Method signature - ideas

Look at this method signature:
public ArrayList getFollowUpEmails() throws Exception{}
This ArraysList contains several EmailTO transfer objects - but I had to tell you this. Now look at this signature:
public EmailTO[] getFollowUpEmails() throws Exception{}
See how the above method is self explaining. For classes that are to be re-used often by other developers would it be better to use arrays because they are more obvious? How do other people deal with this or do you just not worry about it and leave it up to the comments to explain?

See how the above method is self explaining. Yes, returning an array is more self explanatory. Are you defensively copying the array?
For classes that are to be re-used often by other developers would it be better to use arrays because they are more obvious? It depends. Yes its more obvious but if folks are going to stick the array contents into a Collection then returning a Collection is nice, too.
How do other people deal with this or do you just not worry about it and leave it up to the comments to explain?Thats what javadoc is for. i.e. @return a List of EmailTo objects
In jdk1.5 templates will help with this a bit.
One of the most painful bugs you will encounter is when you don't make defensive copies of objects and another class mutates an internal data structure. Of course, defensive copies waste object references and in some cases, can really cause a slow down. You can always provide access via ye old getNumberOfFollowUpEmails/getFollowUpEmail(int i)
Ian

Similar Messages

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    Uma,
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    --Mukul                                                                                                                                                                                                                                                                                                                                                                                                                                                               

  • Changing exception clause in method signature when overwriting a method

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    Yuthura wrote:
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    I read that methods live in their own special place in memory (and each has an address)? And is that address inserted into the bytecode when the Java source is compiled? So, while in the runtime every object knows its type, and this would enable selection of the correct method, you can't wait because of the need for compile-time method linking? Or, while waiting is technically possible, you can't because the developers of Java wanted to help developers to minimize run-time errors.
    If this question makes no sense, please help clear-up my misunderstanding about method linkage. thanks.

    dpxqb wrote:
    It only cares about the reference type of the expression you pass to foo(expression), which is Object for both cases.awesome. So, I hope this means that the "type" of the concrete object is not relevant for method signature. Rather, it is the "type" of the reference .Correct. I believe it's common to say class when talking about the concrete runtime object, and "type" when talking about the compile-time reference.
    And "reference typing" (aka "casting") happens at compile-time while "object typing" happens in the run-time.Yes and no. Your terminology is non-standard, so I'm not sure exactly what you mean, but approximately, yes, references types matter at compile time and object classes matter at runtime (for polymorphism in overridden methods, for example).
    Casting is both a compile-time and a runtime operation, however. At compile time, the reference type has to be one that could possibly be cast to whatever the target type is, and at runtime, the actual object has to be of an appropriate class for the cast to succeed.
    String s1 = (String)new Date(); // compile time error can't cast "across" the hierarchy
    String s2 = (String)new Object(); // compiles fine, but ClassCastException at runtime
    Object o1 = "abc";
    String s3 = (String)o1; // success

  • Generic method signatures

    I've searched but can't find that a question I have has been asked (or answered). I apologize in advance if it has. Here is my question.
    In Java Generics FAQ by Angelika Langer states in FAQ 802 ( [http://www.angelikalanger.com/GenericsFAQ/FAQSections/TechnicalDetails.html#FAQ802] ) "the type parameters of a generic method including the type parameter bounds are part of the method signature."
    In FAQ 810, many examples are presented of method declarations, including generic ones, and their corresponding method signatures. For example,
    <T> T method(T arg) has the following signature in the example:
    <$T1_extends_Object>method($T1_extends_Object>)
    It would seem to be intuitively clear that the type parameter and bounds would be part of the method signature but I can't seem to find such a stipulation/requirement of such in the Java Language Specification. Anybody know where it's stipulated in the JLS?
    Best Regards

    user13143654 wrote:
    Yeah, I know. The title of the subsection is "Determining Method Signature," but then it never seems to expressly do that other than in some ephemeral wafting byproduct of overload resolution.I wouldn't call it "ephemeral" and "wafting." It's pretty specific. If you're looking for the $T1_extends_Object notation, you won't find it. That's not part of the spec.
    I can't seem to find a specific spot in the subsection where I can say "OK, now I've got the method signature and now can proceed to ..." Well, it goes on to Phase 3, and then on to 15.12.2.5 Choosing the Most Specific Method. I'm not sure what you're looking for. It does describe in detail how we get from all the methods in the universe, to which type's methods we'll be considering to which signatures could match to which one is the best match. I don't know what else you're looking for.
    If you're looking for somebody to digest, translate, and simplify all that for you, good luck, but it ain't gonna be me. :-)
    If you have specific questions about smaller pieces of it I (or somebody else) might be able to help out. At the moment though, your question is rather vague.
    Edited by: jverd on May 3, 2011 1:48 PM

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