Moving a document library to the top level subsite

Hi community
As part of period of extensive user engagement, I want to move the development documents library to the main community site I have set up for the project board ( rather than project office site where it is now). Now I don't do this very often - last
time was in MOSS 2007 but I find myself scratching my head as to why are can't in the brave new world of SharePoint 2013. I tried in SPD 2013 and that didn't work either.
I have checked that all the relevant documents are check in. I wonder if it is a publishing feature restriction a bit like site templates????

One way to do this (via the UI), is to save the document library as a list template (and include the contents of the list with the template). Then create a new list from the template in the root site (and afterwards, delete the old list).
Regards, Matthew
MCPD | MCITP
My Blog
View
Matthew Yarlett's profile
See my webpart on the TechNet Gallery that allows administrative users to upload, crop and format user profile photos. Check it out here:
Upload and Crop User Profile Photos

Similar Messages

Display a document library from the top site on a subsite

I want to display a document library located on the top site in a webpart located on a subsite.
I've found different solutions in 2010 but none of them have been possible to achive in 2013.
The only way that i've got it working in 2013 is described in
this Stackexchange-post, however this solution will give the webpart it's own ribbon inside of the webpart-frame.
Im wondering whether it's possible to achieve this in 2013 OOTB.
Kr, Rasmus

Depends, you could use the content search web part to dipslay the document lbirary, bit in that case the result is limited to what's already indexed.
Kind regards,
Margriet Bruggeman
Lois & Clark IT Services
web site: http://www.loisandclark.eu
blog: http://www.sharepointdragons.com

Failed to load XML from the package file "" due to error 0xC00CE556 "Invalid at the top level of the document.Line.

Using Installation wizard to deploy SSIS packages from DEV server to QA server package store cause this error;
Failed to load XML from the package file "" due to error 0xC00CE556 "Invalid at the top level of the document. Line 773, Column 93". This happens when loading a package and the file cannot be opened or loaded correctly into XML document. This can be the
result of either providing an incorrect file name to the LoadPackage method or the XML file specified having an incorrect format. Please who have the idea of how this issue can be resolved?BI Developer

Hi ,
for this Error one and only one solution
go to view Code, line number and Column number shown in error message,
and Remove code from there till last and save it, it happens when we are moving Package from one server to another server. and VS adds some lines of code at the bottom of package
something like this
andles="1" allownudging="1" isannotation="0" dontautolayout="0" groupcollapsed="0" tabstop="1" visible="1" snaptogrid="0">
<control>
<ddsxmlobjectstreaminitwrapper binary="00080000921400008c040000" />
</control>
<layoutobject>
<ddsxmlobj>
<property name="LogicalObject" value="{BBFB0E
Remove this code and save package it will work.
hope this will help to Developers who are searching for same ......... :)

Portal Invalid at the top level of the document. Error processing resource...

We installed WebLogic Portal. We were able to bring up the webpage while we were configured on port 80. As soon as we wired the portal for port 443, it would not display page. Error: Invalid at the top level of the document. Error processing resource...
We are on a VM with Redhat Linux 5. Oracle Weblogic portal 10.3.5
Has anyone had this issue in the past and was able to resolve it?

Did you upgrade your Portal to 10.1.4? Are you using the Web Cache port # or the HTTP Server port #? You can get this error message if you use the HTTP Server port # on Portal 10.1.4.

XSQL file "Invalid at the top level of the document"

I am trying to insert HTML form parameters into database using <xsql:insert-request>. It worked fine except that it displays <xsql-status action="xsql:insert-request" rows="1"/> after it inserts the data into the database. I am trying to follow the insertnewsform example in Steve's book "building oracle xml applications" to return user a thank-you note. Here is my problem:
I have four files:
faqform.html (html form, action=faqfeed.xsql)
faqfeed.xsql
request-to-faq.xsl (used as transform for faqfeed.xsql)
thankyou.xsl (used for returning user a thank-you)
When I submit the html form, I get an error saying:
"The XML page cannot be displayed
Cannot view XML input using style sheet. Please correct the error and then click the Refresh button, or try again later.
Invalid at the top level of the document. Line 1, Position 43
<?xml version = '1.0' encoding = 'UTF-8'?>"
I didn't put "encoding..." in any of my xsql files, not sure where that came from. When I used faqfeed.xsql?xml-stylesheet=none in the url and it showed up as a well-formed xml file with all the info I need. Here is my faqfeed.xsql and thankyou.xsl
********* faqfeed.xsql ***********
<?xml version="1.0"?>
<?xml-stylesheet type="text/xsl" href="thankyou.xsl"?>
<page connection="template" xmlns:xsql="urn:oracle-xsql">
<xsql:insert-request table="faq" transform="request-to-faq.xsl"/>
<xsql:query tag-case="lower" max-rows="5" rowset-element="" row-element="faq">
select * from faq
</xsql:query>
</page>
********* thankyou.xsl **********
<html xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xsl:version="1.0">
<head><title>Thank you!</title></head>
<body>
<h3>Thank you for your faq!</h3>
Your faq has been successfully inserted to the database!
<table>
<xsl:for-each select="page/faq">
<tr>
<td><xsl:value-of select="question"/></td>
<td><xsl:value-of select="answer"/></td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
Anything I am missing here that caused that error? Any hints would be greatly appreciated!
Wenqi
null

Do the XSQL Demos work correctly on your system?
The error you're getting seems like maybe the *.xsql extension is not mapped properly to the oracle.xml.xsql.XSQLServlet class in your servlet engine.

Invalid at the top level of the document in XML file

Hi,
I am sending an XML file (Which is generated by SAP) through mail to the receiver. When the receiver opens the file he is getting the below error. Kindly help me to rectify this error.
The XML page cannot be displayed
Cannot view XML input using XSL style sheet. Please correct the error and then click the Refresh button, or try again later.
Invalid at the top level of the document. Error processing resource 'file:///C:/Documents and Settings/bnkrishnan/Desktop/X...
Regards,
Navaneeth...

Hi guys,
Could any one help me in this?
Regards,
Navaneeth

Can the top level navigation be three levels?

Hello, everyone!
How many top level navigation can i have at most? It seems that SAP Portal just provide two levels.
Thanks.
Ruanrq.

Hi,
There is only possible for 0,1,2 top level navigation. Not possible for 3 levels. Check the below link for details.
http://help.sap.com/saphelp_nw04/helpdata/en/5a/33befa45ca7f459b24d0c5d51d0749/frameset.htm
But you can customize the top level navigation. Check the below document.
https://www.sdn.sap.com/irj/sdn/go/portal/prtroot/docs/library/uuid/dae78be4-0601-0010-c9ab-c0b8d86fac07
Regards
Basheer

Show a menu of roles in the Top Level Navigation

Hello,
Imagine a scenario where a user has many roles assigned to him (say 40 roles). In that case the user will have 40 tabs in the first level of the top level navigation and by default a horizontal scroller appears on the right part of the screen clicking on which the roles will scroll horizontally. If the user has to go to the 40th role he has to click quite a lot.
Is it possible to have a menu option clciking on which we get the all the list of roles in the top level navigation in a vertical list and we can directly jump to any role clicking on the entry in the list ?
Something like what we get in a tab strip in Web Dynpro.
Thanks in advance for your valuable inputs.
Sundeep
Edited by: Sundeep Sethi on May 3, 2011 3:00 PM

Hi,
Yes it is possible to have menus as you wish .
Look at the following links
http://www.sdn.sap.com/irj/scn/index?rid=/library/uuid/6066b302-09c8-2a10-a894-eb9fef30df85
http://www.sdn.sap.com/irj/scn/go/portal/prtroot/docs/library/uuid/c0a1aea5-a2d1-2a10-c6bc-953bdadfdcb8?QuickLink=index&overridelayout=true
You need to work on navigation tag libraries to extend number of levels .
The above inks helps you only for single level of navigation.
Regards
Karthiheyan M

How can I choose to save a download straight into a sub-folder, rather than just a folder at the top level?

I have altered my preferences on firefox so that it asks me where I wish to save a file I am downloading, but when it opens the box for me to choose the location, only the top level of files is offered (i.e. documents) and not more specific files that are within that file (i.e. pay slips). How can I access these other levels directly? At the moment, I have to save to the desktop and then transfer to the appropriate file later.
Thank you.

Hello,
I think you are looking for this:
https://support.mozilla.org/en-US/kb/change-firefox-behavior-when-open-file

XML document must have a top level element. Error processing resource

Hi,
I am trying to send a XML file to a web browser from a servlet. I read the contents of the XML file into a string and I am sending it to the brower. Before I do this I set the 'Content-type' header of the httpResponse to "application/xml" . Embedded in the XML file is an xml-stylesheet elemetn indicating which *.xsl stylesheet to use to parse the XML content.
I get the following error:
The XML page cannot be displayed
Cannot view XML input using XSL style sheet. Please correct the error and then click the Refresh button, or try again later.
XML document must have a top level element. Error processing resource 'http://127.0.0.1:8080/testReplyingXML/xml-to-html.xs...
Now, if I take the stylesheet element out of the XML string I sent, then the browser stores the content into and *.xml file. I manually run the "xml-to-xsl " stylesheet mentioned in the error output above, and there is no problem, the xml content gets successfully transformed in a viewable HTML .
It is only when I embed the "stylesheet" element into the XML content that I get this error.
So the browser is receiveing valid XML.
I am not sure if the above error is complaining about the XML content I send or the stylesshet .
Does anyone have an idea of what am I doing wrong?
For your information here are my servlet code and the XML file:
servlet:-
package webapps.testReplyingXML;
import java.io.BufferedReader;
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import java.io.FileReader;
import java.util.Enumeration;
import java.util.StringTokenizer;
import java.io.PrintWriter;
public class ReplyXML extends HttpServlet {
          static int transactionCount = 0;
          public void doGet(HttpServletRequest req, HttpServletResponse res) throws ServletException ,IOException {
               String Q_PARAM = "query";
               String requestString = req.getQueryString();
               for ( Enumeration en = req.getParameterNames() ; en.hasMoreElements() ; )
     String k = (String)en.nextElement() ;
     String[] x = req.getParameterValues(k) ;
     String s = null;
     String DATA_PARAM= "";
     for(int i = 0 ; i < x.length ; i++ )
     s = x[i] ;
     //System.out.println("s = " + s);
     if (k.equals("query")){
          try {
                         //res.setHeader("Content-Type", "application/xml");
                         //res.setHeader("Transfer-Encoding", "chunked");
                         //res.setHeader("Cache-Control", "no-cache");
                         //res.setHeader("Server", "Jetty/5.1.10");
                         //res.setHeader("Pragma", "no-cache");
                         //res.setHeader("X-Joseki-Server", "Joseki-3.0-dev");
                         res.setStatus(res.SC_OK);
                         StringBuffer fileData = new StringBuffer(1000);
                    BufferedReader reader = new BufferedReader(new FileReader("sparql_results.xml"));
                    char[] buf = new char[1024];
                    int numRead=0;
                    while((numRead=reader.read(buf)) != -1){
                    String readData = String.valueOf(buf, 0, numRead);
                    fileData.append(readData);
                    buf = new char[1024];
                    reader.close();
                    String xmlMsg= fileData.toString();
                    System.out.println("XMLMSG= " + xmlMsg);
                         PrintWriter outresp = res.getWriter();
                         outresp.println(xmlMsg);
                         outresp.close();
          }catch (Exception e) {
               e.printStackTrace();
          public void doPost(HttpServletRequest req, HttpServletResponse res) throws ServletException, IOException {
               doGet(req, res);
XML FILE:
<?xml version="1.0"?>
<?xml-stylesheet type="text/xsl" href="xml-to-html.xsl"?>
<sparql
xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#"
xmlns:xs="http://www.w3.org/2001/XMLSchema#"
xmlns="http://www.w3.org/2005/sparql-results#" >
<head>
<variable name="book"/>
<variable name="title"/>
</head>
<results ordered="false" distinct="false">
<result>
<binding name="book">
<uri>http://example.org/book/book6</uri>
</binding>
<binding name="title">
<literal>Harry Potter and the Half-Blood Prince</literal>
</binding>
</result>
<result>
<binding name="book">
<uri>http://example.org/book/book5</uri>
</binding>
<binding name="title">
<literal>Harry Potter and the Order of the Phoenix</literal>
</binding>
</result>
<result>
<binding name="book">
<uri>http://example.org/book/book4</uri>
</binding>
<binding name="title">
<literal>Harry Potter and the Goblet of Fire</literal>
</binding>
</result>
<result>
<binding name="book">
<uri>http://example.org/book/book3</uri>
</binding>
<binding name="title">
<literal>Harry Potter and the Prisoner Of Azkaban</literal>
</binding>
</result>
<result>
<binding name="book">
<uri>http://example.org/book/book2</uri>
</binding>
<binding name="title">
<literal>Harry Potter and the Chamber of Secrets</literal>
</binding>
</result>
<result>
<binding name="book">
<uri>http://example.org/book/book1</uri>
</binding>
<binding name="title">
<literal>Harry Potter and the Philosopher's Stone</literal>
</binding>
</result>
</results>
</sparql>

Error processing resource http://127.0.0.1:8080/testReplyingXML/xml-to-html.xs...
Well, if one more character had been deleted from that message then you would have a problem. But as it is, the error message says there's an error processing a resouce whose name ends with "xml-to-html.xs" followed by something. That would be the stylesheet if I'm not mistaken. Most likely the browser can't find it at the URL mentioned in the error message.

Opening a Remote Panel of the Top Level vi for an executable

Hello Everyone
I was wondering how you would open up a remote panel for the top-level vi in an executable?
I have created a LabVIEW application and have tested opening the remote panel when it is running in the full labview development suite - this all works fine. I simply go operate>connect to remote panel and enter the server address, the port (8000) and the vi name using the path "My Project.lvproh/My Computer/main.vi" format.
However, if I then build this application into an executable I do not seem to be able to open a remote panel - it might be that I am just entering the VI name incorrectly.
with VI name = "main.vi" or with VI name = "C:\builds\main.exe\main.vi" and the exe. running I get the error:
Connecting to remote panel server...
Requested VI is not loaded into memory on the server computer
However I am not sure how else I would enter it.
The main.ini has the following configuration:
server.app.propertiesEnabled=True
server.ole.enabled=True
server.tcp.acl="0800000008000000"
server.tcp.enabled=True
server.tcp.paranoid=True
server.tcp.port=6363
server.tcp.serviceName=""
server.vi.access=""
server.vi.callsEnabled=True
server.vi.propertiesEnabled=True
WebServer.Enabled=True
WebServer.TcpAccess="c+*"
WebServer.ViAccess="+*"
DebugServerEnabled=True
DebugServerWaitOnLaunch=False
Both machines have LabVIEW 2011 Profesional Development System SP1 on so I do not think it is a limited remote access licence issue.
Any suggestions as to where I am going wrong would be much appreciated.
Cheers
John
Solved!
Go to Solution.

It appears that you can infact use remote panels within an executable.
The problem I had was that I had left the web server port for the remote panels the same as the LabVIEW development environment. That meant that the main LabVIEW web server was getting in the way of the web server that was associated with my built application.
With the application's web server on a different port and the VI in memory (and the file in a library/directory external to the exe if it is not the top level VI), you just need to specify the VI name such as main.vi .
Solved!

Passing data from a subvi to the top level with continuously running loops

Hi All,
This is a very simple question, for some reason the data available at a subvi indicator is not making it to the top level vi. I think it might be something to do with the while loop I am using but I cant figure it out, any help will be appreciated. I don't think I fully understand how the data gets out of a continuously running loop.
GPSdisplay runs a driver called GPS.vi (im not worried about my event structure just yet which might be wrong, but I am yet to test that bit yet) Probe 1 should have the values from GPSCluster
Loop within GPS.vi. GPSCluster (Probe 2) is being updated correctly
I cant work out why the data is not being passed to GPSCluster in the top vi
Solved!
Go to Solution.

Hi bennymacca,
I think you are on the right track with an FGV. You can do this fairly easily with the GPS vi that you have.
Before I go any further, your GPS while loop will only return the last reading, and because the "Read" boolean output state is FALSE, it will not stop. Do you see it exit at all? From the logic I read, once entering this while loop it won't stop until told to.
There are a 3 options you can try.
1) Use an FGV, as you are looking into. To do this you will need to change the state boolean to TRUE and put shift registers in for the GPSCluster - to parse the information around, holding it each time the vi is called and exited. Outside the while loop you will wire up the Cluster to the indicator that you wish to collect (OR, you could have it inside the case statement where it is read - be careful here, though).
2) in the main code, above the sequence frame you can place the GPS vi while loop (the "Read" one), having the state boolean wired to a Stop button local variable. This while loop will start depending on how LV feels, so wire an error line to both the While loop and Frame start (indicating that both are to run in a parallel fashion), OR you can put it in a case statement and say 'go' when you want to start reading. With this while loop, you can then output the Read data directly into your Cluster variable as it is generated.
But, with (2) you are moving yourself away from the purpose of the GPS vi, which would be to bring all functionality of the GPS functionality into one sub vi - which is a good idea.
3) put a condition on the "Read" case statement boolean state - only make it TRUE when you wish to stop reading data (do you have a time or condition you can refer to here?). Even doing so, you would/may still need shift registers on your while loop to retain data for each iteration.
I hope all of that helps. Cheers. David.

XML document must have a top level element. Error

Hi, I am trying to generate an XML. Below is a sample code from my function. The function generates a 0 byte file which when I try to open gives me 'xml document must have a top level element' error. Any ideas?
FUNCTION generateXml(    p_1      VARCHAR2,
                         p_2      VARCHAR2,
                         p_3      VARCHAR2
                         ) RETURN CLOB
IS
    ctx dbms_xmlgen.ctxHandle;
    xml CLOB;
    v_sql varchar2(2000);
BEGIN
lv_sql:=' select * from v_dc where rownum =1';
ctx := dbms_xmlgen.newContext(v_sql);
dbms_xmlgen.setRowSetTag(ctx, 'CONTENT');
xml := dbms_xmlgen.getXML(ctx);
return xml;
END;
END generateXml;

I just need to understand if we can generate XML from a sql that has sub-queries in it.Should be no problem:
SQL> create or replace function generatexml (p_1 varchar2, p_2 varchar2, p_3 varchar2)
return clob
is
ctx     dbms_xmlgen.ctxhandle;
xml     clob;
v_sql   varchar2 (2000);
begin
v_sql := ' select * from dept left outer join (select * from emp) emp on (emp.deptno = dept.deptno) where rownum = 1';
ctx := dbms_xmlgen.newcontext (v_sql);
dbms_xmlgen.setrowsettag (ctx, 'CONTENT');
xml := dbms_xmlgen.getxml (ctx);
dbms_xmlgen.closecontext (ctx);
return xml;
end generatexml;
Function created.
SQL> select generatexml (null, null, null) xml from dual
XML
<?xml version="1.0"?>
<CONTENT>
<ROW>
<DEPTNO>10</DEPTNO>
<DNAME>ACCOUNTING</DNAME>
<LOC>NEW YORK</LOC>
<EMPNO>7782</EMPNO>
<ENAME>CLARK</ENAME>
<JOB>MANAGER</JOB>
<MGR>7839</MGR>
<HIREDATE>09.06.81</HIREDATE>
<SAL>2450</SAL>
<DEPTNO>10</DEPTNO>
</ROW>
</CONTENT>
1 row selected.Maybe your query simply doesn't return any rows?

Help: How to make the top level navigation into vertical at the left panel

We have a need to change the top-level and 2nd-level navigation bars (horizontal)
into the nodes on the left navigation panel (vertical).
We find some way but it is a very extensive job.
Is there any way to do it quickly?
Thanks a lot! Points guaranteed.

Hi,
Try to develop your own menu by using Navigation Tag Libraries. Check this link :
<a href="http://help.sap.com/saphelp_nw04/helpdata/en/42/f35146a7203255e10000000a1553f7/frameset.htm">Navigation Tag Library</a>
There is also sample codes. You can start your project from this codes.
Regards
Abdul.

XML document must have a top level element

Hi all,
I have deployed my web services in 904. When I try to see the generated wsdl, I am seeing:
XML document must have a top level element.
in IE. Does anyone know why?
Thanks.

If you take a look under the location where the application was deployed, you should find a file with the name of your interface (or class) and the extension .wsdl.
If there is already a file of that name, we do not try to re-generate it. If this file is not a valid XML file, then it will explain the error message you are seing.
Another reason for this error is when the code generation fail silently. It can occurs in some rare case, when you have started oc4j using a JRE instead of JDK (without javac).
Hope this helps,
Eric

Moving a document library to the top level subsite

Similar Messages

Maybe you are looking for