Is there a possibility to photomerge in Elements 8?

Do i need a Plug-in? where can i find this?

http://forums.adobe.com/message/2692160
This thread provides a lot of information .

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    Yes, I see:
    Letzte Aktualisierung
    16.04.2012
    The link I gave is listed in the faqs of this forum.
    Photoshop Elements FAQ List
    mfG
    Michel

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    User hooks is the way to do it
    Check - Understanding and Using Application Program Interface (API) User Hooks in Oracle HRMS [ID 73170.1]
    HRMS API User Hooks
    User hook for SIT

  • Show all the possible combinations of n elements in an array???

    If I have an array of n elements, how to show all the possible combinations of n elements.
    What is the java library for doing the combinations??
    For example,
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  • Printing every possible pair combination of elements in two arrays??

    Hi there,
    I'm trying to implement the problem of printing every possible pair combination of elements in two arrays. The pattern I have in mind is very simple, I just don't know how to implement it. Here's an example:
    g[3] = {'A', 'B', 'C'}
    h[3] = {1, 2, 3}
    ...code...??
    Expected Output:
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    C = 3
    A = 1
    B = 3
    C = 2
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    B = 1
    C = 3
    A = 2
    B = 3
    C = 1
    A = 3
    B = 1
    C = 2
    A = 3
    B = 2
    C = 1
    The code should work for any array size, as long as both arrays are the same size. Anybody know how to code this??
    Cheers,
    Sean

    not a big fan of Java recursion, unless tail recursion, otherwise you are bound to have out of stack error. Here is some generic permutation method I wrote a while back:
    It is generic enough, should serve your purpose.
    * The method returns all permutations of given objects.  The input array is a two-dimensionary, with the 1st dimension being
    * the number of buckets (or distributions), and the 2nd dimension contains all possible items for each of the buckets.
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    * 1    2    3
    * a    d    f
    * b    e    g
    * c
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    * All possible permutaions are:
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    * a    d    g
    * a    e    f
    * a    e    g
    * b    d    f
    * b    d    g
    * b    e    f
    * b    e    g
    * c    d    f
    * c    d    g
    * c    e    f
    * c    e    g
    * You can see the pattern, every possiblity of 3rd bucket is repeated once, every possiblity of 2nd bucket is repeated twice,
    * and that of 1st is 4.  The number of repetition has a pattern to it, ie: the multiplication of permutation of all the
    * args after the current one.
    * Therefore: 1st bucket has 2*2 = 4 repetition, 2nd has 2*1 = 2 repetition while 3rd being the last one only has 1.
    * The method returns another two-dimensional array, with the 1st dimension represent the number of permutations, and the 2nd
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         for(i=(items.length-1);i>=0;i--)
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              out[i] = filter.toArray((Object[])Array.newInstance(objectClassType, filter.size()));
              filter.clear();
         return out;

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    HI
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    "mcmastal" a écrit dans le message news:
    [email protected]..
    > In LabVIEW6i, is there a way to make particular elements of an array
    > invisible while the others stay visible (without losing any element's
    > info.)?
    >
    > I have an array of clusters. Each cluster pertains to a certain
    > oscilloscope I am controlling. There is another control which
    > specifies which oscilloscopes I have "on".
    > If a particular oscilloscope is "on" I want its cluster to be VISIBLE
    > in the array. If a particular oscilloscope is "off" I want its
    > cluster to be INVISIBLE in the array.
    > How can I implement this in my program without losing ANY of the
    > info. in my array?
    LabVIEW, C'est LabVIEW

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