Mouse Position at dragDrop event

I'm dragging and dropping items between canvas containers. When I drop an item, the dragDrop event fires. However, I can't seem to find the mouseX and mouseY values of the drop target container, at the point when the item is dropped. Once the mouseDown event fires to start the drag, it seems as though Flex stops capturing the mouseX and mouseY values.
I put a mouseMove event listener on the container where I'm dropping, and as soon as the mouseDown event starts, the mouseMove event stops.
I looked at mouseUp, and while that gives me the correct current mouse position, it is triggered after the dragDrop event, making it too late to use the x and y position of the item I dropped.
How do I find where the point where I dropped the item?

As soon as the mouseDown event is triggered, the mouseMove event no longer triggers. Thank you for the link. I've read that many times while working on this. What it doesn't address is the position of the item dropped. The only way I can think of to get around this is to listen for the mouseUp instead of the drapDrog event, but that should not be necessary. Use the code below, as an example. No matter where you drop the panel in the second canvas, it puts it at the y value of the mouse at the moment the doDrag (or mouseDown) event triggered.
<?xml version="1.0"?>
<mx:WindowedApplication xmlns:mx="http://www.adobe.com/2006/mxml" layout="horizontal">
    <mx:Script>
        <![CDATA[
            import mx.managers.DragManager;
            import mx.core.DragSource;
            import mx.events.DragEvent;
            import flash.events.MouseEvent;
            import mx.controls.Alert;
            private function mouseOverHandler(event:MouseEvent):void {
                var dragInitiator:Panel=Panel(event.currentTarget);
                var ds:DragSource = new DragSource();
                ds.addData(dragInitiator, "format");
                var PanelProxy:Panel = new Panel();
                PanelProxy.height=myPanel.height;
                PanelProxy.width=myPanel.width;               
                DragManager.doDrag(dragInitiator, ds, event, PanelProxy, 0, 0, 1.00);
            private function dragEnterHandler(event:DragEvent):void {
              if (event.dragSource.hasFormat("format"))
                DragManager.acceptDragDrop(Canvas(event.currentTarget));
            private function dragOverHandler(event:DragEvent):void
                if (event.dragSource.hasFormat("format")) {
                    if (event.ctrlKey) {                   
                        DragManager.showFeedback(DragManager.COPY);
                        return;
                    else {
                        DragManager.showFeedback(DragManager.MOVE);
                        return;
                DragManager.showFeedback(DragManager.NONE);
            private function dragDropHandler(event:DragEvent):void {
              if (event.dragSource.hasFormat("format")) {
                  var draggedPanel:Panel = event.dragSource.dataForFormat('format') as Panel;
                  var dropCanvas:Canvas = event.currentTarget as Canvas;
                  var newPanel:Panel = new Panel();
                  newPanel.x = 0;
                  newPanel.y = drpTgt.mouseY;
                  newPanel.height = draggedPanel.height;
                  newPanel.width = draggedPanel.height;
                  dropCanvas.addChild(newPanel);
                  Alert.show("Item Dropped at "+newPanel.y);
            private function dragCompleteHandler(event:DragEvent):void {
                var draggedPanel:Panel =
                    event.dragInitiator as Panel;
                var dragInitCanvas:Canvas =
                    event.dragInitiator.parent as Canvas;
                if (event.action == DragManager.MOVE)
                    dragInitCanvas.removeChild(draggedPanel);
        ]]>
    </mx:Script>
    <mx:Canvas
        width="250" height="500" 
        borderStyle="solid"
        backgroundColor="#DDDDDD">
        <mx:Panel id="myPanel" x="10" y="192" width="150" height="150" layout="absolute" title="Test Panel" mouseMove="mouseOverHandler(event);" dragComplete="dragCompleteHandler(event);"/>
    </mx:Canvas>
    <mx:Canvas id="drpTgt"
        width="250" height="500" 
        borderStyle="solid"
        backgroundColor="#DDDDDD"
        dragEnter="dragEnterHandler(event);"
        dragOver="dragOverHandler(event);"
        dragDrop="dragDropHandler(event);" horizontalScrollPolicy="on">       
    </mx:Canvas>
</mx:WindowedApplication>

Similar Messages

  • Get mouse position during Custom UI Draw event?

    I am building a Custom UI for one of my plugin effect.
    I want to get the mouse position during the Custom UI Draw event (PF_Event_DRAW), but cannot manage to get it.
    From what I understand, it seems we can only get the mouse position during the events PF_Event_DRAG, PF_Event_DO_CLICK, and PF_Event_ADJUST_CURSOR.
    I tried to use PFAppSuite4::PF_GetMouse() too, but this resulted in the error message "After Effects error: internal verification failure, sorry! {PF_GetMouse can only be called during valid events.}".
    Therefore I want to store the mouse position during PF_Event_ADJUST_CURSOR, and use it later during PF_Event_DRAW.
    Where can I store those values in a "clean" way (ensuring there will not be conflicts if two instances of the same effect are running, etc)?
    Or is there an easier method to get the mouse position during a Custom UI Draw event?

    //SequenceDataVars is the name of your data structure
    //this is how you create the sequence data
    out_data->sequence_data = PF_NEW_HANDLE(sizeof(SequenceDataVars));
    SequenceDataVars *seqData =
    (SequenceDataVars*)PF_LOCK_HANDLE(out_data->sequence_data);
    //and now you can store stuff in it.
    seqData->var1 = 7;
    //after it's created, on other calls, you just do a simple cast
    SequenceDataVars *seqData = *(SequenceDataVars **)out_data->sequence_data;
    seqData->var1 = 100;
    //this is how you delete it. (if you don't delete it, it will be saved with
    the project, and loaded on the next session. (if you want)
    PF_DISPOSE_HANDLE(out_data->sequence_data);
    there's more to know, so look up SequenceSetup, SequenceSetdown, ect in the
    sample project.

  • MAC OS X + stage.fullScreenSourceRect + renderMode set to GPU = problem with mouse position

    When setting stage.fullScreenSourceRect, stage.displayState to StageDisplayState.FULL_SCREEN_INTERACTIVE; and renderMode to GPU, mouse position is read incorrectly. This is not only for mouseX and mouseY position, but also all the mouse interactions with Sprites, Buttons etc are not working correctly.
    Anybody know a solution for this issue?
    Here is the bug reported, but there is no response yet.
    https://bugbase.adobe.com/index.cfm?event=bug&id=3486120
    Greg.

    Bump up.
    Anybody has the same problem and have an idea how to fix it? Or please just check if you have the same problem.. I'm going to submit my game "Amelia and Terror of the Night" (successfully added to iOS store) to MAC App Store but can't do it while this problem appears.
    I am disappointed nobody  even verified the bugs I submitted at  the bugbase.adobe.com for AIR 3.5 and 3.6
    thanks
    Greg

  • Hwo to "track the mouse position"

    I m a java newbie, and need to write a small program to track the mouse position.
    basically, it opens a small window, and tell you the current mouse x, y coordinate. when mouse moves, hte x, y changes...
    by the way, how can i compile it to .exe file, after i finished coding.
    i try this way, but so many errors.
    import javax.swing.*;
    import java.awt.*;
    import java.awt.event.*;
    public class mouseWin {
    public static void main(String[] args)
              protected int last_x=0, last_y=0;
              mouseMoved(MouseEvent e);
    JFrame frame = new JFrame("Mike's Mouse");
    JLabel X = new JLabel("x: " + last_x + "y: " + last_y);
    frame.getContentPane().add(X);
    frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
    frame.pack();
    frame.setVisible(true);
         public mouseMoved(mouseEvent e)
              last_x = e.getx();
              last_y = e.gety();

    please help.
    i rewrite the code, but still cannot get it work
    import javax.swing.*;
    import java.awt.*;
    import java.awt.event.*;
    import java.util.EventListener;
    public class mouseWin implements MouseMotionListener
    public static void main(String[] args)
                   int last_x;
                   int last_y;
                   last_x = 0;
                   last_y = 0;
                   JFrame frame = new JFrame("Mike's Mouse");
                   JLabel X = new JLabel("x: " + last_x + "y: " + last_y);
              frame.getContentPane().add(X);
                   frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
                   frame.pack();
                   frame.setVisible(true);
         public void mouseMoved(MouseEvent e)
              last_x = e.getx();
              last_y = e.gety();
              JLabel X = new JLabel("x: " + last_x + "y: " + last_y);
    }

  • Mouse position capturing

    I was wondering if there is a way to capture the mouse position w/o the use of a frame or jframe? I already know how to use the MouseListener on the JFrame/Frame, but that is no help to me since I'm not using a frame at all. Any suggestions????

    What is your goal. This will work -- (the window is 1 pixel!) -- because the robot starts a "drag" and
    swing has mouse capture during drag, but as soon as the use clicks, it's over...
    import java.awt.*;
    import java.awt.event.*;
    import javax.swing.*;
    public class X {
        public static void main(String[] args) throws AWTException {
            JWindow w = new JWindow();
            Container cp = w.getContentPane();
            cp.addMouseMotionListener(new MouseMotionListener() {
                public void mouseDragged(MouseEvent e) {
                       System.out.println(e.getPoint());
                public void mouseMoved(MouseEvent e) {
            w.setBounds(new Rectangle(0,0,1,1));
            w.setVisible(true);
            Robot rob = new Robot();
            rob.mouseMove(0,0);
            rob.mousePress(InputEvent.BUTTON1_MASK);
            rob.mouseMove(100,100);
    [/code[

  • Detect Mouse Position?

    I can't (within actionscript 3) determine where the mouse is
    relative to the flash player window.
    I can get stage.mouseX and stage.mouseY but those coordinates
    are in relation to the size of the entire ORIGINAL stage at compile
    time.
    I need to know where the mouse is in relation to the window
    playing the swf, which is significantly smaller than the original.
    That is the play screen has been resized.
    If I zoom way in and scroll to the right edge of the stage
    and mouseover a spot on the right edge, then trace the mouse
    position (in a mouseover event proc) it shows me a number that is
    the width of the ORIGINAL stage. It seems to be completely
    oblivious to the play window.
    Is there any way at all to determine where the mouse is
    relative to the play window?
    For example,
    if the original stage is 1350 and the play window is 540 and
    I'm zoomed WAY in and scrolled all the way to the right and
    I put the mouse directly in the middle of the window,
    I need something that tells me (in actionscript 3) that the
    mouse's x coordinate is at 270, NOT 12XX (somewhere near the end of
    the orginal size of the stage).
    Is this possible in Flash C3??

    Hi there!
    I don´t know if it´s right but have you tried
    localX
    localY
    from the occuring MouseEvent?
    Hope that helps :)
    CU
    Ingo

  • Convert mouse position to image position

    Using a zoomed IMAQ image in an image control, I want to recover the position of the mouse in the co-ords of the underlying image. LastMousePositionX (and Y) give the info I want but they are one click in the past and not the current position. Amazingly, there doesn't appear to be an equivalent CurrentMousePositionX. I can't seem to find the info I need to do the conversion manually. The mousedown event returns the current mouse position and I can get the position in the image container by subtracting off its left and top position. But to convert this to the image position I need to know both the zoom and where the images origin is relative to what is displayed. I can't seem to find that origin position in the list of property nodes. The only thing I can seem to come up with is to extract the info from teh image information string, but this seems like an incredibly poor way to extract such obvious information - espeically since the info must be calculated to put in the string anyway. Can anyone help with this?

    Hi,
    I am confused why you get the mouse position one click in the past because it seems to work ok for me. I've had to use four of the image properties to recreate the effect using the mousemove event, but this seems to give the same values as the Last Mouse Position property so I think it does what you want. I couldn't see an origin property so I did the conversion using the position given at the image center. I wanted to post a snippet here but I'm new to posting and couldn't seem to get it to work for the whole block diagram, so I'm using a screenshot instead. I hope this helps in some way.
    Will
    Attachments:
    mouse position test.vi ‏58 KB

  • DnD - Get Drop Mouse Position

    I want to Drag some image file from a JList, and then drop it on a JPanel. The dropping on the panel functions. The problem is, i would like to get the position of the mouse, when the item is dropped on the panel. I use the panel to visualize graphics with Graphics2D, and the image dragged from the list should then be displayed at the position on the panel, where it is dropped. So how could i get this position? I have added a MouseListener to the panel, but it does not react on the mouse events which are caused by the DnD action.

    I am really helpless... Is this a stupid question or does nobody know the answer?
    I just want to get the mouse position of the drop, after a drag and drop.
    I found a MouseDragGestureRecognizer Class, but i am not able to implement. Actually i have just a JList, from which Strings are dragged, and a JPanel, on which the Strings are dropped.
    The drag and dropping functions, but i need the mouse position on the JPanel, when the String is dropped.

  • Get Current Mouse Position

    Is there a way to get the current mouse position on the screen? Unfortunately, I cannot use a listener to provide the mouse position, because I don't know what components (if any) that the mouse is over. I am trying to draw in the glass pane during a drag and drop. During a drag and drop, the glass pane does not get mouseEntered or mouseMoved events (which I would have used to get the ouse position if I could). So I was hoping for a static method that I could use within the glass pane's paint method to give me the current absolute position of the mouse.

    a time ago i used the glasspane and the mousemotionlistener works perfect. you only should be sure to show ( setVisible(true) ) your glasspane. the best way is to look onto the java tutorial how they did it.
    link: http://java.sun.com/docs/books/tutorial/uiswing/components/rootpane.html
    tobais

  • Bitmap Rotation According to Mouse Position?

    Hi,
    I am working on a 2d computer graphics project, and I need a good function to rotate a Bitmap 360 degree according to my mouse position.
    for example: 

    Hi,
    I am working on a 2d computer graphics project, and I need a good function to rotate a Bitmap 360 degree according to my mouse position.
    for example: 
    Hello,
    To rotate that image, we need to deal with the following tips.
    1. The image size.
    If the area for that image rotated is not big enough, it will just lose some parts of that image.
    Here is a nice code shared in this thread
    http://stackoverflow.com/questions/5199205/how-do-i-rotate-image-then-move-to-the-top-left-0-0-without-cutting-off-the-imag/5200280#5200280.
    private Bitmap RotateImage(Bitmap b, float Angle)
    // The original bitmap needs to be drawn onto a new bitmap which will probably be bigger
    // because the corners of the original will move outside the original rectangle.
    // An easy way (OK slightly 'brute force') is to calculate the new bounding box is to calculate the positions of the
    // corners after rotation and get the difference between the maximum and minimum x and y coordinates.
    float wOver2 = b.Width / 2.0f;
    float hOver2 = b.Height / 2.0f;
    float radians = -(float)(Angle / 180.0 * Math.PI);
    // Get the coordinates of the corners, taking the origin to be the centre of the bitmap.
    PointF[] corners = new PointF[]{
    new PointF(-wOver2, -hOver2),
    new PointF(+wOver2, -hOver2),
    new PointF(+wOver2, +hOver2),
    new PointF(-wOver2, +hOver2)
    for (int i = 0; i < 4; i++)
    PointF p = corners[i];
    PointF newP = new PointF((float)(p.X * Math.Cos(radians) - p.Y * Math.Sin(radians)), (float)(p.X * Math.Sin(radians) + p.Y * Math.Cos(radians)));
    corners[i] = newP;
    // Find the min and max x and y coordinates.
    float minX = corners[0].X;
    float maxX = minX;
    float minY = corners[0].Y;
    float maxY = minY;
    for (int i = 1; i < 4; i++)
    PointF p = corners[i];
    minX = Math.Min(minX, p.X);
    maxX = Math.Max(maxX, p.X);
    minY = Math.Min(minY, p.Y);
    maxY = Math.Max(maxY, p.Y);
    // Get the size of the new bitmap.
    SizeF newSize = new SizeF(maxX - minX, maxY - minY);
    // ...and create it.
    Bitmap returnBitmap = new Bitmap((int)Math.Ceiling(newSize.Width), (int)Math.Ceiling(newSize.Height));
    // Now draw the old bitmap on it.
    using (Graphics g = Graphics.FromImage(returnBitmap))
    g.TranslateTransform(newSize.Width / 2.0f, newSize.Height / 2.0f);
    g.RotateTransform(Angle);
    g.TranslateTransform(-b.Width / 2.0f, -b.Height / 2.0f);
    g.DrawImage(b, 0, 0);
    return returnBitmap;
    2. The location of that control which displays that image.
    If we use a picturebox, and set its sizemode to autosize like the following line, then if you just want to rotate that image to show, and you don't want to that affects the original image, then we need to keep its center point.
    this.pictureBox1.SizeMode = PictureBoxSizeMode.AutoSize;
    We could add resize event handler after we set image for that picturebox.
            Point pOrign;
            Size sOrign;private void Form1_Load(object sender, EventArgs e)
    this.pictureBox1.SizeMode = PictureBoxSizeMode.AutoSize;
    Image img = Image.FromFile(@"D:\Documents\New folder\New folder\TestImage.PNG");
    this.pictureBox1.Image = img;
    this.pictureBox1.InitialImage = img;
    pOrign = new Point(this.pictureBox1.Left , this.pictureBox1.Top );
    sOrign = new Size(this.pictureBox1.Width, this.pictureBox1.Height);
    this.pictureBox1.BorderStyle = BorderStyle.FixedSingle;
    this.pictureBox1.Resize += pictureBox1_Resize;
    private void pictureBox1_Resize(object sender, EventArgs e)
    this.pictureBox1.Left = this.pOrign.X + (this.sOrign.Width - this.pictureBox1.Width) / 2;
    this.pictureBox1.Top = this.pOrign.Y + (this.sOrign.Height - this.pictureBox1.Height) / 2;
    3. The angle between that center point and your mouse postion.
    We could get that value inside the picturebox's container's mouse_move event.
    Double angleNew ; private void pictureBoxContainer_MouseMove(object sender, MouseEventArgs e)
    angleNew = Math.Atan2(this.pOrign.Y + this.sOrign.Height / 2 - e.Y, this.pOrign.X + this.sOrign.Width/2 - e.X) * 180.0 / Math.PI;
    But when to start rotate that image, it should be your chooice, and you could decide when rotate that image with the following line.
    this.pictureBox1.Image = (Image)RotateImage(new Bitmap(this.pictureBox1.InitialImage), (float)angleNew);
    If you just want to save that change to that image, then you could save that bitmap to file directly.
    Happy new year.
    Regards.
    Carl
    We are trying to better understand customer views on social support experience, so your participation in this interview project would be greatly appreciated if you have time. Thanks for helping make community forums a great place.
    Click
    HERE to participate the survey.

  • Rotate matrix by mouse position.

    Hey guys I have been banging my head against this problem for the past few hours.  I have a rectangle object created, I want the rectangle's rotation to follow my mouse cursor. ( I am easily able to do this).  Where things get hard is that I want the rectangle to rotate around it's bottom right corner, to do this I've found that I need to use a matrix transformation.  At this point I am able to have my rectangle rotate around the bottom right point, but I cannot figure out how to have it follow my mouse cursor as well while rotating.  The reason being that with a matrix you can only tell it a amount of radians to rotate (matrix.rotate) rather than just being able to set its current rotation.... Here is my code
    var point:Point=new Point(myRectangle.x+myRectangle.width/2, myRectangle.y+myRectangle.height/2);
    function rotateObject( event:Event ):void
              var m:Matrix=myRectangle.transform.matrix;
                                  m.tx -= point.x;
                                  m.ty -= point.y;
                                  m.rotate (45*(Math.PI/180));
                                  m.tx += point.x;
                                  m.ty += point.y;
                                  myRectangle.transform.matrix=m;
    addEventListener( Event.ENTER_FRAME, rotateObject);
    So with the current code it is constantly rotating around the bottom right corner, I have tried changing the "45" to "Math.atan(mouseX/mouseY), but again it seems that would only work if i could set the rotation of the matrix to that rather than telling it how much to rotate by....
    Any thoughts or ideas would be much appreciated, thanks!

    can you not calculate the new rotation based on the mouse position and the rotate by the difference with the current rotation on your rectangle?
    function rotateObject( event:Event ):void
              var newRot:Number = Math.atan(mouseX/mouseY);
              var rotationDelta:Number = myRectangle.rotation - newRotation
              var m:Matrix=myRectangle.transform.matrix;
                                  m.tx -= point.x;
                                  m.ty -= point.y;
                                  m.rotate (rotationDelta*(Math.PI/180));
                                  m.tx += point.x;
                                  m.ty += point.y;
                                  myRectangle.transform.matrix=m;

  • Interesting way to detect array index from mouse position

    Ever programmed something and then been surprised it works? This was the first time for me. Wrote a bit of code with the intention of identifying the array index clicked from the mouse position for use in a 'mouse down?' event and it worked first time. Then I went back and realised I had been half asleep and it doesn't even use the mouse position- but as if by magic it works!
    VI snippet below. For some reason LabVIEW modifies the array reference when I create a snippet, so you'll need to change that array reference for one pointing to array 2. <= Anyone able to raise a CAR against this?

    In the past I've used this VI.  I think it is quite similar to yours and I could probably simplify based on what you have done.  One thing my VI does is it tries to take into account the scrollbar size if one is being shown for the array.
    Unofficial Forum Rules and Guidelines - Hooovahh - LabVIEW Overlord
    If 10 out of 10 experts in any field say something is bad, you should probably take their opinion seriously.
    Attachments:
    Coordinates to Index.vi ‏20 KB

  • Getting mouse position without a listener

    Hi all,
    I'm trying to achieve the equivalent of Component.getMousePosition() that Sun
    so kindly put into 1.5, without forcing all my users to immediately upgrade to 1.5.
    Any ideas? Just the normal relative-to-component mouse position is all I need, but I have to get it even if the mouse hasn't moved, so there are no events.
    Thanks a lot

    I guess the easiest way is still to use a MouseMotionListener that you could add to your top level container. You could then store the value of the last position and still be able to access it even if the mouse hasn't moved.
    You might also want to use the following method : SwingUtilities.convertPointFromScreen(Point p, Component c);

  • Manually shift mouse position

    During a drag/drop operation, I want to do some calculation
    if the user pauses for a 1/2 second and potentially reposition the
    drag proxy object relative to the mouse or perhaps just move the
    mouse location. Essentially a “snap to grid” type
    thing. I've captured the pausing with a timer event but I need to
    do the repositioning. Does anyone know if there is there a way to
    do one of the following?
    1) Shift the offset of the proxy image on the fly?
    2) Shift the actual mouse position on the fly which will also
    shift the proxy image?
    I'd prefer the 1st option but the 2nd would work too.
    Thanks very much in advance!

    I'm sure there's somebody out there who would know better
    than I do, but in lieu of that, my guesses for you:
    1) No - I don't think so, though you could implement the
    drag/drop functionality yourself and have full control.
    2) I really doubt it, since the position of the mouse is
    courtesy of the operating system.

  • Zooming image from mouse position(like in  windows vista photo gallery)

    hello all;
    here's my situation, hope someone can help..
    i wanna Zoom an image, which zoom from my mouse position
    like in windows photo gallery in windows vista
    so i do this..
    g2.translate(iMoux,iMouy);       
            g2.scale(zoom, zoom);       
            g2.translate(-iMoux,-iMouy);       
            g.drawImage(icon.getImage(), iSposx, iSposx, d.width/2-iValue, d.height-iBawah, null);
            g.drawImage(icon2.getImage(), d.width/2, iSposy, d.width/2-iValue, d.height-iBawah, null);the problem come when i move my mouse to the different location (like from top right to bottom left)
    the zoom image displayed in the screen like jump from latest location to new location
    anybody can help me...a clue how to do that?
    thx appreciate your help guys
    mao
    Edited by: KingMao on 31 Mei 08 14:27

    Hi Frank.
    Thanks for the response.
    Agreed, the pertinent question is why can't my colleague edit the JPG exported by Aperture. It's probably also worth pointing out, the same problem occurs with JPGs exported from iPhoto.
    The Windows software usually plays nicely with JPGs by all acounts, just not the ones I send - which I do via eMail or my public space on Mobile Me incidently.
    So, another key question is: all settings being equal (color profile, quality, etc.) are the JPGs as produced by iPhoto and Aperture indistinguishable from those produced by other apps on other platforms - i.e. does the use of JPG enforce a common standard?
    If that is the case, I suspect ours might be a permissions issue.
    According to the Microsoft support page on editing in Windows Live Photo Gallery, the inability to edit a picture is commonly caused by unsupported file type, or read-only attribute set on the file.
    Unfortunately, he and I are not in the same place, and he's not particularly au-fait with this type of problem solving. Hence, before involving him, I'd like to know:
    1. it's possible (i.e. someone else does it), and,
    2. what's involved (at my end and/or his).
    Thanks again,
    PB

Maybe you are looking for

  • Problem creating a 'used sources' list based on EXIF data in InDesign CS5

    Hello everyone, I recently started to use InDesign CS5 to work on school projects. These projects regularly require us to have a list of sources, not only for citations and referenced work, but also for images. As I sometimes make quite long document

  • How to remove buttons from a selection-screen as window.

    Hello SAPients. I'm using CALL SELECTION-SCREEN 100 STARTING AT 10 10 to call a previously created selection-screen. The window shows 4 buttons: Execute,  Check input, Save as variant and Cancel. The user is asking to remove the Check input and Save

  • C6280 Photo printing problems

    Any time I want to print photos on HP photo paper they come out with alot of pink and yellow - grey clouds show up as pink and light green shows as yellow.  It doesnt matter if I use the printer 'reprint photos' button or go through the print functio

  • I want to install my Photoshop Exange CC and does not work me.

    I want to install my Photoshop Exange CC and does not work me.

  • ROWTYPE and "Too many values" error...

    I'm in the middle of trying to understand the inner workings of %ROWTYPE and how I can copy the structure of a table with it. I think I'm understanding the gist of it, but I continue to fail in pinpointing the actual values I try to insert with an ex