Init parameters in web.xml file

Hi,
I have a query related to the init parameters defined in web.xml file.
When does a servlet read these parameters?
Also, how does servlet use these parameters while processing the client's request?
Thanks in advance......

hai,
In order to make servlet flexible we must avoid hard-coding(writing-directly).so there are two ways in that one one way is init param's.
create ServletConfig object as show below
ServletConfig config=getServletConfig();then retrieve the init param value in to your servlet us getInitParameter(..) method as show below
String something=config.getInitParameter("init param name");

Similar Messages

Servlet parameters in web.xml file

Hi Guys
What is ctx:dynamo: in web.xml why we have to use this one in servlet parameters
Please give me a clear picture on this
<init-param>
    <param-name>jumpServlet</param-name>
    <param-value>
      ctx:dynamo:/atg/dynamo/servlet/dafpipeline/JumpServlet
    </param-value>
</init-param>

Hi Guys
What is ctx:dynamo: in web.xml why we have to use this one in servlet parameters
Please give me a clear picture on this
<init-param>
    <param-name>jumpServlet</param-name>
    <param-value>
      ctx:dynamo:/atg/dynamo/servlet/dafpipeline/JumpServlet
    </param-value>
</init-param>

Help on web.xml file, what if the parameters contains key words ?

Hi:
I am just wondering what should I do if I want to include key words suchs
as <param> in web.xml file for a servlet config.
Example:
<servlet>
<servlet-name>testServlet</servlet-name>
<parameter>
<param-name>some name</param-name>
<param-value>some value</param-value>
</parameter>
</servlet>
What should I do if I want to repleace 'some value' with '</param-value>some
value' and still to prevent the engine to terminate parsing the param-value
at the fake ending? Is there a standard way in XML to distanguish that?
(in URL format it can be replaced %xx for some chars).
ie,
<param-value> </param-value>some value</param-value>
where the second </param-value> is the real ending.
Thank you!
Gang

Hi!
You can use "& lt ;" and "& gt ;" xml entities for that. Or wrap text element in <![CDATA[...]]> section.
Regards,
Ignat.

How can I get the context-parm from a web.xml file using struts?

Hello:
I need get the context-param from the web.xml file of my web project using struts. I want configurate the jdbc datasource connection pooling here. For example:
<context-param>
<param-name>datasource</param-name>
<param-value>jdbc/formacion</param-value>
<description>Jdbc datasource</description>
</context-param>
and then from any Action class get this parameter.
Similar using a simple server can be:
/** Initiates new XServlet */
public void init(ServletConfig config) throws ServletException {
          for (Enumeration e = config.getInitParameterNames(); e.hasMoreElements();) {
               System.out.println(e.nextElement());
          super.init(config);
          String str = config.getInitParameter("datasource");
          System.out.println(str);
     public void doPost(HttpServletRequest req, HttpServletResponse res)
          throws ServletException, IOException {
          // res.setContentType( );
          System.out.println("Got post request in XServlet");
          PrintWriter out = res.getWriter();
          out.println("nada");
          out.flush();
          out.close();
but only this works for init-params, if I use
<servlet>
     <servlet-name>MyServlet</servlet-name>
     <display-name>MyServlet</display-name>
     <servlet-class>myExamples.servlet.MyServlet</servlet-class>
     <init-param>
     <param-name>datasource</param-name>
     <param-value>jdbc/formacion</param-value>
</init-param>
</servlet>
inside my web.xml. I need something similar, but using struts inside the action class for that I can get the context-params and call my database.
Thank you

To get context parameters from your web.xml file you can simply get the ActionServlet object from an implementing action object class. In the perform (or execute) method make the following call.
ServletContext context = getServlet().getServletContext();
String tempContextVar =
context.getInitParameter("<your context param >");

Init-params in web.xml are not loaded (Tomcat 4)

Hello all...
I register a servlet in webapps/<my-servlet>/WEB-INF/web.xml file, and pass 1 <init-param> tag. The file gets parsed (I know because when I made errors tomcat complained during initialization). However, when in the init method of the servlet I try to access this parameter, its not there. In fact, the servlet has NO init params at all.
=================================================
I have the following web.xml file
<?xml version="1.0" encoding="ISO-8859-1"?>
<!DOCTYPE web-app
PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd">
<web-app>
<servlet>
<servlet-name>XServlet</servlet-name>
<servlet-class>com.fxcm.xml.xengine.xdas.XServlet</servlet-class>
<init-param>
<param-name>xengine.configFile</param-name>
<param-value>c:/projects/re/das.config/config.xng</param-value>
</init-param>
</servlet>
<servlet-mapping>
     <servlet-name>XServlet</servlet-name>
     <url-pattern>/xservlet</url-pattern>
</servlet-mapping>
</web-app>
=======================================================
I have the following servlet
* XServlet.java
* Created on May 6, 2002, 1:17 PM
package com.fxcm.xml.xengine.xdas;
import javax.servlet.*;
import javax.servlet.http.HttpServlet;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.ServletConfig;
import java.util.Enumeration;
import com.fxcm.xml.xengine.XEngine;
public class XServlet extends HttpServlet{
/** Initiates new XServlet */
public void init(ServletConfig config)
throws ServletException
          for (Enumeration e = config.getInitParameterNames(); e.hasMoreElements();){
//This statement never gets printed because the loop never enters here since there are no init parameters
               System.out.println(e.nextElement());
super.init(config);
String str = config.getInitParameter("xengine.configFile");
System.out.println(str);
XEngine.init(str.trim()); //This line throws NullPointer, because str is null since there are no initParameters.
public void doPost(HttpServletRequest req, HttpServletResponse res)
throws ServletException, IOException{
// res.setContentType( );
          System.out.println("Got post request in XServlet");
PrintWriter out = res.getWriter();
out.println(XEngine.process(req.getInputStream()));
out.flush();
out.close();
================================================================
I get the follwoing error in the browser:
type Exception report
message Internal Server Error
description The server encountered an internal error (Internal Server Error) that prevented it from fulfilling this request.
exception
java.lang.NullPointerException
     at com.fxcm.xml.xengine.xdas.XServlet.init(Unknown Source)
     at org.apache.catalina.core.StandardWrapper.loadServlet(StandardWrapper.java:918)
     at org.apache.catalina.core.StandardWrapper.allocate(StandardWrapper.java:655)
     at org.apache.catalina.servlets.InvokerServlet.serveRequest(InvokerServlet.java:400)
Please help.
Thank you,
Elana

I know what the problem is. If you call servlet with the default URL (http://host/app/servlet/package.Servlet) than Servlet DOES NOT read init parameters. I don't know why it was designed this way.
To make servlet read init parameters, you have to assign it a name and then call it with that name, like this:
<servlet>
<servlet-name>ServletName</servlet-name>
<servlet-class>package.ServletClass</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>ServletName</servlet-name>
<url-pattern>/app/path/ServletName</url-pattern>
</servlet-mapping>
You can then call servlet using path specified in url-pattern and read init parameters in the normal way.

Web.xml file not being read

Hello, I did a quick search but could not find an answer to my specific problem. (this is also my first night tackling servlets) i hope this hasnt been answered before. here goes...
i'm using Tomcat 4.1 and this is my file structure where i put my servlets:<intstall dir>/webappps/ROOT/WEB-INF/classes/TestPackage.
this is my code for the servlet
package TestPackage;
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
/** Example using servlet initialization. Here the message
* to print and the number of times the message should be
* repeated is taken from the init parameters.
public class ShowMessage extends HttpServlet
     private String message;
     private String defaultMessage = "No message.";
     private int repeats = 1;
     public void init(ServletConfig config) throws ServletException
          //Always call super.init
          super.init(config);
          message = config.getInitParameter("message");
          if (message == null)
               message = defaultMessage;
          try
               String repeatString = config.getInitParameter("repeats");
               repeats = Integer.parseInt(repeatString);
          catch(NumberFormatException nfe)
               //do nothing
     public void doGet(HttpServletRequest request, HttpServletResponse response) throws
                                        ServletException, IOException
          response.setContentType("text/html");
          PrintWriter out = response.getWriter();
          String title = "The ShowMessage Servlet";
          out.println("<!DOCTYPE HTML PUBLIC \"-//W3C//DTD HTML 4.0 " +
                           "Transitional//EN\">\n" +
                           "<HTML>\n" +
                         "<body bgcolor=\"#FDF5E6\">\n" +
                         "<h1 align=center>" + title + "</h1>");
          for(int i=0; i<repeats; i++)
               out.println(message + "<br>");
          out.println("</body></html>");
}my web.xml file is in <intstall dir>/webappps/ROOT/WEB-INF. it looks like:
<?xml version="1.0" encoding="ISO-8859-1"?>
<!DOCTYPE web-app
    PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
    "http://java.sun.com/dtd/web-app_2_3.dtd">
<web-app>
<display-name>Welcome to Tomcat</display-name>
<description>
     Welcome to Tomcat
</description>
<servlet>
      <servlet-name>
        ShowMsg
      </servlet-name>
      <servlet-class>
        TestPackage.ShowMessage
      </servlet-class>
      <init-param>
        <param-name>
          message
        </param-name>
        <param-value>
          Shibboleth
        </param-value>
      </init-param>
      <init-param>
        <param-name>
          repeats
        </param-name>
        <param-value>
          5
        </param-value>
      </init-param>
</servlet>
</web-app>when i access the servlet i get "No message" one time which is the default message. Any ideas as to why its not picking up the init parameters. I've restarted my laptop and started and stopped Tomcat a few times and i always get the default message...i also tried ShowMessage in replace of ShowMsg as the <servlet-name>, to no avail. I also tried removing the package name in the <servlet-class>, still nothing. Is there another web.xml file some where else that i need to update?
Thanks! (sorry for the long code)
BB

The doGet method works if you are sending data from a form using get method. It is better to use service method.

Can i run a servlet without a web.xml file for servlet mapping?

Hello everyone.
The code i want to run compiles and everythink looks ok.
It produces the .class file.
I run Tomcat 4.1 and i build my Web site with Dreamweaver.
I have a form in a page and i want to send the data upon form completion to a database i already have build with MySql.
The database is up and running and the server is set-up ok.
I have changed the port in Tomcat to run on port 80.
The directory i have my site is
Tomcat41\webapps\ROOT\se
and the directory where i keep the servlet class is
Tomcat41\webapps\ROOT\se\WEB-INF\servlet
I have a web.xml file to map the servlet and placed it in
Tomcat41\webapps\ROOT\se\WEB-INF
In the Form action i write action:"/servlets/Classes/GroupRegistration"
and I RECEIVE AN 404 ERROR FROM APACHE.
Somethink is wrong .
The following is the code from the GroupRegistration.java file
and follws the web.xml file.
Please Help.
import java.sql.*;
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
public class GroupRegistration extends HttpServlet
Connection con;
public void doPost (HttpServletRequest req, HttpServletResponse res)
                         throws ServletException, java.io.IOException
     handleForm(req, res);
public void init() throws ServletException {
     try{
     /* Loading the driver for the database */
     Class.forName("com.mysql.jdbc.Driver");
     Connection Con = DriverManager.getConnection("jdbc:mysql://localhost/se?user=luser&password=");
     catch (ClassNotFoundException e) {
     throw new UnavailableException("Couldn't load JdbcOdbcDriver");
     catch (SQLException e) {
     throw new UnavailableException("Couldn't get db connection");
     private void handleForm(HttpServletRequest req, HttpServletResponse res)
     throws ServletException {
     //ServletOutputStream out = res.OutputStream();
     //res.setContentType("text/html");
     //Extract the form Data Here
     String group = req.getParameter("GroupNo");
     String Name1 = req.getParameter("Name1");
     String LoginID1 = req.getParameter("LoginID1");
     String Name2 = req.getParameter("Name2");
     String LoginID2 = req.getParameter("LoginID2");
     String Name3 = req.getParameter("Name3");
     String LoginID3 = req.getParameter("LoginID3");
     String Name4 = req.getParameter("Name4");
     String LoginID4 = req.getParameter("LoginID4");
     String URL = req.getParameter("URL");
     String Title2 = req.getParameter("Title2");
     String date = req.getParameter("date");
     String INSERT = "INSERT INTO registration (groupno, name1, loginid1, name2, loginid2, name3, loginid3, name4, loginid4, url, topic, date) VALUES (" + group + "," + Name1 + "," + LoginID2 + "," + Name2 + "," + LoginID2 + "," + Name3 + "," + LoginID3 + "," + Name4 + "," + LoginID4 + "," + URL + "," + Title2 + "," + date + ")";
     PreparedStatement pstmt = null;
     try{
     pstmt = con.prepareStatement(INSERT);
     pstmt.executeUpdate();
     catch (SQLException e) {
     throw new ServletException(e);
     finally {
     try {
     if (pstmt != null)pstmt.close();
     catch (SQLException ignored){
The web.xml file
<?xml version="1.0" encoding="ISO-8859-1"?>
<web-app xmlns="http://java.sun.com.xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd" version="2.4">
<servlet>
<servlet-name>GroupRegistration</servlet-name>
<servlet-class>GroupRegistration</servlet-class>
</servlet>
<servlet-maping>
<servlet-name>GroupRegistration</servlet-name>
<url-pattern>/myGroupRegistration</url-patern>
</servlet-mapping>
</web-app>
I apreciate your time.
Thanks for any help.

and the directory where i keep the servlet class is
Tomcat41\webapps\ROOT\se\WEB-INF\servletOthers have pointed out that "servlet" should be "classes", but there is another mistake that hasn't been spotted. If you want your servlet to appear in the root context, you should use:
Tomcat41\webapps\ROOT\WEB-INF\classes
If you want your servlet to appear under the /se context, then you should use:
Tomcat41\webapps\se\WEB-INF\classes
and also, in the latter case, your form action should be /se/myGroupRegistration.

Problem in web.xml file with weblogic server 8.1

Hi frnds,
I was deployed one Enterprise Application,it deploys successfully. But in server side thows Exeception in web.xml file.
Here the actual Exception
<HTTP> <BEA-101248> <[Application:
'G:\bea\user_projects\domains\mydomain\myserver\upload\jasmine.ear', Module: 'Ja
smine']: Deployment descriptor "web.xml" is malformed. Check against the DTD: or
g.xml.sax.SAXParseException: The content of element type "web-app" must match "(
icon?,display-name?,description?,distributable?,context-param*,filter*,filter-ma
pping*,listener*,servlet*,servlet-mapping*,session-config?,mime-mapping*,welcome
-file-list?,error-page*,taglib*,resource-env-ref*,resource-ref*,security-constra
int*,login-config?,security-role*,env-entry*,ejb-ref*,ejb-local-ref*)". (line 61
, column 11).>
My web.xml file as follws....
<?xml version="1.0" encoding="ISO-8859-1"?>
<!DOCTYPE web-app
PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.4//EN"
"http://java.sun.com/dtd/web-app_2_4.dtd">
<web-app>
<display-name>Jasmine Applications</display-name>
<description>
Jasmine Applications
</description>
<servlet>
<servlet-name>LoginServlet</servlet-name>
<servlet-class>examples.LoginServlet</servlet-class>
<init-param>
<param-name>java.naming.factory.initial</param-name>
<param-value>weblogic.jndi.WLInitialContextFactory</param-value>
</init-param>
<init-param>
<param-name>java.naming.provider.url</param-name>
<param-value>t3://localhost:7001</param-value>
</init-param>
</servlet>
<servlet>
<servlet-name>ShowQuoteServlet</servlet-name>
<servlet-class>examples.ShowQuoteServlet</servlet-class>
<init-param>
<param-name>java.naming.factory.initial</param-name>
<param-value>weblogic.jndi.WLInitialContextFactory</param-value>
</init-param>
<init-param>
<param-name>java.naming.provider.url</param-name>
<param-value>t3://localhost:7001</param-value>
</init-param>
</servlet>
<servlet>
<servlet-name>CatalogServlet</servlet-name>
<servlet-class>examples.CatalogServlet</servlet-class>
<init-param>
<param-name>java.naming.factory.initial</param-name>
<param-value>weblogic.jndi.WLInitialContextFactory</param-value>
</init-param>
<init-param>
<param-name>java.naming.provider.url</param-name>
<param-value>t3://localhost:7001</param-value>
</init-param>
</servlet>
<servlet-mapping>
<servlet-name>LoginServlet</servlet-name>
<url-pattern>/login/*</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>ShowQuoteServlet</servlet-name>
<url-pattern>/showQuote/*</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>CatalogServlet</servlet-name>
<url-pattern>/catalog/*</url-pattern>
</servlet-mapping>
<security-constraint>
<web-resource-collection>
<web-resource-name>My secure resources</web-resource-name>
<description>Resources to be placed under security control.</description>
<url-pattern>/private/*</url-pattern>
<url-pattern>/registered/*</url-pattern>
</web-resource-collection>
<auth-constraint>
<role-name>guest</role-name>
</auth-constraint>
</security-constraint>
<login-config>
<auth-method>FORM</auth-method>
<realm-name>WebApp</realm-name>
<form-login-config>
<form-login-page>/login.jsp</form-login-page>
<form-error-page>/error.jsp</form-error-page>
</form-login-config>
</login-config>

<security-role>
<description>The role allowed to access our content</description>
<role-name>guest</role-name>
</security-role>
</web-app>
pls give me a good solution this exception.. I tried lot..
Thanks in Advance
Regards
Priya

Your DOCTYPE references 2.4, it should be 2.3. WLS 8.1 supports J2EE 1.3 which was servlet 2.3.
Servlet 2.4 is part of J2EE 1.4 and is supported by WLS 9.0/9.1. Also it uses XML Schema not a DTD.
-- Rob
WLS Blog http://dev2dev.bea.com/blog/rwoollen/

How to configure a JNDI ressource in the web.xml file

Hi,
does someone know if there is a way to configure a JNDI ressource with its parameters only in the web.xml file ?
In my case, the JNDI ressouce is an oracle database an its conenction paramters: driverClassName, username, password, etc...
Actually, I put everything in the configuration file of Tomcat but I would like my war file to be 100% independent of the application server.
Thanks in advance.
Fred.

I wrestled with this for a long time. I may have done something wrong, but to get my mySQL JDNI reference to work, I had to add it to the server.xml file. You can try with web.xml, but I eventually just got frustrated and put it in server.xml.
The following is between two <context> tags:
<Resource name="jdbc/instance_name_goes_here"
               auth="Container"
               type="javax.sql.DataSource"/>
          <ResourceParams name="jdbc/same_instance_name_here">
               <parameter>
                    <name>username</name>
                    <value>user_name_goes_here</value>
               </parameter>
               <parameter>
                    <name>password</name>
                    <value>password_goes_here</value>
               </parameter>
               <parameter>
                    <name>driverClassName</name>
                    <value>jdbc_fully_qualified_class_name</value>
               </parameter>
               <parameter>
                    <name>factory</name>
                    <value>org.apache.commons.dbcp.BasicDataSourceFactory</value>
               </parameter>
               <parameter>
                    <name>url</name>
                    <value>jdbc_connect_url_database_vendor_specific</value>
               </parameter>
               <parameter>
                    <name>maxActive</name>
                    <value>8</value>
               </parameter>
               <parameter>
                    <name>maxIdle</name>
                    <value>8</value>
               </parameter>
          </ResourceParams>
- Saish
"My karma ran over your dogma." - Anon

Configuring a JNDI ressource in the web.xml file

Hi,
does someone know if there is a way to configure a JNDI ressource with its parameters only in the web.xml file ?
In my case, the JNDI ressouce is an oracle database an its conenction paramters: driverClassName, username, password, etc...
Actually, I put everything in the configuration file of Tomcat but I would like my war file to be 100% independent of the application server.
Thanks in advance.
Fred.

I'm pretty sure you can't do it that way round. The logic of the thing is that database access URLs etc. tend to depend on the where the server is. The whole idea of these resources is to put the stuff that's specific to the server in server.xml and refer to it using names that should remain the same if you deploy your webapp on another server. Of, for example, you have test, stage and production servers running the same webapps but connecting to different databases.

XCM configuration path in web.xml file

Hi,
Here is a requirement that all the XCM configuration files are stored at local desktop(like QAT, PRD..), and need to use them by modifying web.xml.
Please let me know at
1)which web.xml tag the path of XCM confiuration files to be specified.
2) specify the names of the XCM files for configuration to be put in that folder.
Thanks,
Devender V

Hi,
1)which web.xml tag the path of XCM confiuration files to be specified.
Try to find below lines in your web.xml
<context-param>
        <param-name>path.xcm.config.isa.sap.com</param-name>
        <param-value>/WEB-INF/xcm/sap/system/bootstrap-config.xml</param-value>
        <description>Turns the Extended Configuration Management on if a
            path to the configuration file is specified. It is a
            relative path, with context-root of web application as root</description>
    </context-param>
bootstrap-config.xml file contains XCM configuration related XML file path. You can modify or extend this file and give your user Define path.
Also you can find below line in web.xml file.

    <servlet>
        <servlet-name>action</servlet-name>
        <servlet-class>com.sap.isa.core.ActionServlet</servlet-class>
        <init-param>
            <param-name>config</param-name>
            <param-value>/WEB-INF/config.xml,/WEB-INF/xcmadmin-config.xml,/WEB-INF/ccmsims-config.xml,/WEB-INF/ipc-config.xml,/ipc/customer/config.xml,/WEB-INF/config_lwc_b2b.xml,/WEB-INF/scheduler-config.xml,/WEB-INF/ipcpricing-config.xml</param-value>
        </init-param>
        <init-param>
            <param-name>config/user</param-name>
            <param-value>/WEB-INF/config_user.xml</param-value>
        </init-param>
        <init-param>
            <param-name>config/dealerlocator</param-name>
            <param-value>/WEB-INF/config_dealerlocator.xml</param-value>
        </init-param>
        <init-param>
            <param-name>initconfig</param-name>
            <param-value>/WEB-INF/xcm/sap/system/init-config.xml</param-value>
        </init-param>
I hope this will help you.
eCommerce Developer

Maintaining Portal Desk top URL aliases in web.xml file

Hi All,
I am planning to configure portal url alias i.e http://localhost:53000/irj/portal/finance
should take me directly to finance portal desk top.
1) Created a Desktop named finance_desktop
2) Master rule has been set for URL Alias.
3) I need to set URL alias name: finance in web.xml file
4) path for the web.xml file is C:\usr\sap\SID\JCXX\j2ee\cluster\server0\apps\sap.com\irj\servlet_jsp\irj\root\WEB-INF\web.xml
5) Where exactly i have to change web.xml file
Infact i have seen a pdf "How to configure the J2ee engine deployment descriptor"
Thanks in advance
Regards,
Murali

Hi
indeed one small copy/paste mistake from me ... sorry for that...
After you copyed the large chunk of code (as i discribe in step 1 and 2) you must rename:
<param-name>portal</param-name>
to
<param-name>portal/finance</param-name>
so then that part of the web.xml will look like this:
<init-param>
<param-name>portal</param-name>
<param-value>
anonymous=0,proxy=0,low_bandwidth=0,include_in_url=1,include_application_name_in_url=1
</param-value>
</init-param>
<init-param>
<param-name>portal/finance</param-name>
<param-value>
anonymous=0,proxy=0,low_bandwidth=0,include_in_url=1,include_application_name_in_url=1
</param-value>
</init-param>
Good luck again...
Cheers,
Benjamin Houttuin
Message was edited by:
Benjamin Houttuin

How to get Context paramters out of Tomcat web.xml file

The Documentation at Tomcat seems to suggest:
Context initialization parameters that define shared
String constants used within your application, which
can be customized by the system administrator who is
installing your application. The values actually
assigned to these parameters can be retrieved in a
servlet or JSP page by calling:
String value =
getServletContext().getInitParameter("name");
Now I want to write a jsp, where the user enters his username and pwd, and this contacts a jdbc connection bean. I want to store the driver name in the web.xml file. Now can some1 please suggest a method as to how I can extract this (It ain't that straightforward as suggested in tomcat doumntation. You cannnot call the above method ithout Servlet Initialization (actually to say ithout HTTP Connection). I succeeded when I had written a servlet, but can some1 please suggest an alternative (bcoz othrwise just to extract that I am writing a servlet).
Hope I am clear.
Thanks in advance.

Edit your web.xml file and add these entries,
<context-param>
<param-name>dbUrl</param-name>
<param-value>jdbc:oracle:thin:@server5:1521:pl2java</param-value>
</context-param>
<context-param>
<param-name>dbDriver</param-name>
<param-value>oracle.jdbc.driver.OracleDriver</param-value>
</context-param>
Place the above entries in between your already existing <web-app> and </web-app> tags.
Now in your jsp, you can use, <% application.getInitParameter(); %> and in servlet, getServletContext().getInitParameter();
Hope this helps.
Sudha

Trouble adding alias to the web.xml file (External Facing Portal)

I'm trying to implement the external facing portal. I don't really have any real custom content to add to it but have just created an iView that contains a webpage that's contained within a copy of the light framework.
I'm having trouble adding or accessing the alias that I've created to go to this iView.
I can test my iView by adding it to the master rule collection under one of the predefined aliases in the web.xml (e.g. portal/anonymous etc) but when i define my own (e.g. "ext" etc) and then go to http://portal:<port>/irj/ext I'm just getting an error:
The requested resource does not exist.
Details:   Go to main page of this application!
This is what my entry in the web.xml file looks like:
<web-app>
<display-name>The Java iView Runtime</display-name>
<listener>
<listener-class>
com.sapportals.portal.prt.session.HttpSessionHandler
</listener-class>
</listener>
<servlet>
<servlet>
<init-param>
   <param-name>
      portal/anonymous
   </param-name>
   <param-value>
anonymous=1,proxy=0,low_bandwidth=0,include_in_url=1,include_application_name_in_url=1
   </param-value>
</init-param>
<init-param>
<param-name>
   ext
</param-name>
<param-value>
anonymous=1,proxy=0,low_bandwidth=1,include_in_url=1,include_application_name_in_url=1
</param-value>
<init-param>
</servlet>
My master rule collection seems to be correct, since I can test the iView etc by adding it to a predefined alias. I've tried closing all browsers etc. Nothing seems to work.
Any ideas what this could be?
Thanks!
I'll award points for any help.

Hi Beau
Just Have a try.
In the servlet mapping add the following entry.
<servlet-mapping>
<servlet-name> gateway </servlet-name>
<url-pattern> /portal/* </url-pattern>
</servlet-mapping>
<b><servlet-mapping>
<servlet-name> gateway </servlet-name>
<url-pattern> /ext/* </url-pattern>
</servlet-mapping></b>
<servlet-mapping>
<servlet-name> prt </servlet-name>
<url-pattern> /irj/* </url-pattern>
</servlet-mapping>
Restart after making the changes.
Regards
Geogi Luke

Console WAR deployment editor tool damage my web.xml file

I put many servlet and servlet-mapping items in web.xml file. When I deployed my
web app into weblogic 7.0 SP1 server, I use the console to open the deployment
description, and change some parameters for the servlet. After I clicked the persist
button, the web.xml file was changed, but some servlet and servlet-mapping items
was removed unexpected.
Why?
When I start the server in Development mode, this error occured rather often.
In the product mode, this error occured a few times.
My operation steps:
1. undeploy the original app from console
2. copy the new war file to the applications directory, overwrite the old one
3. use the console to open the deployment description, make the changes
4. persist the changes
5. re-deploy the web app
Please give the solution as soon as possible

The tag
<target name="deploy" depends="clover-yes, clover-no">...is never closed.
close that tag:
<target name="deploy" depends="clover-yes, clover-no">
     <javac srcdir="${src.dir}" destdir="${classes.dir}" classpath="${libs}" debug="off" optimize="on" deprecation="on" compiler="${compiler}">
          <include name="org/apache/commons/fileupload/**/*.java" />
          <include name="com/portalbook/portlets/**/*.java" />
          <include name="com/portalbook/portlets/content/**/*.java" />
     </javac>
</target>Second error is that the depends in there (clover-yes, clover-no) are not existing as targets in your xml.

Init parameters in web.xml file

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