IN: int a, int b; OUT:Vector filled with numbers ranging from a to b

Question

Hello,
is there any method to fill in a vector with numbers ranging from a value "a" to value "b"? Of course it can be done using a for-loop, but I was wondering if there is not a simpler way to do it. Thanks for your advices.
Example:
INTPUT:
int a = 4;
int b = 9;
Vector seq = new Vector();
seq.setSize(b-a);
OUTPUT:
pseudocode: seq = {4,5,6,7,8,9};

Answer 1

Darryl.Burke wrote:
Hmmm.. what happens when the other methods of AbstractList are invoked on an instance of IntRangeList? Wouldn't you need to override pretty nearly all the methods for consistency? And some methods, like remove and set, would have to throw a UnsupportedOperationException.If you read the API documentation of AbstractList then you could find out that you could implement a fully functional, fully compliant (unmodifiable) List implementation by just providing size() and get(int). All other accessor methods (including subList() and iterator()) will be using those two methods and fully work.
Writing a loop to populate a simple ArrayList would be trivial by comparison :-)Indeed, but if it's needed often and with big ranges, then there's no loss in using this implementation.
db
edit In fact, extending AbstractList appears irrelevant as none of the features of AbstractList are used. The IntRangeList, in fact, is-NOT-a AbstractList but just fakes it in respect of the 2 methods overridden in your code sample.What? All the features are used. Read the API doc. If I handn't extended AbstractList, but instead implemented List directly, then I'd have to implement all the methods myself (including an Iterator, which, while trivial in this case, can be non-fun to implement correctly).