IMIC - how the **** does it work?

I've read the posts regarding this tricky little
beast but cant get a signal through on my mac. I've
followed all the offered advice on settings and
levels, noted the "counter-intuitive" button on the
gadget itself, used garageband, audacity, toast, peak
and final vinyl and I even got to the point where I
cut off the phono plugs and stuck the bare wires into
the speaker outlets - at least that got a connection,
but obviously not much good for sound quality!
Do you think that the aux outlets on my hifi dont
work? Unfortunately my other, newer, hifi doesn't
have aux outlets - is there any other way of making a
connection or any other way of geting a couple of
hundred cds - mostly deleted classical recordings -
zapped onto my mac's hard drive? I've spent alot of
time on this, so any help would be
welcome.
imac
G5(powerpc) Mac OS X (10.4.7) 1.8Ghz 1GB RAM
150GB Hard Drive
imac G5(powerpc) Mac OS X
(10.4.7) 1.8Ghz 1GB RAM 150GB Hard Drive
Yes...I had been working through the night on my dissertation, but that's no excuse, I really didn't deserve any responses for a stupid slip of the keyboard like that - of course I meant cassettes! I really have checked all avenues suggested with my hifi and borrowed a second one with aux and still no success. So I'll buy another of those pesky little imics - unless there's something better on the market. It breaks my heart to see those now unobtainable recordings just sitting there without any possibility of re-editing them to bring them up to modern standards...
Anyways, thank you for your advice, guys.
imac G5(powerpc) Mac OS X (10.4.7) 1.8Ghz 1GB RAM 150GB Hard Drive

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Assign points if useful

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javalover2002 wrote:
Hi Gurus,
I downloaded this program from forum to convert the byte[] to hex strings, but no idea how does it work!!!
If you please take a exmple value and tell me exactly how that value is converted to hex string, i would greatly appreciate it.
thanks,
public String toHexString ( byte[] b )
StringBuffer sb = new StringBuffer( b.length * 2 );
for ( int i=0; i<b.length; i++ )
// look up high nibble char
sb.append( hexChar [( b[i] & 0xf0 ) >>> 4] );
// look up low nibble char
sb.append( hexChar [b[i] & 0x0f] );
String hStr = sb.toString();
return Pattern.compile("0+").matcher(hStr).matches()?"":hStr;
OK, I'll have a stab:
1. A byte is 8 bits long, and made up of 2 hexadecimal digits, each of 4 bits (0-15).
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3. The real 'worker' bits of the code are "*( b\[i\] & 0xf0 ) >>> 4*" and "*b\[i\] & 0x0f*".
Lets take the first:
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