Making sure black is black

My print shop requests that I check my document to make sure that anything black on the pages is black, not CMYK or RGB.
I see the Black tile on the Color panel, but don't know how to see that when the black is indeed based on CMYK or RGB. (As I recall, I changed a couple black text boxes to CMYK, thinking that was a good thing. Now I know it's not.)
Where do I adjust the color to make sure the text black is black? And although this forum doesn't address Illustrator, the same issue may be there as well, so I hope this will help me fix anything over there. (Ugh, and a few graphics are in Paint! Bigger question than I thought!)
Thanks!

After making sure your InDesign document color space is CMYK, just open your Separations Preview.
In the Separations Preview there should be plates for Cyan, Magenta, Yellow & Black, (also Spot Colors if any were used)
Select "View Separations" and turn OFF the Black plate, and anything that is Black only should disappear. If it doesn't, then the object has some values in the other plates - C, M, Y
While you have View Separations active you can move your cursor over any element in your document and the color values of the color will show up in the Separations Preview panel.
Since CS4 Illustrator has finally gotten a Separations Preview, but it doesn't have as many features as the one in InDesign.
Acrobat Pro has an Output Preview that is even more useful.

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Welcome to the Support Communities!
Have you set up Photo Stream on your iPhone 5C? I can't tell what computer you have from your post, so I'll include all of the Photo Stream information for you:
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http://support.apple.com/kb/PH2596
iCloud: Set up My Photo Stream
http://support.apple.com/kb/PH13693
iCloud: My Photo Stream troubleshooting
http://support.apple.com/kb/TS3989http://support.apple.com/kb/TS3989
Cheers,
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Making sure I understand release/retain correctly

Let's say I do the following (foo starts out as some object):
[foo release];
// STUFF with foo
[foo retain];
As long as I'm not re-assigning foo, at the end of this I'll still have the same foo, right? I'm not risking losing foo during the //STUFF am I?
I guess I'm making sure that my understanding of release is correct. If I release foo, it doesn't actually go away until all handles on it are gone. In other words, foo would have to be assigned to some other object in the //STUFF, or foo would have to go out of scope in the //STUFF (and presumably have a new foo created) in order for the actual original foo object to be deleted, right?
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foo = [A alloc];
[foo inita];
break;
case 2:
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[foo initb];
break;
case 3:
[foo setupc];
break;
case 4:
f = [D alloc];
[foo initd];
break;
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Message was edited by: Brian Postow

Brian Postow wrote:
Let's say I do the following (foo starts out as some object):
[foo release];
// STUFF with foo
[foo retain];
As long as I'm not re-assigning foo, at the end of this I'll still have the same foo, right? I'm not risking losing foo during the //STUFF am I?
There is no way to tell. If the retain count of foo was one just before the release, then all bets are off.
I guess I'm making sure that my understanding of release is correct. If I release foo, it doesn't actually go away until all handles on it are gone.
I'm not sure I understand your understanding. I wouldn't use a term like "handle" since that has a specific meaning that is different than "retain count". If you replace "handle" with "retain count", then you are correct.
In other words, foo would have to be assigned to some other object in the //STUFF, or foo would have to go out of scope in the //STUFF (and presumably have a new foo created) in order for the actual original foo object to be deleted, right?
I'm not sure what you are saying. Objective-C is not C++. A variable going out of scope means nothing in Objective-C. It isn't that complex. It keeps track of the number of times "retain" is called on the object (including the original, implicit "retain"). When the number of releases matches the number of retains, then the object is deallocated.
Ok, edit for motivation, because that's kind of a dumb thing to want to do, right?
The reason I want to do this is that lets say I have the following switch statement:
switch (test)
case 1:
foo = [A alloc];
[foo inita];
break;
case 2:
foo = [B alloc];
[foo initb];
break;
case 3:
[foo setupc];
break;
case 4:
f = [D alloc];
[foo initd];
break;
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Making all blacks rich black in AI?

Hi there, this is an Illustrator image and you can see what is rich black and what isn't... I did go through all files and just select all and adjust the black to rich black, but obviously that didn't work (thankfully the place that I sent it to for production was able to change it all to rich black). Anyway... How can I make sure everything is rich black? Can I do a universal change? Or do I have to select every path, shape, etc.? Thanks for the help.
-Kristie

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Click ok.
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Making sure black is black

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