Need help reg SUBTOT

Hi,
I am using slis_sortinfo_alv for doing subtotal in a report,but the problem is i even wat to display some text like 'Subtot'before the value.
Need help.
I want to display my sub total like below format.
Ex:SubTot:2345

Hi,
Make use of the below statement :
display_text_for_subtotal = 'TEXT'.
For reference you can refer to LSLVC_FULLSCREENF02 Include program.
Thanks,
Sriram POnna.

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In sender JDBC channel, only one update query we can give...how i can update two tables?
Regards,
Venkata Ramana.

Hello Venkat,
For your requirement, go for stored procedure and find the below thread.
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Re: Executing an Oracle Stored Procedure from Sender JDBC adapter
Re: Sender JDBC adapter not picking up data
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Thanks,
Venky

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hi friends,
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pl forward to this mail id:[email protected]
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srikanth.

Hello Srikanth,
REMEDY : It is issue management tool used by the service provider to manage their tickets/issues. The documentation you can find from your project team, but mainly the process will be as follow for managing issues:
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db

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Hi,
I Have a table with below structure
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try this
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union
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hi wmchisholm!
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I need help.
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ls_sort-spos = 1.
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ls_sort-fieldname = 'SUBTOT'.
ls_sort-up = 'X'.
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PROCEDURE REGISTRO_551 (
VPNUMPARTE IN PARTESC.NUMPARTE%TYPE,
VPFRACCION IN IMPOMAT.FRACCIONMEXIMPO%TYPE,
VPDESCRIPCION IN PARTESC.DESCESPANOL%TYPE,
VPVALORDLS IN IMPOMAT.VALORDOLARES%TYPE,
VPCANTIDAD IN IMPOMAT.CANTIDAD%TYPE,
VPUNIMED IN PARTESC.UNIMEDPARTE%TYPE,
VPCANTIDADTARIFA IN IMPOMAT.CANTIDAD%TYPE,
VPVALORAGREGADO IN EXPOPT.VALORAGREGADO%TYPE,
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VPPESONETO IN IMPOMAT.PESONETO%TYPE,
VPTIPOMONEDA IN MIMPOMAT.TIPOMONEDAEXTRANJERA%TYPE
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BEGIN
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    IF LENGTH(VLTEMP)>80 THEN
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    END IF;
    vgproceso := 207313;
    vllong2:=length(vlCadena);
    IF VLTEMP IS NULL THEN
        vlCadena:=vlCadena||'|'; --3. DESCRIPCION
    ELSE
        vlCadena:=vlCadena||VLTEMP||'|'; --3. DESCRIPCION
    END IF;
    vgproceso := 207314;
    vllong2:=length(vlCadena);
    IF VPNUMPARTE IS NULL THEN
        vlCadena:=vlCadena||'|';--4. NO. DE PARTE
    ELSE
        vlCadena:=vlCadena||VPNUMPARTE||'|';--4. NO. DE PARTE
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    vllong2:=length(vlCadena);
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    vgproceso := 207317;
    vllong2:=length(vlCadena);
    IF VPUNIMED IS NULL THEN
        VPDESCERROR:='ALGUNA PARTIDA CON FRACCION '||VPFRACCION||' NO TIENE UNIDAD DE MEDIDA';
    END IF;
    vgproceso := 207320;
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    ELSE
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            VLUMCOMERCIAL:='0'||VLUMCOMERCIAL;
        END IF;
        vlCadena:=vlCadena||VLUMCOMERCIAL||'|'; --7. UNIDAD MEDIDA COMERCIAL
    END IF;
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    vlCadena:=vlCadena||CL_D2||'|'; --11. METODO DE VALORACION
    vlCadena:=vlCadena||'|'; --12. MARCA
    vlCadena:=vlCadena||'|'; --13. MODELO

If the expected maximum length of the concatenated string is less than 32K, then use VARCHAR2 and at the end convert to CLOB if necesary.
:p
PS: At what line in the code does it give the error?
Edited by: LKBrwn_DBA on Aug 20, 2009 2:49 PM

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Hi
Thanks again , plz bear with me as i am new to this kind of assignment.
This is a part of my requirement, so i suppose that I have to create a Data type as node for the customer fields corresponding to the node in IDOC and just map the source node to the target node , and it will repeat it self as many times as there is line items in the sales order.
Customer fields              Idoc fields.
                    segment E1EDP01
DETAIL_ANTAL     E1EDP01-MENGE - LOOP
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DETAIL_STK_PRIS     E1EDP26-BETRG - QUALIFIER = 001- LOOP
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the site is the following
http://www.uni-koeln.de/ew-fak/Mathe/Projekte/VisuPro/pythagoras/pythagoras.html
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Pardon my ASCII art, but I've always liked the following, simple, geometric proof:
     a                   b
---------------------------------------+
|       |                                |
a|   I   |              II                |
|       |                                |
---------------------------------------+
|       |                                |
|       |                                |
|       |                                |
|       |                                |
|       |                                |
b| IV   |              III               |
|       |                                |
|       |                                |
|       |                                |
|       |                                |
|       |                                |
|       |                                |
---------------------------------------+It almost goes without saying that I+II+III+IV == (a+b)^2, and II == IV == a*b,
I == a*a and III == b*b, showing that (a+b)^2 == a^2+a*b+a*b+b^2.
I hope the following sketch makes sense, stand back, ASCII art alert again:     a                   b
---------------------------------------+
|               .             VI         |
|     .                 .                |a
| V                               .      |
|                                        +
|                                        |
|   .                                    |
b|                                     . |
|                                        |
|                  IX                    |
| .                                      |
|                                    .   |b
|                                        |
+                                        |
|      .                                 |
a|               .                  . VII |
| VIII                   .              |
---------------------------------------+
                 a                    bThe total area equals (a+b)^2 again and equals the sum of the smaller areas:
(a+b)^2 == V+VI+VII+VIII+IX. Let area IX be c^2 for whatever c may be.
V+VII == VI+VIII == a*b, so a^2+b^2+2*ab= c^2+2*a*b; IOW a^2+b^2 == c^2
Given this fundamental result, the others can easily be derived from this one,
or did I answer a question you didn't ask?
kind regards,
Jos

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Hi ,
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