Java constructor overload error

Question

I just tried a simple java program and it works on Linux but fails on Mac. Here is the code:
package TestProject;
public class Main {
           * @param args
          public static void main(String[] args) {
  // TODO Auto-generated method stub
              int x =5;
              int y = 6;
              double a=5.0;
              double b=6.0;
              testout to1 = new testout(x,y);
              testout to2 = new testout(a, b);
              System.out.println(to1.getIntResult());
              System.out.println(to2.getDoubleResult());
package TestProject;
public class testout {
    private int a=0, b=0;
    private double c=0.0, d=0.0;
    public void testout(int x, int y)
        a = x;
        b = y;
    public testout(double x, double y)
        c = x;
        d = y;
    public double getDoubleResult()
        return c + d;
    public int getIntResult()
        return a + b;
As you see I have a constructor to pass either two ints or two doubles. When I run the program on Linux I get the expected result. When I run on Mac, the getIntResult returns zero. I debugged the program and the int constructor is using the double instead. I verified on both netbeans and eclipse.
Looks like a bug but maybe I am doing something stupid.....

Answer 1

Not being a Java developer, only have taken one semester of Java, and not having slept in a Holiday Inn recently, I couldn't tell you if it is a bug or not, but since an int can be freely cast to a double, maybe the Mac OS X JRE is finding the double, double constructor and saying to itself, "self, I can make those ints into doubles, so let's just use this double, double signature. la la la alaalla lla alllaaaaalllaa la al."
If you can find documentation in the Java implementation that directs you use the best constructor vice any appropriate constructor, file a bug report.
I would imagine you should always use the best match, not just one that works.