Java.lang.ClassNotFoundException: access

Question

Hi,i typed in a code and started compiling it,it got compiled but while running its giving
the following error
Unable to create MIDlet access
java.lang.ClassNotFoundException: access
     at com.sun.midp.midlet.MIDletState.createMIDlet(+29)
     at com.sun.midp.midlet.Selector.run(+22)
i tried the methods which i found in this forum but it did not work for me pls help me out of this error.........
import java.io.*;
import javax.microedition.io.*;
import javax.microedition.lcdui.*;
import javax.microedition.midlet.*;
import javax.microedition.midlet.MIDletStateChangeException;
public class AccessUrl extends MIDlet{
private Display display;
String url = "http://localhost:8080";
public AccessUrl(){
display = Display.getDisplay(this);
public void startApp(){
try{
connection(url);
} catch (IOException e){
System.out.println("IOException " + e);
e.printStackTrace();
public void pauseApp(){}
public void destroyApp(boolean unconditional){}
void connection(String url) throws IOException{
StreamConnection sc = null;
InputStream is = null;
StringBuffer buffer = new StringBuffer();
TextBox access;
try{
sc = (StreamConnection)Connector.open(url);
is = sc.openInputStream();
int chars;
while((chars = is.read()) != -1){
buffer.append((char) chars);
System.out.println(buffer.toString());
access = new TextBox("Access Text", buffer.toString(), 1024, 0);
}finally{
if(is != null){
is.close();
if(sc != null){
sc.close();
display.setCurrent(access);
the above is the code pls help me out

Answer 1

Seems you have typed your MIDlet name as access whereas it should be AccessUrl in the tool (ktoolbar / eclipseme / netbeans)you are using for executing.
Edited by: Atul.Moglewar on Mar 23, 2009 8:01 AM