Is Safari Find function flexible? (Search for inner strings of characters?)

I'm running 10.6.8 with Safari Version 5.1.7 (6534.57.2). I see that when you search a web page using the Safari Find function, you can only search for the beginnings of words, not for character strings within the words. Is it possible to expand the Find function's capability to search for inner strings of characters?

use command F or the edit menus to make the page search box visible - click the magnify/arrow icon at the left side of it - choose "contains" or "starts with".

Similar Messages

I cannot search for a string of characters in Lion that is a dollar amount, e.g., $90

Greetings! I just upgraded to Lion. Finder no longer allows me to search files, e.g., Word files for amounts, e.g., $90, $100, $85. The "$" character ruins the search. What do I do?!

I don't think you can use that symbol as it is part of the OS. Just like in Windows there are charactrers that can't be used in file names or in searches. They mean something totally different to the OS then what you are using them for.
Just open a terminal window and you will see the OS using the $ sign symbol.

My mac is infected with viruses, Safari can not normally search for constantly appear commercials and some unknown site. What to do? antivirus free program that you recommend?

my mac is infected with viruses, Safari can not normally search for constantly appear commercials and some unknown site. What to do? antivirus free program that you recommend?

You may have installed the "VSearch" trojan, perhaps under a different name. Remove it as follows.
Malware is constantly changing to get around the defenses against it. The instructions in this comment are valid as of now, as far as I know. They won't necessarily be valid in the future. Anyone finding this comment a few days or more after it was posted should look for more recent discussions or start a new one.
Back up all data before proceeding.
Step 1
From the Safari menu bar, select
          Safari ▹ Preferences... ▹ Extensions
Uninstall any extensions you don't know you need, including any that have the word "Spigot," "Trovi," or "Conduit" in the description. If in doubt, uninstall all extensions. Do the equivalent for the Firefox and Chrome browsers, if you use either of those.
Reset the home page and default search engine in all the browsers, if it was changed.
Step 2
Triple-click anywhere in the line below on this page to select it:
/Library/LaunchAgents/com.vsearch.agent.plist
Right-click or control-click the line and select
          Services ▹ Reveal in Finder (or just Reveal)
from the contextual menu.* A folder should open with an item named "com.vsearch.agent.plist" selected. Drag the selected item to the Trash. You may be prompted for your administrator login password.
Repeat with each of these lines:
/Library/LaunchDaemons/com.vsearch.daemon.plist
/Library/LaunchDaemons/com.vsearch.helper.plist
/Library/LaunchDaemons/Jack.plist
Restart the computer and empty the Trash. Then delete the following items in the same way:
/Library/Application Support/VSearch
/Library/PrivilegedHelperTools/Jack
/System/Library/Frameworks/VSearch.framework
~/Library/Internet Plug-Ins/ConduitNPAPIPlugin.plugin
Some of these items may be absent, in which case you'll get a message that the file can't be found. Skip that item and go on to the next one.
This trojan is distributed on illegal websites that traffic in pirated content. If you, or anyone else who uses the computer, visit such sites and follow prompts to install software, you can expect much worse to happen in the future.
You may be wondering why you didn't get a warning from Gatekeeper about installing software from an unknown developer, as you should have. The reason is that this Internet criminal has a codesigning certificate issued by Apple, which causes Gatekeeper to give the installer a pass. Apple could revoke the certificate, but as of this writing, has not done so, even though it's aware of the problem. This failure of oversight has compromised both Gatekeeper and the Developer ID program. You can't rely on Gatekeeper alone to protect you from harmful software.
*If you don't see the contextual menu item, copy the selected text to the Clipboard by pressing the key combination command-C. In the Finder, select
          Go ▹ Go to Folder...
from the menu bar and paste into the box that opens by pressing command-V. You won't see what you pasted because a line break is included. Press return.

Can you use Find/Change to search for many different words at once?

I have an 80 page catalogue in Indesign (CS5) - it has several thousands of catalogue numbers listed as text within it. I've just been given a list of 1000 catalogue numbers to search for and if they appear, remove them - is there any way to search for them all in one go, rather than one by one?
I've started using Find/Change to search for the catalogue numbers but seem to only be able to search one catalogue number at a time that way.
Any ideas welcome!
Thanks

GREP can search for more than one phrase "at once" (i.e., in one operation), like this:
word1|word2|word3
-- the pipe | delimits the separate words. Then again, GREP Is Not Magic™. This --
... a list of 1000 catalogue numbers to search for ...
is a bit too much to copy-and-paste into the single Find What line. There is a limit of ten or twelve (or something) OR phrases you can use in GREP.
On the other hand: GREP is great at finding numbers. If all of your catalogue numbers obey some basic rule, for instance "all of them consist of 6 digits and there are no other numbers with exactly 6 digits", well, that we can probably work with.

How to search for a string in ALL Function Modules source code

Hello,
I want to search for the string "HELLO" in all FUNCTION MODULES source code(FM, no reports/programs).
Is this possible? How?
Cheers,
Andy

hi,
Execute RPR_ABAP_SOURCE_SCAN to search for a string in the code ... Press where-used-list button on the program which takes to the function group or the function module where it is used ..
Regards,
Santosh

Search for a string in SAP Script

Hello Experts,
Is there a way to search for a string in all Z SAP scripts, like ABAP source scan?
Regards,
Hari.

Try using function module "READ_FORM" (you will have to write a simple z-program to find all SAPscripts in your system then use this function module to search the SAPScript Forms for a particular string).
All you have to do is supply the "FORM" name and it will return all of the Pages, Paragraphs, and Texts etc....
More specifically, try looping at the "FORM_LINES" internal table result and you will see the SAPScript text there....
Have fun !
Edited by: Christopher Twirbutt on Sep 16, 2009 12:43 AM

How can I search for a string like a partial IP address in the global search

When searching for a string like "10.255." the global search finds messages containing "255" or "10" and both.
This happens no matter whether quotation is used or not.
When quotation is used it probably will match on the given order as well, but beeing in the timezone '+0100' the string "10" is always found first (in the email headers...).
Is there a way to tell the global search not to use '.' or any other character as whitespace?

When searching for a string like "10.255." the global search finds messages containing "255" or "10" and both.
This happens no matter whether quotation is used or not.
When quotation is used it probably will match on the given order as well, but beeing in the timezone '+0100' the string "10" is always found first (in the email headers...).
Is there a way to tell the global search not to use '.' or any other character as whitespace?

Search for a String within a document (Word, txt, doc) using JSP, JAVA

Hi
I have created a little application that uses combination of JSP and HTML. Users of this application can upload documents which are then stored on the server. I need to develop functionality where I can allows users to search for a string within a document. More precisely, user would type in some string in a text box and application will search all uploaded documents for that string and return the downloadable links to those documents that contains that string. I have never done this before. I was wondering if someone could get me started on this or point me to some thread where this idea is already discussed. Any Jave code exists for searching through documents??
Thanks for your help
Riz

http://www.ibm.com/developerworks/java/library/j-text-searching.html
http://en.wikipedia.org/wiki/Full_text_search
Type these parameter in yahoo:+efficient text search
you will need something like openoffice library to read microsoft word document.

How to search for a variety of characters

I am working on a document wherein a script I ran has applied differential results to page indicators. I am trying to ensure that I have easy accessibility to indexing in an e-book format, and so I am doing the following:
1.) Inserting notes at physical page breaks in the print layout in InDesign
2.) making those notes visible
3.) applying the "page" style to them, which I have set to display hidden in my CSS but will allow me to insert anchor points for a hyperlink index
The problem is the note shows up differentially. Some say:
{~?~PG: @##@} while others show {~?~PG: %##%} where ## represents some page number. The @##@ received the page style properly, but not the %#%. What would be the GREP approach to searching for every instance of {~?~PG: %##%} and applying the page style to it?
I know how to make sure that the page style is applied. I know that I'd use (\d+) for the numbers. I don't know hwo to represent the brackets, tildes, question marks, or other characters. Is there a good reference for this somewhere or perhaps a tutorial? I hate to bug the forum community with it. I just don't know where to go to get the info I need.
Edit: To be clear, I'm trying to search for the string
{~?~PG: %##%}
All of the characters in the string are the same each time, but the numbers are sequentially higher and higher. There are hundreds of these in my document, so replacing each manually is taking a long time. Thanks for any feedback.
Edit #2: After a lot of trial and error, I nailed it. This worked for me:
\{(.+)\%(\d+)\%.
I left the "change to" blank and in the big Change Format window, I added character style "page", though of course this is going to be different for you depending on how you have the name of that style set up in your CSS file if you're making an e-book too. : )
Message was edited by: 1John5vs7

You should definitely look into full-text search. The idea that Kalman floated is doable, but it require a lot more work on your part. Full-text does a lot work for you, for instance handling inflections, so that a search on "goose" will get a
hit on "geese".
If you have never worked with full-text search before, I recommend to get your hands on this book:
http://www.sqlservermvpdeepdives.com/
http://www.amazon.com/SQL-Server-MVP-Deep-Dives/dp/1935182048/ref=sr_1_1?ie=UTF8&qid=1400851023&sr=8-1&keywords=sql+server+mvp+deep+dives
This book is a collection of chapters written by a number of SQL Server MVPs, and all our royalties goes to War Child International, so you are supporting a good aim if you buy this book.
Chapter 13 by Robert Cain is an excellent introduction to full-text search, although it does not handle Semantic Search added in SQL 2012.
As it happens, my chapter, describes a solution of what Kalman had in mind, although it aimed for the case where you want to permit users to search arbitrary character sequence, and that is not want you want.
Erland Sommarskog, SQL Server MVP, [email protected]

How do i search for a string in a txt file using java??

How do i search for a string in a txt file using java??
could you please help thanks
J

Regular expressinos work just fine, especially when
searching for patterns. But they seem to be impying
it's a specific group of characters they're looking
for, and indexOf() is much faster than a regex.If he's reading from a file, the I/O time will likely swamp any performance hit that regex introduces. I think contains() (or indexOf() if he's not on 5.0 yet) is preferable to regex just because it's simpler. (And in the case of contains(), the name makes for a very clear, direct mapping between your intent and the code that realizes it.)

Searching for a string in an excel file and return true if found.

How can I search for a string in an excel file and return true if found, its location and also a value.

The problem with searching an excel file is that it contains a header. It would be easiest if you just read the file into a LabVIEW array and search the array. This way you can also get the index and the value of the location.

Search for a String in a list of files

Could anyone please send me a java sample code which searches for a string from a list of files and returns me the filename and the line in which the Search String was found ?
Thanks in advance
RR

Simple solution would be -
1. Traverse a directory for each file.
2. Read each file using Buffered Reader.
3. Use readLine() method to read a line.
4. Use String.indexOf to see if the data which you are looking for is there in the line or not.
5. If its there then store the line number and file name.
6. When the loop will end you will have list of file name and line number where the data which you are looking for is present.

How to find as ascii value for a string or char in unicode system?

Hello,
How to find an ascii value for a string or char in unicode system?
Thanks in Advance

hi ,
report demtest.
data : c.
field-symbols : <n> type x.
data : rn type i.
c = 'A'.
assign c to <n> casting.
move <n> to rn.
write rn.
This will convert 'A' to 65.
Tom Demuyt
How to convert ascii value to character.
If I give input as 65 (ascill value) I want display 'A'.
Below logic is for convert from character to ascii value , now I want to know how to convert ascii value to character.
Naveen
report demtest.
*going from A to 65
data : c value 'A'.
field-symbols : <n> type x.
data : rn type i.
assign c to <n> casting.
move <n> to rn.
write rn.
*going from 66 to B
data : i type i value 66.
data : x type x.
field-symbols : <fc> type c.
move i to x.
assign x to <fc> casting type c.
move <fc> to c.
write c.
regards,
venkat.

How to search for particular string in array?

I am struggling to figure out how to search array contents for a string and then delete the entry from the array if it is found.
The code for a program that allows the user to enter up to 20 inventory items (tools) is posted below; I apologize in advance for it as I am also not having much success grasping the concept of OOP and I am certain it is does not conform although it all compiles.
Anyway, if you can provide some assistance as to how to go about searching the array I would be most grateful. Many thanks in advance..
// ==========================================================
// Tool class
// Reads user input from keyboard and writes to text file a list of entered
// inventory items (tools)
// ==========================================================
import java.io.*;
import java.text.DecimalFormat;
public class Tool
private String name;
private double totalCost;
int units;
// int record;
   double price;
// Constructor for Tool
public Tool(String toolName, int unitQty, double costPrice)
      name = toolName;
      units = unitQty;
      price = costPrice;
   public static void main( String args[] ) throws Exception
      String file = "test.txt";
      String input;
      String item;
      String addItem;
      int choice = 0;
      int recordNum = 1;
      int qty;
      double price;
      boolean valid;
      String toolName = "";
      String itemQty = "";
      String itemCost = "";
      DecimalFormat fmt = new DecimalFormat("##0.00");
      // Display menu options
      System.out.println();
      System.out.println(" 1. ENTER item(s) into inventory");
      System.out.println(" 2. DELETE item(s) from inventory");
      System.out.println(" 3. DISPLAY item(s) in inventory");
      System.out.println();
      System.out.println(" 9. QUIT program");
      System.out.println();
      System.out.println("==================================================");
      System.out.println();
      // Declare and initialize keyboard input stream
      BufferedReader stdin = new BufferedReader(new InputStreamReader(System.in));
      do
         valid = false;
         try
            System.out.print(" Enter an option > ");
            input = stdin.readLine();
            choice = Integer.parseInt(input);
            System.out.println();
            valid = true;
         catch(NumberFormatException exception)
            System.out.println();
            System.out.println(" Only numbers accepted. Try again.");
      while (!valid);
      while (choice != 1 && choice != 2 && choice != 9)
            System.out.println(" Not a valid option. Try again.");
            System.out.print(" Enter an option > ");
            input = stdin.readLine();
            choice = Integer.parseInt(input);
            System.out.println();
      if (choice == 1)
         // Declare and initialize input file
         FileWriter fileName = new FileWriter(file);
         BufferedWriter bufferedWriter = new BufferedWriter(fileName);
         PrintWriter dataFile = new PrintWriter(bufferedWriter);
         do
            addItem="Y";
               System.out.print(" Enter item #" + recordNum + " name > ");
               toolName = stdin.readLine();
               if (toolName.length() > 15)
                  toolName = toolName.substring(0,15); // Convert to uppercase
               toolName = toolName.toUpperCase();
               dataFile.print (toolName + "\t");
               do
                  valid = false;
                  try
                     // Prompt for item quantity
                     System.out.print(" Enter item #" + recordNum + " quantity > ");
                     itemQty = stdin.readLine();
                     // Parse integer as string
                     qty = Integer.parseInt (itemQty);
                     // Write item quantity to data file
                     dataFile.print(itemQty + "\t");
                     valid=true;
                  catch(NumberFormatException exception)
                     // Throw error for all non-integer input
                     System.out.println();
                     System.out.println(" Only whole numbers please. Try again.");
               while (!valid);
               do
                  valid = false;
                  try
                     // Prompt for item cost
                     System.out.print(" Enter item #" + recordNum + " cost (A$) > ");
                     itemCost = stdin.readLine();
                     // Parse float as string
                     price = Double.parseDouble(itemCost);
                     // Write item cost to data file
                     dataFile.println(fmt.format(price));
                     valid = true;
                  catch(NumberFormatException exception)
                     // Throw error for all non-number input (integers
                  // allowed)
                     System.out.println();
                     System.out.println(" Only numbers please. Try again.");
               while (!valid);
               // Prompt to add another item
               System.out.println();
               System.out.print(" Add another item? Y/N > ");
               addItem = stdin.readLine();
               while ((!addItem.equalsIgnoreCase("Y")) && (!addItem.equalsIgnoreCase("N")))
                  // Prompt for valid input if not Y or N
                  System.out.println();
                  System.out.println(" Not a valid option. Try again.");
                  System.out.print(" Add another item? Y/N > ");
                  addItem = stdin.readLine();
                  System.out.println();
               // Increment record number by 1
               recordNum++;
               if (addItem.equalsIgnoreCase("N"))
                  System.out.println();
                  System.out.println(" The output file \"" + file + "\" has been saved.");
                  System.out.println();
                  System.out.println(" Quitting program.");
        while (addItem.equalsIgnoreCase("Y"));
// Close input file
dataFile.close();
   if (choice == 2)
   try {
      Read user input (array search string)
      Search array
      If match found, remove entry from array
      Confirm "deletion" and display new array contents
   catch block {
} // class
// ==========================================================
// ListToolDetails class
// Reads a text file into an array and displays contents as an inventory list
// ==========================================================
import java.io.*;
import java.util.StringTokenizer;
import java.text.DecimalFormat;
public class ListToolDetails {
   // Declare variable
   private Tool[] toolArray; // Reference to an array of objects of type Tool
   private int toolCount;
   public static void main(String args[]) throws Exception {
      String line, name, file = "test.txt";
      int units, count = 0, record = 1;
      double price, total = 0;
      DecimalFormat fmt = new DecimalFormat("##0.00");
      final int MAX = 20;
      Tool[] items = new Tool[MAX];
      System.out.println("Inventory List");
      System.out.println();
      System.out.println("REC.#" + "\t" + "ITEM" + "\t" + "QTY" + "\t"
            + "PRICE" + "\t" + "TOTAL");
      System.out.println("\t" + "\t" + "\t" + "\t" + "PRICE");
      System.out.println();
      try {
         // Read a tab-delimited text file of inventory items
         FileReader fr = new FileReader(file);
         BufferedReader inFile = new BufferedReader(fr);
         StringTokenizer tokenizer;
         while ((line = inFile.readLine()) != null) {
            tokenizer = new StringTokenizer(line, "\t");
            name = tokenizer.nextToken();
            try {
               units = Integer.parseInt(tokenizer.nextToken());
               price = Double.parseDouble(tokenizer.nextToken());
               items[count++] = new Tool(name, units, price);
               total = units * price;
            } catch (NumberFormatException exception) {
               System.out.println("Error in input. Line ignored:");
               System.out.println(line);
            System.out.print(" " + count + "\t");
            System.out.print(line + "\t");
            System.out.print(fmt.format(total));
            System.out.println();
         inFile.close();
      } catch (FileNotFoundException exception) {
         System.out.println("The file " + file + " was not found.");
      } catch (IOException exception) {
         System.out.println(exception);
      System.out.println();
   // Unfinished functionality for displaying "error" message if user tries to
   // add more than 20 tools to inventory
   public void addTool(Tool maxtools) {
      if (toolCount < toolArray.length) {
         toolArray[toolCount] = maxtools;
         toolCount += 1;
      } else {
         System.out.print("Inventory is full. Cannot add new tools.");
   // This should search inventory by string and remove/overwrite matching
   // entry with null
   public Tool getTool(int index) {
      if (index < toolCount) {
         return toolArray[index];
      } else {
         System.out
               .println("That tool does not exist at this index location.");
         return null;
} // classData file contents:
TOOL 1     1     1.21
TOOL 2     8     3.85
TOOL 3     35     6.92

Ok, so you have an array of Strings. And if the string you are searching for is in the array, you need to remove it from the array.
Is that right?
Can you use an ArrayList<String> instead of a String[ ]?
To find it, you would just do:
for (String item : myArray){
   if (item.equals(searchString){
      // remove the element. Not trivial for arrays, very easy for ArrayList
}Heck, with an arraylist you might be able to do the following:
arrayList.remove(arrayList.indexOf(searchString));[edit]
the above assumes you are using 1.5
uses generics and for each loop
[edit2]
and kinda won't work it you have to use an array since you will need the array index to be able to remove it. See the previous post for that, then set the value in that array index to null.
Message was edited by:
BaltimoreJohn

Help to search for a string value and return the index in the arraylist

Hello,
I just start java programming for the last three weeks and I cannot find a solution for this problem. I have the following List with string and integer value as shown below:
List<Empl> list= new ArrayList<Empl>();
     list.add(new Empl(1,"Jim", "Balu",88);
     list.add(new Empl(3,"Bob", "Howards",2);
     list.add(new Empl(2,"Chris", "Hup",8);
I have no problem of sorting this arraylist either by firstname or lastname. However, I cannot think of a way to search for a firstname or lastname and returing the whole row. I do not want to use index since I am asking user to enter the name to search. Here is my code to search for an empl based on index.
System.out.print("Please enter index to search or (q)uit: ");
          String ans = sc.next();
          System.out.println();
          int ians = Integer(ans);
          if (ans.equalsIgnoreCase("q"))
                    choice = "n";
          else
          System.out.println("index " + list.get(ians)); //this will print out the whole row based on the index
Since the user will never seen the contents of the arraylist, is there a way that I can search by string last/first name and will get the index location in int if the result is met?
Please advice and thank you.
Bob.

user11191663 wrote:
Since the user will never seen the contents of the arraylist, is there a way that I can search by string last/first name and will get the index location in int if the result is met?Another possibility is to set up an ArrayList for each thing you want to search on and then every time you add an employee, add the piece of data you want as well, viz:
Empl e = new Empl(1,"Jim", "Balu",88);
list.add(e);
firstNames.add(e.firstName());As long as you always add them in the same order, the indexes will match, so you could do something like
ians = firstNames.indexOf(nameToFind);to return the index of the name, if it's there (if not, it will return -1).
I wouldn't recommend this as standard practise, but it should be OK for the level you're at.
NOTE: indexOf() returns the index of the FIRST matching item. You may want to think about what you want to do if there are more than 1.
Winston

Is Safari Find function flexible? (Search for inner strings of characters?)

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