Move an animator object from right to left

How do I move an animator object from right to left? I tried using the value with a minus sign in front of it. (i.e. -(xcoord) ) Please help.
Thanks,
Chris

After you create the animator, click on it on the panel, you will see a rectangle. You can drag the rectangle to bigger or smaller. The graphic will be moving inside of this rectangle. In this rectangle, bottom left corner is x0 y0. Top right cornet is x100, y100.
Ryan Shi
National Instruments
Attachments:
process1.zip ‏1 KB

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How to shift Negative sign from Right to left

Hi friends,
please tell me How to shift Negative sign from Right to left for quan data type i am getting on right side but i want to display it on left exactly preceding my output number display.

hi yogesh
check this function module..
<u><i><b>CLOI_PUT_SIGN_IN_FRONT</b></i></u>
this will move the negative sign from the left hand side of a number, to the right hand side of the number. Note that The result will be left justified (like all character fields), not right justifed as numbers normally are.
chck this example..
data: a1 type i value 56 ,
a2 type i value 60,
res type i.
res = a1 - a2.
data: res1(10).
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I<u><i><b>MPORTANT</b></i></u>
You can use this FM CLOI_PUT_SIGN_IN_FRONT.
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Message was edited by:
navjot sharma

Execution from right to left : a=b=c;

Help!
I am using a tutorial to study for the certification exam.
Unfortunately, I do not understand the answer of a very simple question.
Can you give me a hand on this one?
************* This is the Question of the tutorial ************************************
After the execution of the code-fragment below, what will be the values of i and a?
1.     public class CalcMe {
2.     public static void main(String[] args) {
3.     int [] b = {3,7};
4.     int i = 2, a = 4;
5.     b[i] = i = 0;
6.     a += b;
7.     }
8.     }
Answer 1 i: 0 a: 11
Answer 2 i: 0 a: 4
Answer 3 i: 3 a: 4
Answer 4 An exception is thrown
Answer 5 None of the above
************* This is the Answer to the Question of the tutorial ************************************
After the execution of the code-fragment below, what will be the values of i and a?
1. i: 0 a: 11
2. i: 0 a: 4
3. i: 3 a: 4
4. An exception is thrown
5. None of the above
Answer 4 is correct, an ArrayIndexOutOfBoundsException is thrown at line 5. The value of i
evaluated from the right hand side to the left, it is element b[2] that should get a value assigned,
arrays in Java starts from 0, element 2 is out of scope.
*************************** This is my answer *********************************************************
Despite I read the answer (and created and run it) I still do not understand how line 5 is executed because it seems
that the expression is evaluated from left to right instead of right to left.
I believe that correct answer should be:
in line 5. b[i]=i=0 if expression is executed from right to left then
first i=0 and after that b[0]=0
which leads to believe that the values for i & a will be : i=0 a=4
[Copied from Complete Java 2 Certification Study Guide ISBN 0-7821-4077-7 Phillip Heller & Simon Roberts Chapter #2 Operators and Assignments Page 66]
Given three int varibles a,b,c, the statement a=b=0; is entirely legal. It is executed from right to left,
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that was assigned to the left side - that is 0. Next, the assignment of b takes place, using the value of
the expression to the right to the equal sign-again, 0. SImilarly, that expression takes the value that was assigned ,
so finally the variable a is also set to 0.
I'd appreciate an explanation

Does this mean that the assignment of indexes in arrays have higher priority than assignment operations?
in other words,
b[2]= ...whatever
will happen before anything else is evaluated in the right side of the expression.
Is that right?
Bingo. Section [url
http://java.sun.com/docs/books/jls/second_edition/html/
xpressions.doc.html#5295]15.26.1:"If the left-hand operand expression [of a simple
assignment operator] is an array access expression
(15.13), then many steps are required:
# First, the array reference subexpression of the
left-hand operand array access expression is
evaluated. If this evaluation completes abruptly, then
the assignment expression completes abruptly for the
same reason; the index subexpression (of the left-hand
operand array access expression) and the right-hand
operand are not evaluated and no assignment occurs.
# Otherwise, the index subexpression of the left-hand
operand array access expression is evaluated. If this
evaluation completes abruptly, then the assignment
expression completes abruptly for the same reason and
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# Otherwise, the right-hand operand is evaluated. If
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Transferring the negative sign from Right to Left for a currency field.

Hi All,
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I am trying to transfer the negative sign by first converting the currency field into character field.
Kindly help for the same.
Thanks,
Sharadendu

Hi,
Use FM CLOI_PUT_SIGN_IN_FRONT.
Try this code as well
data: var(10),
length type i.
var = '300-'.
write var.
length = strlen( var ).
length = length - 1.
replace first occurrence of '-' in var+length(1) with ''.
concatenate '-' var into var.
write:/ var.
Regards,
Satish
Message was edited by:
Satish Panakala

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use this
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link
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<script src="http://ajax.aspnetcdn.com/ajax/jQuery/jquery-1.9.1.min.js" type='text/javascript'></script>
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    <hr/>
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            <option value="right">Right</option>
            <option value="left">Left</option>
            <option value="up">Up</option>
            <option value="down">Down</option>
        </select>
        <button id="button" class="myButton">Run Effect</button>
    </p>
<div id="myDiv">
        <p>Lorem Ipsum is simply dummy text of the printing and typesetting industry. Lorem Ipsum has been the industry's standard d still in their infancy. Various versions have evolved over the years, sometimes by
accident, sometimes on purpose (injected humour and the like).</p>
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</div>
Thanks.

Hi ,
Vincent Han thanks for ur reply.
this is my latest code but still not working.
having same issue : panel is about to slide but as soon as page gets refreshed it starts sliding and return on ppage as it is.
<html xmlns="http://www.w3.org/1999/xhtml">
<head runat="server">
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</body>
</html>

Move an animator object from right to left

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