Need help to find GPOs with a specific word

Hi Experts,<o:p></o:p>
In my environment, we have 500+ GPOs and I have been asked to find the GPOs with a specific word like "dns". I believe powershell is the better way to find my requirement and I
am in KG standard in Powersell :(<o:p></o:p>
Thanks
Sajoor

Get-GPO (From the GroupPolicy module) doesn't allow for wildcards in the -Name parameter, so the best you can do with that cmdlet is something like this:
Get-Gpo -All | Where {
$_.DisplayName -match 'dns'
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Need help in finding the number of occurrences of a pattern.

Hi All,
I need help in finding the number of occurrences of a pattern in a table's column's data.
Consider sample data - one row's column from a table:
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Thanks in advance,
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Edited by: Girish G on Jul 21, 2011 11:22 PM

I am sure there exists a better way then this one:
SQL> with dt as
2 (select 'S-S-S-A-S-S-P-S-S-B-S-A-P-S-S-C' str from dual)
3 SELECT SUM(Regexp_count(Regexp_substr(str, '(S\-?)+(A|P)+', 1,
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5                                                  LEVEL - 1 )), 'S')) len
6 FROM   dt
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8 /
       LEN
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Edited by: SAP PQ on Sep 26, 2011 5:24 PM

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Need help in finding patterns and there counts

Hi All,
I need help in finding patterns as well as number of occurrences of those patterns in a table's column's data.
Consider sample data - one row's column from a table:
"S-S-S-P-S-B-S-S-C-S-P"
My requirement is:
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Example: for the above given data the patterns and counts are
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SS - count is 1
There is one more condition for the above requirement:
If 'S' is followed by 'A', then 'SA' should not be considered as a pattern. The pattern should stretch until a non 'A' character is found.
Consider sample data for the above case:
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for the above given data the patterns and counts are
SS - count is 2
SP - count is 1
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Hi, Girish,
Girish G wrote:
Hi All,
I need help in finding patterns as well as number of occurrences of those patterns in a table's column's data.
Consider sample data - one row's column from a table:
"S-S-S-P-S-B-S-S-C-S-P"
My requirement is:
I should get all the patterns that are followed by 'S'.Do you mean "I should get all patterns that *start with* 'S'"?
Example: for the above given data the patterns and counts are
SS - count is 3
SP - count is 2
SB - count is 1
SS - count is 1Why are there two rows of output for 'SS'? What does the second one, with count=1, mean?
There is one more condition for the above requirement:
If 'S' is followed by 'A', then 'SA' should not be considered as a pattern. The pattern should stretch until a non 'A' character is found.
Consider sample data for the above case:
"S-S-A-S-S-A-A-C-S-P-S-A"
for the above given data the patterns and counts are
SS - count is 2
SP - count is 1
SAS - count is 1
SAAC - count is 1
The data column is stored as VARCHAR2 type.
I have Oracle Database 11g Enterprise Edition Release 11.1.0.6.0 - 64bit ProductionThanks; the version information is very helpful.
Thanks in advance,
Girish GWhenever you have a question, please post a little sample data (CREATE TABLE and INSERT statements) and the results you want from that data.
For example, your sample data might be:
CREATE TABLE     table_x
(       x_id     NUMBER     PRIMARY KEY
,     txt     VARCHAR2 (30)
INSERT INTO table_x (x_id, txt) VALUES (1, 'S-S-S-P-S-B-S-S-C-S-P');
INSERT INTO table_x (x_id, txt) VALUES (2, 'S-S-A-S-S-A-A-C-S-P-S-A');and the results you want from that data might be:
X_ID TXT                       PATTERN                          CNT
   1 S-S-S-P-S-B-S-S-C-S-P     SB                                 1
   1 S-S-S-P-S-B-S-S-C-S-P     SC                                 1
   1 S-S-S-P-S-B-S-S-C-S-P     SP                                 2
   1 S-S-S-P-S-B-S-S-C-S-P     SS                                 3
   2 S-S-A-S-S-A-A-C-S-P-S-A   SAAC                               1
   2 S-S-A-S-S-A-A-C-S-P-S-A   SAS                                1
   2 S-S-A-S-S-A-A-C-S-P-S-A   SP                                 1
   2 S-S-A-S-S-A-A-C-S-P-S-A   SS                                 2(This corresponds to what you posted, except that there is only one output row for 'SS' when x_id=1.)
One way to get those results in Oracle 11 is:
WITH   got_s_cnt    AS
     SELECT     x_id, txt
     ,     REGEXP_COUNT (txt, 'S')     AS s_cnt
     FROM     table_x
,     cntr          AS
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     FROM     dual
     CONNECT BY     LEVEL <= (
                               SELECT MAX (s_cnt)
                         FROM    got_s_cnt
,     got_pattern     AS
     SELECT     s.x_id
     ,     s.txt
     ,     c.n
     ,     REGEXP_SUBSTR ( REPLACE ( SUBSTR ( txt
                                             , INSTR (s.txt, 'S', 1, c.n)
                     , 'SA*[^A]'
                        )       AS pattern
     FROM    got_s_cnt s
     JOIN     cntr        c ON c.n <= s.s_cnt
SELECT       x_id
,       txt
,       pattern
,       COUNT (*)     AS cnt
FROM       got_pattern
WHERE       pattern     IS NOT NULL
GROUP BY x_id
,            txt
,       pattern
ORDER BY x_id
,            pattern
;At the heart of this query is the call to REGEXP_SUBSTR:
REGEXP_SUBSTR ( x
           , 'SA*[^A]'
           )which is looking for:
S = the letter S
A* = the letter A, repeated 0 or more times
[^A] = anything except the letter A

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