Just received update 7.1.1. How do I enter passcode with letters

Just received advice of update 7.1.1
I am being asked to enter Passcode using a telephone keypad. My passcode has letters. How do I enter them?

I have only ever used my 10 digit code which contains mainly words. Never used a all numbered code.

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HT1414 How to enter passcode with voiceover

How to enter passcode with voiceover?

Have you tried to enter the passocde this way?
When you see the password entry keys, tap each key once to select it, then double tap the key to enter it. So if I had a passcode of 1234 I would:
tap 1, pause, double tap 1 (see the entry field get filled)
tap 2, pause, double tap 2
etc.
It should work the same way for a full password, only more tedious.
There is another possibility worth trying first. Triple tap the
Home
button. If you have Accessibility set up this way you should get a popup that will let you turn Voice Over off.
I copied the text from this forum.
http://www.ipadforums.net/new-member-introductions-site-assistance/60272-how-tur n-off-voice-over-command-while-password-lock-mode.html

JDBC Receiver: updates only header table how to update detail

Hi
here the scenario idoc having one header and one details segments, header data goes to one sql table detail date to another sql table.
i created the sql structure   in two ways one
table name
insert table
     header table
        action
        access
        detail table
            action
            access
2nd
table name
insert table
     header table
        action
        access
     detail table
        action
        access
in both ways one header table is updating detail table not. please help how to data will go in both tables
thanks
Message was edited by: sri rao

Hi,
could you pls try something like this..i was reading the documentation and thought of asking you to try this..
<root>
<HDR_StatementName>
<hdrtablename action=INSERT>
<table>hdrtablename</table>
<access>
<hfield1>val1</col1>
<hfield2>val2</col2>
</access>
</hdrtablename>
</HDR_StatementName>
<ITM_StatementName>
<itmtablename action=INSERT>
<table>itmtablename</table>
<access>
<ifield1>val1</col1>
<ifield2>val2</col2>
</access>
</itmtablename>
</ITM_StatementName>
</root>
Thanks & Regards,
Renjith

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How to compare Entering Password with existing encrypted pasword in APEX4.1

Hello everyone,
In my application am using the following package,
create or replace PACKAGE BODY app_security_pkg
AS
PROCEDURE login
           p_uname IN VARCHAR2
          ,p_password IN VARCHAR2
          ,p_session_id IN VARCHAR2
          ,p_flow_page IN VARCHAR2
IS
lv_goto_page NUMBER DEFAULT 1;
BEGIN
-- This logic is a demonstration of how to redirect
-- to different pages depending on who successfully
-- authenticates. In my example, it simply demonstrates
-- the ADMIN user going to page 1 and all other users going
-- to page 2. Add you own logic here to detrmin which page
-- a user should be directed to post authentication.
IF UPPER(p_uname) = 'ADMIN'
THEN
lv_goto_page := 1;
ELSE
lv_goto_page := 2;
END IF;
APEX_UTIL.SET_SESSION_STATE('FSP_AFTER_LOGIN_URL');
wwv_flow_custom_auth_std.login
p_uname => p_uname,
p_password => p_password,
p_session_id => p_session_id,
p_flow_page => p_flow_page || ':' || lv_goto_page
EXCEPTION
WHEN OTHERS
THEN
RAISE;
END login;
PROCEDURE add_user
p_username IN VARCHAR2
,p_password IN VARCHAR2
AS
BEGIN
INSERT INTO app_users (username, PASSWORD)
    VALUES (UPPER (p_username),
        get_hash (TRIM (p_username), p_password));
COMMIT;
EXCEPTION
WHEN OTHERS
THEN
ROLLBACK;
RAISE;
END add_user;
-- Function to Perform a oneway hash of the users
-- passwords. This cannot be reversed. This exmaple
-- is a very week hash and if been used on a production
-- system, you may want to use a stronger hash algorithm.
-- Read the Documentation for more info on DBMS_CRYPTO as
-- this is the supported package from Oracle and
-- DBMS_OBFUSCATION_TOOLKIT is now depricated.
FUNCTION get_hash (p_username IN VARCHAR2, p_password IN VARCHAR2)
RETURN VARCHAR2
AS
BEGIN
RETURN DBMS_OBFUSCATION_TOOLKIT.md5 (
input_string => UPPER (p_username)
                || '/'
                || UPPER (p_password));
END get_hash;
PROCEDURE valid_user2 (p_username IN VARCHAR2, p_password IN VARCHAR2)
AS
v_dummy VARCHAR2 (1);
BEGIN
SELECT '1'
INTO v_dummy
FROM app_users
WHERE UPPER (username) = UPPER (p_username)
AND PASSWORD = get_hash (p_username, p_password);
EXCEPTION
WHEN NO_DATA_FOUND
THEN raise_application_error (-20000, 'Invalid username / password.');
END valid_user2;
FUNCTION valid_user (p_username IN VARCHAR2, p_password IN VARCHAR2)
RETURN BOOLEAN
AS
BEGIN
valid_user2 (UPPER (p_username), p_password);
RETURN TRUE;
EXCEPTION
WHEN OTHERS
THEN RETURN FALSE;
END valid_user;
END app_security_pkg;Here the ADD_USER Procedure will convert the password and stores into the app_users Table in encrypted form.
In my application the users can change their password,
so I need to compare the entering password in the Current_password field with the Encrypted password in the app_users table,
so I used the following code,
declare
l_x varchar2(30);
begin
select username into l_x
        from app_users
    where upper(username) = upper(:P7_USERNAME)
      and password = :P7_CURRENT_PASSWORD;
return (true);
exception
when no_data_found then
    return (false);
end;This code is working fine when the password is stored without encryption,but after encryption it showing error,
because the entering password is simply password and not encrypted so both are different even if the user enters right password,
Please tel me how to encrypt the entering password to compare with existing encrypted password.
Thank you,
Regards,
gurujothi.

Dear Sunil and vdotcherukuri     ,
Thank you for your reply as per your suggestion I tried the following code and its working fine.
declare
l_x varchar2(30);
begin
select username into l_x
        from app_users
    where upper(username) = upper(:P7_USERNAME)
      and password = app_security_pkg.get_hash (TRIM (:p7_username), :P7_CURRENT_PASSWORD);
return (true);
exception
when no_data_found then
    return (false);
end;Thank you,
Regards,
Gurujothi.

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3194?
http://support.apple.com/kb/TS3694#error3194
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Hello Nikkii,
Thanks for using Apple Support Communities.
For more information on this, take a look at:
iOS: Troubleshooting FaceTime and iMessage activation
http://support.apple.com/kb/ts4268
Troubleshooting telephone-number activation (iPhone only)
After each step, toggle FaceTime and iMessage off and then on in Settings > Messages and Settings > FaceTime.
Update to the latest version of iOS.
Ensure that your iPhone is set to the correct time zone. Tap Settings > General > Date & Time.
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Verify that you can send SMS messages. You need a valid SMS messaging plan to activate FaceTime.
Contact your carrier to verify that there are no restrictions or blocks on text messages. Blocks on text messaging will prevent iMessage and FaceTime registration.
If you are unable to activate iMessage or FaceTime on a device after remote wiping it, wait at least 24 hours and try again.
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Hello nikhilb05,
Thank you for using Apple Support Communities.
I have provided a couple of articles for you to provide information on administering your Apple ID and changing your password:
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If you forgot your Apple ID password
Regards,
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Just received update 7.1.1. How do I enter passcode with letters

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