Need help with fixing a resolution problem

Hello
I was working on a file to test out PS6, the file has several layers, 30x80 at 300pi,
in addition a friend came by and tried the same thing but her file size was slightly diferent, 29,99x80,05 28,346pi, she created over 20 diferent layers and i like some of them, is there a way to make them all 30x80 at 300pi so i can use them with the file i have?
Some of her layers are solid backgrounds hile others are photo frames,
cheers

I don't know what pi is. You are using it two ways in same sentence. It is 30 x 80 p (pixels) at 300 ppi (pixels per inch)
You can change the resolution, but remember you can not add detail that is not there.
So if you change the resolution without resampling (check box at bottom of Image Size window) you will see the pixel size remains the same and the document size changes.
If you do the same thing and check resampling the image size will change and the document size will not change. If you change resolution from 100 to 300 it does NOT mean you have 3 times as good of resolution. It means photoshop as added pixels as a best guess logarithm. Actual resolution may be a little worse as there is no free lunch.
As I said before it can get confusing.

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DoubleSkin wrote:
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Try MacBook notebook forum to talk to other users, or OS Software (Lion or Snow Leopard)
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//Create a new monitor
final private Object monitor = new Object();
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synchronized(monitor)
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synchronized(monitor) {
try
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>
The reason I believe this was a race condition is because when I run this code without the synchronized call and the DialogUtils.showinfoDialog commented out as shown below. When the zip occurs some of the files do not show up in the newly created .zip. But if I uncomment the dialog call then the .zip contains everything I expect it to.
>
Okay, so let's restate this:
Problem
I try to zip a file, but when I try to run the code above, then some of the files don't make it to the Zip archive. Some do, some don't.
Diagnostics
I notice when I call DialogUtils.showinfoDialog then the zip is formed properly. I think this is because the showinfoDialog method makes the user click on a button before returning. So my concern is that I am generating a race condition by <doing something... I have no idea what...>.
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Alright guys, it is a homework problem but I have definitely put in the work. I believe I have everything right except for the toString method in my Line class. The program compiles and runs but I am not getting the right outcome and I am missing parts. I will post my problems after the code. I will post the assignment (sorry, its long) also. If anyone could help I would appreciate it. It is due on Monday so I am strapped for time.
Assignment:
-There are two ways to uniquely determine a line represented by the equation y=ax+b, where a is the slope and b is the yIntercept.
a)two diffrent points
b)a point and a slope
!!!write a program that consists of three classes:
1)Point class: all data MUST be private
a)MUST contain the following methods:
a1)public Point(double x, double y)
a2)public double x ()
a3public double y ()
a4)public String toString () : that returns the point in the format "(x,y)"
2)Line class: all data MUST be private
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b1)public Line (Point point1, Point point2)
b2)public Line (Point point1, double slope)
b3)public String toString() : that returns the a text description for the line is y=ax+b format
3)Point2Line class
c1)reads the coordinates of a point and a slope and displays the line equation
c2)reads the coordinates of another point (if the same points, prompt the user to change points) and displays the line equation
***I will worry about the user input later, right now I am using set coordinates
What is expected when the program is ran: example
please input x coordinate of the 1st point: 5
please input y coordinate of the 1st point: -4
please input slope: -2
the equation of the 1st line is: y = -2.0x+6.0
please input x coordinate of the 2nd point: 5
please input y coordinate of the 2nd point: -4
it needs to be a diffrent point from (5.0,-4.0)
please input x coordinate of the 2nd point: -1
please input y coordinate of the 2nd point: 2
the equation of the 2nd line is: y = -1.0x +1.0
CODE::
public class Point{
     private double x = 0;
     private double y = 0;
     public Point(){
     public Point(double x, double y){
          this.x = x;
          this.y = y;
     public double getX(){
          return x;
     public double setX(){
          return this.x;
     public double getY(){
          return y;
     public double setY(){
          return this.y;
     public String toString(){
          return "The point is " + this.x + ", " + this.y;
public class Line
     private double x = 0;
     private double y = 0;
     private double m = 0;
     private double x2 = 0;
     private double y2 = 0;
     public Line()
     public Line (Point point1, Point point2)
          this.x = point1.getX();
          this.y = point1.getY();
          this.x2 = point2.getX();
          this.y2 = point2.getY();
          this.m = slope(point1, point2);
     public Line (Point point1, double slope)
          this.x = point1.getX();
          this.y = point1.getY();
     public double slope(Point point1, Point point2)//finds slope
          double m1 = (point1.getY() - point2.getY())/(point1.getX() - point2.getX());
          return m1;
     public String toString()
          double temp = this.x- this.x2;
          return this.y + " = " +temp + "" + "(" + this.m + ")" + " " + "+ " + this.y2;
          //y-y1=m(x-x1)
public class Point2Line
     public static void main(String[]args)
          Point p = new Point(3, -3);
          Point x = new Point(10, 7);
          Line l = new Line(p, x);
          System.out.println(l.toString());
}My problems:
I dont have the right outcome due to I don't know how to set up the toString in the Line class.
I don't know where to put if statements for if the points are the same and you need to prompt the user to put in a different 2nd point
I don't know where to put in if statements for the special cases such as if the line the user puts in is a horizontal or vertical line (such as x=4.7 or y=3.4)
Edited by: ta.barber on Apr 20, 2008 9:44 AM
Edited by: ta.barber on Apr 20, 2008 9:46 AM
Edited by: ta.barber on Apr 20, 2008 10:04 AM

Sorry guys, I was just trying to be thorough with the assignment. Its not that if the number is valid, its that you cannot put in the same coordinated twice.
public class Line
     private double x = 0;
     private double y = 0;
     private double m = 0;
     private double x2 = 0;
     private double y2 = 0;
     public Line()
     public Line (Point point1, Point point2)
          this.x = point1.getX();
          this.y = point1.getY();
          this.x2 = point2.getX();
          this.y2 = point2.getY();
          this.m = slope(point1, point2);
     public Line (Point point1, double slope)
          this.x = point1.getX();
          this.y = point1.getY();
     public double slope(Point point1, Point point2)//finds slope
          double m1 = (point1.getY() - point2.getY())/(point1.getX() - point2.getX());
          return m1;
     public String toString()
          double temp = this.x- this.x2;
          return this.y + " = " +temp + "" + "(" + this.m + ")" + " " + "+ " + this.y2;
          //y-y1=m(x-x1)
public class Point2Line
     public static void main(String[]args)
          Point p = new Point(3, -3);
          Point x = new Point(10, 7);
          Line l = new Line(p, x);
          System.out.println(l.toString());
}The problem is in these lines of code.
public double slope(Point point1, Point point2) //if this method finds the slope than how would i use the the two coordinates plus "m1" to
          double m1 = (point1.getY() - point2.getY())/(point1.getX() - point2.getX());
          return m1;
     public String toString()
          double temp = this.x- this.x2;
          return this.y + " = " +temp + "" + "(" + this.m + ")" + " " + "+ " + this.y2;
          //y-y1=m(x-x1)
     }if slope method finds the slope than how would i use the the two coordinates + "m1" to create a the line in toString?

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GeorgeFN
I work on behalf of HP.

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