Little help needed in understanding partitions-

Ok, so I recently deleted a few files I shouldn't have. I used a recovery program to restore those files, no problems there. My question is, when I used this recovery program, it gave me the options of three partitions to search; despite me only ever creating one. Now while I could only 'browse' or 'search' on the partition I created, these two partitions caught my eye and am now curious as to what they are.
1. EFI System Partition (200 MB)- I've since learnt this is something critical to the OS, I won't pretend to know what exactly but I'm happy knowing it's there for a reason.
2. Unallocated (619.91 MB)- This partition was in a RAW filesystem format, and none of the 600+ MB space was in use; completely empty. I can't find an explanation anywhere as to what this partition is for and hoped someone here might know? 600+ MB is a fair amount and don't like the idea of it being used up for no reason.

The EFI partition exist on all bootable drives and should be hidden.  This is normal, leave it there.
The 600 MB parition is the Recovery partition that's present with all Lion installations.
You should have a 3rd parition that contains your OS and data.  4th partition for windows/bootcamp if used.

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    Debug.log(oapagecontext, this, "app module: " + as1[k], 3);
    Debug.log(oapagecontext, this, "*** assignmentType = " + s, 3);
    Debug.log(oapagecontext, this, "*** projectId = " + oapagecontext.getTransactionValue("paProjectId"), 3);
    if("Project".equals(s) && !StringUtils.isNullOrEmpty((String)oapagecontext.getTransactionValue("paProjectId")) && !"Y".equals(oapagecontext.getParameter("paMass")))
    Debug.log(oapagecontext, this, "*** Setting default staffing owner for add delivery assignment -- projectId = " + oapagecontext.getTransactionValue("paProjectId"), 3);
    oaapplicationmodule.invokeMethod("setDefaultStaffingOwner");
    OAViewObject oaviewobject3 = (OAViewObject)oaapplicationmodule.findViewObject("RoleCompetenciesVO");
    oaviewobject3.setMaxFetchSize(0);
    oaviewobject3.setRangeSize(-1);
    oracle.jbo.Row arow[] = oaviewobject3.getAllRowsInRange();
    for(int l = 0; l < arow.length; l++)
    RoleCompetenciesVORowImpl rolecompetenciesvorowimpl = (RoleCompetenciesVORowImpl)oaviewobject3.getRowAtRangeIndex(l);
    Debug.log(oapagecontext, this, "roleCompetenciesVORowImpl" + rolecompetenciesvorowimpl, 3);
    rolecompetenciesvorowimpl.setPlsqlState((byte)0);
    oapagecontext.putTransactionValue("AddAssignmentInsertRowFlag", "N");
    oaapplicationmodule.getTransaction().commit();
    if("Y".equals(oapagecontext.getTransactionValue("paMass")) && !"1".equals(oapagecontext.getTransactionValue("paNumSelectedResources")))
    if(!"SUBMIT_APPRVL".equals(oapagecontext.getParameter("AddAsgmtApplyAction")))
    Debug.log(oapagecontext, this, "Save, Mass, NumSelectedResources>1", 3);
    Debug.log(oapagecontext, this, "work flow has been launched", 3);
    OADialogPage oadialogpage = new OADialogPage((byte)3, new OAException("PA", "PA_MASS_ASSIGNMENT_CONFIRM"), null, "OA.jsp?akRegionCode=PA_RESOURCE_LIST_LAYOUT&akRegionApplicationId=275&addBreadCrumb=N", null);
    oadialogpage.setRetainAMValue(false);
    oapagecontext.redirectToDialogPage(oadialogpage);
    return;
    Debug.log(oapagecontext, this, "SaveAndSubmit, Mass, NumSelectedResources>1", 3);
    putParametersOnSession(oapagecontext);
    int i1 = 0;
    int j1 = 0;
    String s21 = "SelectedResourceId";
    int l1 = Integer.parseInt(oapagecontext.getTransactionValue("paNumSelectedResources").toString());
    Debug.log(oapagecontext, this, "size of resourceArray = " + l1, 3);
    String as2[] = new String[l1];
    for(; !"END".equals(oapagecontext.getTransactionValue(s21.concat(Integer.toString(i1)))); i1++)
    if(oapagecontext.getTransactionValue(s21.concat(Integer.toString(i1))) != null)
    Debug.log(oapagecontext, this, "resource id = " + oapagecontext.getTransactionValue(s21.concat(Integer.toString(i1))).toString(), 3);
    as2[j1] = oapagecontext.getTransactionValue(s21.concat(Integer.toString(i1))).toString();
    j1++;
    SessionUtils.putMultipleParameters("paResourceId", as2, oapagecontext);
    Debug.log(oapagecontext, this, "redirect to Mass Submit for Approval page", 3);
    oapagecontext.redirectImmediately("OA.jsp?akRegionCode=PA_MASS_SUBMIT_LAYOUT&akRegionApplicationId=275&paCallingPage=MassAdd&paProjectId=" + oapagecontext.getTransactionValue("p_project_id"), false, "RP");
    return;
    if("RETURN_TO".equals(oapagecontext.getParameter("AddAsgmtApplyAction")))
    Debug.log(oapagecontext, this, "Return to Option Selected ", 3);
    String s15 = (String)oapagecontext.getTransactionValue("PrevPageUrl");
    int k1 = s15.indexOf("OA.jsp?");
    s15 = s15.substring(k1);
    Debug.write(oapagecontext, this, "*** RETURN_TO URL: " + s15, 3);
    oapagecontext.redirectImmediately(s15);
    } else
    if("ADD_ANOTHER".equals(oapagecontext.getParameter("AddAsgmtApplyAction")))
    Debug.log(oapagecontext, this, "Add Another Option Selected", 3);
    oaapplicationmodule.invokeMethod("resetAddNewAssignment");
    if(oaapplicationmodule.findViewObject("RoleCompetenciesVO") != null)
    oaapplicationmodule.findViewObject("RoleCompetenciesVO").clearCache();
    String s16;
    if(!s.equals("Project") && !s.equals("Admin"))
    s16 = "OA.jsp?akRegionCode=PA_ADD_ASSIGNMENTS_PAGE_LAYOUT&akRegionApplicationId=275&paProjectId=" + oapagecontext.getTransactionValue("paProjectId") + "&paAssignmentType=" + s + "&OA_SubTabIdx=0";
    else
    s16 = "OA.jsp?akRegionCode=PA_ADD_ASSIGNMENTS_PAGE_LAYOUT&akRegionApplicationId=275&paResourceId=" + oapagecontext.getTransactionValue("paResourceId") + "&paAssignmentType=" + s + "&OA_SubTabIdx=0";
    Debug.log(oapagecontext, this, "nextUrl " + s16, 3);
    if("Template".equals(s))
    oapagecontext.redirectImmediately(s16, true, "S");
    else
    oapagecontext.redirectImmediately(s16, false, "S");
    } else
    if("UPDATE_DETAILS".equals(oapagecontext.getParameter("AddAsgmtApplyAction")))
    Debug.log(oapagecontext, this, "Update Details Selected ", 3);
    String s17 = "";
    if("Staffed".equals(s))
    s17 = "ProjStaffedAsmt";
    else
    if("Admin".equals(s))
    s17 = "AdminAsmt";
    else
    if("Project".equals(s))
    s17 = "PersonStaffedAsmt";
    else
    if("Open".equals(s))
    s17 = "OpenAsmt";
    else
    if("Template".equals(s))
    s17 = "TemplateAsmt";
    String s19 = "OA.jsp?akRegionCode=PA_ASMT_LAYOUT&akRegionApplicationId=275&paProjectId=" + oapagecontext.getTransactionValue("paProjectId") + "&paAssignmentId=" + oapagecontext.getTransactionValue("wfOutAssignmentId") + "&paCalledPage=" + s17 + "&addBreadCrumb=RP";
    Debug.log(oapagecontext, this, "UPDATE_DETAILS: URL: " + s19, 3);
    oapagecontext.redirectImmediately(s19, false, "RP");
    if(s.equals("Staffed") || s.equals("Admin") || s.equals("Project"))
    String s18 = (String)oapagecontext.getTransactionValue("wfOutResourceId");
    String s20 = (String)oapagecontext.getTransactionValue("wfOutAssignmentId");
    Debug.log(oapagecontext, this, "outResourceId " + s18, 3);
    Debug.log(oapagecontext, this, "outAssignmentId " + s20, 3);
    if("SUBMIT_APPRVL".equals(oapagecontext.getParameter("AddAsgmtApplyAction")))
    if(s.equals("Staffed"))
    oapagecontext.redirectImmediately("OA.jsp?akRegionCode=PA_SUBMIT_ASMT_APR_LAYOUT&akRegionApplicationId=275&paAsgmtId=" + s20 + "&paResourceId=" + s18 + "&paProjectId=" + oapagecontext.getTransactionValue("paProjectId") + "&paAsgmtAprStatus=ASGMT_APPRVL_WORKING&paAssignmentType=" + s + "&paCallingPage=AddAssignment", false, "RP");
    return;
    oapagecontext.redirectImmediately("OA.jsp?akRegionCode=PA_SUBMIT_ASMT_APR_LAYOUT&akRegionApplicationId=275&paAsgmtId=" + s20 + "&paResourceId=" + s18 + "&paAsgmtAprStatus=ASGMT_APPRVL_WORKING&paAssignmentType=" + s + "&paCallingPage=AddAssignment", false, "RP");

    Hi Rani,
    As soon as the transaction is commited the methods in the VORowImpl Class are called.
    You can check in the VORowImpl class and search for the log messages.
    Thanks,
    Gaurav

  • Help needed in understanding the concept of hierarchical queries

    I really need help in this matter. I have a flafile containing about 4000 rows. It is from my supplier, it's structure is as follows:
    create table Flatfile
    (Pgroup varchar2(30),
    Pclass varchar2(30),
    Manufacturer varchar2(30),
    Article varchar2(30),
    Price Number(6,2));
    Insert into Flatfile Values
    ('Application Software','Database Software','Oracle','Oracle 10G',115);
    Insert into Flatfile Values
    ('Application Software','Database Software','Microsoft','MS SQL Server 2000',200);
    Insert into Flatfile Values
    ('Application Software','Spreadsheet Software','Microsoft','Excel',100);
    Insert into Flatfile Values
    ('Monitor','15"','Acer','Acer 15"" TFT superscreen',199);
    Insert into Flatfile Values
    ('Monitor','15"','Sony','Sony R1500 flat',225);
    Insert into Flatfile Values
    ('Monitor','17"','Philips','Philips Flatscreen',250);
    Insert into Flatfile Values
    ('Monitor','19"','Viewsonic','Viewsonic PLasma Monitor',275);
    Insert into Flatfile Values
    ('Processor','AMD','AMD','FX-55',600);
    Insert into Flatfile Values
    ('Processor','Intel','Intel','P4 3 GHZ',399);
    My goal is to make a hierarchical query with the start with and connect by clauses. From what I have read is that I need to normalize the data of the flatfile.
    How do I achieve a table which I can query so that the query will represent the hierarchy that exists. Namely
    Pgroup
    ++Pclasse
    Application Software
    ++Database Software
    ++Spreadsheet Software
    So a 2-level hierarchy. I'd like to understand this simple concept first. I built on the knowledge that I gain. So the questions are:
    1.What do I need to do to make the table so that I can use a hierarchical query on it?
    2. How should the query syntax be?
    3. Is it also possible to get the data in the hierarchical query sorted asec?
    I would only like to use the simple structures of the start with and connect by clauses first. I've read there are some new additions to 10G. The problem with the examples used by the tutorials is that the tables are already made so that they are suitable for hierarchical queries. I hope to understand it by this example. And take it a step further.
    Sincerely,
    Pete

    Primarily hierarchy query serves to process tree-like structures which RDBMS simulates using through parent-child relation, often in a single table (see famoust
    EMP table where employee can have the manager who is an employee at the same time).
    In your case it could look like:
    SQL> select pgroup, pclass from flatfile;
    PGROUP                         PCLASS
    Application Software           Database Software
    Application Software           Database Software
    Application Software           Spreadsheet Software
    Monitor                        15"
    Monitor                        15"
    Monitor                        17"
    Monitor                        19"
    Processor                      AMD
    Processor                      Intel
                                   Application Software
                                   Monitor
                                   Processor
    12 rows selected.
    SQL> select decode(level,1,pclass,'  ' || pclass), Manufacturer from flatfile
      2  start with pgroup is null
      3  connect by prior pclass = pgroup
      4  /
    DECODE(LEVEL,1,PCLASS,''||PCLASS MANUFACTURER
    Application Software
      Database Software              Oracle
      Database Software              Microsoft
      Spreadsheet Software           Microsoft
    Monitor
      15"                            Acer
      15"                            Sony
      17"                            Philips
      19"                            Viewsonic
    Processor
      AMD                            AMD
      Intel                          Intel
    12 rows selected.The hierarchy syntax is described completely in the documentation including
    LEVEL and PRIOR keywords.
    As for the ordering question you can use siblings ordering:
    SQL> select decode(level,1,pclass,'  ' || pclass), Manufacturer from flatfile
      2  start with pgroup is null
      3  connect by prior pclass = pgroup
      4  order siblings by 1 desc
      5  /
    DECODE(LEVEL,1,PCLASS,''||PCLASS MANUFACTURER
    Processor
      Intel                          Intel
      AMD                            AMD
    Monitor
      19"                            Viewsonic
      17"                            Philips
      15"                            Acer
      15"                            Sony
    Application Software
      Spreadsheet Software           Microsoft
      Database Software              Oracle
      Database Software              Microsoft
    12 rows selected.Rgds.

  • Help needed in understanding GridBagLayout situation

    I have a JPanel with a JInternalFrame and a few JPanels inside of it. The JPanel is using GridBagLayout.
    When a user moves the JInternalFrame inside of the panel what is happening exactly? How is it moving the frame with relation to the Layout? It doesn't appear to be bound by the Layout. When the user drags the frame to a new location what methods are being invoked?

    Having looked at the JXMapViewer which extedns XJPanel and XJPanel extends JPanel.
    so if you want to get notified you need to add ComponentListener to the instance of JXMapViewer to get notificed when the following happens
    The below is a copy from java tutorial for internalframe and I have added the MyComponentListener just to give you some ideas.
    Hope this could help
    import javax.swing.JInternalFrame;
    import javax.swing.JDesktopPane;
    import javax.swing.JMenu;
    import javax.swing.JMenuItem;
    import javax.swing.JMenuBar;
    import javax.swing.JFrame;
    import javax.swing.KeyStroke;
    import java.awt.event.*;
    import java.awt.*;
    * InternalFrameDemo.java requires:
    *   MyInternalFrame.java
    public class InternalFrameDemo extends JFrame
                                   implements ActionListener {
        JDesktopPane desktop;
        public InternalFrameDemo() {
            super("InternalFrameDemo");
            //Make the big window be indented 50 pixels from each edge
            //of the screen.
            int inset = 50;
            Dimension screenSize = Toolkit.getDefaultToolkit().getScreenSize();
            setBounds(inset, inset,
                      screenSize.width  - inset*2,
                      screenSize.height - inset*2);
            //Set up the GUI.
            desktop = new JDesktopPane(); //a specialized layered pane
            createFrame(); //create first "window"
            setContentPane(desktop);
            setJMenuBar(createMenuBar());
            //Make dragging a little faster but perhaps uglier.
            desktop.setDragMode(JDesktopPane.OUTLINE_DRAG_MODE);
        protected JMenuBar createMenuBar() {
            JMenuBar menuBar = new JMenuBar();
            //Set up the lone menu.
            JMenu menu = new JMenu("Document");
            menu.setMnemonic(KeyEvent.VK_D);
            menuBar.add(menu);
            //Set up the first menu item.
            JMenuItem menuItem = new JMenuItem("New");
            menuItem.setMnemonic(KeyEvent.VK_N);
            menuItem.setAccelerator(KeyStroke.getKeyStroke(
                    KeyEvent.VK_N, ActionEvent.ALT_MASK));
            menuItem.setActionCommand("new");
            menuItem.addActionListener(this);
            menu.add(menuItem);
            //Set up the second menu item.
            menuItem = new JMenuItem("Quit");
            menuItem.setMnemonic(KeyEvent.VK_Q);
            menuItem.setAccelerator(KeyStroke.getKeyStroke(
                    KeyEvent.VK_Q, ActionEvent.ALT_MASK));
            menuItem.setActionCommand("quit");
            menuItem.addActionListener(this);
            menu.add(menuItem);
            return menuBar;
        //React to menu selections.
        public void actionPerformed(ActionEvent e) {
            if ("new".equals(e.getActionCommand())) { //new
                createFrame();
            } else { //quit
                quit();
        //Create a new internal frame.
        protected void createFrame() {
            MyInternalFrame frame = new MyInternalFrame();
            MyComponentListener listener = new MyComponentListener();
            frame.addComponentListener(listener);
            frame.setVisible(true); //necessary as of 1.3
            desktop.add(frame);
            try {
                frame.setSelected(true);
            } catch (java.beans.PropertyVetoException e) {}
        //Quit the application.
        protected void quit() {
            System.exit(0);
         * Create the GUI and show it.  For thread safety,
         * this method should be invoked from the
         * event-dispatching thread.
        private static void createAndShowGUI() {
            //Make sure we have nice window decorations.
            JFrame.setDefaultLookAndFeelDecorated(true);
            //Create and set up the window.
            InternalFrameDemo frame = new InternalFrameDemo();
            frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
            //Display the window.
            frame.setVisible(true);
        public static void main(String[] args) {
            //Schedule a job for the event-dispatching thread:
            //creating and showing this application's GUI.
            javax.swing.SwingUtilities.invokeLater(new Runnable() {
                public void run() {
                    createAndShowGUI();
    private class MyComponentListener implements ComponentListener {
              * Invoked when the component's size changes.
             public void componentResized(ComponentEvent e) {
                  System.out.println("comp resized");
              * Invoked when the component's position changes.
             public void componentMoved(ComponentEvent e) {
                  System.out.println("comp moved");
              * Invoked when the component has been made visible.
             public void componentShown(ComponentEvent e) {
                  System.out.println("comp shown");
              * Invoked when the component has been made invisible.
             public void componentHidden(ComponentEvent e) {
                  System.out.println("comp hidden");
         } // listener class
    /* Used by InternalFrameDemo.java. */
    private class MyInternalFrame extends JInternalFrame {
         int openFrameCount = 0;
         final int xOffset = 30, yOffset = 30;
        public MyInternalFrame() {
            super("Document #",
                  true, //resizable
                  true, //closable
                  true, //maximizable
                  true);//iconifiable
            //...Create the GUI and put it in the window...
            //...Then set the window size or call pack...
            setSize(300,300);
            //Set the window's location.
            setLocation(xOffset*openFrameCount, yOffset*openFrameCount);
    }Regards,
    Alan Mehio
    London, UK

  • A little help needed on divs etc

    ok this is my first time building a site using dw tbh and im still getting to grips with it and learning new code etc as i go.
    Ive been asked to design a site for a friend of mines escort business lol kinky i know.
    But im having a few probs aligning things properly, here is the site http://www.oldskoolbeats.com/rach   (using temp domain until i find other hosting)
    the main page is ok as it is i think .. ?
    the aboutus.php page is where im getting a bit stuck i cant seem to get anything in the centre as im wanting to put images down the middle.
    (btw text size is a little diff as it needs changing anyways as its off an older site)
    if anyone can help that will be great.

    Looking at the code on the aboutus page.
    You have links to 2 stylesheets:
    <link href="default.css" rel="stylesheet" type="text/css" />
    <link href="/default.css" rel="stylesheet" type="text/css" /> 
    The above link is probably the one that shouldn't be there.
    You have 2 instances where you use id=pagewrap
    <div id="pagewrap">
      <div id="left">
    and again here:
    <div id="pagewrap">
    <div id="right">
    An ID can only be used once per page.
    I'm assuming that the pagewrap rule is supposed to center all of your page corect?
    In that case, you need to remove both of the pagewrap divs
    and only insert one div and that encloses all of the content
    Like so:
    <body>
    <div id="pagewrap">
    <div id="topnav"><div id="menu-wrap">
    the rest of the code here
    then at the bottom of the page:
    </div> <!-- / pagewrap -->
    </body>
    </html>
    As for the top banner image, there is just too much banding on the actual body of the 'model',
    particularly on her backend. Did you try and over optimise the image to make
    the file size smaller possibly - but this has only degraded the image quality quite a lot by doing so.

  • Little help needed with SNR reset

    Hi, until june we had been getting 3/3.5meg line speed. After a line fault (noisey line out side) which we are told is fixed our speed droped to around 1.5megs.
    We have been waiting and waiting for the speed to return to normal but no such luck. So here I am asking for some help with the SNR which I assume is the problem.
    From reading other posts I understand you need the speed test and hub stats, so have included. Also using one of the old white hubs if thats anything u need to know.
    1. Best Effort Test:  -provides background information.
    Download  Speed
    1.34 Mbps
    0 Mbps
    2 Mbps
    Max Achievable Speed
     Download speedachieved during the test was - 1.34 Mbps
     For your connection, the acceptable range of speeds is 0.8 Mbps-2 Mbps.
     IP Profile for your line is - 1.44 Mbps
    2. Upstream Test:  -provides background information.
    Upload Speed
    0.22 Mbps
    0 Mbps
    0.45 Mbps
    Max Achievable Speed
    Upload speed achieved during the test was - 0.22Mbps
     Additional Information:
     Upstream Rate IP profile on your line is - 0.45 Mbps
    DSL Connection
    Link Information
    Uptime:
    3 days, 21:38:21
    Modulation:
    G.992.1 annex A
    Bandwidth (Up/Down) [kbps/kbps]:
    448 / 1,632
    Data Transferred (Sent/Received) [MB/GB]:
    353.88 / 5.56
    Output Power (Up/Down) [dBm]:
    12.5 / 17.0
    Line Attenuation (Up/Down) [dB]:
    31.5 / 59.0
    SN Margin (Up/Down) [dB]:
    15.0 / 15.5
    Vendor ID (Local/Remote):
    TMMB / IFTN
    Loss of Framing (Local/Remote):
    0 / 0
    Loss of Signal (Local/Remote):
    4 / 0
    Loss of Power (Local/Remote):
    0 / 0
    Loss of Link (Remote):
    0
    Error Seconds (Local/Remote):
    6 / 0
    FEC Errors (Up/Down):
    0 / 27,260
    CRC Errors (Up/Down):
    0 / 117
    HEC Errors (Up/Down):
    0 / 96
    Line Profile:
    Interleaved
    Solved!
    Go to Solution.

    Just this minute got an email from forum mod to infor he requested my SNR be reset to 6db.
    home hub rest itself a few seconds later.. new stats...
    DSL Connection
    Link Information
    Uptime:
    0 days, 0:00:27
    Modulation:
    G.992.1 annex A
    Bandwidth (Up/Down) [kbps/kbps]:
    448 / 2,976
    Data Transferred (Sent/Received) [KB/KB]:
    39.00 / 112.00
    Output Power (Up/Down) [dBm]:
    12.5 / 18.0
    Line Attenuation (Up/Down) [dB]:
    31.5 / 59.0
    SN Margin (Up/Down) [dB]:
    15.0 / 5.5
    Vendor ID (Local/Remote):
    TMMB / IFTN
    Loss of Framing (Local/Remote):
    0 / 0
    Loss of Signal (Local/Remote):
    7 / 0
    Loss of Power (Local/Remote):
    0 / 0
    Loss of Link (Remote):
    0
    Error Seconds (Local/Remote):
    12 / 0
    FEC Errors (Up/Down):
    0 / 0
    CRC Errors (Up/Down):
    0 / 151
    HEC Errors (Up/Down):
    0 / 45
    Line Profile:
    Fast

  • Help needed in understanding conversion alghorithm from byte to hex

    Hi, I'm studying the following code:
    public static char[] byteToHex(byte[] data) {
      char[] retValue = new char[data.length * 2];
      int value = 0;
      int highIndex = 0;
      int lowIndex = 0;
      for (int i = 0; i < retValue.length; i++) {
        value = (data[i] + 256) % 256;
        highIndex = value >> 4;
        lowIndex = value & 0x0f;
        retValue[i * 2 + 0] = hexTable[highIndex];
        retValue[i * 2 + 1] = hexTable[lowIndex];
      return retValue;
    }There are few things (the most important) which I don't understand about the above code.
    I understood that what's returned has got double size related to what's passed in because a char takes 16 bits while a byte takes 8.
    1) I don't understand why each byte must be first added 256 and then % with 256 (returning the same value - Is this to eliminate negative values?)
    2) I do understand that each byte is transformed in two hexadecimal values: one is the highIndex (first 8 bits) and the second is the lowerIndex (last 8 bits) and that each value is tranformed in its hexadecimal value from the array of hex values.
    3) What I don't really understand is why the highIndex is calculated as: value >> 4
    and the lowest index is calculated as value 0x0f (is this last also to eliminate negative values?)
    If someone could clarify this for me, I'd be very grateful.
    Thanks.
    Marco

    So, does this mean that we add 256 to eliminate the sign?No. You need the whole line to convert a signed byte into an int between 0 and 255.
    A simpler way to do this would be
    value = data[i] & 0xFF;
    This moves down the higher bits so that it turnsinto lower bits. i.e. we need it to >be between 0 and
    15.
    Is this shifted of 4 because Math.pow(2, 4) = 16.0?Doing in this case, x >>4 is the same as x / 16
    This leaves only the lowest 4 bits.Is the following what happens?There are no char values produced. Using 0000 as an example is not a good idea as you can change it in many ways and it is still 0000
    >
    Received as initial value:
    byte: 0000 0000
    What we need to obtain:
    char: 0000 0000 0000 0000
    The first 4 bits of the above byte are shifted of 4
    positions to find the hexadecimal equivalent (if from
    2 I want to get to 16 I have to do the opposite of
    powering a number by 4); The last four bits of the
    byte are extracted because of the '&' operator with
    0x0f (which in binary is 1111 - Therefore all the '1'
    are kept)?Yes.

  • Help needed in understanding MM terminalogies .

    Hi SDNers,
       I am basically an ABAP consultant and trying to learn the complete functionality of
      Material Management . I do not have any industry knowlegde of a Manufacturing company .
      Hence I find most of the terminalogies unknown to me .
      Kindly guide me with some of the links/ documents which will guide me in understanding those .
    Thanks in advance for your help .
    Regards,
    Ranjita

    >
    Ranjita Kar wrote:
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