Moving the last record to 1st position
Hi,
I have 200 records in my internal table.I want to move the last record(200 position) to 1st position(i.e Index1). How to do it?
Hi
U can try something like this
DATA: BEGIN OF ITAB OCCURS 0,
FIELD(1) TYPE C,
END OF ITAB.
DO 9 TIMES.
MOVE SY-INDEX TO ITAB-FIELD.
APPEND ITAB.
ENDDO.
* Check table
DESCRIBE TABLE ITAB LINES SY-TABIX.
* Read last record
READ TABLE ITAB INDEX SY-TABIX.
* Delete last record
DELETE ITAB INDEX SY-TABIX.
* Append the last record to the top
INSERT ITAB INTO ITAB INDEX 1.
LOOP AT ITAB.
WRITE: / ITAB.
ENDLOOP.
Max
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Can anyone help me to tell me:
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A. Use FCC at sender side, it will convert CSV to XML like this
Input XML
<documentName>
<recordset>
<record>
<Time>20110820</Time>
<ID>220DNE0220</ID>
<Quan>140.13</Quan>
<Volume>0.000</Volume>
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Create a target DT like this
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<record>
<StartTime>20110820</StartTime>
<EndTime>20110822</EndTime>
<Quan>140.13</Quan>
<Volume>0.000</Volume>
<Auc>E01</Auc>
<No>0</No>
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1.Time -> CopyValue[0] -> StartTime
2.Time -> below UDF -> EndTime
3.Quan -> Quan
4.Volume -> Volume
5.Auc -> Auc
6.No -> No
UDF u2013 Execution type u2013 All values of Queue
public void getLastTimeValue(String[] inputEndTime, ResultList result, Container container) throws StreamTransformationException{
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B. At receiver use again FCC to convert XML to CSV.
FYI. If you want to optimize more, you can use
1.globalContainer concept OR
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Raghu_Vamsee -
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hi,
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Hi..
I am new to ABAP. So i have one condition to read the address number field in the last record from database table by using the person number where clause field.
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u mean to say
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aa1 0000000000001
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hope this helps,
Regards,
Vijay
Message was edited by: Vijay
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