Need clarification on the Hyperion stuff

Question

I have some clarification on the following question which i came in certification last 2 days back.
A calcualtion is performed on a database for which create block on equation is off.The command SET CREATEBLOCKONEQ ON is issued immediately before an equation in the script.which statements accurately describe when blocks will be created?
1) blocks will be created ONLY when the equation assigns non - constant values to members of sparse diemension.
2)blocks will be created only when the equation assigns constant values to memebers of sparse dimension
3)blocks will be created when the equation assignes either constant or non constant values to a members of sparse dimension
4)No blocks will be created.
please clarify on the above.

Answer 1

Vinith,
I suppose I could ask the obvious question: How do you happen to have a question from an Oracle certification test? I don't have access to those questions. How do you?
In the interests of actually providing (what I at least believe) the right answer, I think this thread is confusing what the docs say with what Essbase does.
If you use SET CREATBLOCKONEQ ON, the docs state that Essbase will create a block even with a non-constant assign. But Essbase will also create a block with a constant assignment -- it always does that. That makes the third answer correct.
Regards,
Cameron Lackpour