Looking for AppleScript / Automator Help

I have a spreadsheet of 2000+ users which includes their user ID, email address and a temporary password. I need an automated way to individually e-mail each user their user ID and temporary password, along with a paragraph of login instructions. It doesn't seem too overly complex but I don't know where to start. Can anyone point me in the right direction?

All due respect to Camelot, working with Excel is not so bad, you just need to work around its limitations.  the following should work, without the need of creating a tab-delimited file:
tell application "Microsoft Excel"
  -- use the correct range for your data, obviously
          set theSpreadsheetPeople to value of range "A1:C2000" of worksheet 1 of document 1
end tell
repeat with thisPerson in theSpreadsheetPeople
          set {userid, email, pass} to items 1 thru 3 of thisPerson
          tell application "Mail"
                    set newMess to make new outgoing message at end of outgoing messages with properties {subject:"This is the Subject line", sender:"[email protected]", visible:true}
                    tell newMess
  make new to recipient at end of to recipients with properties {address:email}
                              set content to "Text string with email contents, including user id: " & userid & " and password: " & pass
                    end tell
  -- uncomment the following line to send automatically
  -- send newMess
          end tell
end repeat
test it a few times on a short list of data lines (say 4 or 5 lines) with the send command commented out, so that you can make sure that the email is being structured properly and looks the way you want it to.  Once you're satisfied, you can uncomment the send line and use visible:false in the make new outgoing message line.  that will let Mail create and send the emails invisibly.  but again, make sure the emails are being created correctly before you uncomment that send line - nothing worse then sending out a bulk message with errors in it.

Similar Messages

  • I have acquired windows office 2011 for my macbook but unable to open it. There are currently 3 files in the folder, 1 of which seems to be the actual program which is a hfs file. iv tried looking for programs to help me open it but failed

    i have acquired windows office 2011 for my macbook but unable to open it. There are currently 3 files in the folder, 1 of which seems to be the actual program which is a hfs file. iv tried looking for programs to help me open it but failed.
    when double clicking on the image it says unable to open and gives me the option to search the app store.
    any help would be much appreciated
    Adam

    Well, first, just make sure it's the Mac version and not the Windows version (which indeed would not run on your Mac). You say "Windows Office" which is why I mention it. I think you probably just mean "Microsoft Office" though.
    Next, is this on a disk (DVD), or did you purchase and download it from the Microsoft site?
    Matt

  • Looking for friends to help me get over a breakup

    PSN  MAGIIK-STICKZ  Hello All, This is very embarrassing and quite silly that I have to do this really. It's scary that I have to turn to the Internet to look for friends to help me in this time of need. In the beginning of the month my girl friend left me, we was together for 4 years, we had our ups and downs but we always remained strong. She told me she wanted to be with me forever and I wanted the same. I've only just turned 19 so this was my first relationship. Don't want to get into too much details why she left me, but I will tell you that she has already moved on after only leaving me for a month. The pain hurts so much and I'm trying to move on because I can't... Because I have no friends... I mean I have friends but they're definitely not the ones you can count on in this situation. They're more "Gym Bros" I believe if I can find people to group with, play games with, literally just talk to that would be amazing for me. I just needs things to take my mind off of her and I believe talking to new people will do that. We don't even have to play games, I'm very open to you just in-boxing me on PlayStation to socialize.  I'm opened to both males and females but if there are any females you would be helping a lot! I cut off all female ties for her for 4 years and now I have no female acquaintances so It would be nice to get experience talking to other females again just to boost my confidence back.  I understand what I am asking for might sound like a lot, and I definitely understand how needy I sound, but this was my last resort of trying to get over her as quickly as I can. I've been in a really really REALLY Dark Place for the past month and I can't take it anymore.  My psn/PS4 is MAGIIK-STICKZ  Inbox me and I will be forever grateful ! 

    rancidpunk wrote:
    Shuffles slowly away, no, no, no me and Mrs Rancid haven't been engaged for more than ten years without tying the knot, no, no, no, honest. Hey at least you got engaged, that took me ten years (dont let Sooz know)  Friends I can't help you with bud As for the forum and PS , as Sooz said there's here, and you might want to try some of the events http://community.eu.playstation.com/t5/Events/bd-p/bEN_CommunityEvents There's some good eggs around those folk that'll have you chatting rubbish on the mic within minutes  Heart breaks do indeed sux. Even some of the really short relationships can break your heart (I know one of my short ones did, proper knocked me about that one. Although now I see it as a positive turnaround in my life)  Hope one of us tools here will some how give you some cheer. Have a man hug   Oh ow, and just in case there's always the Cat Threadhttp://community.eu.playstation.com/t5/PlayStation-Off-Topic/Cat-Thread/m-p/15658225/highlight/true#M1060419 or Dogshttp://community.eu.playstation.com/t5/PlayStation-Off-Topic/The-Dog-Thread/td-p/16511247/highlight/true Although they get pretty deep in there. And the thought of being a lonely old man with lots of cats and a brown setee scares me way more  

  • Ran msconfig, but not sure what to look for... help?

    i ran msconfig and this is what is under my startup tab... can someone please help me understand what this means and what i should be looking for?
    These items are checked:
    real sched
    tgcmd
    qttask
    iTunesHelper
    ypwoa
    msmsgs
    MySpaceIM
    poxq
    these items are not checked:
    aim
    Ati2mdxx
    atiptaxx
    carpserv
    cpqset
    hptasks
    nvojln
    iTunesHelper
    dumprep 0 -k
    medgs1
    navapw32
    opr
    PCCClient
    pccguide
    Pop3trap
    setup
    PSof1
    OneTouch
    qttask
    REGSHAVE
    srmclean
    UsrPrmpt
    jusched
    SAdBlock
    SNDMon
    SynTPEnh
    SynTPLpr
    pokapoka6s
    realsched
    ypwoa
    wintask
    pcfagg
    ybinstall_1
    Adobe Reader Speed Launch
    America Online 8.0 Tray Icon
    drnc
    poxq
    Data Keeper
    Lime Wire on Startup
    PowerRegScheduler
    can anyone tell me what this means? and if there is anything here that may be causing my problem? Thank you if so!
    Compaq Presario 2190US   Windows XP  

    jaimeleighann, that MSCONFIG screen is saying that you've got a Qoologic adware infection, just like i've been saying (in all your other threads where i've tried replying to you).
    try replying to answers to your previous posts rather than spraying new threads all over the show. your current posting technique is obviously not helping you resolve this.

  • SQL novice looking for a little help

    A little SQL help asked for…because my solution works but runs like a pig.
    I have two tables with a link many-many association table between them with two FK's defined on the PK's in the tables either side of the join.
    CREATE TABLE TABLE1
    ID VARCHAR2(20 BYTE) NOT NULL
    , NAME VARCHAR2(20 BYTE)
    , AGE NUMBER
    , ADDR1 VARCHAR2(20 BYTE)
    , CONSTRAINT TABLE1_PK PRIMARY KEY
    ID
    ENABLE
    CREATE TABLE TABLE2
    ID2 VARCHAR2(20 BYTE) NOT NULL
    , TYPE VARCHAR2(20 BYTE)
    , DATE_CREATED DATE
    , CONSTRAINT TABLE2_PK PRIMARY KEY
    ID2
    ENABLE
    CREATE TABLE LINK_TABLE
    ID VARCHAR2(20 BYTE) NOT NULL
    , ID2 VARCHAR2(20 BYTE) NOT NULL
    , CONSTRAINT LINK_TABLE_PK PRIMARY KEY
    ID
    , ID2
    ENABLE
    ALTER TABLE LINK_TABLE
    ADD CONSTRAINT LINK_TABLE1_FK1 FOREIGN KEY
    ID
    REFERENCES TABLE1
    ID
    ENABLE;
    ALTER TABLE LINK_TABLE
    ADD CONSTRAINT LINK_TABLE2_FK2 FOREIGN KEY
    ID2
    REFERENCES TABLE2
    ID2
    ENABLE;
    Populated with the simple data set below that also establishes the many to many links between table1 and table2.
    Insert into TABLE1 (ID,NAME,AGE,ADDR1) values ('a','jake',23,'london');
    Insert into TABLE1 (ID,NAME,AGE,ADDR1) values ('d','jimmy',26,'lamelane');
    Insert into TABLE1 (ID,NAME,AGE,ADDR1) values ('b','jenny',55,'lakeside');
    Insert into TABLE1 (ID,NAME,AGE,ADDR1) values ('c','jemima',21,'lothian');
    Insert into TABLE2 (ID2,TYPE,DATE_CREATED) values ('z','type1',to_date('10-MAR-12','DD-MON-RR'));
    Insert into TABLE2 (ID2,TYPE,DATE_CREATED) values ('x','type1',to_date('09-MAR-12','DD-MON-RR'));
    Insert into TABLE2 (ID2,TYPE,DATE_CREATED) values ('n','type2',to_date('04-MAR-12','DD-MON-RR'));
    Insert into TABLE2 (ID2,TYPE,DATE_CREATED) values ('d','type1',to_date('03-MAR-12','DD-MON-RR'));
    Insert into TABLE2 (ID2,TYPE,DATE_CREATED) values ('e','type1',to_date('03-MAR-13','DD-MON-RR'));
    Insert into TABLE2 (ID2,TYPE,DATE_CREATED) values ('f','type2',to_date('16-MAR-12','DD-MON-RR'));
    Insert into TABLE2 (ID2,TYPE,DATE_CREATED) values ('s','type4',to_date('04-MAR-12','DD-MON-RR'));
    Insert into TABLE2 (ID2,TYPE,DATE_CREATED) values ('w','type3',to_date('05-APR-12','DD-MON-RR'));
    Insert into TABLE2 (ID2,TYPE,DATE_CREATED) values ('h','type1',to_date('02-APR-12','DD-MON-RR'));
    Insert into TABLE2 (ID2,TYPE,DATE_CREATED) values ('v','type2',to_date('23-APR-12','DD-MON-RR'));
    Insert into TABLE2 (ID2,TYPE,DATE_CREATED) values ('k','type3',to_date('30-MAR-12','DD-MON-RR'));
    REM INSERTING into LINK_TABLE
    SET DEFINE OFF;
    Insert into LINK_TABLE (ID,ID2) values ('a','z');
    Insert into LINK_TABLE (ID,ID2) values ('a','x');
    Insert into LINK_TABLE (ID,ID2) values ('a','f');
    Insert into LINK_TABLE (ID,ID2) values ('d','d');
    Insert into LINK_TABLE (ID,ID2) values ('d','e');
    Insert into LINK_TABLE (ID,ID2) values ('b','w');
    Insert into LINK_TABLE (ID,ID2) values ('b','x');
    Insert into LINK_TABLE (ID,ID2) values ('b','v');
    Insert into LINK_TABLE (ID,ID2) values ('a','n');
    Insert into LINK_TABLE (ID,ID2) values ('c','s');
    Insert into LINK_TABLE (ID,ID2) values ('c','k');
    Insert into LINK_TABLE (ID,ID2) values ('a','s');
    Insert into LINK_TABLE (ID,ID2) values ('a','v');
    And thus when queried using the join, gives me this data.
    select t1.*, t2.* from table1 t1, link_table lt, table2 t2
    where lt.id = t1.id
    and t2.id2 = lt.id2;
    ID NAME AGE ADDR1 ID2 TYPE DATE_CREATED
    a jake 23 london f type2 16-MAR-12
    a jake 23 london n type2 04-MAR-12
    a jake 23 london s type4 04-MAR-12
    a jake 23 london v type2 23-APR-12
    a jake 23 london x type1 09-MAR-12
    a jake 23 london z type1 10-MAR-12
    b jenny 55 lakeside v type2 23-APR-12
    b jenny 55 lakeside w type3 05-APR-12
    b jenny 55 lakeside x type1 09-MAR-12
    c jemima 21 lothian k type3 30-MAR-12
    c jemima 21 lothian s type4 04-MAR-12
    d jimmy 26 lamelane d type1 03-MAR-12
    d jimmy 26 lamelane d type1 03-MAR-13
    12 rows selected
    However, what I need is
    for every unique ID in table1, I need the maximum date for in table2 but given that there needs to be a precedence on types in a predefined order, that order being
    type4 trumps type2 which trumps type3 which trumps type1.
    therefore the query I'm looking for will return the type, type4 and it's max date even if other types exist. If no type4's exist for a link from table1.id in table2 then return type2 and it's max date and so forth.
    essentially my query should return
    ID     TYPE     MAX_DATE_CREATED
    a     type4     04-MAR-12
    b     type2     23-APR-12 (since it has no type4 and type2 trumps the other)
    c     type4     04-MAR-12
    d     type1     03-MAR-13 (the highest precedence is type1 and it's highest date is 03-MAR-13)
    Hmmm
    I have achieved this using some odd SQL where I use CASE to score the type against the precedence and then sum the total in an aggregate super query but as I say, it runs like a pig, my real dataset is much bigger than this. Hope there's a nice chap/lady out there who rises to this challenge.
    TIA
    Jenny.

    Hi, Jenny,
    Welcome to the forum!
    Here's one way:
    WITH   got_r_num   AS
         SELECT t1.*
         ,      t2.*
         ,      ROW_NUMBER () OVER ( PARTITION BY  t1.id
                                        ORDER BY         CASE    t2.type
                                              WHEN  'type4'  THEN  1
                                              WHEN  'type2'  THEN  2
                                              WHEN  'type3'  THEN  3
                                              WHEN  'type1'  THEN  4
                                          END
                            ,            t2.date_created     DESC
                          )      AS r_num
         FROM   table1          t1
         ,      link_table      lt
         ,      table2          t2
         WHERE  lt.id      = t1.id
         AND    t2.id2      = lt.id2
    SELECT     *     -- or whatever columns you want
    FROM     got_r_num
    WHERE     r_num     = 1
    ;This is an example of a Top-N Query , where we pick N items (N=1 in this case) from the top of an ordered list (or lists; in this case, we need a separate list for each id.) The analytic ROW_NUMBER function can assign numbers 1, 2, 3, ..., in order, with a separate set of numbers for each id. The tricky part in this problem is getting your trumping order. I used a CASE expresion to map each of the types to a number that reflected the order.
    Thanks for posting the CREATE TABLE and INSERT statements; that's very helpful!
    Would you like to be even more helpful? Post your best attempt at a query. Even if it performs really poorly, it can help illustrate what you need to do, and maybe give ideas about how to do it. It could be that a small change in what you already have is all that's needed.
    The query above will work in Oracle 9.1 or higher. It never hurts to say which version of Oracle you have.

  • Houston based Oilfield company looking for part time help

    i-Tec Well Solutions, a Houston Texas based company, is looking for someone to set up existing pressure transducers and load cells to work with existing Labview Signal Express software.  This should be a short term contract job, which would include:
    Wiring up all equipment for easy and frequent use.
    Installing software  on a dedicated shop computer.
    Programing the software for collecting pressure data and force data.
    Recommendations for purchasing additional equipment.
    Recommendations for purchasing additional equipment to equip existing analog pressure pumps.
    Design and build a stand-a-lone shop test cart for mounting/storing all essential equipment.
    If interested, please contact Dennis @ [email protected]
    i-TEC Well Solutions
    5535 Brystone Drive
    Houston, TX 77041
    web: www.i-tec.no
    email: [email protected]

    Hello Joe:
    Do you need someone on-site? I could offer you remote work with the best pool of designers and DPS experts? We have been using it since the initial publi release in 2011
    Email me if you are interested => [email protected]

  • Looking for suggestion/idea/help WITH T-SQL

    Hi all,
    The scenario I have is a person can have one or more charges on his/her case. 
    One charge could be adjudicated as GUILTY and the other charge
    is DROPPED.  If this is the scenario, I would like to assign GUILTY Adjudication to this case.
    OR
    One charge could be WITHHELD and the other charge is DROPPED. 
    If this is the scenario, I would like to assign WITHHELD to this case.
    Under Adjudication column, I would like to see GUILTY for case number 12345 and WITHHELD for case 98765
    Sample data:
    Case Number                Charge                       Charge
                            Adjudication
    Disposition
    ==========           ======                    ===========         
    ============
    12345                        DUI                            
    GUILTY
    12345                        Driving w/o license       DROPPED
    98765                        DUI                            
    WITHHELD  
    98765                        Driving w/o license       DROPPED
    Below is the query that returned the above sample Charge Disposition.  I am thinking of using CASE expression to determine Adjudication but not sure.
    Thank you for everyone's help!
    declare @Begindate datetime--
    declare @Enddate datetime
    set @begindate = '05/01/2014'
    set @Enddate = '05/31/2014'
    SELECT
    (CASE
    WHEN cc1.ProsecutorFinalAction IN ('L','O','R') AND
    (cc1.ProsecutorFinalDecisionDate >= @BeginDate) AND
    (cc1.ProsecutorFinalDecisionDate < DateAdd(d, 1, @EndDate))
    THEN pfa1.Description
    WHEN (cc1.CourtDecisionDate >= @BeginDate)AND
    (cc1.CourtDecisionDate < DateAdd(d, 1, @EndDate))
    THEN dbo.fnGetLookupDescription(cc1.CourtActionTaken,'CourtActionTaken')
    END)
    FROM tblCase c1 with(nolock)
    INNER JOIN tblCaseCharge cc1 with(nolock)
    ON c1.caseid = cc1.caseid
    LEFT OUTER JOIN tblProsecutorFinalAction pfa1 WITH(NOLOCK)
    ON cc1.ProsecutorFinalAction = pfa1.ProsecutorCode
    WHERE c1.CaseID = @CaseID

    If you want to return just one row for each case, then:
    ;with cte as (SELECT *, ROW_NUMBER() over (PARTITION BY case_number
    ORDER BY case [Charge Disposition] WHEN 'GUILTY' then 1 WHEN 'WITHHELD' ELSE 3 END) AS RN
    FROM CasesInfo)
    SELECT * FROM cte WHERE Rn = 1 -- will select rows with GUILTY status or WITHHELD status
    and not dropped status
    For every expert, there is an equal and opposite expert. - Becker's Law
    My blog
    My TechNet articles

  • New bee looking for applescript help with text edit app

    I have a huge text files (20+) , I want to find a list of words like weather, farmers, ploughing. I want to find these words one at a time, as my text file is 250+ Mb in size.
    I want applescript to count the how many times each word appears in the text.
    Paste that occurrence of word into an spreadsheet file in a row named after text file , and in a column named weather, farmers, ploughing.
    Please help.
    Thanks much.
    CF
    PS so far I can open the text files with applescript, that is about the extent of my ability in programing.
    Message was edited by: coldfusions onco

    For a file of that size, you would need to use some shell utilities to get decent performance. To count words, the following script breaks up the text into words, then counts the number of times the specified word is found (a dictionary file is used as an example, so the match is equivalent to 'contains'):
    <pre style="
    font-family: Monaco, 'Courier New', Courier, monospace;
    font-size: 10px;
    font-weight: normal;
    margin: 0px;
    padding: 5px;
    border: 1px solid #000000;
    width: 720px;
    color: #000000;
    background-color: #DAFFB6;
    overflow: auto;"
    title="this text can be pasted into the Script Editor">
    set theFile to "/usr/share/dict/web2" -- a 2.5MB list of words
    set someWords to {¬
    {theWord:"weather", theCount:0}, ¬
    {theWord:"farmers", theCount:0}, ¬
    {theWord:"ploughing", theCount:0}}
    repeat with anItem in someWords
    set aWord to quoted form of theWord of anItem
    try -- break up into individual words, then search and count
    set theCount of anItem to (do shell script "tr -cs '[:alpha:]' " & quoted form of linefeed & " < " & theFile & " | grep -ic " & aWord) as integer
    end try
    end repeat
    someWords
    </pre>
    Is this related to your Automator post?

  • Looking for trouble shooting help -Connections being dropped from app.

    I need a little help in hunting down the source of a problem. We have Oracle 10gR2 (10.2.0.1) running on Solaris 10. The web application is based on WEBLOGIC on another server also running Solaris 10 with a new firewall in between. When started, the application will get 176 connections to the database. Over time, still working on how long, the connections get dropped. The profile they app is connecting to is for unlimited connections and connection time. I do not have an setting to disconnect after idle for x minutes. Even the listener spawned processes die. Other applications from other machines also have problems if idle for a period of time, SQLDeveloper, SQLPlus, TOAD, SQLNAVIGATOR.
    We are trying to hunt down the source of the problem but are at a loss. I have checked and verified that the oracle instance does not have a parameter set to kill idle connections for the users the apps are connecting as. The sys admin says there are no unix parameters he knows about on either solaris box that is killing connections and that the firewall settings should not be killing them.
    A duplicate environment running all the same versions of software work fine, the only differences between the two is the box and operating system, Sun V120 w/Solaris 8 vs. Sun V40Z w/Solaris 10.
    This system goes live in two weeks so we are trying to get this figured out soon. Any hints on where to look or has any one else had similar problems?
    thanks

    listener.ora on Oracle server machine:
    # listener.ora Network Configuration File: /u01/app/oracle/product/10.2/db_1/network/admin/listener.ora
    # Generated by Oracle configuration tools.
    SID_LIST_LISTENER =
    (SID_LIST =
    (SID_DESC =
    (SID_NAME = PLSExtProc)
    (ORACLE_HOME = /u01/app/oracle/product/10.2/db_1)
    (PROGRAM = extproc)
    LISTENER =
    (DESCRIPTION_LIST =
    (DESCRIPTION =
    (ADDRESS = (PROTOCOL = TCP)(HOST = ng-db01)(PORT = 1521))
    (ADDRESS = (PROTOCOL = IPC)(KEY = EXTPROC0))
    Weblogic machine is not useing a client so has no sqlnet.ora file on it. Others having problem:
    # sqlnet.ora Network Configuration File: C:\oracle\product\10.2.0\db_1\network\admin\sqlnet.ora
    # Generated by Oracle configuration tools.
    # This file is actually generated by netca. But if customers choose to
    # install "Software Only", this file wont exist and without the native
    # authentication, they will not be able to connect to the database on NT.
    SQLNET.AUTHENTICATION_SERVICES= (NTS)
    NAMES.DIRECTORY_PATH= (TNSNAMES, EZCONNECT)

  • QUESTION FOR Applescript / Automator killers

    Hi guys,
    Can someone tell me a way to select folder(s) by the type of files of their content ?
    and then pass them as variable to proceed a search only in those folders ?
    For example :  get every folders containing .wav files ---> = Variable
    Search files named "xxx.app" in all the folders of Variable...
    Automator or applescript are welcome .
    Thanx in advance.
    Best from paris (sorry for my english)
    Nico

    okay this is how i want it to work but it didn't ...
    Where am i wrong ??
    i feel im getting closer thanx to you
    on run {input, parameters}
              set filesFound to do shell script "
    OLDIFS=$IFS
    IFS=$'\\n'
    a=($(find ~/Documents -iname '*.wav' -execdir pwd \\; | sort -u))
    for i in \"${a[@]}\"
    do
              find \"$i\" -iname '*.app'
    done
    IFS=$OLDIFS
              set theResult to quoted form of filesFound
              repeat with i from 1 to the count of theResult
                        set this_file to (item i of theResult)
                        tell application "Finder" to open this_file
                        tell application "System Events"
                                  if exists (process "my process") then
                                            repeat until not (exists (process "my process"))
                                                      delay 1
                                            end repeat
                                  end if
                        end tell
              end repeat
    end run
    Message was edited by: Nico44044

  • Looking for AppleScript site

    Hello all,
    I've tried a couple Google searches to find some AppleScripts, but haven't had much luck. I thought it would be a pretty straightforward task that I'm trying to find a solution for: Open a browser window with the selected text as the URL.
    I've yet to find anything helpful, and don't want to hack a solution over a couple days if I can find a ready-made one.
    Does anyone know where such a script might be found?
    Pointers appreciated,
    Markie

    Hello Markie,
    I am not an expert at scripting enough to know how easy/possible it is to grab the "selected text", but there are built in scripts in the /Library/Scripts/URLs/ which are made to open a browser window with a URL.
    If this functionality is all you need, you can use the "Open URL" in every application's Services menu which will do exactly what you are asking.
    By the way, Apple's AppleScript Resources page shows several references and third-party websites. Perhaps going there will give you the answers you want.
    Thane Heninger

  • Applescript/Automator help entering text

    Hi. I have a terminal script: defaults write com.apple.dock persistent-apps -array-add '{tile-data={}; tile-type="spacer-tile";}'
    (Enter)
    killall Dock
    This is to create a blank space in the dock. I would like to create an Automator workflow or Applescript to run this without having to remember the script or look it up. But the problem is, Automator cant enter text and if i try to enter it with Applescript, the quotation marks mess it up. What should i do other than copy and paste the script to a text document?

    Try using:
    do shell script "defaults write com.apple.dock persistent-apps -array-add '{tile-data={}; tile-type=\"spacer-tile\";}'"
    do shell script "killall Dock"
    (56374)

  • Applescript/Automator help needed.

    I attempting to create an Automator Folder Action that will do two things.  First, when an image is added to the “Upload” folder, a new mail message will be created.  Second, it will run an applescript that allows me to select from a list of album names.  This value will go into the title field of the new email.  Here’s what the Automator Folder Action looks like so far:
    1.  Automator Action:  Get Selected Finder Items - this will get the item just added to the “Upload” folder. 
    2.  Automator Action:  Set Value of Variable - Since I don’t see a way to save the image itself as a variable, I store the image name here and call it “Image Name.”
    3.  Automator Action:  Run AppleScript - When run, this will bring up a list of album names.  I click on the one I want and click OK.
    4.  Automator Action:  Set Value of Variable - set the value that holds the album name from step 3.
    5.  Automator Action:  Get Value of Variable - gets the value stored in step 2.
    6.  Automator Action:  New Mail Message - Fills out the To: field, populates the Subject: field with the Album name.  But here’s where it fails.  It populates the message field with the name of the path where the image is located, not with the image. 
    Note the first and last actions are disabled.
    It seems this would work if I could pass the image itself as a variable, but I see no way to do that.  I apparently can only pass the name of the image.
    Any ideas how I can fix this? Thanks!

    There is an error in the AppleScript.  It should read...
    on run {input, parameters}
              set the_list to {"Album 1", "Album 2", "Album 3"}
    choose from list the_list
              set album_name to result
              return album_name
    end run
    But the problem is still there.

  • Young CC user looking for a little help

    Hi. I am a student user of many of Adobe's products, and I recently began using the Creative Cloud service, which is currently £15 a month here in Britain but will be hiked to £22.50 a month next year. Since I don't really work much yet (I do a few design/film jobs here and there), the whole thing feels a bit expensive. I do graphic design, photography, film-making and a little bit of web design, which is obviously a lot! Moreover, I am really frustrated with the recent hacks, and as a result I have been consolidating my future with the software. Since the web side of Adobe is neither too unique nor essential, I do not feel so bad losing them. However, programs like Photoshop and After Effects are really irreplaceable, so I am considering purchasing the Production Premium CS6 package for Mac on a student discount, which is around £470 on the Adobe website as an alternative to continuing next year with CC. I own a Mac and a Windows-based laptop, and obviously CC suits this better. All in all, this is a bit of a dilemma, and I'm struggling to come up with a resolution. Does anyone know somewhere I can get the Production Premium cheaper, will I still be able to buy CS6 in June when my year's worth of promotional CC runs out, could I face compatibility issues and, of course, does anyone have any suggestions? All help would be greatly appreciated- thank you!

    To all,
    Here are links to the
    Oracle® Healthcare Transaction Base
    Implementation Guide - 2003
    http://download.oracle.com/docs/cd/B12190_11/current/acrobat/ctb11ig.pdf
    Oracle® Healthcare Transaction Base
    Implementation Guide - 2004
    http://download.oracle.com/docs/cd/B15436_01/current/acrobat/ctb115ig.pdf

  • Mac App Store works fine for buying/installing new software, but times out when looking for updates. Help?

    I just got a (lightly) used Mac Mini as a second computer (2010 model). Logged into Mac App Store with my Apple ID and tried to check for updates...received "An error has occurred - The request timed out" message. Was able to go to the main App Store page and download/install OS X Mountain Lion...then tried again and still got the time-out error. Any ideas of what is happening and how to get Software Update to work?

    Apps already installed by the former owner of the Mini are associated with that persons Apple iD. You won't be able to update any of those apps using your Apple iD. Those apps will have to be purchased from your Apple ID only.
    Apparently the previous owner had not upgraded to Mountain Lion as yet, or you would not have been able to download and install that OS X.

Maybe you are looking for