Invoking Webservice using ABAP Proxy

Hi,
    I have a synchronous scenario with ABAP proxy invoking the external webservice.In the SOAP receiver target URL confiuration,do I need to give the operation(method)name in the webservice? I have read in the forum that we need to give the target URL with .asmx extension.What is the meaning of .asmx extension?
Thanks,
Leo

Hi Teresa,
We meet again !!
Right, we have a simple solution for this without using BPM.
In the proxy, set a field on the outbound data structure from the proxy to indicate to XI which receiver determination in XI can use to send the message to the right interface.
We have exactly the scenario you are talking about and it works like a treat.
Send me an e-mail @ [email protected] and I will send you a screenshot of how simple this is without using BPM.
Cheers
Colin.

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    Hi Jani,
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    String xmlString = "<?xml version=\"1.0\" encoding=\"UTF-8\"?><web-services>Sample Application</web-services>";
    System.setProperty( "javax.xml.rpc.ServiceFactory", "weblogic.webservice.core.rpc.ServiceFactoryImpl");
    ServiceFactory factory = ServiceFactory.newInstance();
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    Service service = factory.createService(new QName(serviceName));
    Call call = service.createCall(new QName(portName));
    call.setTargetEndpointAddress(address);
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    call.setProperty(Call.SOAPACTION_URI_PROPERTY, "");
    call.setProperty(ENCODING_STYLE_PROPERTY, URI_ENCODING);
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    call.addParameter("string", stringQName, String.class, ParameterMode.IN);
    call.addParameter("string0", stringQName, String.class, ParameterMode.IN);
    call.addParameter("string1", stringQName, String.class, ParameterMode.IN);
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    call.setReturnType(stringQName);
    Object[] inParams = new Object[3];
    inParams[0] = new String(agencyID);
    inParams[1] = new String(fileName);
    inParams[2] = new String(xmlString);
    String result = ((String)call.invoke(inParams)).toString();
    System.out.println(result);
    }catch (Exception e){
    e.printStackTrace();
    Please give your suggestions for the above said exception....
    Thanks & Regards....

    Hi All,
    I am getting the below exception while invoking webservices using Dynamic client without WSDL.
    javax.xml.rpc.soap.SOAPFaultException: Exception during processing: java.lang.RuntimeException: Missing license file for: WebLogic Platform 8.1 (see Fault Detail for stacktrace)
    at weblogic.webservice.core.ClientDispatcher.receive(ClientDispatcher.java:313)
    at weblogic.webservice.core.ClientDispatcher.dispatch(ClientDispatcher.java:144)
    at weblogic.webservice.core.DefaultOperation.invoke(DefaultOperation.java:457)
    at weblogic.webservice.core.DefaultOperation.invoke(DefaultOperation.java:443)
    at weblogic.webservice.core.rpc.CallImpl.invoke(CallImpl.java:558)
    at weblogic.webservice.core.rpc.CallImpl.invoke(CallImpl.java:411)
    at atthi.webservice.TestWSWithWSDL.main(TestWSWithWSDL.java:41)
    Exception in thread "main"
    Please find my source file below....
    import javax.xml.rpc.ServiceFactory;
    import javax.xml.rpc.Service;
    import javax.xml.rpc.Call;
    import javax.xml.rpc.ParameterMode;
    import javax.xml.namespace.QName;
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    String portName = "<portName>";
    String ENCODING_STYLE_PROPERTY = "javax.xml.rpc.encodingstyle.namespace.uri";
    String URI_ENCODING = "http://schemas.xmlsoap.org/soap/encoding/";
    String agencyID = "AGN00533";
    String fileName = "testWS";
    String xmlString = "<?xml version=\"1.0\" encoding=\"UTF-8\"?><web-services>Sample Application</web-services>";
    System.setProperty( "javax.xml.rpc.ServiceFactory", "weblogic.webservice.core.rpc.ServiceFactoryImpl");
    ServiceFactory factory = ServiceFactory.newInstance();
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    Service service = factory.createService(new QName(serviceName));
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    call.setTargetEndpointAddress(address);
    call.setProperty(Call.SOAPACTION_USE_PROPERTY, new Boolean(true));
    call.setProperty(Call.SOAPACTION_URI_PROPERTY, "");
    call.setProperty(ENCODING_STYLE_PROPERTY, URI_ENCODING);
    QName stringQName = new QName("http://www.w3.org/2001/XMLSchema", "string");
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    call.setOperationName(new QName(namespaceURI,"<operationName>"));
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    call.addParameter("string", stringQName, String.class, ParameterMode.IN);
    call.addParameter("string0", stringQName, String.class, ParameterMode.IN);
    call.addParameter("string1", stringQName, String.class, ParameterMode.IN);
    * Set definition of the return type.
    call.setReturnType(stringQName);
    Object[] inParams = new Object[3];
    inParams[0] = new String(agencyID);
    inParams[1] = new String(fileName);
    inParams[2] = new String(xmlString);
    String result = ((String)call.invoke(inParams)).toString();
    System.out.println(result);
    }catch (Exception e){
    e.printStackTrace();
    Please give your suggestions for the above said exception....
    Thanks & Regards....

  • Invoke Webservices using SAPXI

    Hi,
    I am following this weblog
    /people/siva.maranani/blog/2005/09/03/invoke-webservices-using-sapxi
    where can I calculator webservice.
    Its not available in http://xmethods.com/ve2/index.po
    Thanks
    dushanth
    Message was edited by:
            dushanth ry

    Thanks Prateek for the link
    I am new to webservice. Pls help me
    when I open the link you mentioned
    I clicked on ADD...
    It gives me SOAP 1.1  and SOAP 1.2 which one I have to use it and how I should start the scenario (I should use this as inbound interface or outbound interface)
    could you pls explain the steps ? It would be really helpful for me
    thanks
    dushanth
    Message was edited by:
            dushanth ry

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