Material entries for cenvattable and cenvattable goods

Hi SAP GURUS,
I am using one material for different fgs. In some cases cenvat credit is available. In other cases there is no cenvat credit available.
How the accounting entries will flow in both cases.
Thanks
Cheers

Dear,
Entries at the time of MIGO-
Stock Account - Dr
GR/IR Clearing A/c - Cr
At the time of J1IEX-
CENVAT Input BED - Dr
CENVAT Input ECS - Dr
CENVAT Input SECess - Dr
CENVAT Clearing - Cr
At the time of MIRO-
Vendor Account - Cr
GR/IR Clearing A/c - Dr
CENVAT Clearing - Dr
When there is no CENVAT for the material then the entry will be..
At the time of MIGO-
Stock Account - Dr
GR/IR Clearing A/c - Cr
At the time of MIRO-
Vendor Account - Cr
GR/IR Clearing A/c - Dr

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But even though the total length of the stock is 30000mm where can i maintain the breakage.i.e. for example say,
1000mm - 10 Nos. 2000mm - 5 Nos. 2500mm - 4 Nos.
Dear
ANS:
First create different material code specific to length so identity of material at store will be their.(with specification at purchasing text tab)
Now as ur sure with ordering unit keep as kg. (this is at info record level)
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So now about issue part keep conversion factor as u require and make some standard according ur client .
some of our friends are saying that we can map this via batch. But even batch is not possible. There is a reason. Say if length is the batch number and basic unit of measure is Nos, then how can you give the conversion between Nos & Kgs in additional data. For example how can i say 1000 kgs = 1 nos or 2 nos. This will be ridiculous then. I can give every dia available into different material codes. Thats not a problem. But how to receive rods in different length. I need the length & numbers combination. Also while issuing the materal after cutting numbers should reduce accordingly.
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ANS:
Dear for this make material master as name with ur spacification and UOM as kg after cutting or processing according to Wight u can make issue note in the system.
Name as plate x*y sqr mm
So ordering as kg
Issue as kg

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import java.util.*;
class SolveDomain {
     int newton_iter = 0, m = 0, work_count = 0;
     double t = 0, dx, dy, dt, start_t=0;
     double[][] v;
Details obDetails = new Details();
     public double[][] solveDomainMethod(Double vAxn, Double vAyn, Double vBxn, Double vByn, Integer nxn, Integer nyn, double dt, Double error1n, Double error2n, double end_tn, int stepsn, Integer kcn, Double u_n[][], Double v_n[][], Double bc1, Double bc2, Double bc3, Double bc4, double u[][]) {
     double dx2, dy2, err = 1000000;
     v = new double[nxn+1][nyn+1];
     DoublevAxn, Double vAyn, Double vBxn, Double vByn, Integer nxn, Integer nyn, double dt, Double error1n, Double error2n, double end_tn, int stepsn, Integer kcn, double u_n[][], double v_n[][], Double bc1, Double bc2, Double bc3, Double bc4;
double k[][] = new double [nxn+1][nyn+1]; double kp[][] = new double [nxn+1][nyn+1];
double kpp[][] = new double [nxn+1][nyn+1]; double dudx[][] = new double [nxn+1][nyn+1];
double dudy[][] = new double [nxn+1][nyn+1]; double d2udx2[][] = new double [nxn+1][nyn+1];
double d2udy2[][] = new double [nxn+1][nyn+1]; double dudt[][] = new double [nxn+1][nyn+1];
double a[][] = new double [nxn+1][nyn+1]; double b[][] = new double [nxn+1][nyn+1];
double c[][] = new double [nxn+1][nyn+1]; double d[][] = new double [nxn+1][nyn+1];
double F[][] = new double [nxn+1][nyn+1]; double A[][] = new double [nxn+1][nyn+1];
double B[][] = new double [nxn+1][nyn+1]; double C[][] = new double [nxn+1][nyn+1];
double D[][] = new double [nxn+1][nyn+1]; double E[][] = new double [nxn+1][nyn+1];
double s[][] = new double[nxn+1][nyn+1];
          KDerivatives1 obK1 = new KDerivatives1();
          KDerivatives2 obK2 = new KDerivatives2();
UDerivatives obU = new UDerivatives();
          CalcPdeCoefficients obPde = new CalcPdeCoefficients();
          CalcFdCoefficients obFd = new CalcFdCoefficients();
          Gs obGs = new Gs();
dx = obDetails.seg(vBxn, vAxn, nxn);
dy = obDetails.seg(vByn, vAyn, nyn);
dx2 = dx*dx;
dy2 = dy*dy;
if (bc1 != -999999999) obDetails.initialiceBCDomainL(dx, dy, vAxn, vAyn, bc1, u);
if (bc2 != -999999999) obDetails.initialiceBCDomainU(dx, dy, vAxn, vAyn, bc2, u);
if (bc3 != -999999999) obDetails.initialiceBCDomainR(dx, dy, vAxn, vAyn, bc3, u);
if (bc4 != -999999999) obDetails.initialiceBCDomainD(dx, dy, vAxn, vAyn, bc4, u);
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++ newton_iter;
if (kcn == 1) {
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               obU.calc_dudx(u, dx, dudx);
          obU.calc_dudy(u, dy, dudy);
               obU.calc_d2udx2(u, dx2, d2udx2);
               obU.calc_d2udy2(u, dy2, d2udy2);
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          obPde.calcPdeCoefficientsa(k, a);
          obPde.calcPdeCoefficientsb(kp, dudx, b);
          obPde.calcPdeCoefficientsc(kp, dudy, c);
          obPde.calcPdeCoefficientsd(kp, kpp, dudx, dudy, d2udx2, d2udy2, d);
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          obFd.calcFdCoefficientsA(a, b, dx, dx2, A);
          obFd.calcFdCoefficientsB(a, b, dx, dx2, B);
          obFd.calcFdCoefficientsC(a, c, dy, dy2, C);
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          obFd.calcFdCoefficientsE(a, d, dx2, dy2, dt, E);
          obGs.gsMethod(v_n, A, B, C, D, E, F, dt, error2n, v);
          m = m + obGs.iter;
          for (int i=1; i < u.length - 1;i++ ) {
               for (int j=1; j < u[0].length - 1 ;j++ ) {
     u[i][j] = u[i][j] + v[i][j];
err = 0;
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               for (int j=0; j < u[0].length ;j++ ) {
               err = err + Math.pow(v[i][j],2);
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while (err > error1n);
     return u;
public double[][] rectangleDomainF (Vector vAxvector, Vector vAyvector, Vector vBxvector, Vector vByvector, Vector nxvector, Vector nyvector, Vector error1vector, Vector error2vector, double end_t, int steps, Vector kcvector, double numberdomains, Vector bc1vector, Vector bc2vector, Vector bc3vector, Vector bc4vector) {
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++work_count;
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while (t < end_t);
return u;

The only way to, for instance, multiply a Double object by another Double object is to convert them back to primitives, multiply them, and create a new Double instance:
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Hi ,
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