Java.exe Error while running Tomcat

Question

Hello,
I encountered a very strange Java.exe error while testing my servlet.
Here is the screen dump of the aforementioned error:
http://www.shelleysauction.com/db07-22-02.jpg . The error's message is
as follows: "There is no disk in the drive. Please insert a disk into
drive \Device\Harddisk1\DR1."
Would appreciate any help; I don't claim to be any good at this stuff.
All of the information on that page is derived from a database on a
remote intranet machine (including input type, title, descriptions,
etc.). I am not sure if it is a server-side error or a client-side
error as my computer is running the server; another computer is not
possible--I'm a lowly summer intern hired to build a servlet that
interfaces with a database, and I'm not a good programmer.
The only thing I can think of is that I recently began using the
com.oreilly.servlet.* package for its Base64Encoder, Base64Decoder, and
MultiPartRequest methods. That form was working fine for weeks before
then.
Jennica Humphrey

Answer 1

Hello all,
Thank you for your help. I was using the MultiPartRequest class in the com.oreilly.servlet.* package so I could add a "section" that allowed users to upload CSV files to the database. It required, I think, that an opening FORM tag would have the following attribute: enctype="multipart/form-data"
Now, I made a HtmlGenerator class that writes the HTML for me, with all sorts of methods like html.startTableCell( String stylesheet, String align, String valign, String width ) so I could just type html.startTableCell( "palepurple", "left", "top", "50%" ); ... made reading my own crap a lot easier.
Anyway, I had html.startForm( ) and html.startUploadForm( )... the only difference was that the upload one had the enctype="multipart/form-data" attribute and the first one didn't. Now, my DoPost() method was supposed to determine if there were "regular" parameters passed on by the form and if there were "MultiPart" parameters... with code like this:
// Initialize MultipartRequest.  This is required for file uploading.
boolean isMulti = true;
MultipartRequest multi = null;
try {
     multi = new MultipartRequest( request, "..\\..\\Files", 10 * 1024 * 1024 );
} catch( Exception e ) { isMulti = false; }
Enumeration paramNames = request.getParameterNames();
// Attempt to initialize parameter names.
try {
     if ( !paramNames.hasMoreElements( ) ) paramNames = multi.getParameterNames();
} catch ( Exception e ) {
     /* Ignore */
***code snipped out***
if ( isMulti )
      paramValues = multi.getParameterValues( paramName );
else
     paramValues = request.getParameterValues( paramName );This was working fine, but after submitting "regular" (not uploaded) forms 3 or 4 times, it'd give me that error. Then I decided to change html.startForm() to work exactly like html.startUploadForm()--in effect making every form a MultiPartRequest. It works fine, without any errors. Do you know what was going on?