Leap Year

Hi Everyone..
I have two columns called base date and final due date from which we calculate the number of days. Can someone tell me how to calculate leap year in OBIEE.

Hi
Thanks for your reply. I am able to calculate the number of days using the above function TIMESTAMPDIFF(SQL_TSI_DAY,Day1, Day2). But my issue is to calculate leap year.
eg : No of days >0 and < =365 , its 1st year
if No of days >365 and < = 730 , its 2nd year.
In this i need to verify if there is any leap year coming in btw like if No of days is 366 then ?
Thanks in advance for the reply.

Similar Messages

HELP! Files won't open and previously had Firefox icon instead of DW icons! Leap Year thing?

Hi! I went to update my website, which I do every night before the first day of every month and all the files had a FIrefox icon instead of the usual Dreamweaver one. I have shut down, reinstalled DW MX 2004 but the files still do not open. The icons have now changed to DW but they are not opening with right click, opening from Applications folder, double clicking the file, from get info and open with DW. I am stumped. HELP! Need to update for March 1st.
Is it something to do with Leap Year 29th Feb? Checked the clock in preferences but can't see how this affects it.
Firefox is always updated but the latest version does not seem to be as efficient as previous upgrades. We installed Chrome as well. Do they interfere with each other?

Hi Ken
I wish the 7.1 updater download had helped but it didn¹t. All the files
were backed up before the installation, which went fine.
Mac 10.5.8
We used Disc Warrior to defrag the hard drive, which did not make a
difference.
We recently started using Chrome, so now have 3 browsers in the dock,
Safari, Firefox and Chrome. Do they interfere in any way with each other?
The files, which I hadn¹t touched for a month as I update on a monthly
basis, initially had the Firefox icon.
Below is the message to send to Apple, which did not go through their report
system! A little disillusioned with the service!
Model: iMac9,1, BootROM IM91.008D.B08, 2 processors, Intel Core 2 Duo, 3.06
GHz, 4 GB
Graphics: kHW_NVidiaGeForceGT130Item, NVIDIA GeForce GT 130,
spdisplays_pcie_device, 512 MB
Memory Module: global_name
AirPort: spairport_wireless_card_type_airport_extreme (0x14E4, 0x8E),
Broadcom BCM43xx 1.0 (5.10.91.22)
Bluetooth: Version 2.1.9f10, 2 service, 0 devices, 1 incoming serial ports
Network Service: Ethernet, Ethernet, en0
Network Service: AirPort, AirPort, en1
Serial ATA Device: WDC WD1001FALS-40K1B0, 931.51 GB
Serial ATA Device: PIONEER DVD-RW DVRTS08
USB Device: Built-in iSight, (null) mA
USB Device: Keyboard Hub, (null) mA
USB Device: iLok, (null) mA
USB Device: Apple Optical USB Mouse, (null) mA
USB Device: Apple Keyboard, (null) mA
USB Device: Deskjet 3840, (null) mA
USB Device: BRCM2046 Hub, (null) mA
USB Device: Bluetooth USB Host Controller, (null) mA
USB Device: IR Receiver, (null) mA
FireWire Device: d2 quadra (button), LaCie, 800mbit_speed
Does not mean a thing to me.
I am not late with updating the site, which is about New Zealand culture,
month by month (www.englishteacher.co.nz). Probably only the third time I
have been late since 2005. Not a huge amount of traffic, ~300 a month and
free access to content but I would like to solve this problem.
Could a reciprocal link have caused a problem?
At my wits end.
I really appreciate the help though.
Cheers Yvonne
From: Ken Binney <[email protected]>
Reply-To: <[email protected]>
Date: Wed, 29 Feb 2012 06:42:11 -0700
To: Yvonne and Bill Hynson <[email protected]>
Subject: HELP! Files won't open and previously had Firefox
icon instead of DW icons! Leap Year thing?
Re: HELP! Files won't open and previously had Firefox icon instead of DW
icons! Leap Year thing?
created by Ken Binney <http://forums.adobe.com/people/Ken+Binney> in
Dreamweaver - View the full discussion
<http://forums.adobe.com/message/4236682#4236682>
Not necessarily related, but did you also install the 7.1
updater? http://www.adobe.com/support/dreamweaver/downloads_updaters.html
Windows or MAC?
Replies to this message go to everyone subscribed to this thread, not
directly to the person who posted the message. To post a reply, either reply
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http://forums.adobe.com/message/4236682#4236682 To unsubscribe from this
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http://forums.adobe.com/message/4236682#4236682. In the Actions box on the
right, click the Stop Email Notifications link. Start a new discussion in
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Unable to generate the file report pdf on 29 february 2012 or during any leap year day...

hii this is manab......
sir/mam i have face the following error in 29 february 2012 for my overall company report .But i can easily get the
report of another department on 29feb 2012....but when i try generate the overall report of my comapany then i find the errors
REP-1401: 'cf_mc_prod_lyrformula': Fatal PL/SQL error occurred.
ORA-01839: date not valid for month specified
The following is the logfile.........
...........................................................................................log file................................................................................................................
HPCL Custom Application: Version : UNKNOWN
Copyright (c) 1979, 1999, Oracle Corporation. All rights reserved.
HPCCMDS module: HPC Modified CMD Report
+---------------------------------------------------------------------------+
Current system time is 04-SEP-2013 11:37:20
+---------------------------------------------------------------------------+
+-----------------------------
| Starting concurrent program execution...
+-----------------------------
Arguments
P_MILL='NPM'
P_TRANSACTION_DATE='2012/02/29 00:00:00'
Current NLS_LANG and NLS_NUMERIC_CHARACTERS Environment Variables are :
American_America.US7ASCII
REP-1401: 'cf_mc_prod_lyrformula': Fatal PL/SQL error occurred.
ORA-01839: date not valid for month specified
Report Builder: Release 6.0.8.24.0 - Production on Wed Sep 4 11:37:20 2013
(c) Copyright 1999 Oracle Corporation. All rights reserved.
Enter Username:
+---------------------------------------------------------------------------+
Start of log messages from FND_FILE
+---------------------------------------------------------------------------+
+---------------------------------------------------------------------------+
End of log messages from FND_FILE
+---------------------------------------------------------------------------+
Program exited with status 1
Concurrent Manager encountered an error while running Oracle*Report for your concurrent request 11426643.
Review your concurrent request log and/or report output file for more detailed information.
+---------------------------------------------------------------------------+
Executing request completion options...
Finished executing request completion options.
+---------------------------------------------------------------------------+
Concurrent request completed
Current system time is 04-SEP-2013 11:59:23
+---------------------------------------------------------------------------+
kindly give me solution .....i have e-business suite 11i
internet explorer latest version...

Hi,
Please confirm whether this is a custom or standard report.
If this is a custom report, then probably the respective issue has not been handled by exception handling.
Also please refer note:
How to check if version 11.5.10.2 is certified to Handle Leap Years (Doc ID 549937.1)
Thanks &
Best Regards,

How to find leap year in sql query

How to find leap year in sql query

Select
CASE
WHEN result = 0 THEN 'Leap_Year'
WHEN result <> 0 THEN 'Not_A_Leap_Year'
END
From (Select mod((EXTRACT(YEAR FROM DATE '2013-08-24')), 4) result FROM DUAL);

ICal bug -- leap year has broken reoccuring events

Since last week , when there were 29 days in February instead of 28, events in iCal which are re-occuring (a meeting which occurs every month on the second Monday for example) is simply wrong.
It is clear that this is an artifact of "Leap Year." The error compounds.
In March in was off by one day -- scheduled on Tuesday instead of Monday. In April the error compounds... now scheduled on Friday in April.
Events which were scheduled by data "appear" to be correct, but now I don't know that I can even trust them.
This problem propigates through iCloud and infects my iPhone and iPads as well.
iMac 10.7.3
iPhone 5.1
iPad 5.1
Mac mini 10.6.8
It turns out this Bug dates back to 2008!!!!!
https://discussions.apple.com/message/6309125#6309125

No. not really.
I spent some time on the phone with Apple support and basically discovered that if I looked at the reoccurring event back in February (the previous month), it showed up correctly as an event being repeated as, in my case, "Custom, Every Month on the first Monday." However, then comparing that entry to the incorrect March entry, I noted the March entry was showing up as repeat "Every Month." (Which translated into every 30 or 31 days, looking at subsequent events.)
Simply changing the bad March event back to the Custom "Every Month on the First Monday," and then applying it to the forward "worked around" the issue.
We never did come up with any idea what caused the change. (i.e. the support person could find no references to any kind of similar problem.)
I was told to go to "www.apple.com/feedback" and to select "iCal" from the list of "OS C Apps" near the bottom of the page, and report the problem.

How to Calculate Leap Year ago in OBIEE 11g

Hi Gurus,
I have one fact table and having one measure column. I have to calculate current year and Last year.
Using Time series function (Todate,Ago) have calculated current year as well last year also.
The problem is Current year is showing correct value only but Last year was showing wrong data.
We found the problem is Leap year, last year FEB month is having 29 dates. Due to this we are getting wrong date.
Kindly suggest me how to achieve this requirement.
Thanks

Hi Gurus,
How to resolve Leap Year calculation in OBIEE 11g.
The problems is Year Ago column.
Please suggest me how to resolve this.
Thanks

How to do a date validation with leap years

I'm doing a date validation program in my Java class, and well it's pretty hard (for me that is). I have to be able to type in a date, have it say whether it's a leap year or not, and print out the number of days in the month. It seems pretty straight forward, but I get confused on trying to do the 'if else' statements and even the simplest things like getting the day prompting to work. >< The years I'm doing only goes through 1000 to 1999, so that's why those numbers are there. The program isn't complete, so if anyone could help show me what I'm doing wrong in the areas I'm working on then I'd appreciate it...and I'm still kind of in the basics of Java so if you do hint me with some code then I'd appreciate it if it was stuff that's not too advanced so yea.
// Dates.java
// Determine whether a 2nd-millenium date entered by the user
// is valid
import java.util.Scanner;
public class Dates
public static void main(String[] args)
int month, day, year; //date read in from user
int daysInMonth; //number of days in month read in
boolean monthValid, yearValid, dayValid; //true if input from user is valid
boolean leapYear; //true if user's year is a leap year
Scanner scan = new Scanner(System.in);
//Get integer month, day, and year from user
System.out.print("Type in the month: " );
          month = scan.nextInt();
System.out.print("Type in the day: " );
          day = scan.nextInt();
System.out.print("Type in the year: " );
          year = scan.nextInt();
//Check to see if month is valid
if (month >= 1)
month = month;
else
if (month <= 12)
month = month;
else;
//Check to see if year is valid
if (year >= 1000)
year = year;
else
if (year <= 1999)
year = year;
else;
//Determine whether it's a leap year
//Determine number of days in month
if (year == 1 || 3 || 5 || 7 || 8 || 10 || 12)
     System.out.println (Number of days in month is 31);
     else (year == 4 || 6 || 9 || 11)
     System.out.println (Number of days in month is 30);
//User number of days in month to check to see if day is valid
//Determine whether date is valid and print appropriate message
// Dates.java
// Determine whether a 2nd-millenium date entered by the user
// is valid
import java.util.Scanner;
public class Dates
public static void main(String[] args)
int month, day, year; //date read in from user
int daysInMonth; //number of days in month read in
boolean monthValid, yearValid, dayValid; //true if input from user is valid
boolean leapYear; //true if user's year is a leap year
Scanner scan = new Scanner(System.in);
//Get integer month, day, and year from user
System.out.print("Type in the month: " );
          month = scan.nextInt();
System.out.print("Type in the day: " );
          day = scan.nextInt();
System.out.print("Type in the year: " );
          year = scan.nextInt();
//Check to see if month is valid
if (month >= 1)
month = month;
else
if (month <= 12)
month = month;
else;
//Check to see if year is valid
if (year >= 1000)
year = year;
else
if (year <= 1999)
year = year;
else;
//Determine whether it's a leap year
//Determine number of days in month
if (year == 1 || 3 || 5 || 7 || 8 || 10 || 12)
     System.out.println (Number of days in month is 31);
     else (year == 4 || 6 || 9 || 11)
     System.out.println (Number of days in month is 30);
//User number of days in month to check to see if day is valid
//Determine whether date is valid and print appropriate message
}

Here are some helpfull hints for you:
1. Your code is really hard to read, there are two main reasons for this. First, your indentation sucks. Second, you seem to be fascinated with saving two (ok four if you count the shift key) keypresses to avoid using { and }.
2. Not using the brackets (you know { and } which you like to avoid) also is causing your code to do some stuff you don't realize or want to happen, or at least it would be if your code compiled.
3. If statements require arguements, "year == 1" is an arguement, "3" is not an arguement. Each operator like the or operator ("||") is essentially a new if and requires a complete arguement. So the following code peice:
if (year == 1 || 3 || 5 || 7 || 8 || 10 || 12)Literally translates to if year equals 1 or if 3 or if 5 or if 7 or if 8 or if 10 or if 12. Doesn't make much sense in english, and it doesn't make much sense in Java either.
4. I am pretty sure "year" is not the variable you want in the code snippet above (the one used in hint 3), especially considering years 1, 3, 5, 7, 8, 10, and 12 are not between 1000 and 1999. You need to be really carefull not make these kind of mistakes when coding, because they are by far the hardest to track down and fix later since they don't really throw up any flags or anything at compile or run time. Take your time and think thuroughly about each line of code while coding it, it will save you tons of time in the long run.
5. What exactly do you expect statements like "month = month;" to do? That translates as make month equal to month. Do you go to the bank and say " I have exactly $3.56 in my pocket, so I would like to deposite all $3.56 and then withdraw $3.56 and put it back in my pocket"? How do you think the teller would look at you? Teller would probably do it, but the teller would feel like he/she wasted time with you and that you are not really right in the head. Java feels the same way when you make it do the same thing, and you love to do it.
6. Code like the following is all wrong, and for more reasons than pointed out in hint 5.
if (month >= 1)
month = month;
else
if (month <= 12)
month = month;
else;Let's say someone put 13 in as the month. It passes the first check because 13 is greater than or equal to 1. so month which is 13, now gets set to 13 (gee that was effective). Now we hit the else and things get confusing because you didn't use brackets or proper indentation (hint 1) so we don't know what your real intent was. Did you mean else do nothing, and the next if statement is then executed, or did you mean to just run the next if statement if the else condition was met? Fortunatly it doesn't matter here because the next if statement is failed anyways since 13 is not less than or equal to 12.
So, we leave this code with month ebing 13, wait when did we add a 13th month to the calendar? Are you using the Jewish calendar? Could be, except even if I put 1234567 as the month your code would except it as valid, and I know no calendar with that many months. Try writing this in english first and translating it to jave, like i would probably say "if the month is greater than or equal to 1 and less than or equal to 12 then the month is valid." Course now what do you do if it is invalid? Hmm, maybe I would actually say "while the month is less than 1 or greater than 12 ask the user for the month" until they get it right.
There are a few other problems, but most of them are probably things you haven't learned yet, and they are not show stoppers so we will let them fly. You already have a lot of work to do to make this better. But I do have one more really really big usefull hint for you:
Never, ever, under any circumstances, should you ever ask in any way or even hint at asking for someone else to provide code solutions to your problems. So "so if you do hint me with some code then I'd appreciate it if it was stuff that's not too advanced " was a very bad thing to do, but fortunatly for you you followed it with proof you were trying to write the code yourself. Had the code you provided not been so full of problems it was obvious a beginner wrote it, you would probably have gotten much less cordial responses. I would seriously consider avoiding any implication of wanting code, at least until you become a regular poster here and people know you are not just looking to get your homework done for you.
Hope some of this helps.
JSG

Add 1 day to the Month of February on leap year

I know how to calculate leap year. The calculation is working great.
However, I need to add a day to the month of February if a leap year is selected.
Do you have any pointers on this?
Thanks!

Thanks!
I got it
if(leapYear){
if (month==2)
numDays = numDays +1;
}

Leap year bug adding days to a date?

Please try this xquery:
<dd>
for $i in 0 to 4
return
<d>
{xs:date('2008-12-29')+xs:dayTimeDuration(concat('P',$i,'D')) }
</d>
</dd>
If the starting date is a leap year date (eg: 2008-12-29), the result does not contain the 30rd of december!
Is this a (known) bug or there is something wrong in my xquery?
Thanks!
Bye
Mirko

Hi Mirko,
There's nothing wrong with your query - that looks like a bug in our date displaying code. Thanks for your analysis of the problem - I'll take a look into fixing it.
John

Problem with leap years in Calendar demo

I've just looked at the Calendar demo component:
http://developers.sun.com/prodtech/javatools/jscreator/reference/codesamples/samplecomps/calendar.html
There is a little bug : it doesn't seem to manage leap years.
Go to february 2008, and you won't the the 29th of February 2008 in the calendar.
Please try to correct this bug quickly. It is a bad idea to let people get source code with bugs as a a demo.
Thanks
Thibaut REGNIER
See TastePhone, my Open Source app made whith Java Studio Creator:
http://www.club-java.com/TastePhone/J2ME/MIDP_mobile.jsp

The Calendar Component does take account of the leap year.
If you look at the code, it has
if ((month == FEBRUARY) && (isLeapYear(year))) numCells++;Not sure what went wrong. I'll take a look at it.
- Winston

Leap year issue

Hi friends,
I have a problem in one of the existing codes.
The cancellation amount is calculated for a range of dates.
Say the active line item has a start date of 01.03.2006 and end date of 01.03.2012 say (B).
Now if a rejection/Cancellation is put on date 01.05.2007 (A), the current program is calculating a value
based on the diffrence of days (B - A).
then this cancelled amnt = the no of cancelled days * (a constn value * 12 / 365).
Now I want to modify my logic in such a way that the leap is also accounted.
If I use the same dates , i realise that 2008 is the leap yr.
So how can i modify my calculation for the range if it contains a leap yr.
Please suggest something on this, as it will be really helpful.
Thanks,
Sapna Agarwal

Hi Sapna,
    try to use the FM /SDF/CMO_DATETIME_DIFFERENCE, it will take care of the leap year, just pass the two dates for which you want the difference.
CALL FUNCTION '/SDF/CMO_DATETIME_DIFFERENCE'
EXPORTING
   DATE1                   = s_date
*   TIME1                  =
   DATE2                   = e_date
*   TIME2                  =
IMPORTING
   DATEDIFF                = DATEDIFF
*   TIMEDIFF               =
*   EARLIEST               =
EXCEPTIONS
   INVALID_DATETIME        = 1
   OTHERS                  = 2
IF sy-subrc <> 0.
MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
         WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
ENDIF.
if the gap is for more one year than you have to do the calculation year wise only, in this case use the fm '/SAPNEA/JSC_LEAP_YEAR' that which year is a leap year. And than go for a IF condition while calculating either it should be 365 or 366 days.
With luck,
Pritam.

Leap year without date objects

I need to check to see how many leap years are between two user-inputted years and I can't use date objects. I figure I need to start with a for loop, but I get lost when to by the mod 4, mod 100, or mod 400. Any help?
for(int l=cYear; l <= eYear; l++){
                    if(l%4 == 0){
                         if(l%100 == 0){
               }also, if anyone is bored and really wants to give of themselves, I could use some more help with a pretty challenging-for-my-level program. Let me know.
Message was edited by:
kaluga

yeah, he said like 20 times "one big main method, no
other methods"He's a moron and should not be teaching CS or Java.
Problems: 1. I am having trouble wrapping my mind
around the logic,Meaning what? You described it--or was that just copy/paste of what's in the asisgnent? I gave you some pseudocode that's practically Java already.
Just try it. Take your best shot and write some test cases and see how close you are.
2. I don't know if this (below)
syntax works.Try it. If the syntax is wrong, it won't compile.
Once you get it to compile, then test it. Here's one reason why you'd want a separate method--you could test just that method by itself. As it stands, the easiest way to test it is to always give it just one year and see if you end up with the proper count--zero or one. If you give it many, you could end up with the right number by having the same number of false positives and false negatives.
Once you know it works for one year, feed it a few lists of 5 or 10.
btw jverd, I appreciate your helpYou're quite welcome. It looks like you're on the right track. Just don't be afraid to try stuff and see what happens, and then come back with specific questions about the specific problems you observed. :-)
---- Edit ----Or do like DrClap suggested and print each one. This way you can still test many at once.
Note to self: Duh, Jeff.
---- ---- ----Message was edited by:
jverd

Leap year check

I have a class called Date and this method:
private boolean dateOK(int dd, int mm, int yy)
return ( (dd >= 1) && (dd <= 31) &&
(mm >= 1) && (mm <= 12) &&
(yy >= 0000) && (yy <= 9999) );
How can i check the date is ok if it is a leap year?

public static boolean isLeapYear(int year) {
          if(year % 4 != 0)
               return false;
          if(year % 100 != 0)
               return true;
          if(year % 400 == 0)
               return true;
          return false;
     }I could be wrong, but I think leap year didn't start until a specific date (1600 comes to mind), so it should take that into account.
Remember: Those whom don't understand how a saw
works, cut their own hand off
Message was edited by:
Lumantu

Leap year help

Basically I have the program running great and works fine. But I have to get it to make you put in another date if it is less then 1582. But that's where it goes down to the end and prints out no years processed. But I have been trying to get it to enter in another date and then continue with the program. Any suggestions? Here is my code.
import java.util.Scanner;
public class LeapYear {
     public static void main(String[] args)
          int year;
          int numYear = 0;
          Scanner scan = new Scanner(System.in);
          System.out.println("please enter a year from 1582 onward.");
          year = scan.nextInt();
          while (year >=1582)
               numYear++;
               if (year<1582)
                    numYear++;
                    System.out.println("Please enter in a year from 1582 and up");
                    year = scan.nextInt();
               if (year%400 == 0 || (year%4 == 0)&& (year%100 != 0))
                    System.out.println("It's a leap year!");
                    else
                    if(!(year%400 == 0) || !(year%4 == 0)&& (year%100 == 0))
                         System.out.println("It's not a leap year...");
               System.out.print("Enter the next year (a negative to quit): ");
               year = scan.nextInt();
     if (numYear > 0)
          System.out.println("Fin");
     else
          System.out.println("No years processed.");
}

I did have this at the end
while (true)
            numYear++;
          if (year<1582)
            //don't ++ the numYear again
            System.out.println("Please enter in a year from 1582 and up");
            year = scan.nextInt();
          else if (year%400 == 0 || (year%4 == 0)&& (year%100 != 0))
            System.out.println("It's a leap year!");
          else
              System.out.println("It's not a leap year...");
               System.out.print("Enter the next year (a negative to quit): ");
               year = scan.nextInt();
                      if(numYears<0)
                         System.out.println("Fin.");
}But it makes me delete it, it's not letting me terminate the program. I enter in -9 it does
Please enter in a year from 1582 and upI want it to say
Fin

Leap Year Calendar

I am working on a project where the user enters a year. The string is then converted into an int and goes through a series of tests to see if it is a leap year or not. The problem I am having is when the user inputs letters when they are supposed to enter numbers. This gives the "java.lang.NumberFormatException" error. I used the try and catch code to make the user re input a year, but how do you make that into a loop. I want to make it so if the user keeps putting in letters, the computer keeps asking for numbers.
this is my code so far:
import javax.swing.JOptionPane; //import this at top
public class finding_the_leap_year {
public static void main(String[]args){
int year = 0;
{color:#ff0000}
try{
String inputValue = JOptionPane.showInputDialog("Input a year");
year = Integer.parseInt(inputValue);
catch(java.lang.NumberFormatException ex){
while(????????????????????){
System.out.println("Please enter a year");
String inputValue = JOptionPane.showInputDialog("Input a year");
year = Integer.parseInt(inputValue);
}          }{color}
if(year % 4 == 0)
System.out.println(year + " is a leap year.");
if(year % 100 == 0)
if(!(year%400==0)){
System.out.println(year + " is a leap year.");
else{
System.out.println(year + " is not a leap year.");
Edited by: chibioj on Sep 29, 2007 12:50 PM
Edited by: chibioj on Sep 29, 2007 12:51 PM

Put more in the while loop. I sometimes use a boolean value such as dataValid or inputValid and set it to false. I only set it to true if the input entered is ok. It is set to true in the try block but AFTER the data is obtained and parsed. The code will only reach that line if the input is valid.
        String inData = "";
        boolean dataValid = false;
        while (!dataValid) // while we don't have a correct answer yet
            try
                inData = JOptionPane.showInputDialog("Input a number");
                if (inData != null) // if they didn't press the cancel button
                    year = Integer.parseInt(inData);
                dataValid = true; // won't get here if numberformatexception tripped
            catch (java.lang.NumberFormatException ex)
                JOptionPane.showMessageDialog(null, "You didn't enter a valid year. Please try again.");
        if (inData != null) // if cancel button not pressed on input dialog
            if (......Also, you have some logic errors in the rest of your code that need fixing.
Good luck!

Leap Year Exception in Exit Variable

Hello Experts,
                       I have a Customer exit variable(ZVAR_PREVIOUS_MONTH) which displays data for previous month of input date. When i am entering 02/29/2008(which is a leap year) as input then the variable throws an error saying "Value "20070229" for user exit varaible is invalid. And thats true since 2007 is not a leap year. So how can i handle this Leap Year Exception
Regards,
Vishnu.

Vishnu,
Your description doesn't make sense. If you input 2008, why is the error showing 2007? Could you post your code here so we can have a look?
I think you are trying to implement the exit such that if you supply 02/29/2008, the variable should resolve to 01/01/2008 - 01/31/2008. Is that correct?
variable-sign = 'I'.
variable-option = 'BT'.
* received_value = 02/29/2008
received_value+6(2) = '01'.                        " 02/01/2008
variable-high = received_value - 1.            " 01/31/2008
variable-low = variable-high.                      " 01/31/2008
variable-low+6(2) = '01'.                             " 01/01/2008

Leap Year

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