Is it possible to localize preset name?
Hi,
I would like to localize the name of presets that my Export Plugin defines (the preset that are inside the plugin, in the presets/ dir). Using the LOC function does not work. I looked at the built-in Export Plugin in Lightroom, they use another function (ZSTR), and the actual string files are located in a totally different place.
Is there a way of translating a preset name?
Thanks,
Raphael
Hi Raphael, this is not possible with the LR2 SDK. I'll note that as a feature request. I don't know yet whether it will be possible for LR3 or not.
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We are getting calls from our clients complaining of slowdowns in loading our Java applet. The reason is a virusscanner. If a virusscanner is in the middle, it can drastically slow down the download process, and therefore cause some high delay before the user can work on the our product as expected.
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Hi!
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Where are my sound module preset names in the track list?
I've been using Logic since version 2.5 and, since I have several MIDI sound modules whose sounds I'm perfectly happy with, I am now using those sound modules with Logic 8.
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Fistae -
Possible to get variable name?
Is it possible to get the name that you have used in your code of a variable?
ie.
procedure main_procedure
is
l_var varchar2(10) := 'Hello';
begin
dbms_output.put_line(get_var_name(l_var));
end;
function get_var_name(p_var in varchar2)
return varchar2
is
begin
-- insert magic here
end;
-- End code; Now call the procedure
exec main_procedure;-- Needed output:
"variable passed had name l_var and value Hello"Hi Sam,
OK, this is definitely for fun only and NOT recommended for any production database!!
With that out of the way, this has been adapted from Tom Kyte's who_called_me:
SQL> create or replace procedure get_var_name (
2 p_var in varchar2
3 )
4 as
5 call_stack varchar2(4096) default dbms_utility.format_call_stack;
6 n number;
7 found_stack boolean default false;
8 l_line varchar2(255);
9 cnt number := 0;
10 l_owner varchar2(255);
11 l_name varchar2(255);
12 lineno number;
13 caller_t varchar2(255);
14 calling_line varchar2(4000);
15 var_name varchar2(1000);
16 begin
17 loop
18 n := instr( call_stack, chr(10) );
19 exit when ( cnt = 3 or n is null or n = 0 );
20 l_line := substr( call_stack, 1, n-1 );
21 call_stack := substr( call_stack, n+1 );
22 if ( not found_stack ) then
23 if ( l_line like '%handle%number%name%' ) then
24 found_stack := true;
25 end if;
26 else
27 cnt := cnt + 1;
28 -- cnt = 1 is ME
29 -- cnt = 2 is MY Caller
30 -- cnt = 3 is Their Caller
31 if ( cnt = 2 ) then
32 lineno := to_number(substr( l_line, 13, 6 ));
33 l_line := substr( l_line, 21 );
34 if ( l_line like 'pr%' ) then
35 n := length( 'procedure ' );
36 elsif ( l_line like 'fun%' ) then
37 n := length( 'function ' );
38 elsif ( l_line like 'package body%' ) then
39 n := length( 'package body ' );
40 elsif ( l_line like 'pack%' ) then
41 n := length( 'package ' );
42 elsif ( l_line like 'anonymous%' ) then
43 n := length( 'anonymous block ' );
44 else
45 n := null;
46 end if;
47 if ( n is not null ) then
48 caller_t := ltrim(rtrim(upper(substr( l_line, 1, n-1 ))));
49 else
50 caller_t := 'TRIGGER';
51 end if;
52
53 l_line := substr( l_line, nvl(n,1) );
54 n := instr( l_line, '.' );
55 l_owner := ltrim(rtrim(substr( l_line, 1, n-1 )));
56 l_name := ltrim(rtrim(substr( l_line, n+1 )));
57 end if;
58 end if;
59 end loop;
60 select text
61 into calling_line
62 from all_source
63 where line = lineno
64 and type = caller_t
65 and name = l_name
66 and owner = l_owner;
67 var_name := trim ( substr (
68 calling_line
69 , instr(calling_line, '(') + 1
70 , instr(calling_line, ')') - instr(calling_line, '(') - 1
71 ));
72 dbms_output.put_line('variable passed had name '||var_name||' and value '||p_var);
73 end;
74 /
Procedure created.
SQL> create or replace procedure main_procedure
2 is
3 l_var varchar2(10) := 'Hello';
4 begin
5 get_var_name(l_var);
6 end;
7 /
Procedure created.
SQL> exec main_procedure;
variable passed had name l_var and value Hello
PL/SQL procedure successfully completed.cheers,
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Has anyone tried to release an app with differrent names lately?
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This was working a couple of releases before. Has anyone seen this behavior as well and maybe found a way to get the right file name displayed on the device?
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I would like to localize the name ONLY for an app I created in the xml file. For example, if I localize the name in English and Spanish, what name would appear for someone viewing the app in the AppStore in Italy? Would it default to English?
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