Leaf node Hierarchy based on tree position

Question

Hi All,
I need to find the Hierarchy of given leaf node. Can you please help me. Here are details
create table t_rk_4 (child_id number, parent_id number, treenum varchar2(100));
insert into t_rk_4 values (2,1,'1');
insert into t_rk_4 values (3,1,'1');
insert into t_rk_4 values (6,2,'1.2');
insert into t_rk_4 values (7,6,'1.2.6');
insert into t_rk_4 values (4,3,'1.3');
insert into t_rk_4 values (5,4,'1.3.4');
insert into t_rk_4 values (7,5,'1.3.4.5');
insert into t_rk_4 values (8,7,'1.2.6.7');
insert into t_rk_4 values (4,9,'1.9');
insert into t_rk_4 values (9,1,'1');
In the above date, child 8's parent is 7 only in case if tree context 1.2.6.7
select child_id,parent_id connect_by_isleaf,level,lpad(' ',level*3)||a.child_id
from t_rk_4 a
start with child_id = 8 connect by child_id = prior parent_id ORDER SIBLINGS BY child_id;
when I run the above query I am getting all tree contexts,
Is there a way I can only get tree positins thru 1.2.6.7 ?
In real table I have more than 1 million records..
Any help would be helpful..
Thanks
ay.

Answer 1

Hi,
Welcome to the forum!
Thanks for posting the CREATE TABLE and INSERT statements! It clarifies things a lot and makes it much easier to reply.
Another very helpful thing is to post the results you want from the data you posted. In this case, I think you want:
. CHILD_ID  PARENT_ID CONNECT_BY_ISLEAF      LEVEL INDENTED
         8          7                 0          1    8
         7          6                 0          2       7
         6          2                 0          3          6
         2          1                 1          4             2Is that right?
Notice how multiple spaces are not compressed in the section above. That's because I typed {code} (all small letters, in curly brackets) before and after that section.
To get those results, I just added one line to your CONNECT BY clause, saying that the parent's treenum has to be the first part of the child's treenum:
SELECT     child_id
,     parent_id
,     CONNECT_BY_ISLEAF
,     LEVEL
,     LPAD (' ', LEVEL * 3) || a.child_id     AS indented
FROM     t_rk_4     a
START WITH     child_id = 8
CONNECT BY     PRIOR parent_id     = child_id
AND          PRIOR treenum     LIKE treenum || '.%'     -- *** NEW CONDITION ***
ORDER SIBLINGS BY     child_id;What do you want to do if the node you're starting with has two (or more) parents?
If we START WITH child_id = 7, the query above produces this output:
. CHILD_ID  PARENT_ID CONNECT_BY_ISLEAF      LEVEL INDENTED
         7          5                 0          1    7
         5          4                 0          2       5
         4          3                 0          3          4
         3          1                 1          4             3
         7          6                 0          1    7
         6          2                 0          2       6
         2          1                 1          3          2That is, there are two rows in the table with child_id = 7, so the query shows two lines of ascent. The alternate route, going through the node with child_id = 9, is not shown. Is that what you want?