MS Access 2002 Database to Oracle.
Migration of tables failed in both ways:
Exporter for MS Access Rel. 3.2.0.00.13 displayed the following error:
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Volker Ricke

There was a similar issue logged here
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Dermot.

Logical database vs direct access of database table

Hi
I have created a FI report. I am trying to get data from large FI tables like BSAK, BSEG, BKPF, RSEG. eventhough there are 10 records as per my criteria, system is taking morethan an hour time even in background processing. This may be becaz of lot of conditions that I am applying to filter the data. But still trying to improve the performance
For fetching data which is the better way for getting optimum performance of the report.
a) directly fetching data from database tables
b) using logical database collecting data into an itab
regards,
mallik

Hi,
If you are accessing the database tables more than once with different criteria then definetly it will take more time. In such case write only one Select statement on the table and get all the required data into an internal table and then process this internal table as per your logic.
Use of LDBs is definetly faster but filter conditions might not match with your filter conditions. In such case direct access of database table is preferable but as i said in above paragraph.
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sksingh

Accessing shared database throws exception from one of 2 web roles

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Shared database
Main site and "admin site" each using separate web roles accessing shared database.
I had things working and running correctly until about 2 days ago. Then, only the "admin site" stopped working. I am using the same code to access the database across both sites but am getting the following exception when trying to access the
database in the admin site:
Message: Unable to open connection to "Microsoft SQL Server, provider V2.0.0.0 in framework .NET V2.0".
Stack Trace: at IBatisNet.DataMapper.SqlMapSession.OpenConnection(String connectionString) at IBatisNet.DataMapper.SqlMapSession.OpenConnection() at IBatisNet.DataMapper.Commands.DbCommandDecorator.System.Data.IDbCommand.ExecuteReader() at IBatisNet.DataMapper.MappedStatements.MappedStatement.RunQueryForObject[T](RequestScope
request, ISqlMapSession session, Object parameterObject, T resultObject) at IBatisNet.DataMapper.MappedStatements.MappedStatement.ExecuteQueryForObject[T](ISqlMapSession session, Object parameterObject, T resultObject) at IBatisNet.DataMapper.MappedStatements.MappedStatement.ExecuteQueryForObject[T](ISqlMapSession
session, Object parameterObject) at IBatisNet.DataMapper.SqlMapper.QueryForObject[T](String statementName, Object parameterObject) at AutoOffers.Persistence.SqlMapperWrapper.QueryForObject[T](String statementName, Object parameter) at AutoOffers.Persistence.Mappers.DbUserMapper.FindByEmailAddress(String
emailAddress) at AutoOffers.Persistence.Repositories.UserRepository.FindByEmailAddress(String emailAddress) at AutoOffers.Core.Domain.Services.Authentication.MembershipService.ValidateUser(String username, String password) at Admin.AutoOffers.Web.Controllers.HomeController.Login(LoginModel
model, String returnUrl) at lambda_method(Closure , ControllerBase , Object[] ) at System.Web.Mvc.ActionMethodDispatcher.Execute(ControllerBase controller, Object[] parameters) at System.Web.Mvc.ReflectedActionDescriptor.Execute(ControllerContext controllerContext,
IDictionary`2 parameters) at System.Web.Mvc.ControllerActionInvoker.InvokeActionMethod(ControllerContext controllerContext, ActionDescriptor actionDescriptor, IDictionary`2 parameters) at System.Web.Mvc.Async.AsyncControllerActionInvoker.<>c__DisplayClass42.<BeginInvokeSynchronousActionMethod>b__41()
at System.Web.Mvc.Async.AsyncResultWrapper.<>c__DisplayClass8`1.<BeginSynchronous>b__7(IAsyncResult _) at System.Web.Mvc.Async.AsyncResultWrapper.WrappedAsyncResult`1.End() at System.Web.Mvc.Async.AsyncControllerActionInvoker.EndInvokeActionMethod(IAsyncResult
asyncResult) at System.Web.Mvc.Async.AsyncControllerActionInvoker.<>c__DisplayClass37.<>c__DisplayClass39.<BeginInvokeActionMethodWithFilters>b__33() at System.Web.Mvc.Async.AsyncControllerActionInvoker.<>c__DisplayClass4f.<InvokeActionMethodFilterAsynchronously>b__49()
at System.Web.Mvc.Async.AsyncControllerActionInvoker.<>c__DisplayClass37.<BeginInvokeActionMethodWithFilters>b__36(IAsyncResult asyncResult) at System.Web.Mvc.Async.AsyncResultWrapper.WrappedAsyncResult`1.End() at System.Web.Mvc.Async.AsyncControllerActionInvoker.EndInvokeActionMethodWithFilters(IAsyncResult
asyncResult) at System.Web.Mvc.Async.AsyncControllerActionInvoker.<>c__DisplayClass25.<>c__DisplayClass2a.<BeginInvokeAction>b__20() at System.Web.Mvc.Async.AsyncControllerActionInvoker.<>c__DisplayClass25.<BeginInvokeAction>b__22(IAsyncResult
asyncResult)
NOTE: I've tried to go to the v4 provider but get the same error (except with v4 in place of v4). I would suspect something amiss with my application if I didn't have a working one using shared code...though I'm still not ruling out that I'm doing
something wrong, just waiting for input from here.
Thanks in advance.

Hey there, and apologies for the lack of response. Are you still having this issue and still needing help? If so can you tell me a little more. Where is the application running (web/worker rolls)? what are the details on the SQL Database?
Thanks Guy

Illegal access of database

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