Java debugging - problems with standard input

Hi
I hope somebody can help me with this problem.
I'm developing a Java app that reads from the standard input. I use System.in.read() to do that. When I debug it, I use the Standard I/O window instead of the Run Log window to pass in values, but nothing happens (i.e. the line following the read() is never reached). I also tried to run the app and then attach the debugger to use the Run Log window as standard input, with the same result. If I add a breakpoint before the call to read(), the debugger pauses the execution, so I suppose the breakpoints are OK.
In the executable Info window, Debugging tab, I use the pseudo terminal with the Java debugger.
So my question is: how can I enter values from the standard input in debugging mode?

I believe that you are seeing these problems because we have found the
current versions of RMI found in the JDK to be inherently unscalable -- we
do not listen for them. As you noticed, we recommend that you use our
packages for now, and then do the simple change that you found if you decide
that you do not like WLS. (If you do decide that you do not like us, please
definitely let us know why you chose the way you did!)
Thanks,
Michael
Michael Girdley
Product Manager, WebLogic Server & Express
BEA Systems Inc
"Tim Dawson" <[email protected]> wrote in message
news:397b8cc2$[email protected]..
We're developing a J2EE application on NT using WLS 5.1, SP3, but we don't
want to be tied to any particular J2EE server, so we're making sure that
none of our code is weblogic specific.
In keeping with this philosophy, I created an RMI service that used the
standard java.rmi.* imports instead of weblogic.rmi.* and used thestandard
RMIC compiler rather than the weblogic.rmic compiler.
Unfortunately, I couldn't get the system to work. I kept getting
"java.rmi.MarshalException: Error marshaling transport header; nested
exception is: java.io.EOFException" whenever I'd call Naming.lookup().
Of course, when I did the search & replace with java.rmi.* with
weblogic.rmi.*, and switched from the standard rmic to weblogic.rmic,
everything started working just fine. This is the ONLY change I made!
Has anyone else run into similar problems?
Tim Dawson
Sr. Software Architect
is.com

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            MLGN,                          "Material Data per Whse Number
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                DYNPRO_NUMBER = SYST-DYNNR
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               FILE_NAME     = S_PATH-LOW
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      PARMS-DS_TYP    = P_DS_TYP.
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      PERFORM 0020_DS_NAME.
      PERFORM 0030_OPEN_FILE.
      PERFORM 0040_INIT_STRUCTS.
    ENDFORM.
    *eject
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    *eject
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    *eject
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                UNIX                = PARMS-UNIX
                PC                  = PARMS-PC
                FILETYPE            = PARMS-DS_TYP
                FILENAME            = PARMS-PATH
                HDR_LINES           = PARMS-HDR_LINES
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                DATA_TAB            = INP_DATA
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                CONVERSION_ERROR    = 1
                FILE_OPEN_ERROR     = 2
                FILE_READ_ERROR     = 3
                INVALID_TABLE_WIDTH = 4
                INVALID_TYPE        = 5
                NO_BATCH            = 6
                UNKNOWN_ERROR       = 7
                INVALID_SOURCE      = 8
                OTHERS              = 9.
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    *eject
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          Write record in standard SAP structure to UNIX file           *
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    *eject
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          text                                                           *
    -->  p1        text
    <--  p2        text
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            CODEPAGE            = ' '
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            WK1_N_SIZE          = ' '
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               UNKNOWN_ERROR       = 7
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         SEPARATOR_NOT_ALLOWED           = 8
         FILESIZE_NOT_ALLOWED            = 9
         HEADER_TOO_LONG                 = 10
         DP_ERROR_CREATE                 = 11
         DP_ERROR_SEND                   = 12
         DP_ERROR_WRITE                  = 13
         UNKNOWN_DP_ERROR                = 14
         ACCESS_DENIED                   = 15
         DP_OUT_OF_MEMORY                = 16
         DISK_FULL                       = 17
         DP_TIMEOUT                      = 18
         FILE_NOT_FOUND                  = 19
         DATAPROVIDER_EXCEPTION          = 20
         CONTROL_FLUSH_ERROR             = 21
         OTHERS                          = 22.
      IF SY-SUBRC NE 0.
         MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
               WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
      ENDIF.
    *END OF BLOCK ADDED BY SRY28NOV05
    ENDFORM.                               " 2100_WS_DOWNLOAD
    *eject
          FORM 4000_PROGRESS_INDICATOR                                  *
          Write progress text to status bar                             *
    -->  TEXT   " Text passed as parameter                             *
    FORM 4000_PROGRESS_INDICATOR USING TEXT.
      CALL FUNCTION 'SAPGUI_PROGRESS_INDICATOR'
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                PERCENTAGE = 0
                TEXT       = TEXT
           EXCEPTIONS
                OTHERS     = 1.
    ENDFORM.
    *eject.
          FORM 9000_END_OF_JOB                                          *
          Close files on UNIX                                           *
    FORM 9000_END_OF_JOB.
      CLOSE DATASET PARMS-DS_NAME.
    ENDFORM.
    FORM 1000_GET_SOURCE_DATA TABLES INP_DATA.
      CALL FUNCTION 'Z_FILE_UPLOAD'
           EXPORTING
                UNIX                = PARMS-UNIX
                PC                  = PARMS-PC
                FILETYPE            = PARMS-DS_TYP
                FILENAME            = PARMS-PATH
                HDR_LINES           = PARMS-HDR_LINES
           TABLES
                DATA_TAB            = INP_DATA
           EXCEPTIONS
                CONVERSION_ERROR    = 1
                FILE_OPEN_ERROR     = 2
                FILE_READ_ERROR     = 3
                INVALID_TABLE_WIDTH = 4
                INVALID_TYPE        = 5
                NO_BATCH            = 6
                UNKNOWN_ERROR       = 7
                INVALID_SOURCE      = 8
                OTHERS              = 9.
    ENDFORM.
    *eject
          FORM 2000_WRITE_OUTPUT                                        *
          Write record in standard SAP structure to UNIX file           *
    -->  I_STRUCT   " Name of record passed as parameter               *
    *FORM 2000_WRITE_OUTPUT USING I_STRUCT."SRY28NOV05
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        MESSAGE A099.
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    ENDFORM.
    *eject
    *&      Form  2100_WS_DOWNLOAD
          text                                                           *
    -->  p1        text
    <--  p2        text
    FORM 2100_WS_DOWNLOAD TABLES INP_DATA.

    Hi,
    Thnaks for your reply, This is my requirement.
    Here my problem is i am trying to upload the data from flatfile which contain materil number, denominator, Actual UOM, Nominator field values.
    Which is the data i need to upload into MM02 and MM01, if material number is new then it has to create the material, if material is already existing it has to update the UOM values.
    here i am getting data into my internal table INP_DATA, from that i am trying to upload the data to database by using job name MRP_MATERIAL_MASTER_DATA_UPLOAD with direct input program RMDATIND.
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    Thanks & Regards,
    RamNV

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    0.0
    0.01
    0.02
    0.03
    0.04
    0.05
    0.060000000000000005
    0.07
    0.08
    0.09
    0.09999999999999999
    0.10999999999999999
    0.11999999999999998
    0.12999999999999998
    0.13999999999999999
    0.15
    0.16
    0.17
    0.18000000000000002
    0.19000000000000003
    0.20000000000000004
    0.21000000000000005
    0.22000000000000006
    0.23000000000000007
    0.24000000000000007
    0.25000000000000006
    0.26000000000000006
    0.2700000000000001
    0.2800000000000001
    0.2900000000000001
    0.3000000000000001
    0.3100000000000001
    0.3200000000000001
    0.3300000000000001
    0.34000000000000014
    0.35000000000000014
    0.36000000000000015
    0.37000000000000016
    0.38000000000000017
    0.3900000000000002
    0.4000000000000002
    0.4100000000000002
    0.4200000000000002
    0.4300000000000002
    0.4400000000000002
    0.45000000000000023
    0.46000000000000024
    0.47000000000000025
    0.48000000000000026
    0.49000000000000027
    0.5000000000000002
    0.5100000000000002
    0.5200000000000002
    0.5300000000000002
    0.5400000000000003
    0.5500000000000003
    0.5600000000000003
    0.5700000000000003
    0.5800000000000003
    0.5900000000000003
    0.6000000000000003
    0.6100000000000003
    0.6200000000000003
    0.6300000000000003
    0.6400000000000003
    0.6500000000000004
    0.6600000000000004
    0.6700000000000004
    0.6800000000000004
    0.6900000000000004
    0.7000000000000004
    0.7100000000000004
    0.7200000000000004
    0.7300000000000004
    0.7400000000000004
    0.7500000000000004
    0.7600000000000005
    0.7700000000000005
    0.7800000000000005
    0.7900000000000005
    0.8000000000000005
    0.8100000000000005
    0.8200000000000005
    0.8300000000000005
    0.8400000000000005
    0.8500000000000005
    0.8600000000000005
    0.8700000000000006
    0.8800000000000006
    0.8900000000000006
    0.9000000000000006
    0.9100000000000006
    0.9200000000000006
    0.9300000000000006
    0.9400000000000006
    0.9500000000000006
    0.9600000000000006
    0.9700000000000006
    0.9800000000000006
    0.9900000000000007
    1.0000000000000007
    1.0100000000000007
    1.0200000000000007
    1.0300000000000007
    1.0400000000000007
    1.0500000000000007
    1.0600000000000007
    1.0700000000000007
    1.0800000000000007
    1.0900000000000007
    1.1000000000000008
    1.1100000000000008
    1.1200000000000008
    1.1300000000000008
    1.1400000000000008
    1.1500000000000008
    1.1600000000000008
    1.1700000000000008
    1.1800000000000008
    1.1900000000000008
    1.2000000000000008
    1.2100000000000009
    1.2200000000000009
    1.2300000000000009
    1.2400000000000009
    1.2500000000000009
    1.260000000000001
    1.270000000000001
    1.280000000000001
    1.290000000000001
    1.300000000000001
    1.310000000000001
    1.320000000000001
    1.330000000000001
    1.340000000000001
    1.350000000000001
    1.360000000000001
    1.370000000000001
    1.380000000000001
    1.390000000000001
    1.400000000000001
    1.410000000000001
    1.420000000000001
    1.430000000000001
    1.440000000000001
    1.450000000000001
    1.460000000000001
    1.470000000000001
    1.480000000000001
    1.490000000000001
    1.500000000000001
    1.5100000000000011
    1.5200000000000011
    1.5300000000000011
    1.5400000000000011
    1.5500000000000012
    1.5600000000000012
    1.5700000000000012
    1.5800000000000012
    1.5900000000000012
    1.6000000000000012
    1.6100000000000012
    1.6200000000000012
    1.6300000000000012
    1.6400000000000012
    1.6500000000000012
    1.6600000000000013
    1.6700000000000013
    1.6800000000000013
    1.6900000000000013
    1.7000000000000013
    1.7100000000000013
    1.7200000000000013
    1.7300000000000013
    1.7400000000000013
    1.7500000000000013
    1.7600000000000013
    1.7700000000000014
    1.7800000000000014
    1.7900000000000014
    1.8000000000000014
    1.8100000000000014
    1.8200000000000014
    1.8300000000000014
    1.8400000000000014
    1.8500000000000014
    1.8600000000000014
    1.8700000000000014
    1.8800000000000014
    1.8900000000000015
    1.9000000000000015
    1.9100000000000015
    1.9200000000000015
    1.9300000000000015
    1.9400000000000015
    1.9500000000000015
    1.9600000000000015
    1.9700000000000015
    1.9800000000000015
    1.9900000000000015
    2.0000000000000013
    2.010000000000001
    2.020000000000001
    2.0300000000000007
    2.0400000000000005
    2.0500000000000003
    Thanks for answerers !
    Joseph

    This result is entirely unsurprising, and the flaw lies in your program, not in Java.
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    The correct way to approach what you are trying to do would be to perform the addition using integers, and multiply each time you want to scale it to a double.
    This has been asked many times - I would suggest you:
    - Search the forums
    - Check out the language spec
    - or do a degree in CompSci :-)
    A calculator is a little more accurate because it does not have to conform to agreed standards, and so can use special logic to minimise such errors. The average pocket calulator also works to a much lower level of accuracy (usu 8 digits), and therefore masks the errors to you. You'd find that you got the same effect if you played with it long enough.
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    Hi,
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    2: getting a StoredKeySet from said map
    3: getting a StoredIterator on said StoredKeySet
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    Everything checked out ok.
    What it boils down to is this: my key creator is adding DatabaseEntries of the correct size to the results set, but when the keys are being read back later on, my key binding is only receiving 2 bytes of data. For the one SecondaryDatabase that doesn't use a SecondaryMultiKeyCreator, but just a SecondaryKeyCreator, there are no issues and I am able to iterate through its secondary keys as expected.
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    Thank you for your attention,
    -Justin
    Message was edited by:
    Steamroller

    Hi Justin,
    Sorry about the delayed response here. I have created a patch that resolves the problem.
    If you apply the patch to your 4.6.21 source tree, and then rebuild Berkeley DB, the improper behavior should be resolved.
    Regards,
    Alex
    diff -rc db/db_am.c db/db_am.c
    *** db/db_am.c     Thu Jun 14 04:21:30 2007
    --- db/db_am.c     Fri Jun 13 11:20:28 2008
    *** 331,338 ****
           F_SET(dbc, DBC_TRANSIENT);
    !      switch (flags) {
    !      case DB_APPEND:
                 * If there is an append callback, the value stored in
                 * data->data may be replaced and then freed.  To avoid
    --- 331,337 ----
           F_SET(dbc, DBC_TRANSIENT);
    !       if (flags == DB_APPEND && LIST_FIRST(&dbp->s_secondaries) == NULL) {
                 * If there is an append callback, the value stored in
                 * data->data may be replaced and then freed.  To avoid
    *** 367,388 ****
    -            * Secondary indices:  since we've returned zero from an append
    -            * function, we've just put a record, and done so outside
    -            * __dbc_put.  We know we're not a secondary-- the interface
    -            * prevents puts on them--but we may be a primary.  If so,
    -            * update our secondary indices appropriately.
    -            * If the application is managing this key's data, we need a
    -            * copy of it here.  It will be freed in __db_put_pp.
    -           DB_ASSERT(dbenv, !F_ISSET(dbp, DB_AM_SECONDARY));
    -           if (LIST_FIRST(&dbp->s_secondaries) != NULL &&
    -               (ret = __dbt_usercopy(dbenv, key)) == 0)
    -                ret = __db_append_primary(dbc, key, &tdata);
                 * The append callback, if one exists, may have allocated
                 * a new tdata.data buffer.  If so, free it.
    --- 366,371 ----
    *** 390,401 ****
                /* No need for a cursor put;  we're done. */
                goto done;
    !      default:
    !           /* Fall through to normal cursor put. */
    !           break;
    !      if (ret == 0)
                ret = __dbc_put(dbc,
                    key, data, flags == 0 ? DB_KEYLAST : flags);
    --- 373,379 ----
                /* No need for a cursor put;  we're done. */
                goto done;
    !      } else
                ret = __dbc_put(dbc,
                    key, data, flags == 0 ? DB_KEYLAST : flags);
    diff -rc db/db_cam.c db/db_cam.c
    *** db/db_cam.c     Tue Jun  5 21:46:24 2007
    --- db/db_cam.c     Thu Jun 12 16:41:29 2008
    *** 899,905 ****
           DB_ENV *dbenv;
           DB dbp, sdbp;
           DBC dbc_n, oldopd, opd, sdbc, *pdbc;
    !      DBT olddata, oldpkey, newdata, pkey, temppkey, tempskey;
           DBT all_skeys, skeyp, *tskeyp;
           db_pgno_t pgno;
           int cmp, have_oldrec, ispartial, nodel, re_pad, ret, s_count, t_ret;
    --- 899,905 ----
           DB_ENV *dbenv;
           DB dbp, sdbp;
           DBC dbc_n, oldopd, opd, sdbc, *pdbc;
    !      DBT olddata, oldpkey, newdata, pkey, temppkey, tempskey, tdata;
           DBT all_skeys, skeyp, *tskeyp;
           db_pgno_t pgno;
           int cmp, have_oldrec, ispartial, nodel, re_pad, ret, s_count, t_ret;
    *** 1019,1026 ****
            * should have been caught by the checking routine, but
            * add a sprinkling of paranoia.
    !      DB_ASSERT(dbenv, flags == DB_CURRENT || flags == DB_KEYFIRST ||
    !            flags == DB_KEYLAST || flags == DB_NOOVERWRITE);
            * We'll want to use DB_RMW in a few places, but it's only legal
    --- 1019,1027 ----
            * should have been caught by the checking routine, but
            * add a sprinkling of paranoia.
    !       DB_ASSERT(dbenv, flags == DB_APPEND || flags == DB_CURRENT ||
    !             flags == DB_KEYFIRST || flags == DB_KEYLAST ||
    !             flags == DB_NOOVERWRITE);
            * We'll want to use DB_RMW in a few places, but it's only legal
    *** 1048,1053 ****
    --- 1049,1107 ----
                     goto err;
                have_oldrec = 1; /* We've looked for the old record. */
    +      } else if (flags == DB_APPEND) {
    +           /*
    +            * With DB_APPEND, we need to do the insert to populate the
    +            * key value. So we swap the 'normal' order of updating
    +            * secondary / verifying foreign databases and inserting.
    +            *
    +            * If there is an append callback, the value stored in
    +            * data->data may be replaced and then freed.  To avoid
    +            * passing a freed pointer back to the user, just operate
    +            * on a copy of the data DBT.
    +            */
    +           tdata = *data;
    +           /*
    +            * If this cursor is going to be closed immediately, we don't
    +            * need to take precautions to clean it up on error.
    +            */
    +           if (F_ISSET(dbc_arg, DBC_TRANSIENT))
    +                dbc_n = dbc_arg;
    +           else if ((ret = __dbc_idup(dbc_arg, &dbc_n, 0)) != 0)
    +                goto err;
    +
    +           pgno = PGNO_INVALID;
    +
    +           /*
    +            * Append isn't a normal put operation;  call the appropriate
    +            * access method's append function.
    +            */
    +           switch (dbp->type) {
    +           case DB_QUEUE:
    +                if ((ret = __qam_append(dbc_n, key, &tdata)) != 0)
    +                     goto err;
    +                break;
    +           case DB_RECNO:
    +                if ((ret = __ram_append(dbc_n, key, &tdata)) != 0)
    +                     goto err;
    +                break;
    +           default:
    +                /* The interface should prevent this. */
    +                DB_ASSERT(dbenv,
    +                    dbp->type == DB_QUEUE || dbp->type == DB_RECNO);
    +
    +                ret = __db_ferr(dbenv, "DBC->put", 0);
    +                goto err;
    +           }
    +           /*
    +            * The append callback, if one exists, may have allocated
    +            * a new tdata.data buffer.  If so, free it.
    +            */
    +           FREE_IF_NEEDED(dbenv, &tdata);
    +           pkey.data = key->data;
    +           pkey.size = key->size;
    +           /* An append cannot be replacing an existing item. */
    +           nodel = 1;
           } else {
                /* Set pkey so we can use &pkey everywhere instead of key.  */
                pkey.data = key->data;
    *** 1400,1405 ****
    --- 1454,1465 ----
      skip_s_update:
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    +       * secondary updates, so we are finished.
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    +           goto done;
    +      /*
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            * to it, perform the operation.  Duplicate the cursor and call the
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    however what is happening when i run this code is the numbers are being put into the right stacks of the tree, but any commands such as printLevelOrder or PrintPopRoot are entering the code that is for placing numbers onto the stack instead of executing that command and skipping past this piece of code.
    so my question is, why is the if statement if (word =="printLevelOrder") not being executed when thats whats in the word ?
    example input and output shown below code fragment.
              try {
                  BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
                 String line = "";
                 while (line != "***") {
                      System.out.print("> prompt ");
                      line = in.readLine();
                      StringTokenizer tokenizer = new StringTokenizer(line," ");
                      String word = new String();
                      while (tokenizer.hasMoreTokens()) {
                             word = tokenizer.nextToken();
                             boolean notCommand = true;
                             if (word =="printLevelOrder") {
                                  theTree.printLevelOrder();
                                  System.out.println("(word ==printLevelOrder)");
                                  notCommand=false;
                             if (word == "printPopLevelOrder") {
                                  theTree.printPopLevelOrder();
                                  notCommand=false;
                             if (word == "printPopInorder") {
                                  theTree.printPopInorder();
                                  notCommand=false;
                             if (word == "printPopPreorder") {
                                  theTree.printPopPreorder();
                                  notCommand=false;
                             if (word == "printPopRoot") {
                                  theTree.printPopRoot();
                                  notCommand=false;
                             if (word == "***") {
                                  notCommand=false;
                             if (notCommand == true) {
                                  System.out.println("(notCommand == true)");
                                  boolean notPlaced = true;
                                  int v = 1;
                                  while ((notPlaced==true) && (v < theTree.size())) {
                                       if (theTree.element(v).isEmpty()) {
                                            theTree.element(v).push(Integer.valueOf(word));
                                            System.out.println("Inserting"+word);
                                            System.out.println("in empty stack at location: "+v);
                                            notPlaced=false;
                                       if (notPlaced==true) {
                                            if (  Integer.valueOf(word) >= Integer.valueOf( theTree.element(v).top().toString() )  ) {
                                                 theTree.element(v).push(Integer.valueOf(word));
                                                 System.out.println("Inserting"+word);
                                                 System.out.println("in stack at location: "+v);
                                                 notPlaced=false;
                                       v++;
              }valid inputs: int value, printLevelOrder, printPopLevelOrder, printPopInorder, p
    rintPopPreorder, printPopRoot, *** to quit
    prompt 1 3 2 4 2 printLevelOrder(notCommand == true)
    Inserting1
    in empty stack at location: 1
    (notCommand == true)
    Inserting3
    in stack at location: 1
    (notCommand == true)
    Inserting2
    in empty stack at location: 2
    (notCommand == true)
    Inserting4
    in stack at location: 1
    (notCommand == true)
    Inserting2
    in stack at location: 2
    (notCommand == true)
    Exception in thread "main" java.lang.NumberFormatException: For input string: "printLevelOrder"
    at java.lang.NumberFormatException.forInputString(NumberFormatException.java:48)
    at java.lang.Integer.parseInt(Integer.java:447)
    at java.lang.Integer.valueOf(Integer.java:553)
    at TreeStack.main(TreeStack.java:73)
    Press any key to continue . . .

    lol aww, shame that you forgot to do that. i had 10 / 10 for mine, and seing as the deadline is now well and trully over,
    here is the entire source for anybody who was following the discussion or whatever and wanted to experiment.
    additional files needed >
    http://users.cs.cf.ac.uk/Paul.Rosin/CM0212/Stack.java
    http://users.cs.cf.ac.uk/Paul.Rosin/CM0212/ArrayStack.java
    http://users.cs.cf.ac.uk/Paul.Rosin/CM0212/StackEmptyException.java
    http://users.cs.cf.ac.uk/Paul.Rosin/CM0212/StackFullException.java
    /*TreeStack.java - reads command line input of values and assigns them to stacks in a  binary tree and performs
    operations on the ADT. valid inputs: <int>,   printLevelOrder,   printPopLevelOrder,
    printPopInorder,   printPopPreOrder,   printPopRoot.         Terminates on invalid input.
    Written by George St. Clair.
    S/N:0208456         22/11/2005
    import java.util.Vector;
    import java.io.*;
    import java.util.StringTokenizer;
    public class TreeStack {
         private final int TREE_CAPACITY = 7 + 1;
         private final int STACK_CAPACITY = 10;
         Vector tree = new Vector(TREE_CAPACITY) ;
         //collect input from command line, add values to stacks at nodes of the teee
         //and perform required operations on the treestack
         public static void main (String [] args) {
              //create a tree of stacks
              TreeStack theTree = new TreeStack ();
              try {
                   //collect standard input
                  BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
                 String line = "";
                 while (line != null) {
                        System.out.print("");
                      line = in.readLine();
                      //tokenise input
                      StringTokenizer tokenizer = new StringTokenizer(line," ");
                      String word = new String();
                      while (tokenizer.hasMoreTokens()) {
                             //assign word to the token
                             word = tokenizer.nextToken();
                             boolean notCommand = true;
                             //perform operation on treestack depending on what word is
                             if (word.equals("printLevelOrder"))  {
                                  System.out.println("printLevelOrder");
                                  theTree.printLevelOrder();
                                  notCommand=false;
                             if (word.equals("printPopLevelOrder"))  {
                                  System.out.println("printPopLevelOrder");
                                  theTree.printPopLevelOrder();
                                  notCommand=false;
                             if (word.equals("printPopInorder"))  {
                                  System.out.println("printPopInorder");
                                  theTree.printPopInorder();
                                  notCommand=false;
                             if (word.equals("printPopPreorder"))  {
                                  System.out.println("printPopPreorder");
                                  theTree.printPopPreorder();
                                  notCommand=false;
                             if (word.equals("printPopRoot"))  {
                                  System.out.println("printPopRoot");
                                  theTree.printPopRoot();
                                  notCommand=false;
                             //if word was not a command it must be a number
                             if (notCommand == true) {
                                  boolean notPlaced = true;
                                  int v = 1;
                                  //starting at the root, find suitable place for number
                                  while ((notPlaced==true) && (v < theTree.size())) {
                                       //if the stack at v is empty, number goes here
                                       if (theTree.element(v).isEmpty()) {
                                            theTree.element(v).push(Integer.valueOf(word));
                                            System.out.println("inserting: "+word);
                                            System.out.println("in empty stack at location: "+(v-1));
                                            notPlaced=false;
                                       //if the stack is not empty
                                       if (notPlaced==true) {
                                            //if the value on the top of the stack is smaller than number, number goes onto the stack
                                            if (  Integer.valueOf(word) > Integer.valueOf( theTree.element(v).top().toString() )  ) {
                                                 theTree.element(v).push(Integer.valueOf(word));
                                                 System.out.println("inserting: "+word);
                                                 System.out.println("in stack at location: "+(v-1));
                                                 notPlaced=false;
                                       //if that node was no good, check the next one for suitability
                                       v++;
              catch (Exception e) {
                   //occurs when user inputs something that is neither a command, or a number, or upon EOF, or stack is full
         public TreeStack () {
              //create the TreeStack ADT by adding stacks in the vector, note vector 0 is instantiated but not used.
              for (int i = 1;i<=TREE_CAPACITY;i++)
                   tree.add(new ArrayStack(STACK_CAPACITY));
         public int size() {
              //return the size of the tree +1 (as 0 is not used)
              return tree.size();
         public ArrayStack element (int v) {
              //return the ArrayStack at v
              return (ArrayStack)tree.get(v);
         public int leftChild (int v ) {
              //return left child of v
              return v*2;
         public int rightChild (int v ) {
              //return the right child of v
              return v*2+1;
         public boolean children (int v ) {
              //search for children of v and return true if one exists
              for (int i =v;i<size();i++) {
                   if (i/2==v ) {
                         //left child found at i
                         return true;
                   if ((i-1)/2==v ) {
                        //right child found at i
                        return true;
              //no children found
              return false;
         public boolean isInternal (int v ) {
              //test whether node v is internal (has children)
              if (children (v)== true) {
                   //has children
                   return true;
              return false;
         //print the top value in each stack encountered on a level-order traversal of tree
         public void printLevelOrder() {
              //for every node of tree v
              for (int v = 1;v<size();v++) {
                   if (!element(v).isEmpty() ) {
                        //print the top value in stack v
                        System.out.println(" "+element(v).top());
                   else {
                        //stack at v is empty
                        System.out.println(" -");
         //pop off and print the top value in each stack encountered on a level-order traversal of tree
         public void printPopLevelOrder () {
              //pop off and print the top value in stack v
              for (int v = 1;v<size();v++) {
              //for each node of tree v
                   if (!element(v).isEmpty() ) {
                        //if v isnt empty print the top value in stack v
                        System.out.println(" "+element(v).top());
                        //pop the top value in the stack at v
                        element(v).pop();
                   else {
                        //stack at v is empty
                        System.out.println(" -");
         //pop off and print the top value in each stack encountered on an in-order traversal of tree
         public void printPopInorder () {
              printPopInorder (1);
         public void printPopInorder (int v) {
              boolean isInternal = false;
              if (isInternal (v)) {
                   //use a boolean for isInternal to save on running the method twice
                   isInternal = true;
                   //recursively search left subtree
                   printPopInorder (leftChild(v));
              //pop off and print the top value at v
              if (element(v).isEmpty() ) {
                   //stack at v is empty
                   System.out.println(" -");
              else {
                   //if v isnt empty print the top value in stack v then pop
                   System.out.println(" "+element(v).top());
                   element(v).pop();
              if (isInternal ) {
                   //recursively search right subtree
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              printPopPreorder(1);
         public void printPopPreorder(int v) {
              //pop off and print the top value at v
              if (!element(v).isEmpty() ) {
                   //if v isnt empty print the top value in stack v then pop
                   System.out.println(" "+element(v).top());
                   element(v).pop();
              else {
                   //stack at v is empty
                   System.out.println(" -");
              if (isInternal (v)) {
                   //recursively search left and right subtrees
                   printPopPreorder (leftChild(v));
                   printPopPreorder (rightChild(v));
         //pop off and print all values from the stack at the root
         public void printPopRoot (){
              //while the root stack has values left
              while (!element(1).isEmpty()) {
                   //print, then pop
                   System.out.println(" "+element(1).top());
                   element(1).pop();
    }

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