More than 8 level of release

Dear Friends ,
If more than 8levels of release for perticular release statergy , how i can go head 9th level . Is it through user exits.
RB

Hello,
This is a system limitation. It is not possible to have more than 8.
Best Regards,
Arminda jack

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I installed lv 6.1 on a windows 98 system. As I am having problems of stability (much more than with the former release 6.0), I would like to know if there is some specific problem with windows 98 or there is some patch.

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My experience with Win98 is that it is not a very stable system, regardless of software used. For example, Win2000 and XP are far more stable than 98. I've had it crash on its own if I leave the computer on for several days.
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select case when connect_by_isleaf = 1 then 0
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Hi Vidya,
Thanks for posting your example. You may want to remove your workspace details from the previous posting, or at least update the password on the workspace. I've taken a look at your example and initially couldn't see anything wrong with your tree query. However, when I ran your query in SQL Workshop, it only returned one row, which would explain why you were only seeing one node in your tree! I've updated your query to use a WITH clause, and the tree is now working correctly. I believe you've hit an underlying database bug where the CONNECT BY query is only returning 1 row, when in fact it should return > 1 row. By re-writing the query to use a WITH clause, you can get around the problem.
Regards,
Hilary

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I have the following file format that needs to be converted into XML, but because it has more than one level of substructure I'm not able to give the correct file conversion parameter
source file sample:
1headeryyyyyyyyyyyyy
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[]´s
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Can a subquery be nested more than 2 levels in oracle 10g

hi
can a subquery be nested more than 2 levels in oracle..10g
thank u
rajiv
Message was edited by:
user500763

You will never learn anything about Oracle if you just keep posting your 1z0-001 exam questions here.
Look it up, try it, test it. Otherwise all you're learning how to do is cut and paste.

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Hi,
I am trying to have multiple drill paths for a single dimension. For example, the Date dimension should be navigable by the following hierarchies:
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However, when I model this in the Admin tool, it allows it, but then I add the column in Answers and get a runtime error:
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Hi,
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Find parent/child relationships At More Than 2 Levels

Hello,
Does anyone have a solution to find parent/child relationship for data more than 2 levels deep?
I have a solution when there's a simple parent-child relationship but not when there's a grandparent-parent-child relationship or deeper.
Ex. I have a table company_parent_child that stores the relationship betwen a company and it's direct parent.
create table TEMP_COMPANY_PARENT_CHILD
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insert into TEMP_COMPANY_PARENT_CHILD values (1, 11);
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insert into TEMP_COMPANY_PARENT_CHILD values (2, 13);
insert into TEMP_COMPANY_PARENT_CHILD values (10, 100);
insert into TEMP_COMPANY_PARENT_CHILD values (10, 101);
insert into TEMP_COMPANY_PARENT_CHILD values (10, 102);
insert into TEMP_COMPANY_PARENT_CHILD values (11, 103);
1->
___10->
______100,101,102,
___11->103
Companies 100, 101 and 102 are under parent 10 and grandparent 1.
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start by learning CONNECT BY/START WITH. once you've
written a query to read the grandparent-parent-child
relationship, then come back with more questionsYes. we did look heavily into connect by/start with, in fact along with "connect_by_iscycle","connect_by_isleaf","connect_by_root" as well.
Our dilemma is that when a joint is made between those two tables mentioned above TEMP_COMPANY_PARENT_CHILD and TEMP_JOIN, we are not able to create a view that would contain distinct company_ids, each mapped to a unique order id.
The problem is we cannot have this type of joint when there are "n" level relationship between companies (or company_id). Basically, I think we should have our unique order id mapped to a unique key. This unique key should be a specialized key that we can know at anytime the entire path of the ancestry which we can know by sys_connect_by_path(company_id,'/') path.
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Then you query by path using INSTR to pull records by company_id.
for example, if you want to get all the children for company_id "10" you would just say
select * from X where INSTR(PATH,10,1,1) <> 0
or if you want to get all the children for company_id "11" you would just say
select * from X where INSTR(PATH,11,1,1) <> 0
What do you think? Has anyone used the path information for traversing the tree? Or is there any article that tells us how to make effective use of sys_connect_by_path(company_id,'/') path.
Thank you. Hope it made sense!

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Reward with Points.
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Hi Senthil,
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You mean to say :
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http://wiki.sdn.sap.com/wiki/display/ERPLO/ReleaseprocedureforPurchaseRequisitioninMM
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regards
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