More Binary to Decimal

I can't this simple code to work:
public void sampleMethod()
        Scanner in = new Scanner(System.in);
        System.out.println("Please enter a dammmm number");
        String myString = in.next();
        while(in.hasNext())
            someString = Integer.parseInt(myString);
            if(someString == 0000)
                output = output + 0;
            else if(someString == 0001)
                output = output + 1;
            else
                output = output + 2;
        System.out.printf("%s\n", output);
    }

Stopper is quite correct. You are missing the things Stopper noted.
To trouble shoot such code use your compiler output or a decent IDE like Eclipse or JBuilder which will auto compile and highlight your errors quickly.
You can clean up your method code by adding the variable defnition and initialization code mentioned at the beginning of the method.

Similar Messages

  • Binary to Decimal problems

    Ok to give a background to why i am writing this and so everyone has a better understanding of exactly what it is that i want it to do it goes like this.... My girlfriend got a message from a friend that was all in ones and zeros, and no its not because something on one of the mail servers is messed up he meant for it to be that way. But through the process of converting the 8 digit binary numbers into decimal values so that the corresponding ANSI character could be found I decided that it was taking to damn long so i would just write a prog to do it for me and then i could send back an annoying long message to that guy with ease. Only there is a catch over the summer i went from hotshot for a newb to a newb without a clue, i more or less didnt write a single line of code over 4 months and now i am having problems.
    I wanted to write a program that could-
    -convert long strings of chars into all 8 digit binary code
    -as well as convert large blocks of 8 digit binary back into ANSI letter values and then ANSI characters
    -I want it to use a frame and have a relativly simple usage procedure
    Now that you know what i set out to do I can show you how far i got -
    import javax.swing.*;
    import java.awt.*;
    import java.awt.event.*;
    import java.awt.GradientPaint.*;
    public class BinaryToDec extends JFrame implements ActionListener
         // member variables
         JButton quit;
         JButton color;
         JButton convert;
         JLabel     label11_5, labelPassingWord;
         JTextField inputBinary, outputDecimal;
         Color      colorStore;
         String drawString;
         String bin;
         public BinaryToDec()
              drawString = "";
              setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
              setLocation(100,250);
              setTitle("Binary to Decimal");
              setSize(420,200);
              getContentPane().setBackground(Color.BLACK);
              getContentPane().setLayout(null);
              quit= new JButton("DONE");
              quit.setForeground(Color.GREEN);
              quit.setBackground(Color.BLACK);
              quit.setBounds(100,10,75,20);
              getContentPane().add(quit);
              quit.addActionListener(this);
              color= new JButton("Bkgnd Clr");
              color.setForeground(Color.GREEN);
              color.setBackground(Color.BLACK);
              color.setBounds(15,10,75,20);
              getContentPane().add(color);
              color.addActionListener(this);
              convert= new JButton("Convert to Decimal");
              convert.setForeground(Color.GREEN);
              convert.setBackground(Color.BLACK);
              convert.setBounds(185,10,75,20);
              getContentPane().add(convert);
              convert.addActionListener(this);
              label11_5 = new JLabel("Enter a Binary Number");
              label11_5.setBounds(75,60,250,20);
              label11_5.setForeground(Color.GREEN);
              getContentPane().add(label11_5);
              inputBinary = new JTextField(25);
              inputBinary.setBounds(5,40,225,20);
              inputBinary.setForeground(Color.BLACK);
              getContentPane().add(inputBinary);
              inputBinary.addActionListener(this);
              labelPassingWord = new JLabel("Your Deciaml Equivilant");
              labelPassingWord.setBounds(75,120,250,20);
              labelPassingWord.setForeground(Color.GREEN);
              getContentPane().add(labelPassingWord);
              outputDecimal = new JTextField(25);
              outputDecimal.setBounds(5,100,225,20);
              outputDecimal.setForeground(Color.BLACK);
              getContentPane().add(outputDecimal);
              outputDecimal.addActionListener(this);
              setVisible(true);
         }// end of constructor
         public void actionPerformed (ActionEvent evt)
              if(evt.getActionCommand().equals("DONE"))
                   System.out.println("Quit Caught");
                   int choice = JOptionPane.showConfirmDialog(null , "You Pressed " + evt.getActionCommand() + " are you sure?"
                        , "Close Frame",JOptionPane.YES_NO_OPTION);
                   if(choice == 0)
                        this.dispose();
                   if (evt.getSource() == color)
                        Color color = Color.lightGray;
                        color = JColorChooser.showDialog(BinaryToDec.this,"Choose a color",color);
                        getContentPane().setBackground(color);
                   if (evt.getSource() == convert)
                        bin = inputBinary.getText();
                        int strLength = bin.length();
                        int pos1=0, pos2=7;
                        String temp = "";
                        String Decimal1 = "";
                        String Decimal2 = "";
                        int binLength = 8;
                        int count = 0;
                             do
                                  temp = bin.substring(pos1,pos2);
                                  Decimal1 = Convert(temp);
                                  Decimal2 = Decimal2 + "" + Decimal1;
                                  pos1 = pos1 + binLength;
                                  pos2 = pos2 + binLength;
                                  count++;
                                  outputDecimal.setText(Decimal2);
                                  repaint();
                             }while((strLength/8) >count);
         }//end of actionPerform
         public void paint( Graphics g)
              super.paint(g);
         public String Convert(String a)
              int ctr=1, decimal=0;
              for (int i = a.length()-1; i>=0; i--)
              if(a.charAt(i)=='1')      decimal+=ctr;
              ctr*=2;
              String converted = "" + decimal;
              return converted;
         public static void main(String args[])
              System.out.println("Binary to Dec");
              BinaryToDec in = new BinaryToDec();
         }// end of main()
    }// end of class FrameExample1
    OK so other than that i decided to play with some of the paint functions i more or less stayed on task, at first i had it just convert 8 digit binary nums into decimal form using this -
              int ctr=1, decimal=0;
              for (int i = a.length()-1; i>=0; i--)
              if(a.charAt(i)=='1')      decimal+=ctr;
              ctr*=2;
    which i found in someone elses post and made some changes to, thank you someone whoever you are i hope you see this, anyways,.. then i decided i wanted it to check the length of a string and divide it by 8 assuming that it it a perfect block of 8 digit nums and then cut it into substring and go through the proccess of converting the binary to deciaml one piece at a time. I did it more or less, well it compiles right but whenever you put in more than one 8 digit binary number it ends up giving you some really strange decimal numbers and i cant seem to figure out why the hell it is doing this.??? I was hoping that some one could help me out.
    If you read this far than thanks for taking the time on my post :)

    Did you try to decode that message by hand and verified that it really is encoded the way you think it is?
    Here some code to try
    public static void decode(String fileIn, String fileOut) {
            try {
            FileReader in=new FileReader(fileIn);
            PrintWriter out=new PrintWriter(fileOut);
            char[] buffer=new char[8];
            int i;
            do {
                i=in.read(buffer, 0, 8);
                if(i==8) {
                    out.write(Integer.parseInt(new String(buffer),2));
            } while(i==8);
            in.close();
            out.close();
            } catch (Exception e) {}
        public static void encode(String fileIn, String fileOut) {
            try {
            FileReader in=new FileReader(fileIn);
            PrintWriter out=new PrintWriter(fileOut);       
            int i;
            while( (i=in.read()) >= 0 ) {
                String str=Integer.toBinaryString(i);
                for(int j=str.length(); j<8; j++)
                    out.write('0');
                out.write(str);
            in.close();
            out.close();
            } catch (Exception e) {}
        }

  • "value cannot have more than 0 decimal places" error

    CRM gurus,
    Whenever I try to create a Counter, I receive the following warning which doesn't allow me to do anything further..
    "<b>value cannot have more than 0 decimal places"</b>
    I first received this when I tried to assign a counter to a product in an Installed Base. So when I tried creating a counter here, I got the above message. I then tried to assign a counter to the product in the product master data, and I still received the same error message. I then tried creating a counter from the "Maintain Counter" screen (Transaction Code: <b>crm_mpk_admin</b>), and still received the same error message.
    In this effort I created my own custom Counter Category, and Attributes. Nothing helped.
    Could someone throw some light on this concept and tell me where am I going wrong.
    Thanks and regards,
    -Pras

    Hi
    I think its a program error, you need to Implement the source code corrections.
    Please refer <b>SAP Note : 855670</b>
    Regards,
    Johnny.
    Reward if it helps.

  • More than 3 decimal in Bill of Material component quantity

    I want to know whether we can use more than 3 decimals in quantities in Bill of Material. I heard that it was an issue in SAP but is that issue still exist in ECC 6.0.
    Regards

    Dear,
    During maintaing the unit of measure in T-code CUNI we can define No. of decimal places to which rounding should be performed which specifies the number of decimal places to which this measurement unit should be rounded.
    System will not allow more than 3 decimal places in satandard SAP.
    You can use a larger base quantity of 100 or 1000 in the BOM header (instead of 1).
    That would eliviate your issue with the 3 decimal places in the component quantity.
    SAP always takes the base quantity into account during requirements calculation.
    Hope clear to you.
    Please refer this link,
    [Decimal in Bill of Material|Re: Decimal Points in BOM]
    Regards,
    R.Brahmankar

  • NI 9870 and binary coded decimal (BCD)

    I have a scale that outputs the weight in 4 digit ASCII form which I would like to input into a CompactRio 9072 with a NI 9870 card and convert to a binary integer. The weight appears as the 7th to 10th character on lines that are terminated by a CR. I am thinking I will need a loop that once the 10th character is read, the 4 least significant bits of the 4 characters are converted from BCD to binary and the character counter resets to 0 when a CR is read. I need a good method for converting BCD to an integer value in either labview or vhdl. The rest of the logic for this project is in vhdl, so I would not mind adding the conversion logic there, except that all the algorithms I have found require decimal division or comparison in several clock cycles.
    Solved!
    Go to Solution.

    Hello imr
    Thank you very much for getting in touch with us!
    I believe the following community example will resolve part of your issue.
    Binary String to Number
    https://decibel.ni.com/content/docs/DOC-11704
    I have also provided some further information for those unaware of what Binary Coded Decimal represents.
    What is Binary Coded Decimal (BCD)?
    http://digital.ni.com/public.nsf/allkb/59C2A05C123​008F286256CA90069A6F8
    Thank you for choosing National Instruments!
    Sincerely,
    Greg S.

  • Help converting binary to decimal.

    Hi all.
    I'm taking a course in Java programming and so far its been a great experience. I'm currently stumped on one of my assignments and I am kindly requesting some assistance.
    Basically I have to convert a binary entry into its decimal comparison.
    so for instance an entry of 1101 would output 13.
    I have the calculation formula, but my problem is finding out whether the point i'm looking at is either a 1 or a 0. I can't seem to 'strip it down' to the value.
    My current thought is something like this:
    binary = 1101;
    // problem is here
    thou = (binary % 1000) / 1000;
    hund = (thou % 100) / 100;
    tens = (hund % 10) / 10;
    ones = (tens % 1) / 1;
    // then do formular
    decimal = ones * 1 + tens * 2 + hund * 4 + thou * 8;
    I have searched but all the suggestions say to use a custom function or other obscure method. I don't know that stuff real well and we aren't even that far in the book either. All we've done so far is while, if .. else, condition statements.
    I will include the actual text for the question, in case i'm not clear. This text also includes a 'tip' which isn't helping me. (http://www.geocities.com/kaveman2000/q-4-25.pdf)
    Thanks again for any pointers.

    angeles1016 (and all),
    thanks for your great help and code snippets.
    angeles1016,
    using the code you provided i noticed that the last (single digit) was giving the wrong response in certain cases. (1000, 0111, 0001, ..) i could be off one.
    either way, i decided to fix it up and give you all the update.
    // do class, main function stuff
         if(binary/1000 == 1){
              thousands += (binary/1000);
         temp = binary % 1000;          
         if(temp/100 == 1){
              hundreds += (temp/100);
         temp = temp % 100;          
         if(temp/10 == 1){
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         temp = temp % 10;
         if(temp/1 == 1){
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         decimal = (ones * 1) + (tens * 2) + (hundreds * 4) + (thousands * 8);
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         result += "Decimal: " + decimal + "\n";
    // display in gui ?
    // end function and class stuff(note: i suppose the statements similar to "thousands += (binary/1000);" can be simplified as "thousands = 1;")

  • Qty with more than 3 decimal places in BOM

    HI ALL,
    CAN I PUT QTY IN BOM WITH MORE THAN 3 DECIMAL PLACES ITS VERY URGENT REQUIREMENT.
    THANKS
    R SEHGAL

    Dear Rakesh
    I am not sure, but you can try this
    1. Define one more UOM for example 4dec then in MM02 give the conversion of 4dec to your 3 decimal, give conversion in it. for eg 10*3dec = 4 dec
    2. Now when you define bom enter quantity in 3dec(i,e, multiplying by 10) and then convert the uom in BOM to 4dec
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    Regards
    Jitesh

  • Print Scale Percentage - Can the percentage go more than 2 decimal places??

    Hello All,
    Illustrator CS6
    I want to know if it is possible to get more than 2 decimal places in the Print Scale Percentage option box (as shown below)?
    It seems to round to 2 and I would like to get at least 3 for better accuracy.
    Any thoughts?
    Thanks
    Geoff

    Not that I know of. If you need it to be more exact, resize the artboard and scale the content. It's an arguable point, anyway, given how your printer will translate/ rasterize the stuff. Even if there were more digits, the result after the halfftoning might not at all be any different...
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  • Query to find records with more than 2 decimal places

    I have written the below query to find records with more than 2 decimal places, but it is returning records with decimal places 1 & 2.
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    SELECT amt  FROM amount_table
    WHERE substr(amt, instr(amt, '.')) LIKE '.%'
           AND length(substr(amt, instr(amt, '.') + 1)) > 2Output:-
    AMT
    *41591.1*
    *275684.82*
    *64491.59*
    *3320.01*
    *6273.68*
    *27814.18*
    *30326.79*
    131.8413635
    162.5352898
    208.5203816
    8863.314632
    22551.27856
    74.716992
    890.0158441
    2622.299682
    831.6683841
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    2328.195877
    3132.453438
    5159.827334
    3.236234727
    37.784
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    Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - 64bi
    create table amount_table
      LINE_NUMBER        NUMBER not null,
      FEE_AMT            NUMBER not null
    insert into amount_table (LINE_NUMBER, FEE_AMT)
    values (60208, 41591.1);
    insert into amount_table (LINE_NUMBER, FEE_AMT)
    values (60213, 275684.82);
    insert into amount_table (LINE_NUMBER, FEE_AMT)
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    insert into amount_table (LINE_NUMBER, FEE_AMT)
    values (63026, 3320.01);
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    values (59906, 6273.68);
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    values (83114, 30326.79);
    insert into amount_table (LINE_NUMBER, FEE_AMT)
    values (2112395, 131.8413634682);
    insert into amount_table (LINE_NUMBER, FEE_AMT)
    values (2112399, 162.5352898104);
    insert into amount_table (LINE_NUMBER, FEE_AMT)
    values (2112402, 208.5203815738);
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    values (2112403, 8863.3146321954);
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    values (2112406, 22551.2785551322);
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    values (2112411, 2622.2996817048);
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    insert into amount_table (LINE_NUMBER, FEE_AMT)
    values (2112422, 5159.8273341686);
    insert into amount_table (LINE_NUMBER, FEE_AMT)
    values (2112423, 3.2362347266);
    insert into amount_table (LINE_NUMBER, FEE_AMT)
    values (2112426, 37.784);
    insert into amount_table (LINE_NUMBER, FEE_AMT)
    values (2112427, 198.7423503696);
    insert into amount_table (LINE_NUMBER, FEE_AMT)
    values (2112430, 0.7220848332);
    insert into amount_table (LINE_NUMBER, FEE_AMT)
    values (2112433, 12.4149375254);

  • Help with binary to decimal, binary to hex, and hex to ascii or ascii to hex program

    I decided to do a program that will do binary to decimal, binary to hex, and hex to ascii for a project related to a java programming course, which only needs to perform features from chapters 1-6 and 8 of Tony Gaddis's book. The functions work fine as their own main programs out side of this combined effort, so can anyone help me determine why I get the following 41 errrors saying: class, interface, or enum expected as well as any other errors that may show up afterwards because I'm stumped. My flowcharts, which have to be revised after discovering that my previous function were logically incorrect after running them in their own main are attached below as the spec sheet.
    My code is as follows and I hope you don't mind the commented lines of unused code because I'm not sure where I want things and what I want at the moment:
    import java.util.Scanner;
    import java.io.*;
    import java.lang.*;
    public class BintoDectoHextoAscii
       public static void main(String[] args)throws IOException
          Scanner input = new Scanner(System.in);
          System.out.println("Enter a binary number: ");
          String binary = input.nextLine(); // store input from user
         if (binary == input.nextLine())
          //int i= Integer.parseInt(hex,2);
          //String hexString = Integer.toHexString(i);
          //System.out.println("Hexa decimal: " + hexString);
          //int finaldecimalvalue = binaryToDecimal(hexString);
          int finaldecimalvalue = binaryToDecimal(hexString);
         if (binary != input.nextLine())
          String hexInput; // The variable Bin Input declared as the datatype int to store the Binary value  
          // Create a Scanner object for keyboard input.
          //Scanner keyboard = new Scanner(System.in);
          // Get the number of binary files.
          System.out.print("Enter the Hex value: ");
          hexInput = keyboard.nextLine();
          System.out.println("Original String: "+ hexInput);
          //String hexEquivalent = asciiToHex(demoString);
          String hexEquivalent = asciiToHex(hexInput);
          //Hex value of original String
          System.out.println("Hex String: "+ hexEquivalent);
          String asciiEquivalent = hexToASCII(hexEquivalent);
          //ASCII value obtained from Hex value
          System.out.println("Ascii String: "+ asciiEquivalent);String finalhexOutput = HextoAsciiConverter(hexEquivalent);
         if (binary != input.nextLine() && hexInput != keyboard.nextLine())
             BufferedReader binInput = new BufferedReader(new InputStreamReader(System.in));
             System.out.println("Enter the Binary number:");
             String hex = binInput.readLine();
             //String finaldecimalvalue = binaryToDecimal(decimal);
             //long finalhexvalue = BinaryToHexadecimal(num);
             long finalhexvalue = BinaryToHexadecimal();
       public static String BinaryToHexadecimal(String hex)
          //public static void main(String[] args)throws IOException
             //BufferedReader bf= new BufferedReader(new InputStreamReader(System.in));
             //System.out.println("Enter the Binary number:");
             //String hex = binInput.readLine();
             long num = Long.parseLong(hex);
             long rem;
             while(num > 0)
             rem = num % 10;
             num = num / 10;
             if(rem != 0 && rem != 1)
             System.out.println("This is not a binary number.");
             System.out.println("Please try once again.");
             System.exit(0);
             int i= Integer.parseInt(hex,2);
             String hexString = Integer.toHexString(i);
             System.out.println("Hexa decimal: " + hexString);
          return num.tolong();
      //int i= Integer.parseInt(hex,2);
      //String hexString = Integer.toHexString(i);
      //System.out.println("Hexa decimal: " + hexString);
    //} // end BintoDectoHextoAsciil
       //public static String HexAsciiConverter(String hextInput)
          // Get the number of binary files.
          //System.out.print("Enter the Hex value: ");
          //hexInput = keyboard.nextLine();
          //System.out.println("Original String: "+ hexInput);
          //String hexEquivalent = asciiToHex(demoString);
          //String hexEquivalent = asciiToHex(hexInput);
          //Hex value of original String
          //System.out.println("Hex String: "+ hexEquivalent);
          //String asciiEquivalent = hexToASCII(hexEquivalent);
          //ASCII value obtained from Hex value
          //System.out.println("Ascii String: "+ asciiEquivalent);
       //} // End function  
       private static String asciiToHex(String asciiValue)
          char[] chars = asciiValue.toCharArray();
          StringBuffer hex = new StringBuffer();
          for (int i = 0; i < chars.length; i++)
             hex.append(Integer.toHexString((int) chars[i]));
          return hex.toString();
       private static String hexToASCII(String hexValue)
          StringBuilder output = new StringBuilder("");
          for (int i = 0; i < hexValue.length(); i += 2)
             String str = hexValue.substring(i, i + 2);
             output.append((char) Integer.parseInt(str, 16));
          return output.toString();
       public static String binaryToDecimal(String binary)
            //Scanner input = new Scanner(System.in);
            //System.out.println("Enter a binary number: ");
            //String binary = input.nextLine(); // store input from user
            int[] powers = new int[16]; // contains powers of 2
            int powersIndex = 0; // keep track of the index
            int decimal = 0; // will contain decimals
            boolean isCorrect = true; // flag if incorrect input
           // populate the powers array with powers of 2
            for(int i = 0; i < powers.length; i++)
                powers[i] = (int) Math.pow(2, i);
            for(int i = binary.length() - 1; i >= 0; i--)
                // if 1 add to decimal to calculate
                if(binary.charAt(i) == '1')
                    decimal = decimal + powers[powersIndex]; // calc the decimal
                else if(binary.charAt(i) != '0' & binary.charAt(i) != '1')
                    isCorrect = false; // flag the wrong input
                    break; // break from loop due to wrong input
                } // end else if
                // keeps track of which power we are on
                powersIndex++; // counts from zero up to combat the loop counting down to zero
            } // end for
            if(isCorrect) // print decimal output
                System.out.println(binary + " converted to base 10 is: " + decimal);
            else // print incorrect input message
                System.out.println("Wrong input! It is binary... 0 and 1's like.....!");
            return decimal.toint();
       } // end function
    The errors are as follows:
    ----jGRASP exec: javac BintoDectoHextoAscii.java
    BintoDectoHextoAscii.java:65: error: class, interface, or enum expected
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    ----jGRASP wedge2: exit code for process is 1.
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    Attachments:
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