LV 7.1 VI with match pattern fails in LV8

I am seeing something weird with LabVIEW 8. Attached
is a VI that was developed in 7.1 and has been working for the past year and a
half. When I upgraded to 8.0 it started exhibiting weird behavior.
The very first time it is executed it works fine. All subsequent
executions fail. The problem is that the match pattern VI only matches
the search string the first time it is executed, after that the offset past
match is always -1. Why?
If I start from scratch in LabVIEW 8 and recreate this VI it seems to work
fine.
Joshua
Attachments:
Read_RCG_File.zip ‏21 KB

Thanks for looking at this for me. Now that you have pointed out
that the Request Deallocation was causing the problem I need to correct
what said in my original post. If I recreate the VI from scratch
in LabVIEW 8 there is still a problem. The first time I recreated
it I neglected to add the Request Deallocation.
Thanks again for your help.
Joshua
PS This VI is simplier and duplicates the problem.
Attachments:
MatchPatternDeallocateBug.vi ‏9 KB

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"Matt361" <[email protected]> wrote in message news:[email protected]..
Hi,
 
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Case-Insensitive.........: Not Applicable
Data Type      *..............: String
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Matching Only............: Not Applicable
Case-Insensitive........: Not Applicable
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1 | True/False | Active/Disabled|
===After save on step 4 I go to Resource Manager-->Manage Scheduled task--> RUN NOW and the log sende me the same ERROR posted up.=============
I hope you can help me, Thanks.....
Edited by: user11296330 on Oct 18, 2009 8:55 PM
Edited by: user11296330 on Oct 18, 2009 10:10 PM
Edited by: user11296330 on Oct 19, 2009 3:33 PM
Edited by: user11296330 on Oct 20, 2009 1:52 AM
Edited by: user11296330 on Oct 21, 2009 9:08 AM
Edited by: user11296330 on Nov 8, 2009 10:16 PM
Edited by: user11296330 on Nov 8, 2009 10:20 PM

Hi amigo I solve my problem with the next:
OK, all above is good but in the manual they mistake something.... one step.
(All succesful with --> ========================*Step 3 (try 2)*==============)
1.- Ok, if you got every thing like above the last thing you need is follow the next link:
http://www.oracle.com/technology/obe/fusion_middleware/im1014/oim/obe12_using_gtc_for_reconciliation/using_the_gtc.htm
Go to: "Modifying the GTC" ( just do this part)
Restart the OIM and Enjoy it.
Good day Amigo.
And don't forget on step three:
Click the Edit icon of the User ID field of the OIM - User data set.
b. On the Step 1: Provide Field Information page:
- From the Mapping Action list, select Create Mapping Without Transformation.
- Select Matching Only.
- Click Continue.
Mapping Information page, select Reconciliation
Staging from the Dataset list, select EMPLOYEE_ID (your ID Field) from the Field Name
list, and then click Continue.
If something go bad, tell me the steps like I did with the log.... see ya
Edited by: user11296330 on Nov 8, 2009 9:57 PM
Edited by: user11296330 on Nov 8, 2009 10:21 PM

Wrong result in match pattern

Hi, I want to extract the space (sometimes, !#" etc) from "@020 12345' using match pattern function.
When I used [\s!#"] as a regular expression, the result "20".
Why my expression is not worked and Can you propose more suitable expression?
labmaster
*)Enclosed is the VI example in LV2009
Solved!
Go to Solution.
Attachments:
yahoo.vi ‏7 KB

labmaster wrote:
Hi, I want to extract the space (sometimes, !#" etc) from "@020 12345' using match pattern function.
You should also describe what you mean by "extract". If you simply need a space, you can use a space diagram constant. No need to extract it. Do you want the resulting string without the space, for example?
I am sure one of the regex gurus here will jump right on this one...
LabVIEW Champion . Do more with less code and in less time .

Lazy (not greedy) match pattern

Hello
I want to use match pattern to return every substring enclosed between 7E characters in a hexadecimal string.
The string looks like this : ....7E7E ....7E7E....7E7E...
I used the following regular expressions: 7E.*7E, 7E .+ 7E, 7E .+?7E but they return nothing or they return the maximum match possible (greedy match). (The regular expressions actually not like this because 7E is in hexadecimal representation and the other characters are not, the expressions would look like this: ~.*~, ~.+~, ~.+?~)
Is there a way to perform non-greedy matches in LabView?
Thank you for your help

Hi forsaken,
what about this little sub-vi:
'data string' is your data value (without surrounding 0x7E), 'remaining string' is therest of the string (with 0x7E).
Message Edited by GerdW on 06-05-2007 04:44 PM
Best regards,
GerdW
CLAD, using 2009SP1 + LV2011SP1 + LV2014SP1 on WinXP+Win7+cRIO
Kudos are welcome
Attachments:
match.png ‏2 KB

Match Regular Expression does not match what Match Pattern does

I have read through a lot of posts about how Match Pattern does not match what Match Regular Expression will due to not processing some characters.
However, I found a problem with the other way. A simple Reg-Ex that works in Match Pattern but not Match Regular Expression.
What I have here is just an example. I want to use Match Regular Expression so I can specify some sub-matches.
The reg-ex is for: one or more non-numeric characters, a space, one or more numeric characters. At the start of the string.
How can I get this working in Match Regular Expression? I am working in LabVIEW 2010f2 32 bit. Here is the code snippet and the results:
Rob
Solved!
Go to Solution.

Robert Cole wrote:
I think I prefer the ~ for negation since ^ is also used for beginning of the string. But we work with what we have.
Let me offer you a tip and perhaps defend the honor of the regex a little bit. One of my favorite features of regexes is the ability to specify character classes (and their negation). One of the reasons I have to think about the ~ versus ^ is that I rarely use ^ in a regex alternative.
Some examples:
[0-9] = \d (digit)
[^0-9] = \D (not a digit)
The equivalent regex for your case is: \D+ \d+

Split a string using Match Pattern function

I am trying to split a response string from a climate chamber into different parts. The string goes something like this: 0030.0\s0034.6\s0080.0\s0083.4. I am using the match pattern function to split the string using \s as the search string. But it is not splitting the string as required. If I use only \ , its working fine. Can anyone please suggest why \s is not being recognised as a part of the input string?
Subhro.
Solved!
Go to Solution.

Is the string you show in normal display mode or in \ codes display mode?
Anyway, if you need to match a '\' character you'll have to mask it using \, so the match string would be '\\s' to match '\s'.
Alternatively you could use spreadsheet string to array with the correct delimiter. For the data you show this would work perfectly.

Regular Expression for Match Pattern (string) Function

I need to find a variable length string enclosed by brackets and
within a string. Can't seem to get the regular expression right for
the Match Pattern function. I'm able to get the job done using the
Token function, but it's not as slick or tight as I'd like. Does
anybody out there have the expression for this?

Jean-Pierre Drolet wrote in message news:<[email protected]>...
> The regular expression is "\[[~\]]*\]" which means:
> look for a bracket "\[" (\ is the escape char)
> followed by a string not containing a closing bracket "[~\]]*"
> followed by a closing bracket "\]". The match string include the
> brackets
>
> You can also read "Scan from String" with the following format:
> "%[^\[]\[%[^\[\]]" and read the 2nd output. The brackets are removed
> from the scanned string.
Thanks, Jean_Pierre
I did some more experimenting after posting and found that \[.*\] also
works with the match pattern function. Thanks for your input.
sm

LV 7.1 VI with match pattern fails in LV8

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