Need help with java uses or overrides a deprecated API.

i have some issues and have not clue where the issue is this is the error that i receive
Note: C:\Documents and Settings\Adam\My Documents\JCreator LE\MyProjects\Pokemon\src\Pokemon.java uses or overrides a deprecated API.
Note: Recompile with -Xlint:deprecation for details.
here is my code

public void boundry()
               int i;
               //System.out.println("y is "+ (y+23) );
               //System.out.println("x is "+ (x+17) );
               //X10=wall[1].getX();
               //System.out.println("wall[1]X is" + X10);
               //check to see if over boundary
               rightflag=2;
               leftflag=2;
               downflag=2;
               upflag=2;
          for(i=0; i<=8; i++)
               System.out.println("i is" +i);
                //left side
                if ( ( (x+17) > (wall.getX() ) )
               && ( (y) < (wall[i].getY() + wall[i].getHeight()-5) )
               && ( (y+23) > (wall[i].getY()+5 ))
               && ( (x) < (wall[i].getX() + (wall[i].getWidth()/2) )) )
                    rightflag=1;
                    System.out.println("left");
               else
                    rightflag=2;
               //right side
               if ( ( (x) < ((wall[i].getX() + wall[i].getWidth() )))
               && ( (y) < wall[i].getY() + wall[i].getHeight()-5 )
               && (y > (wall[i].getY() ))
               && ( (x) > ((wall[i].getX()+(wall[i].getWidth()/2))) ) )
                    leftflag=1;
                    System.out.println("right");
               else
                    leftflag=2;
               //top side
               if ( ( (y+23) > wall[i].getY() )
               && ( (y+23) < ( wall[i].getY() + (wall[i].getHeight()/2-5) ))
               && ( (x+17) > wall[i].getX())
               && ( (x) < (wall[i].getX()+(wall[i].getWidth() ))) )
               upflag=1;
                    System.out.println("top");
               else
                    upflag=2;
               //bottom boundry
               if(
               (y < (wall[i].getY()+wall[i].getHeight() ))
               && (y > (wall[i].getY() ))
               && ((x+17) > (wall[i].getX()))
               && (x < (wall[i].getX()+wall[i].getWidth() ) ))
                    downflag=1;
                    System.out.println("bottom");
               else
                    downflag=2;
               System.out.println("test");
               //stop them from being over boundary
               if (rightflag==1)
               x=x-10;
               else if (leftflag==1)
               x=x+10;
               else if (upflag==1)
               y=y-10;
               else if (downflag==1)
               y=y+10;
               //draw the player
          public boolean handleEvent (Event e)
               //Get the scroll bars to work
               Y2 = indicatestrength.getValue();
               Y3 = X2.getValue();
               Y4 = Width2.getValue();
               Y5 = height2.getValue();
               repaint();
               return true;
          public void save ()
               File dataFile = new File ("Users/jeffrey/Server/Test.rtf");
               FileWriter out;
               BufferedWriter writeFile;
               //sample data to write
               double testnumber = -34.454;
               String testname="this is a string";
          try{
               out =new FileWriter (dataFile);
               writeFile = new BufferedWriter(out);
               //write all data as strings
               writeFile.write(testname);
               writeFile.newLine();
               writeFile.write(String.valueOf(testnumber));
               writeFile.newLine();
               //Close file
               writeFile.close();
               out.close();
               System.out.println ("data written to file");
               catch (IOException e)
                    System.out.println("there was a error writing to the file");

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Note: ImageViewer.java uses or overrides a deprecated API.

hi,
iam gettin this error after compilation
Note: ImageViewer.java uses or overrides a deprecated API.
Note: Recompile with -Xlint:deprecation for details.
& am running it on j2sdk1.5.0
Plzzz help

waoh man......but what 2 look....
heres da code...
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Java uses or overrides a deprecated API

Please help on this when this error will occur
when i am compile a JSP Page its throwing an error like this
java uses or overrides a deprecated API

Please help on this when this error will occur
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java uses or overrides a deprecated APIThat's a warning. And it should also tell you what you need to do to get a listing of the deprecated methods that you are using.

JCo (in UDF) throws: "...uses or overrides a deprecated API."

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Regards Mario

Hi Mario,
With every latest Java version its APIs keep changing and some functions are removed or "deprecated", so if you are getting this error which means JRE you are using not have that function available so compile your code with Java -deprecation to suppress that error.
To check JRE version type Java - version on command prompt and then refer to Java API (also available online) to get detail about that particular function, otherwise you can also chose alternate function to achieve your programming objecting. I prefer if you see JCO API for help on this function.
Refer to sample code : http://www.sapdevelopment.co.uk/java/jco/jco_callfunc.htm
Regards,
Gourav

What's this mean? - "uses or overrides a deprecated API."

Hi, I'm a newbie at Java and I'm getting this error when I try to compile my program:
"Note: C:\MarsLander\NewUser.java uses or overrides a deprecated API.
Note: Recompile with -deprecation for details."
I haven't a clue what is going on here, can anybody help?

Methods and classes may get deprecated with the threat that they will be removed form the API in a future version. Deprecated things can be but should not be used.
(Deprecated features can be undeprecated in a future version though. There are at least tow examples for this.)
As the message tells, compile it with the -deprecation flag and the compiler will report which method or class it is about.

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IN the second page, you have to make sure that the session
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Put this at the very top of the page -
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Murray --- ICQ 71997575
Adobe Community Expert
(If you *MUST* email me, don't LAUGH when you do so!)
==================
http://www.dreamweavermx-templates.com
- Template Triage!
http://www.projectseven.com/go
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Tutorials & Resources
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==================
"Alidad" <[email protected]> wrote in
message
news:g184i4$jgf$[email protected]..
> have created a login page (php/mysql) with username and
password boxes.
> when
> the form is submitted the mainpage loads up.
>
> i want the main page to be specific to that user, so i
want their name to
> appear in the first line. eg.. Welcome back 'David'
>
> I read a tutorial in the past that tought me to send the
users id in the
> URL
> and then create a record set on the mainpage that was
filtered by the URL
> parameter.
>
> I have forgotten how to do this and the tutorial is no
longer available on
> Adobe's site.
>
> I tried that with
> $_SESSION['MM_Username'] = $loginUsername; \\ in first
page then
> echo $_SESSION["MM_username"]; \\in second page, but
> the
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>
> i need help with that please!
>
> can anyone tell me how to do this? Thanks in advance,
>
> AM
>

Need help with java

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This forum is for Java, not JavaScript. The two have nothing to do with each other.
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Yikes, there is a much better way to go about this that is probably within what you have already learned, but since you are a student and this is how you started, let's just concentrate on fixing what you got.
First, as already noted by another poster, your formatting is really bad. Formatting is really important because it makes the code much more readable for you and anyone who comes along to help you or use your code. And I second that posters comment that brackets should always be used, especially for beginner programmers. Unfortunately beginner programmers often get stuck thinking that less lines of code equals better program, this is not true; even though better programmers often use far less lines of code.
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As for how to check for dupes, well, you obviously at least somewhat understand loops and if statements, thus you have all the tools needed, so where is the problem?
JSG

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+2. when the user enters a "years of service" value for a faculty member - the value entered should be verified to be a valid integer value in the range 1 to 50. If the data entered is outside the valid range or is not a valid integer - your program should reject the value and prompt the user that invalid data has been entered and that a new value is necessary.+
+3. when a faculty salary is entered, verify that it is a floating-point value in the range $35,000 to $200,000. Handle invalid data as described above.+
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Sorry to hear about your problems - lack of time, having fallen behind, imminent failure etc - but none of these are Java problems.
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Programming guide
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Examples...
[http://www.jsresources.org/examples/]

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You SQL would look something like this...
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Jason

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Hi 49ers,
Sorry not to have any real idea of how to help you out here, but this is a Java forum, not JavaScript.
Some Firefox expert may stumble across your post and be able to offer some advice (I hope they do) but this isn't really the best place to post such questions.
Try here: http://www.webdeveloper.com/forum/forumdisplay.php?s=&forumid=3
Good luck!
Chris.

Need help with Java programming installation question

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Or, should I just leave it alone, and not worry about it?
Yeah, I don't have much in the way of technical knowledge...
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Bob VanHorst

Thanks for the feedback. I think I'll do just that. Once in a while I have a problem with Java not bringing up a webcam shot, but when that happens, it seems to be more website based than a general condition.

Need help with java uses or overrides a deprecated API.

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