Merge Adjacent Range Partitions

I have found documentation about how the exchange partition command does not physically move any data, only updates the data dictionary which makes it almost instantaneous. Seems to me that merging adjacent range partitions might also have this behavior. Can anyone confirm this?
Thanks in advance for your reply

Hi! I've used the instructions before but can't remember the exact details. I think what it is talking about is the partition you are changing (ie the one being deleted) will be the one losing data and the space will be returned to the original volume from which it was created. I know this is the way it works using Diskstudio which I have used several times. But be sure you are confident with what you read and decide to do. Tom

Similar Messages

  • Modifing range partition key values

    I have table in oracle 10g with range partiotion , now I want to change or
    modify the partition key values . How i can do that

    Depending on the level of change???
    If your just rejiging boundaries in the range then you can merge, re split partitions? Without specific information on the change its hard to guess what is in your mind.
    I have used this method in the past when some of the partitions remain empty and I wish to rebalance the data skew to even up the distribution of a key? Is this what you want to do?
    Or do you intend adding columns to a key without recreating the object? I don't know any way to change this without creating a new object; sorry…. If you have the space create table as select with new range specification would do. Otherwise create csv and sqlload into new defined object after drop and recreate. Hope this helps.
    Kind regards

  • Create range partition

    hi ,
    Oracle 10.2.0.1.0
    I'm getting error while creating a range partition to already existing table (method employed : partition swap method ) .
    PF screen shot of error
    SQL> ed
    Wrote file afiedt.buf
      1  create table employee_details_temp partition by range (eid) (
      2  partition eid_1r values less than (1000)
      3  partition eid_2r values less than (20000)
      4  partition eid_3r values less than (40000)
      5  partition eid_3r values less than (maxvalue)
      6* )
    SQL> /
    partition eid_2r values less than (20000)
    ERROR at line 3:
    ORA-14020: this physical attribute may not be specified for a table partitionalso ,
    SQL> ed
    Wrote file afiedt.buf
      1  create table employee_details_temp partition by range (eid) (
      2  partition eid_1r values less than (1000)
      3  partition eid_2r values less than (20000)
      4  partition eid_3r values less than (40000)
      5  partition eid_3r values less than (maxvalue)
      6  ) as select * from employee_details where 1=1;
      7* /
    SQL> /
    partition eid_2r values less than (20000)
    ERROR at line 3:
    ORA-14020: this physical attribute may not be specified for a table partition please help .

    answered .

  • How to find out the min & max partition_id in a range partition?

    Hi we have a table set up by range partition
    In the table creation script. It goes something like:
    PARTITION PARTD_CUST_3_1_NEW VALUES LESS THAN ('39500')
    so how we can find out this number '39500' from some of the data_dictionary view?
    What we want to do is to set up parallel processing (do-it-yourself) based on partition.
    So the number of parallel process will be based on this ID-range.
    I can find out how many partitions are there by using something like this:
    SELECT COUNT(*)
    FROM all_tab_partitions WHERE table_owner='OWNER_NAME' AND table_name='TABLE_NAME'
    We have 5 partitions now but the table structure can change in the near future even this table has moer than 130Million rows
    I do not want to hardcode this "39500" just in case the table structure changes (partition structure changes)
    Any idea ??

    vxwo0owxv wrote:
    Hi we have a table set up by range partition
    In the table creation script. It goes something like:
    PARTITION PARTD_CUST_3_1_NEW VALUES LESS THAN ('39500')
    so how we can find out this number '39500' from some of the data_dictionary view?
    What we want to do is to set up parallel processing (do-it-yourself) based on partition.
    So the number of parallel process will be based on this ID-range.
    I can find out how many partitions are there by using something like this:
    SELECT COUNT(*)
    FROM all_tab_partitions WHERE table_owner='OWNER_NAME' AND table_name='TABLE_NAME'
    We have 5 partitions now but the table structure can change in the near future even this table has moer than 130Million rows
    I do not want to hardcode this "39500" just in case the table structure changes (partition structure changes)
    Any idea ??query DBA_TAB_PARTITIONS.HIGH_VALUE

  • Non-Partitioned Global Index on Range-Partitioned Table.

    Hi All,
    Is it possible to create Non-Partitioned Global Index on Range-Partitioned Table?
    We have 4 indexes on CS_BILLING range-partitioned table, in which one is CBS_CLIENT_CODE(*local partitioned index*) and others are unknown types of index to me??
    Means other 3 indexes are what type indexes ...either non-partitioned global index OR non-partitioned normal index??
    Also if we create index as :(create index i_name on t_name(c_name)) By default it will create Global index. Please correct me......
    Please help me in identifying other 3 indexes types by referring below ouputs!!!
    select INDEX_NAME,TABLE_NAME,PARTITIONING_TYPE,LOCALITY from dba_part_indexes where TABLE_NAME='CS_BILLING';
    INDEX_NAME TABLE_NAME PARTITI LOCALI
    CSB_CLIENT_CODE CS_BILLING RANGE LOCAL
    select index_name,index_type,table_name,table_type,PARTITIONED from dba_indexes where table_name='CS_BILLING';
    INDEX_NAME INDEX_TYPE TABLE_NAME TABLE_TYPE PAR
    CSB_CREATE_DATE NORMAL CS_BILLING TABLE NO
    CSB_SUBMIT_ORDER NORMAL CS_BILLING TABLE NO
    CSB_CLIENT_CODE NORMAL CS_BILLING TABLE YES
    CSB_ORDER_NBR NORMAL CS_BILLING TABLE NO
    select INDEX_OWNER,INDEX_NAME,TABLE_NAME,COLUMN_NAME from dba_ind_columns where TABLE_NAME='CS_BILLING';
    INDEX_OWNER INDEX_NAME TABLE_NAME COLUMN_NAME
    RPADMIN CSB_CREATE_DATE CS_BILLING CREATE_DATE
    RPADMIN CSB_SUBMIT_ORDER CS_BILLING SUBMIT_TO_INVOICE
    RPADMIN CSB_SUBMIT_ORDER CS_BILLING ORDER_NBR
    RPADMIN CSB_CLIENT_CODE CS_BILLING CLIENT_CODE
    RPADMIN CSB_ORDER_NBR CS_BILLING ORDER_NBR
    select dip.index_name, dpi.locality, dip.partition_name, dip.status
    from dba_part_indexes dpi, dba_ind_partitions dip
    where dpi.table_name ='CS_BILLING'
    and dpi.index_name = dip.index_name;
    INDEX_NAME LOCALI PARTITION_NAME STATUS
    CSB_CLIENT_CODE LOCAL CSB_2006_4Q USABLE
    CSB_CLIENT_CODE LOCAL CSB_2006_3Q USABLE
    CSB_CLIENT_CODE LOCAL CSB_2007_1Q USABLE
    CSB_CLIENT_CODE LOCAL CSB_2007_2Q USABLE
    CSB_CLIENT_CODE LOCAL CSB_2007_3Q USABLE
    CSB_CLIENT_CODE LOCAL CSB_2007_4Q USABLE
    CSB_CLIENT_CODE LOCAL CSB_2008_1Q USABLE
    CSB_CLIENT_CODE LOCAL CSB_2008_2Q USABLE
    CSB_CLIENT_CODE LOCAL CSB_2008_3Q USABLE
    CSB_CLIENT_CODE LOCAL CSB_2008_4Q USABLE
    CSB_CLIENT_CODE LOCAL CSB_2009_1Q USABLE
    CSB_CLIENT_CODE LOCAL CSB_2009_2Q USABLE
    CSB_CLIENT_CODE LOCAL CSB_2009_3Q USABLE
    CSB_CLIENT_CODE LOCAL CSB_2009_4Q USABLE
    select * from dba_part_indexes
    where table_name ='CS_BILLING'
    and locality = 'GLOBAL';
    no rows selected
    -Yasser
    Edited by: YasserRACDBA on Mar 5, 2009 11:45 PM

    Yaseer,
    Is it possible to create Non-Partitioned and Global Index on Range-Partitioned Table?
    Yes
    We have 4 indexes on CS_BILLING range-partitioned table, in which one is CBS_CLIENT_CODE(*local partitioned index*) and others are unknown types of index to me??
    Means other 3 indexes are what type indexes ...either non-partitioned global index OR non-partitioned normal index??
    You got local index and 3 non-partitioned "NORMAL" b-tree tyep indexes
    Also if we create index as :(create index i_name on t_name(c_name)) By default it will create Global index. Please correct me......
    Above staement will create non-partitioned index
    Here is an example of creating global partitioned indexes
    CREATE INDEX month_ix ON sales(sales_month)
       GLOBAL PARTITION BY RANGE(sales_month)
          (PARTITION pm1_ix VALUES LESS THAN (2)
           PARTITION pm2_ix VALUES LESS THAN (3)
           PARTITION pm3_ix VALUES LESS THAN (4)
            PARTITION pm12_ix VALUES LESS THAN (MAXVALUE));Regards

  • NULL partition key in RANGE partition

    All,
    This is regarding partitioning a table using RANGE partition method. But the partition key contains null. How do I handle this situation? This is because there is no DEFAULT partition in RANGE partition though its present in LIST partition. Will rows with NULL partition key fall in MAXVALUE partition? Seeking your guidence.
    Thanks,
    ...

    NULLS would fit into the MAXVAL partition yes.
    http://download.oracle.com/docs/cd/B19306_01/server.102/b14220/partconc.htm#sthref2590
    Thanks
    Paul

  • How to Implement 30 days Range Partitioning with Date column. Not Interval

    Hi,
    I am using the db:
    Oracle Database 11g Enterprise Edition Release 11.2.0.2.0 - 64bit
    Current table structure is:
    CREATE TABLE A
    a NUMBER,
    CreationDate DATE
    PARTITION BY RANGE (CreationDate)
    INTERVAL ( NUMTODSINTERVAL (30, 'DAY') )
    (PARTITION P_FIRST
    VALUES LESS THAN (TIMESTAMP ' 2001-01-01 00:00:00'))
    How can I define virtual column based partitioning with RANGE partitioning without using INTERVAL partitioning.
    And that is with Intervals of 30 days.
    For monthly I am trying as
    CREATE TABLE A
    a NUMBER,
    CreationDate DATE,
    monthly_interval date as (to_char(CreationDate,'MM-YYYY')) VIRTUAL
    PARTITION BY RANGE (monthly_interval)
    partition p_AUG12 values less than (to_date('08-2012','mm-yyyy')),
    partition p_SEP12 values less than (to_date('09-2012','mm-yyyy')),
    partition p_OCT12 values less than (to_date('10-2012','mm-yyyy'))
    Enable ROw Movement
    BUT CAN'T INSERT the data even for that:
    Insert into a (a, CreationDate)
    Values (1, '12-10-2012')
    Insert into a (a, CreationDate)
    Values (1, '12-10-2012')
    Please suggest..

    Hi rp,
    Interval Partitioned to Range. Created Daily Partitions from Monthly Part. got complicated so I am posting here.
    Basically,
    I know Interval Partitioning is a kind of Range partitioning. But explicitly for Interval Partitioned tables XML Indexes are not allowed as discussed here:
    XMLIndexes on an Interval Partitioned Table??
    I can do monthly partitions as :
    CREATE TABLE A
    a NUMBER,
    CreationDate DATE,
    monthly_interval varchar2(8) as (to_char(CreationDate,'MM-YYYY')) VIRTUAL
    PARTITION BY RANGE (monthly_interval)
    partition p_AUG12 values less than ('09-2012'),
    partition p_SEP12 values less than ('10-2012'),
    partition p_OCT12 values less than ('11-2012')
    ) Enable ROw Movement
    Insert into a (a, CreationDate)
    Values (1, '12-SEP-2012')
    Insert into a (a, CreationDate)
    Values (1, '14-SEP-2012')
    Select * from A partition (p_SEP12)
    Select * from A partition (p_AUG12)
    Select * from A partition (p_OCT12)
    Can we do it for 30 days partitions, instead of the monthly partitions. ANY suggestions..
    Thanks..

  • Is there any plan of allowing non-range partitioning of spatial indexes

    our application is really lacking the ability of spatial index being partitioned by list. We are binning information in our data warehouse by spatial locations, and when we query it (actually, MapViewer is generating a tile), entire geometry set is searched because table is list-partitioned and we cannot have local spatial index.

    Hi,
    I'm not in a position to answer the question about list partitioning, but would a pseudo-list partition implemented as a range partition work? For example, something like this:
    CREATE TABLE customers (
      first_name    VARCHAR2(20),
      last_name     VARCHAR2(20),
      address_1     VARCHAR2(20),
      address_2     VARCHAR2(20),
      city          VARCHAR2(20),
      state_abrv    VARCHAR2(3),
      postal_code   VARCHAR2(10),
      customer_id   NUMBER NOT NULL UNIQUE)
      PARTITION BY RANGE (state_abrv) 
       PARTITION ALASKA         VALUES LESS THAN ('AKz'),
       PARTITION ALABAMA        VALUES LESS THAN ('ALz'),
       PARTITION ARKANSAS       VALUES LESS THAN ('ARz'),
       PARTITION AMERICANSAMOA  VALUES LESS THAN ('ASz'),
       PARTITION ARIZONA        VALUES LESS THAN ('AZz'),
       PARTITION CALIFORNIA     VALUES LESS THAN ('CAz'),
       PARTITION WYOMING        VALUES LESS THAN ('WYz')
       );I've used this method in the past, although I agree a list partitioning solution is much preferred.
    Dan

  • How do I remove disk partition and merge the 2 partitions into main hard disk C drive. Win7

    How do I remove a disk  partition  and merge the 2 partitions into main hard disk C drive. If I delete Drive  D I am left with 250G of unallocated space in drive D Hard drive. And I want the unallocated portion 250G to be allocated
    to the C drive.jc

    I know it is a little bit late to reply. But, I still want to share my experiences with everyone here.
    Actually, I have ever also has the same issue and needed to resize my C drive partition for much more partition space. But, the resizing process just unexpectedly fails at last in Disk Management. The “extend” function is unable to work.
    So, I have no choice but to take chances with some third party partition resizing tools:
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    http://gparted.sourceforge.net/
    IM-Magic Partition Resizer Free
    http://www.resize-c.com/
    Both of them seem efficient. So, I just have tried them one by one and finally added wanted free space to my C drive successfully.
    I even have found a video tutorial that teaches me how to resize my drive with this freeware in details:
    https://www.youtube.com/watch?v=6jCeT7CbsKk

  • Subpartition existing range partition in Oracle

    I have table xyz with following structure
    xyz ( vld_dte date,
    prd_typ varchar2(100),
    sales number
    table XYZ is partitioned by range on field vld_dte and partitions are monthly partitions like JAN-2009 , FEB-2009....DEC-2009 and so on.table is currently loaded with data.
    How can I modify existing range partition into composite range-list partition so that every partiton is subpartitioned on prd_typ , basically three sub-partitions for every partition 1- Grocery , 2-Home decoration,3-OTHERS

    ORA-14759: SET INTERVAL is not legal on this table.
    Cause: ALTER TABLE SET INTERVAL is only legal on a range partitioned table with a single partitioning column. Additionally this table cannot have a maxvalue partition.
    Action: Use SET INTERVAL only on a valid table
    mark answered post as helpful / correct*

  • Problem with a 2 columns Range Partitioning for a indexed organized table

    have an indexed organized table with a 2 column PK. the first field (datum) is a date field the second field (installatieid) is a number(2) field.
    Every minute a 7 records are inserted (installatieid 0-6).
    I like to partition this table with one partition per year per installatieid.
    I tried to do it with:
    partition by range(datum,installatieid)
    (partition P_2004_0 values less than (to_date('2004-01,'yyyy-mm'),1)
    ,partition P_2004_6 values less than (to_date('2004-01','yyyy-mm'),7)
    partition P_2005_0 values less than (to_date('2005-01','yyyy-mm'),1)
    ,partition P_2005_6 values less than (to_date('2005-01','yyyy-mm'),7)
    but now only the P_2004_0 and P_2005_0 are filled.
    I thought about to combine a range partition on datum with a list subpartition on installatieid, but I read this is not allowed with an index organized table.
    How can I solve this problem.

    partition by range(datum,installatieid)
    (partition P_2004_0 values less than
    (to_date('2004-01,'yyyy-mm'))
    ,partition P_2004_6 values less than
    (to_date('2004-07','yyyy-mm'))
    partition P_2005_0 values less than
    (to_date('2005-01','yyyy-mm'))
    ,partition P_2005_6 values less than
    (to_date('2005-07','yyyy-mm'))
    ? Sorry haven't got time to test it this morning ;0)

  • Partition Pruning on Interval Range Partitioned Table not happening when SYSDATE used in Where Clause

    We have tables that are interval range partitioned on a DATE column, with a partition for each day - all very standard and straight out of Oracle doc.
    A 3rd party application queries the tables to find number of rows based on date range that is on the column used for the partition key.
    This application uses date range specified relative to current date - i.e. for last two days would be "..startdate > SYSDATE -2 " - but partition pruning does not take place and the explain plan shows that every partition is included.
    By presenting the query using the date in a variable partition pruning does table place, and query obviously performs much better.
    DB is 11.2.0.3 on RHEL6, and default parameters set - i.e. nothing changed that would influence optimizer behavior to something unusual.
    I can't work out why this would be so. It very easy to reproduce with simple test case below.
    I'd be very interested to hear any thoughts on why it is this way and whether anything can be done to permit the partition pruning to work with a query including SYSDATE as it would be difficult to get the application code changed.
    Furthermore to make a case to change the code I would need an explanation of why querying using SYSDATE is not good practice, and I don't know of any such information.
    1) Create simple partitioned table
    CREATETABLE part_test
       (id                      NUMBER NOT NULL,
        starttime               DATE NOT NULL,
        CONSTRAINT pk_part_test PRIMARY KEY (id))
    PARTITION BY RANGE (starttime) INTERVAL (NUMTODSINTERVAL(1,'day')) (PARTITION p0 VALUES LESS THAN (TO_DATE('01-01-2013','DD-MM-YYYY')));
    2) Populate table 1million rows spread between 10 partitions
    BEGIN
        FOR i IN 1..1000000
        LOOP
            INSERT INTO part_test (id, starttime) VALUES (i, SYSDATE - DBMS_RANDOM.value(low => 1, high => 10));
        END LOOP;
    END;
    EXEC dbms_stats.gather_table_stats('SUPER_CONF','PART_TEST');
    3) Query the Table for data from last 2 days using SYSDATE in clause
    EXPLAIN PLAN FOR
    SELECT  count(*)
    FROM    part_test
    WHERE   starttime >= SYSDATE - 2;
    | Id  | Operation                 | Name      | Rows  | Bytes | Cost (%CPU)| Time     | Pstart| Pstop |
    |   0 | SELECT STATEMENT          |           |     1 |     8 |  7895  (1)| 00:00:01 |       |       |
    |   1 |  SORT AGGREGATE           |           |     1 |     8 |            |          |       |       |
    |   2 |   PARTITION RANGE ITERATOR|           |   111K|   867K|  7895   (1)| 00:00:01 |   KEY |1048575|
    |*  3 |    TABLE ACCESS FULL      | PART_TEST |   111K|   867K|  7895   (1)| 00:00:01 |   KEY |1048575|
    Predicate Information (identified by operation id):
       3 - filter("STARTTIME">=SYSDATE@!-2)
    4) Now do the same query but with SYSDATE - 2 presented as a literal value.
    This query returns the same answer but very different cost.
    EXPLAIN PLAN FOR
    SELECT count(*)
    FROM part_test
    WHERE starttime >= (to_date('23122013:0950','DDMMYYYY:HH24MI'))-2;
    | Id  | Operation                 | Name      | Rows  | Bytes | Cost (%CPU)| Time     | Pstart| Pstop |
    |   0 | SELECT STATEMENT          |           |     1 |     8 |   131  (0)| 00:00:01 |       |       |
    |   1 |  SORT AGGREGATE           |           |     1 |     8 |            |          |       |       |
    |   2 |   PARTITION RANGE ITERATOR|           |   111K|   867K|   131   (0)| 00:00:01 |   356 |1048575|
    |*  3 |    TABLE ACCESS FULL      | PART_TEST |   111K|   867K|   131   (0)| 00:00:01 |   356 |1048575|
    Predicate Information (identified by operation id):
       3 - filter("STARTTIME">=TO_DATE(' 2013-12-21 09:50:00', 'syyyy-mm-dd hh24:mi:ss'))
    thanks in anticipation
    Jim

    As Jonathan has already pointed out there are situations where the CBO knows that partition pruning will occur but is unable to identify those partitions at parse time. The CBO will then use a dynamic pruning which means determine the partitions to eliminate dynamically at run time. This is why you see the KEY information instead of a known partition number. This is to occur mainly when you compare a function to your partition key i.e. where partition_key = function. And SYSDATE is a function. For the other bizarre PSTOP number (1048575) see this blog
    http://hourim.wordpress.com/2013/11/08/interval-partitioning-and-pstop-in-execution-plan/
    Best regards
    Mohamed Houri

  • Range Partitioning a table. Max value to be defined

    Hi,
    I am using a range partitioned table, range partitioned on date, and have defined max value as 6 months after the Creation Date.
    I have a proc which creates the partitions I want in advance by splitting up the max partition.
    - Now what do I do when max partition is reached after 6 months?
    - If I define max partition one year or two year after the current date instead of the currently defined 6 months after creation date. What are the negatives attached with it?
    I can't use Interval Partition and have to use Range only.
    Kindly suggest.
    Thanks..

    >
    I am using a range partitioned table, range partitioned on date, and have defined max value as 6 months after the Creation Date.
    I have a proc which creates the partitions I want in advance by splitting up the max partition.
    - Now what do I do when max partition is reached after 6 months?
    - If I define max partition one year or two year after the current date instead of the currently defined 6 months after creation date. What are the negatives attached with it?
    >
    Any data with a partition key that does NOT match any partition will cause your INSERT query to fail.
    Any partition that has no data to match it will simply remain empty.
    A common partitioning scheme is to define one partition for all old data, one partition with a high max value and then split the max value partition to get the partitions you want in the middle.
    Let's say you want monthly partitions but don't have that much data from before the current year, 2012.
    1. Create one partition for dates < 1/1/2012
    2. One partition each for the 12 months of 2012
    3. One max value partition to be 1/1/4000
    You would just split the max value partition to create each month of 2013. The split could be done ahead of time or a month at a time as you choose.
    The only negative is that any data inserted by mistake that has a super-high date will go into the max value partition. But that is going to happen anyway. If you accidentally enter a date of 3/23/3882 it won't be rejected.
    But it is easy to query periodically to see if you have any 'bad' data like that. And the alternative is that an INSERT would fail because of the one bad record and all of your good data would be rejected anyway so it's not really much of a negative.
    Remember - for best management performance each partition should have its own tablespace and the indexes should all be local if possible.

  • Oracle 11g  List - Range Partition - Help Needed

    Hi All,
    I want to create a composite partition (LIST-RANGE) but RANGE partition should using interval partition
    This is my query .
    CREATE TABLE "DMSDB"."DEVICE_UTILS"
    (     "ULID" VARCHAR2(100 CHAR),
         "IP_ADDRESS" VARCHAR2(24 CHAR),
         "PORT" VARCHAR2(8 CHAR),
         "SHUTDOWN" NUMBER(10,0),
         "LINE_TYPE" NUMBER(10,0) DEFAULT '0',
         "OCCUPIED" NUMBER(10,0),
         "UTILIZATION" NUMBER(10,0),
         "IDLE_TIME" VARCHAR2(32 CHAR),
         "ACTIVATION_TIME" VARCHAR2(32 CHAR),
         "PULLED_DATE" TIMESTAMP (6) DEFAULT SYSDATE,
         "ACCESS_TIME" TIMESTAMP (6) DEFAULT SYSDATE
    PARTITION BY LIST(ULID)
              PARTITION PART_DEVUTILS_ULID VALUES (DEFAULT)
         SUBPARTITION BY RANGE( PULLED_DATE)
         PARTITION PART_DEVUTILS_WEEK INTERVAL (NUMTOYMINTERVAL(1,'WEEK'))
    Somehow its not working. can you please suggest where i am making mistake?

    Interval partitioning is not supported at the subpartition level.
    http://docs.oracle.com/cd/B28359_01/server.111/b28286/statements_7002.htm#BABCDDIA
    Regards
    Girish Sharma

  • Unique key on range-partitioned table

    Hi,
    We are using a composite range-hash interval partitioned table
    Uses index - trying to make this have same tablespace as the partitions i.e. local but not liking it
    alter table RETAILER_TRANSACTION_COMP_POR
    add constraint RETAILER_TRANSACTION_COMP_PK primary key (DWH_NUM)
    using index
    LOCAL
    ora-14039: partitioning columns must form a subset of key columns of a unique index
    Without local then fine but doesn't have same tablespace as the partitions and don't want to make this part of partition key.
    Tbale range partitioned - this is just a UK to prevent duplicates

    [oracle@localhost ~]$ oerr ora 14039
    14039, 00000, "partitioning columns must form a subset of key columns of a UNIQUE index"
    // *Cause:  User attempted to create a UNIQUE partitioned index whose
    //          partitioning columns do not form a subset of its key columns
    //          which is illegal
    // *Action: If the user, indeed, desired to create an index whose
    //          partitioning columns do not form a subset of its key columns,
    //          it must be created as non-UNIQUE; otherwise, correct the
    //          list of key and/or partitioning columns to ensure that the index'
    //          partitioning columns form a subset of its key columns

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