Logical bitwise operator

Hi ALL
Logical bitwise comparison operator 'O' is used between two operands say A and B as "A O B".
A is of type INT1 and B is of type X.
The above mentioned line was working fine till enabling unicode check. But now it says A should be of type X or Xstring.A's type cannot be changed since it is derived from a std structure.
Is there some other operator which does the same function as operator 'O'?
Regards,
Navaneeth

Hi,
Check this..
IF.....XOR.....
Regards
Vijay

Similar Messages

Does bitwise operation on boolean datatypes work like logical operation ?

Does bitwise operation on boolean datatypes work like logical operation ?
For example, in the following code, how is each bitwise operation (say) 'b1 & b2' evaluated ?
1) by converting the values of b1 (true) and b2 (false) to binary and doing '&' on them OR
2) just treating it as a logical operation (i.e. similar to &&) where both have to be equal to be true
Also, does the outcome of the if condition need to result in a 'true' or 'false' for the relevant message to print ? ....... Just fyi, I tried out this program and it goes to condition 2 but I do not understand why.
class SSBool {
public static void main(String[] args) {
boolean b1 = true;
boolean b2 = false;
boolean b3 = true;
if (b1 & b2 | b2 & b3 | b2)
System.out.println ("condition 1");
if (b1 & b2 | b2 & b3 | b2 | b1)
System.out.println ("condition 2");
Thank you,
AG

The Java Tutorial (always my first stop if I need an answer) says :
"When both operands are boolean, the operator & performs the same operation as &&."
That your program goes to condition 2 is obvious because the last test in the if-clause if (b1 & b2 | b2 & b3 | b2 | b1) looks at b1 which is true...

Bitwise Operator ( ) help

I'm a new beginner and I have some problems with such code:
class Test {
     public static void main(String[] args) {
          int i = -1;
          int a = i;
          for ( int k = 0 ; k < 32 ; k ++ ) {
               i = i >>> 1;
               System.out.print(i+" ");
               System.out.println(a >>> (k+1) );
I hope that the two columns of the output wil be the same, but the
last line isn't.
Why a == -1 after " int a = -1; a = a >>> 32 " ? I think a should be 0.
Am I right or is there any mistake?

See the language spec:
http://java.sun.com/docs/books/jls/second_edition/html/expressions.doc.html#5121
in particular:
If the promoted type of the left-hand operand is int, only the five lowest-order bits of the right-hand operand are used as the shift distance. It is as if the right-hand operand were subjected to a bitwise logical AND operator & (�15.22.1) with the mask value 0x1f. The shift distance actually used is therefore always in the range 0 to 31, inclusive.
Though it doesn't say why.

Logical XOR operator in T-SQL (SQL Server 2000)

Hi all....
I was wondering why SQL Server 2000 lacks a logical XOR operator. Do you have a ready to use function that implements it?
How can I program one by myself? I know that A XOR B is equivalent to NOT A * B + A * NOT B. So I tried to create this function :
CREATE FUNCTION XOR
-- Add the parameters for the function here
@A BIT,
@B BIT
RETURNS BIT
AS
BEGIN
RETURN NOT @A AND @B OR @A + NOT @B
END
But it didn't compile.
How can I pass boolean values as parameters? any other hint?
Thanks
Jaime

I have these two views , one of them hard coded as NULL as it always needs to be NULL. I wanted to union them
Now the problem is I have to replace those NULLS if I have a value from other VIEW or else NULL ( no change)
I am getting duplicates of rows with values and NULLS , whereas I needed only records with values
I need records with values and records without value as NULL . please let me know how to eliminate dups with NULLS
21
ARGH
Bus
NULL
NULL
NULL
NULL
21
ARGH
Bus
66
781
HEAVY
00:00.0
21
F1WS
Ship
NULL
NULL
NULL
NULL
21
HGDD
car
NULL
NULL
NULL
NULL
21
HGDT
car
NULL
NULL
NULL
NULL
Below is the code :
--- view having values
SELECT *
FROM Table1 AS S INNER JOIN
Table2 AS P ON S.columnA = P.columnB
WHERE EXISTS
(SELECT 1 AS A
FROM Table2 AS R
WHERE (S.columnA = columnB))
GROUP BY ALL
UNION
--- views harded coded as NULLS
SELECT *, NULL AS APR , NULL AS MAY , NULL AS JUN , NULL AS JUL , NULL AS AUG
FROM Table1 AS S INNER JOIN
Table2 AS P ON S.columnA <> P.columnB
WHERE (NOT EXISTS
(SELECT 1 AS A
FROM Table2 AS R
WHERE (S.columnA = columnB) )) OR
EXISTS
(SELECT 1 AS A
FROM Table2 AS R
WHERE (S.columnA = columnB) )
GROUP BY ALL

How to get a column by applying logical AND operator on two column ?

All column are VARCHAR2 data type.
I have table output in this way :
col1 col2
True True
True False
False FalseBut i want a additional column in this way :
col1 col2 result
True True True
True False False
False False FalseAs the output indicates its clear that resut column is logical AND operator
on col1 and col2. How to achieve this ?

try this
WITH logic AS
     (SELECT 'TRUE' col1, 'TRUE' col2
        FROM DUAL
      UNION ALL
      SELECT 'TRUE' col1, 'FALSE' col2
        FROM DUAL
      UNION ALL
      SELECT 'FALSE' col1, 'TRUE' col2
        FROM DUAL
      UNION ALL
      SELECT 'FALSE' col1, 'FALSE' col2
        FROM DUAL)
SELECT col1, col2,
       CASE
          WHEN 'FALSE' IN (col1, col2)
             THEN 'FALSE'
          ELSE 'TRUE'
       END AS log_and,
       CASE
          WHEN 'TRUE' IN (col1, col2)
             THEN 'TRUE'
          WHEN 'FALSE' IN (col1, col2)
             THEN 'FALSE'
       END AS log_or
FROM logic
Explain complete.
PLAN_TABLE_OUTPUT
| Id | Operation        | Name | Rows | Bytes | Cost (%CPU)|
|   0 | SELECT STATEMENT |      |     4 |    32 |     8   (0)|
|   1 | VIEW            |      |     4 |    32 |     8   (0)|
|   2 |   UNION-ALL      |      |       |       |            |
|   3 |    FAST DUAL     |      |     1 |       |     2   (0)|
|   4 |    FAST DUAL     |      |     1 |       |     2   (0)|
|   5 |    FAST DUAL     |      |     1 |       |     2   (0)|
|   6 |    FAST DUAL     |      |     1 |       |     2   (0)|
Note
   - 'PLAN_TABLE' is old version
16 rows selected.regards,
friend

What is the difference between != and Logical NOT operator

kindly,tell me what is the difference between Not Equality operator and logical negation operator.
Edited by: user13414134 on Dec 3, 2010 8:59 AM

what is the difference between != and Logical NOT operator The NOT operator is transformed into the inequality operator (<>), as can be seen from the Predicate Information of the explain plan:
SQL> explain plan for select * from dual where :x != :y
Explain complete.
SQL> select * from table(dbms_xplan.display())
PLAN_TABLE_OUTPUT
Plan hash value: 3752461848
| Id | Operation          | Name | Rows | Bytes | Cost (%CPU)| Time     |
|   0 | SELECT STATEMENT   |      |     1 |     2 |     2   (0)| 00:00:01 |
|* 1 | FILTER            |      |       |       |            |          |
|   2 |   TABLE ACCESS FULL| DUAL |     1 |     2 |     2   (0)| 00:00:01 |
Predicate Information (identified by operation id):
   1 - filter(:Y<>:X)
14 rows selected.
SQL> explain plan for select * from dual where not :x = :y
Explain complete.
SQL> select * from table(dbms_xplan.display())
PLAN_TABLE_OUTPUT
Plan hash value: 3752461848
| Id | Operation          | Name | Rows | Bytes | Cost (%CPU)| Time     |
|   0 | SELECT STATEMENT   |      |     1 |     2 |     2   (0)| 00:00:01 |
|* 1 | FILTER            |      |       |       |            |          |
|   2 |   TABLE ACCESS FULL| DUAL |     1 |     2 |     2   (0)| 00:00:01 |
Predicate Information (identified by operation id):
   1 - filter(:Y<>:X)
14 rows selected.

Bitwise operator question...

Hi,all.
I have been using Java for around 1 year, but still not very comfortable with bitwise problems. I wish some one can give me a thorough explanation for these. Better yet, if you know how to use bitwise operator to solove the real programming problem, please post here too. I am doing some testing now. I will post some coding example later here, so you may help me on these coding too.
Everyone have a great sunday night.

Integers are represented by 32-bit values. You can have either 'signed' or 'unsigned' integer ranges.
signed int 32000 to - 32000
unsigned int 0 to 65000
(note, these are approximations)
For signed interpretations, the last digit on the left hand side represents wether or not the value is negative (called the most significant bit, msb).
1000 0000
The '1' is the msb
Steps to convert -14 to its binary representation (using 2s complement as explained by above post):
1. write the binary representation of '1' (ignore negative for now)
2. invert the values
3. add 1
1) 0000 1110
2) 1111 0001
3) 1111 0010
As you can see, the msb is a '1', so therefore it represents a negative value
Note: In binary addition,
1 + 1 = 0 carry 1
1 + 0 = 1
0 + 0 = 0
As for other applications of this, I find myself using bitwise calculations in graphical work.
As stated above (I love to reiterate others words, cause it's fun!!), Assembler language programming is a fantastic way to become an expert in the art of bitwise manipulation (if you have the patience).

Pda reproducible bug with logical shift operation when y 3 for arrays

Folks,
I have discovered a problem and wonder if this is a wider bug or if I am doing something wrong:
Labview PDA 8.0.1 - running on a Dell Axim:
I create a 2x1000 array of U32 and feed it as x into the logical shift operator. If y is between -3 and 3, the logical shift works properly. If y >= 4 or <= -4, then the array is returned with all zeros.
I have reproduced this for I32 data and smaller arrays. Logical shift works properly for scalars.
Has anyone else seen this? Is this a bug?
Thanks for any help.

It might very well be a bug. If it works differently on the PC and on the PDA then it is almost certainly one.
I suggest you post a simple example showing this so that people with current versions of the PDA module (i.e. not me) can test this. Maybe it was even fixed for 8.2?
Try to take over the world!

How to make Bitwise operation in Labview ?

Hello.. everyone,
I need to make the bitwise operation (or) in Labview, but I can't find it somewhere!!!
Anybody has the experiece about it, pls help me !!
Thanks a lot

Hi Nok,
The standard OR function in the boolean sub palette of the functions palette performs a bitwise operation on it's input data. This is a polymorphic function so you can input scalar booleans, arrays of booleans or numerics.
Hope this helps,
Nick

Logical OR operator

Hi,
Anyone can help how to solve the following ..
System.out.println( 4 | 7);
I have tried with logical opertor (0100 OR 0111) with result 11 !!
but the answer was 7 ????.
-Alex

It is not logical but numerical operator in this case. Indeed,
System.out.println( 4 || 7);does not even compile.
Gooc old C does not have a logical (boolean) type, it uses integers on the syntax level too. C++ has the "bool" type, but it maintains the logical <-> integer conversion.
In java the logical type is separated from the integral ones; there is no boolean -> integer conversion.
For convenience however single & and | can be applied to booleans.

LPX-00601: Invalid token in: using logical AND operator in XQuery

Hi Pro's,
I am working on DB version 10.2.0.3, I have loaded this document into XMLType column:
<ROOT>
<COUNTRY>
<NAME>India</NAME>
<PERSON>
<NAME>Harinath</NAME>
<CITY>Bangalore</CITY>
<STATE>Karnataka</STATE>
<IMMI_STATUS>Citizen</IMMI_STATUS>
</PERSON>
<PERSON>
<NAME>Mohan</NAME>
<CITY>Kakinada</CITY>
<STATE>Andhra Pradesh</STATE>
<IMMI_STATUS>Citizen</IMMI_STATUS>
</PERSON>
</COUNTRY>
<COUNTRY>
<NAME>USA</NAME>
<PERSON>
<NAME>Drew P</NAME>
<CITY>Appleton</CITY>
<STATE>WI</STATE>
<IMMI_STATUS>Citizen</IMMI_STATUS>
</PERSON>
<PERSON>
<NAME>Bush</NAME>
<CITY>Washington</CITY>
<STATE>DC</STATE>
<IMMI_STATUS>Citizen</IMMI_STATUS>
</PERSON>
<PERSON>
<NAME>Harinath</NAME>
<CITY>Atlanta</CITY>
<STATE>GA</STATE>
<IMMI_STATUS>Alien</IMMI_STATUS>
</PERSON>
</COUNTRY>
</ROOT>
This query returns one row : (As Expected)
===============================
SELECT extractValue(rec.xmldata, '/ROOT/COUNTRY[PERSON/NAME="Drew P"]/NAME') C_COUNTRY
FROM (SELECT VALUE(xml) xmldata
FROM XXSSI_XML_STG stg
,TABLE(XMLSequence(extract(stg.XMLDATA, '//ROOT'))) xml
WHERE stg.REQUEST_ID = 4204203) rec
This query fails: TRUE as "Harinath" appears twice in the document once in "India" and once in "USA";
======================================================
SELECT extractValue(rec.xmldata, '/ROOT/COUNTRY[PERSON/NAME="Harinath"]/NAME') C_COUNTRY
FROM (SELECT VALUE(xml) xmldata
FROM XXSSI_XML_STG stg
,TABLE(XMLSequence(extract(stg.XMLDATA, '//ROOT'))) xml
WHERE stg.REQUEST_ID = 4204203) rec ;
To fix the error I introduced "LOGICAL AND" in the XPath: THIS FAILS
===================================================
SELECT extractValue(rec.xmldata, '/ROOT/COUNTRY[PERSON/NAME="Harinath" AND IMMI_STATUS="Citizen"]/NAME') C_COUNTRY
FROM (SELECT VALUE(xml) xmldata
FROM XXSSI.XXSSI_XML_STG stg
,TABLE(XMLSequence(extract(stg.XMLDATA, '//ROOT'))) xml
WHERE stg.REQUEST_ID = 4204203) rec ;
Please help!!!!!!

Hi !!!
Im sooo thankful to you... it works!!!
Learnt a lesson today "dont blindly go by those user guides" I was refering to Example 6–8 of "B14259" 10g Developer Guide (Page 282) which has this query
SELECT extract(OBJECT_VALUE, '/PurchaseOrder/Item').getClobval()
FROM mypurchaseorders p
WHERE existsNode(OBJECT_VALUE,
'/PurchaseOrder[PONum=1001 AND Company = "Oracle Corp"]') = 1;
may be a printing error :(
Thanks a lot.

BitWise Operations in java

hi Guys
Can any one help me out in explaining the below program
public class Bitwise{
public static void main (String[]args){
int x=12&13;
int y=x^6;
System.out.println(y I 3)
Pls help me with the above program in detail explanation
Raghu

Here's a better idea. You start by:
1) adding print statements to print out x and y immediately after they're set.
2) predicting what you think each print statement will produce, consulting your favorite text or tutorial (see below links) or the JLS if you need to.
3) running the program.
4) seeing if the results match what you expected.
5) trying to figure why they didn't match, if they didn't.
6) poting a specific question here about what you expected and why, and what you saw instead, if you're unable to figure it out.
Installation Notes - JDK 5.0 Microsoft Windows (32-bit)
Your First Cup of Java
New to Java Center
The Java™ Tutorial - A practical guide for programmers
The Java™ Tutorial - Trail: Learning the Java Language
Java Programming Notes - Fred Swartz
How To Think Like A Computer Scientist
Introduction to Computer Science using Java
The Java Developers Almanac 1.4
Object-Oriented Programming Concepts
Object-oriented language basics
Don't Fear the OOP
Books:
The Java Programming Language - 4th Edition
Head First Java, by Bert Bates and Kathy Sierra
Thinking in Java (Free online), by Bruce Eckel
Core Java, by Cay Horstmann and Gary Cornell
Effective Java, by Joshua Bloch
http://java.sun.com/developer/Books/javaprogramming/
Intermediate
The Craftsman Series
Java Design: Building Better Apps and Applets (2nd Edition)
Head First Design Patterns

Bitwise operator: (010|4)

Executing the following code results in "12". I do not understand why?
public class Test {
public static void main(String[] args) {
System.out.println(010|4);
}From what I understand, the answer should be 6. What is wrong with my below logic?
010 = 2
100 = 4
110 = 6
Thanks!

You can check out the JLS - go here:
http://java.sun.com/docs/books/jls/second_edition/html/lexical.doc.html
And look at section 3.10.1
There's no way to explicitly enter a base 2 digit (that I know of) - you can specify it as base 16 by prepending with a 0x, or octal by prepending with a 0. You could use the Integer.parseInt(value, radix) method to do this by passing in the binary digit string and a radix of 2, as int value = Integer.parseInt("010", 2)I hope that helped
Lee

Bitwise Operator

Hi Gurus,
I am bit poor at math and yes i know bitand is used for binary and operation. But i can't figure out this conversion.
Here is a flag column values from ts$
flags   0x40 = COMPRESS
         0x10000 = OLTP Compression
         0x20000 = Columnar Low Compression
         0x40000 = Columnar High Compression
         0x80000 = Archive CompressionAnd here is corrosponding conversion in dba_tablespaces script.
case when bitand(ts.flags, 65536) = 65536 then 'OLTP'
                  when bitand(ts.flags, (131072+262144)) = 131072
                    then 'QUERY LOW'
                  when bitand(ts.flags, (131072+262144)) = 262144
                    then 'QUERY HIGH'
                  when bitand(ts.flags, (131072+262144)) = (131072+262144)
                    then 'ARCHIVE LOW'
                  when bitand(ts.flags, 524288) = 524288
                    then 'ARCHIVE HIGH'
                  else 'BASIC' end))Now, here are my question
1. 0x40 & 0x10000 and othere are hexa values Right ?
2. So what does 65536 means here all other values are multiple (131072) are of this
3. So, what are we checking here with this kind of bitand(ts.flags, (131072+262144)) thing
Can someone please explain in simple terms. I searched manuals and other but they give just high level information but not basic.

decimal 65536 is the same as hexadecimal 10000
You can test it useing a calculator or SQL
select to_char(65536,'fmXXXXXX') hexConversion from dual;
HEXCONVERSION
10000BITAND is used to test if a certain bit is set or not. For example in your case it is used to test if the bits for ARCHIVE + LOW COMPRESSION are set.
Hex 10000 in Binary code (not HEX) looks like this
0x10000 => 0000100000000 .... many 0s
0x20000 => 0001000000000 .... many 0s
0x40000 => 0010000000000 .... many 0s
0x80000 => 0100000000000 .... many 0s Bitand does a binary AND operation on each bit. Therefore it can be used to find out if certain bits are set or not.
example
1000111010001
BITAND
0000110000000
0000110000000For each bit the AND operator works like this
0 AND 0 = 0
0 AND 1 = 0
1 AND 0 = 0
1 AND 1 = 1
Edited by: Sven W. on Aug 30, 2010 5:45 PM

Using ModbusSlave and for bitwise operation

I ran into a problem using a ModbusSlave to read a signed Integer for bitmasking.
I connected the Tag value into D40001 and read the bits from ModbusSlave1.H40002.fx (for bits 0-15) and ModbusSlave1.H40001.fx (for bits 16-31).
When the the MSB (Bit 15) was on, the number returned was a negative value, and the ModbusSlave showed no bits as set.
I alos found this to be a problem using mod( int(WORD) , 2) --> to get Bit 0
mod( int(WORD/2) , 2) --> to get Bit 1...
as this will return an error if WORD is negative.
I saw a suggestion to check for the sign bit by: if ((WORD <0), TRUE, FALSE).
How does this work if the sign bit is the only bit on (WORD = -0)?
The solution we did was to create a new Tag in the PLC as a DINT (double INT-32 bit) and add a rung to move the INT(16 bit) into this new Tag.
However I did find that this will be a problem if the MSB (bit 31) is used in the DINT.
The getbit function worked but I was looking for a solution other than using this as I am often working from existing PLC's and don't always have access to the PLC program to make a change like this.

Hello Khalid,
The application is pretty simple.
I am reading a tag from a AB Controllogix PLC.
Lookout is seeing it as a 16 bit signed Integer.
The tag has each bit assigned to a Photoeye or e-stop and I want to monitor each bit to see of it is true.
It can be simulated using a Pot and ModbusSlave.
I tried the "S" regsitered but did not see a value in the ModbusSlave1.H40002.fx.
Should I use another connection?
Dswift

Logical bitwise operator

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