MFC Custom static control state is always 4

Hi,
I am creating a custom static control, and want to load different bitmap for different state.
I inherited CMyStatic from CStatic and override the below functions. And i created the static control using SS_NOTIFY macro.
I am getting the state of the static control is 4. Then i called staticCtrl..EnableWindow(TRUE),
also the state is 4.
Can some one please help, how to find the correct state of static control like, STN_ENABLED, STN_DISABLE,
STN_CLICKED etc..
//CMyStatic.cpp
BEGIN_MESSAGE_MAP(CMyStatic, CStatic)
ON_WM_DRAWITEM()
END_MESSAGE_MAP()
void CMyStatic::DrawItem(LPDRAWITEMSTRUCT lpDrawItemStruct)
int state = lpDrawItemStruct->itemState;
void CMyStatic::PreSubclassWindow()
CStatic::PreSubclassWindow();
ModifyStyle(0,SS_OWNERDRAW);
//MyDlg.cpp
staticCtrl.Create(L"",BS_FLAT | WS_VISIBLE | SS_CENTER | SS_NOTIFY,CRect(20,20,100,100),this,1111111); //state:4
staticCtrl..EnableWindow(TRUE); //State:4
Can someone please help on this.
Thanks

Hi LokanathNayak,
From your description, you add SS_NOTIFY style to your static control, so the parent windows will get the notification message, STN_ENABLED, STN_DISABLE, STN_CLICKED etc..
You need to manually add the notify message handler. Something like this:
afx_msg void OnClicked();
afx_msg void OnDoubleClicked();
afx_msg void OnEnabled();
BEGIN_MESSAGE_MAP(CMFCStaticNotifyDlg, CDialogEx)
ON_WM_SYSCOMMAND()
ON_WM_PAINT()
ON_WM_QUERYDRAGICON()
ON_STN_CLICKED(ID_STATIC, &CMFCStaticNotifyDlg::OnClicked)
ON_STN_ENABLE(ID_STATIC, &CMFCStaticNotifyDlg::OnEnabled)
ON_STN_DBLCLK(ID_STATIC, &CMFCStaticNotifyDlg::OnDoubleClicked)
ON_BN_CLICKED(IDC_BUTTON1, &CMFCStaticNotifyDlg::OnBnClickedButton1)
ON_BN_CLICKED(IDC_BUTTON2, &CMFCStaticNotifyDlg::OnBnClickedButton2)
END_MESSAGE_MAP()
void CMFCStaticNotifyDlg::OnClicked()
TRACE(L"clicked");
void CMFCStaticNotifyDlg::OnEnabled()
TRACE(L"enabled");
void CMFCStaticNotifyDlg::OnDoubleClicked()
TRACE(L"double click");
Best regards,
Shu
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