Need help with LR5 catalog which refuses to make workable copies

LR catalog refuses to make workable copies.
error message: Catalog cannot be opened due to unexpected error
Is there any way around that? It was working fine then I moved several folders from the main drive to the external HD and saved again. I have had trouble with this drive over the winter though. the  main catalog still opens so far but I am worried that I have no back-up working catalog considering I lost a catalog earlier in he winter when it was residing on the external HD.
I have not made backups as such because I would always copy the catalog to the backup HDs but now those cannot be opened...

Might be time to retire that external drive and buy a new one.
By default LR makes a weekly backup of the catalog you have opened. In the Backup dialog window you can specify where those backups are located. I suggest you place them all on a Known Working internal drive and then Back Up those Backups files to a New external drive.

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    function moveHorizontal_2(evt:Event):void{
        evt.target.x -= Math.random()*10;
        if (evt.target.x >= stage.stageWidth)
            evt.target.removeEventListener(Event.ENTER_FRAME, moveHorizontal);
            removeChild(DisplayObject(evt.target));
    initialiseAtm();
    function moveForward():void{
        bg_mc.x -=10;
    function moveBackward():void{
        bg_mc.x +=10;
    var tank_mc:Tank;
    // create a new Tank and put it into the variable
    // tank_mc
    tank_mc= new Tank;
    // set the location ( x and y) of tank_mc
    tank_mc.x=0;
    tank_mc.y=375;
    // show the tank_mc on the stage.
    addChild(tank_mc);
    stage.addEventListener(KeyboardEvent.KEY_DOWN, onMovementKeys);
    //creates the movement
    function onMovementKeys(evt:KeyboardEvent):void
        //makes the tank move by 10 pixels right
        if (evt.keyCode==Keyboard.D)
        tank_mc.x+=5;
    //makes the tank move by 10 pixels left
    if (evt.keyCode==Keyboard.A)
    tank_mc.x-=5
    //checking if the space bar is pressed and shooting is allowed
    if(evt.keyCode == 32 && shootAllow){
        //making it so the user can't shoot for a bit
        shootAllow = false;
        //declaring a variable to be a new Bullet
        var newBullet:Bullet = new Bullet();
        //changing the bullet's coordinates
        newBullet.y = tank_mc.y + tank_mc.width/2 - newBullet.width/2;
        newBullet.x = tank_mc.x;
        //then we add the bullet to stage
        addChild(newBullet);
    if (tank_mc.hitTestObject(antiTankmine_mc))
            //tank_mc.gotoAndPlay("hit");
            currentHP -= 10;
            // remove anti tank mine
            removeChild(antiTankmine_mc);
    if (tank_mc.hitTestObject(tankMine_mc))
            //tank_mc.gotoAndPlay("hit");
            currentHP -= 10;
            // remove anti tank mine
            removeChild(tankMine_mc);
        //var maxHP:int = 100;
    //var currentHP:int = maxHP;
    //var percentHP:Number = currentHP / maxHP;
        //Incrementing the cTime
    //checking if cTime has reached the limit yet
    if(cTime < cLimit){
        cTime ++;
    } else {
        //if it has, then allow the user to shoot
        shootAllow = true;
        //and reset cTime
        cTime = 0;
    function updateHealthBar():void
        percentHP = currentHP / maxHP;
        healthBar.barColor.scaleX = percentHP;
        if(currentHP <= 0)
            currentHP = 0;
            trace("Game Over");
        updateHealthBar();

    USe the trace function to analyze what happens and what fails to happen in the code you showed.  trace the conditional values to see if they are set up to allow a shot when you press the key

  • Need help with conditional query

    guys this is just an extension of this post that Frank was helping me with. im reposting because my requirements have changes slightly and im having a hell of a time trying to modify the query.
    here is the previous post.
    need help with query that can look data back please help.
    CREATE TABLE "FGL"
        "FGL_GRNT_CODE" VARCHAR2(60),
        "FGL_FUND_CODE" VARCHAR2(60),
        "FGL_ACCT_CODE" VARCHAR2(60),
        "FGL_ORGN_CODE" VARCHAR2(60),
        "FGL_PROG_CODE" VARCHAR2(60),
        "FGL_GRNT_YEAR" VARCHAR2(60),
        "FGL_PERIOD"    VARCHAR2(60),
        "FGL_BUDGET"    VARCHAR2(60)
      )data
    Insert into FGL (FGL_GRNT_CODE,FGL_FUND_CODE,FGL_ACCT_CODE,FGL_ORGN_CODE,FGL_PROG_CODE,FGL_GRNT_YEAR,FGL_PERIOD,FGL_BUDGET) values ('240055','240055','7600','4730','02','11','00','400');
    Insert into FGL (FGL_GRNT_CODE,FGL_FUND_CODE,FGL_ACCT_CODE,FGL_ORGN_CODE,FGL_PROG_CODE,FGL_GRNT_YEAR,FGL_PERIOD,FGL_BUDGET) values ('240055','240055','7240','4730','02','10','1','100');
    Insert into FGL (FGL_GRNT_CODE,FGL_FUND_CODE,FGL_ACCT_CODE,FGL_ORGN_CODE,FGL_PROG_CODE,FGL_GRNT_YEAR,FGL_PERIOD,FGL_BUDGET) values ('240055','240055','7240','4730','02','10','1','0');
    Insert into FGL (FGL_GRNT_CODE,FGL_FUND_CODE,FGL_ACCT_CODE,FGL_ORGN_CODE,FGL_PROG_CODE,FGL_GRNT_YEAR,FGL_PERIOD,FGL_BUDGET) values ('240055','240055','7600','4730','02','11','1','400');
    Insert into FGL (FGL_GRNT_CODE,FGL_FUND_CODE,FGL_ACCT_CODE,FGL_ORGN_CODE,FGL_PROG_CODE,FGL_GRNT_YEAR,FGL_PERIOD,FGL_BUDGET) values ('360055','360055','7200','4730','02','10','1','400');
    Insert into FGL (FGL_GRNT_CODE,FGL_FUND_CODE,FGL_ACCT_CODE,FGL_ORGN_CODE,FGL_PROG_CODE,FGL_GRNT_YEAR,FGL_PERIOD,FGL_BUDGET) values ('360055','360055','7600','4730','02','10','1','400');
    Insert into FGL (FGL_GRNT_CODE,FGL_FUND_CODE,FGL_ACCT_CODE,FGL_ORGN_CODE,FGL_PROG_CODE,FGL_GRNT_YEAR,FGL_PERIOD,FGL_BUDGET) values ('240055','240055','7240','4730','02','10','14','200');
    Insert into FGL (FGL_GRNT_CODE,FGL_FUND_CODE,FGL_ACCT_CODE,FGL_ORGN_CODE,FGL_PROG_CODE,FGL_GRNT_YEAR,FGL_PERIOD,FGL_BUDGET) values ('240055','240055','7600','4730','02','10','14','100');
    Insert into FGL (FGL_GRNT_CODE,FGL_FUND_CODE,FGL_ACCT_CODE,FGL_ORGN_CODE,FGL_PROG_CODE,FGL_GRNT_YEAR,FGL_PERIOD,FGL_BUDGET) values ('240055','240055','7240','4730','02','10','14','200');
    Insert into FGL (FGL_GRNT_CODE,FGL_FUND_CODE,FGL_ACCT_CODE,FGL_ORGN_CODE,FGL_PROG_CODE,FGL_GRNT_YEAR,FGL_PERIOD,FGL_BUDGET) values ('240055','240055','7240','4730','02','10','2','100');
    Insert into FGL (FGL_GRNT_CODE,FGL_FUND_CODE,FGL_ACCT_CODE,FGL_ORGN_CODE,FGL_PROG_CODE,FGL_GRNT_YEAR,FGL_PERIOD,FGL_BUDGET) values ('240055','240055','7240','4730','02','11','2','600');
    I need to find the greatest grant year for the grant by a period parameter.
    once i find the greatest year i need to check the value of period 14 for that grant for the previous year and add it to the budget amount for that grant. however if their is an entry in the greatest year for period 00 then i need to ignore the period 14 of previous year and do this calculation current period +(current period - greatest year 00)
    hope that makes sense so in other words with the new data above. if i was querying period two of grant year 11. i would end up with $800
    because the greatest year is 11 it contains a period 0 with amount of $400 so my total should be
    period 2 amount $ 600
    period 0 amount $ 400 - period 2 amount of $600 = 200
    600+200 = $800
    if i query period 1 of grant 360055 i would just end up with 800 of grnt year 10.
    i have tried to modify that query you supplied to me with no luck. I have tried for several day but im embarrased to say i just can get it to do what im trying to do .
    can you please help me out.
    here is the query supplied by frank kulash who gracefully put this together for me.
    WITH     got_greatest_year     AS
         SELECT     fgl.*     -- or whatever columns are needed
         ,     MAX ( CASE
                     WHEN  fgl_period = :given_period
                     THEN  fgl_grnt_year
                    END
                  ) OVER ()     AS greatest_year
         FROM     fgl
    SELECT     SUM (fgl_budget)     AS total_budget     -- or SELECT *
    FROM     got_greatest_year
    WHERE     (     fgl_grnt_year     = greatest_year
         AND     fgl_period     = :given_period
    OR     (     fgl_grnt_year     = greatest_year - 1
         AND     fgl_period     = 14
    ;Miguel

    Hi, Miguel,
    Are you waying that, when the greatest year that has :given_period also has period='00' (or '0', or whatever you want to use), then you want to double the budget from the given_period (as well as subtract the budget from the '00', and not count the pevious year's '14')? If so, add another condition to the CASE statement which decides what you're SUMming:
    WITH     got_greatest_year     AS
         SELECT       TO_NUMBER (fgl_grnt_year)     AS grnt_year
         ,       fgl_period
         ,       TO_NUMBER (fgl_budget)     AS budget
         ,       MAX ( CASE
                       WHEN  fgl_period = :given_period
                       THEN  TO_NUMBER (fgl_grnt_year)
                      END
                    ) OVER ()     AS greatest_year
         FROM       fgl
    ,     got_cnt_00     AS
         SELECT     grnt_year
         ,     fgl_period
         ,     budget
         ,     greatest_year
         ,     COUNT ( CASE
                       WHEN  grnt_year     = greatest_year
                       AND       fgl_period     = '00'
                       THEN  1
                         END
                    ) OVER ()          AS cnt_00
         FROM    got_greatest_year
    SELECT       SUM ( CASE
                        WHEN  grnt_year     = greatest_year                    -- New
                  AND       fgl_period     = :given_period                    -- New
                  AND       cnt_00     > 0            THEN  budget * 2     -- New
                        WHEN  grnt_year     = greatest_year
                  AND       fgl_period     = :given_period       THEN  budget
                        WHEN  grnt_year     = greatest_year
                  AND       fgl_period     = '00'            THEN -budget
                        WHEN  grnt_year     = greatest_year - 1
                  AND       fgl_period     = '14'     
                  AND       cnt_00     = 0            THEN  budget
                    END
               )          AS total_budget
    FROM       got_cnt_00
    ;You'll notice this is the same as the previous query I posted, except for 3 lines maked "New".

  • Need help with home work see what you got

    1. The MEMBERS table has the phone number broken into three fields:
       CountryCode - e,g., '1' for the United States
       AreaCode - e.g., three digits for the United States
       Phone - e.g., 7 digits, with or without a dash between the first three digits (Exchange) and last four digits (Line)
       Any or all of the fields may be missing (null) or blank or contain only spaces.
       Write a T-SQL statement to concatenate the three fields into a complete phone number
       with the format: CountryCode(AreaCode)Exchange-Line, e.g., 1(816)123-4567
       If no Phone is present, return a blank string.
       If no area code is present, return only the Phone number. Do not return an empty pair of parentheses or the CountryCode.
    2. The PERSON_CAMPAIGN table contains a row for each war/conflict the member served in. A member may have served in multiple conflicts
       For this purpose, each row contains:
       PersonID - unique member identifier
       Campaign - name of war/conflict
       Write a T-SQL statement to return one row per member with all campaigns concatenated into a single field and separated by commas
       E.g., PersonID    Campaigns
             12345678    Global War on Terror, Iraq, Afghanistan
    3. The MEMBER_STATISTICS table contains one row per post.
       For this purpose, each row contains the post's:
       Division - a way of grouping posts by their member size
       Department - the state in which the post is located
       PostNumber - unique post identifier
       Reinstated - count of members whose annual subscription had lapsed for at least two years but who have now subscribed for the current year
       Write a T-SQL statement to determine the top ten posts in each division based on the number of reinstated members, with a minimum of 50 reinstated members.
       Rank them by highest to lowest reinstated count.
       Return their Division, Rank, Department, PostNumber, Reinstated

    I got 3 home work questions think i have the first two need help with the last one please.
    Kinda stuck on #3 hard I can see data not sure witch to sum or count?
    1. The MEMBERS table has the phone number broken into three fields:
       CountryCode - e,g., '1' for the United States
       AreaCode - e.g., three digits for the United States
       Phone - e.g., 7 digits, with or without a dash between the first three digits (Exchange) and last four digits (Line)
       Any or all of the fields may be missing (null) or blank or contain only spaces.
       Write a T-SQL statement to concatenate the three fields into a complete phone number
       with the format: CountryCode(AreaCode)Exchange-Line, e.g., 1(816)123-4567
       If no Phone is present, return a blank string.
       If no area code is present, return only the Phone number. Do not return an empty pair of parentheses or the CountryCode.
    ANSWER******************
    Notes: created a funtion to format the phone 
    Then used the this function in a select to concatenate Phone 
     CREATE FUNCTION dbo.FORMATPHONE (@CountryCode int, @AreCode int, @Phone VARCHAR(14))
    RETURNS VARCHAR(14)
        AS BEGIN
           DECLARE @ReturnPhone VARCHAR(14)
           DECLARE @NewPhone VARCHAR(14)
    -- Note case sets newphone to null if phone null or '' also to see if phone has '-' in it if not inserts into newphone
           case 
                when @Phone is null or @Phone  = ''
                   Then SET @NewPhone = Null
                when @Phone = substring(@Phone,4,1)='-'
          Then SET @NewPhone = @Phone 
           else  
                SET @NewPhone = substring(@Phone,1,3)+'-'+ substring(@Phone,4,4)
           End     
           case 
                when @NewPhone is null then SET @ReturnPhone = @NewPhone            
           elese case
                    when @AreCode is null or @AreCode = '' then SET @ReturnPhone = @NewPhone
                 else 
          SET @ReturnPhone = @CountryCode + '(' + @AreCode + ')' +  @NewPhone
                END
           END
        RETURN @ReturnPhone 
    END
    select dbo.FORMATPHONE(CountryCode,AreCode,Phone)
    from MEMBERS 
    2. The PERSON_CAMPAIGN table contains a row for each war/conflict the member served in. A member may have served in multiple conflicts
       For this purpose, each row contains:
       PersonID - unique member identifier
       Campaign - name of war/conflict
       Write a T-SQL statement to return one row per member with all campaigns concatenated into a single field and separated by commas
       E.g., PersonID    Campaigns
             12345678    Global War on Terror, Iraq, Afghanistan
    ANSWER******************
    SELECT      PersonID,
                STUFF((    SELECT ',' + Campaign AS [text()]
                            FROM PERSON_CAMPAIGN 
                            WHERE (PersonID = Results.ID)
                            FOR XML PATH('') 
                            ), 1, 1, '' )
                AS Campaigns
    FROM  PERSON_CAMPAIGN Results
    3. The MEMBER_STATISTICS table contains one row per post.
       For this purpose, each row contains the post's:
       Division - a way of grouping posts by their member size
       Department - the state in which the post is located
       PostNumber - unique post identifier
       Reinstated - count of members whose annual subscription had lapsed for at least two years but who have now subscribed for the current year
       Write a T-SQL statement to determine the top ten posts in each division based on the number of reinstated members, with a minimum of 50 reinstated members.
       Rank them by highest to lowest reinstated count.
       Return their Division, Rank, Department, PostNumber, Reinstated

  • Hello, I need help with my macbook pro. It looks like I cannot install anything anymore. Everytime I try to install a new software, use the migration assistant or click the lock to make changes, it simply does not react.

    Hello, I need help with my macbook pro.
    It looks like I cannot install anything anymore. Everytime I try to install a new software, I simply get stuck during the installation type process. I put in my password, it does accept it, but it does not go any further.
    I tried to reset the password, put no password, repair the permissions, the disk but nothing will do. I nearly got stuck with the log in screen but finally succeeded in disabling it.
    So I thought I might try to create a new account but I cannot click the lock to make changes. It simply refuses to react.
    I am now thinking about using the migration assistant to save all my settings, data and so fourth, but again I get stuck when I have to type in my password. It accepts it but nothing happens...
    I guess it has something to do with the authorization process, but can't find anything on the internet about it... Can you help me out?
    I am running Lion 10.7.3.
    Regards,
    Nicolas.
    (I apologize if any grammatical/structural mistakes were to be found, english is not my mother-tongue. )

    You probably won't like this suggestion, but I suggest you reinstall Lion.
    First, backup your system. Next, reboot your system, press/hold the COMMAND-R keys to boot into the Recovery HD. Select 'Reinstall Mac OS X'. If you purchased Lion as an upgrade to Snow Leopard, the reinstall process will install Lion 10.7.3. If your system came preinstalled with Lion, you might still get Lion 10.7.2. Both installs are a total install of the OS. None of your apps or data will be impacted. Just the OS.

  • Need help with Berkeley XML DB Performance

    We need help with maximizing performance of our use of Berkeley XML DB. I am filling most of the 29 part question as listed by Oracle's BDB team.
    Berkeley DB XML Performance Questionnaire
    1. Describe the Performance area that you are measuring? What is the
    current performance? What are your performance goals you hope to
    achieve?
    We are measuring the performance while loading a document during
    web application startup. It is currently taking 10-12 seconds when
    only one user is on the system. We are trying to do some testing to
    get the load time when several users are on the system.
    We would like the load time to be 5 seconds or less.
    2. What Berkeley DB XML Version? Any optional configuration flags
    specified? Are you running with any special patches? Please specify?
    dbxml 2.4.13. No special patches.
    3. What Berkeley DB Version? Any optional configuration flags
    specified? Are you running with any special patches? Please Specify.
    bdb 4.6.21. No special patches.
    4. Processor name, speed and chipset?
    Intel Xeon CPU 5150 2.66GHz
    5. Operating System and Version?
    Red Hat Enterprise Linux Relase 4 Update 6
    6. Disk Drive Type and speed?
    Don't have that information
    7. File System Type? (such as EXT2, NTFS, Reiser)
    EXT3
    8. Physical Memory Available?
    4GB
    9. Are you using Replication (HA) with Berkeley DB XML? If so, please
    describe the network you are using, and the number of Replica’s.
    No
    10. Are you using a Remote Filesystem (NFS) ? If so, for which
    Berkeley DB XML/DB files?
    No
    11. What type of mutexes do you have configured? Did you specify
    –with-mutex=? Specify what you find inn your config.log, search
    for db_cv_mutex?
    None. Did not specify -with-mutex during bdb compilation
    12. Which API are you using (C++, Java, Perl, PHP, Python, other) ?
    Which compiler and version?
    Java 1.5
    13. If you are using an Application Server or Web Server, please
    provide the name and version?
    Oracle Appication Server 10.1.3.4.0
    14. Please provide your exact Environment Configuration Flags (include
    anything specified in you DB_CONFIG file)
    Default.
    15. Please provide your Container Configuration Flags?
    final EnvironmentConfig envConf = new EnvironmentConfig();
    envConf.setAllowCreate(true); // If the environment does not
    // exist, create it.
    envConf.setInitializeCache(true); // Turn on the shared memory
    // region.
    envConf.setInitializeLocking(true); // Turn on the locking subsystem.
    envConf.setInitializeLogging(true); // Turn on the logging subsystem.
    envConf.setTransactional(true); // Turn on the transactional
    // subsystem.
    envConf.setLockDetectMode(LockDetectMode.MINWRITE);
    envConf.setThreaded(true);
    envConf.setErrorStream(System.err);
    envConf.setCacheSize(1024*1024*64);
    envConf.setMaxLockers(2000);
    envConf.setMaxLocks(2000);
    envConf.setMaxLockObjects(2000);
    envConf.setTxnMaxActive(200);
    envConf.setTxnWriteNoSync(true);
    envConf.setMaxMutexes(40000);
    16. How many XML Containers do you have? For each one please specify:
    One.
    1. The Container Configuration Flags
              XmlContainerConfig xmlContainerConfig = new XmlContainerConfig();
              xmlContainerConfig.setTransactional(true);
    xmlContainerConfig.setIndexNodes(true);
    xmlContainerConfig.setReadUncommitted(true);
    2. How many documents?
    Everytime the user logs in, the current xml document is loaded from
    a oracle database table and put it in the Berkeley XML DB.
    The documents get deleted from XML DB when the Oracle application
    server container is stopped.
    The number of documents should start with zero initially and it
    will grow with every login.
    3. What type (node or wholedoc)?
    Node
    4. Please indicate the minimum, maximum and average size of
    documents?
    The minimum is about 2MB and the maximum could 20MB. The average
    mostly about 5MB.
    5. Are you using document data? If so please describe how?
    We are using document data only to save changes made
    to the application data in a web application. The final save goes
    to the relational database. Berkeley XML DB is just used to store
    temporary data since going to the relational database for each change
    will cause severe performance issues.
    17. Please describe the shape of one of your typical documents? Please
    do this by sending us a skeleton XML document.
    Due to the sensitive nature of the data, I can provide XML schema instead.
    18. What is the rate of document insertion/update required or
    expected? Are you doing partial node updates (via XmlModify) or
    replacing the document?
    The document is inserted during user login. Any change made to the application
    data grid or other data components gets saved in Berkeley DB. We also have
    an automatic save every two minutes. The final save from the application
    gets saved in a relational database.
    19. What is the query rate required/expected?
    Users will not be entering data rapidly. There will be lot of think time
    before the users enter/modify data in the web application. This is a pilot
    project but when we go live with this application, we will expect 25 users
    at the same time.
    20. XQuery -- supply some sample queries
    1. Please provide the Query Plan
    2. Are you using DBXML_INDEX_NODES?
    Yes.
    3. Display the indices you have defined for the specific query.
         XmlIndexSpecification spec = container.getIndexSpecification();
         // ids
         spec.addIndex("", "id", XmlIndexSpecification.PATH_NODE | XmlIndexSpecification.NODE_ATTRIBUTE | XmlIndexSpecification.KEY_EQUALITY, XmlValue.STRING);
         spec.addIndex("", "idref", XmlIndexSpecification.PATH_NODE | XmlIndexSpecification.NODE_ATTRIBUTE | XmlIndexSpecification.KEY_EQUALITY, XmlValue.STRING);
         // index to cover AttributeValue/Description
         spec.addIndex("", "Description", XmlIndexSpecification.PATH_EDGE | XmlIndexSpecification.NODE_ELEMENT | XmlIndexSpecification.KEY_SUBSTRING, XmlValue.STRING);
         // cover AttributeValue/@value
         spec.addIndex("", "value", XmlIndexSpecification.PATH_EDGE | XmlIndexSpecification.NODE_ATTRIBUTE | XmlIndexSpecification.KEY_EQUALITY, XmlValue.STRING);
         // item attribute values
         spec.addIndex("", "type", XmlIndexSpecification.PATH_EDGE | XmlIndexSpecification.NODE_ATTRIBUTE | XmlIndexSpecification.KEY_EQUALITY, XmlValue.STRING);
         // default index
         spec.addDefaultIndex(XmlIndexSpecification.PATH_NODE | XmlIndexSpecification.NODE_ELEMENT | XmlIndexSpecification.KEY_EQUALITY, XmlValue.STRING);
         spec.addDefaultIndex(XmlIndexSpecification.PATH_NODE | XmlIndexSpecification.NODE_ATTRIBUTE | XmlIndexSpecification.KEY_EQUALITY, XmlValue.STRING);
         // save the spec to the container
         XmlUpdateContext uc = xmlManager.createUpdateContext();
         container.setIndexSpecification(spec, uc);
    4. If this is a large query, please consider sending a smaller
    query (and query plan) that demonstrates the problem.
    21. Are you running with Transactions? If so please provide any
    transactions flags you specify with any API calls.
    Yes. READ_UNCOMMITED in some and READ_COMMITTED in other transactions.
    22. If your application is transactional, are your log files stored on
    the same disk as your containers/databases?
    Yes.
    23. Do you use AUTO_COMMIT?
         No.
    24. Please list any non-transactional operations performed?
    No.
    25. How many threads of control are running? How many threads in read
    only mode? How many threads are updating?
    We use Berkeley XML DB within the context of a struts web application.
    Each user logged into the web application will be running a bdb transactoin
    within the context of a struts action thread.
    26. Please include a paragraph describing the performance measurements
    you have made. Please specifically list any Berkeley DB operations
    where the performance is currently insufficient.
    We are clocking 10-12 seconds of loading a document from dbd when
    five users are on the system.
    getContainer().getDocument(documentName);
    27. What performance level do you hope to achieve?
    We would like to get less than 5 seconds when 25 users are on the system.
    28. Please send us the output of the following db_stat utility commands
    after your application has been running under "normal" load for some
    period of time:
    % db_stat -h database environment -c
    % db_stat -h database environment -l
    % db_stat -h database environment -m
    % db_stat -h database environment -r
    % db_stat -h database environment -t
    (These commands require the db_stat utility access a shared database
    environment. If your application has a private environment, please
    remove the DB_PRIVATE flag used when the environment is created, so
    you can obtain these measurements. If removing the DB_PRIVATE flag
    is not possible, let us know and we can discuss alternatives with
    you.)
    If your application has periods of "good" and "bad" performance,
    please run the above list of commands several times, during both
    good and bad periods, and additionally specify the -Z flags (so
    the output of each command isn't cumulative).
    When possible, please run basic system performance reporting tools
    during the time you are measuring the application's performance.
    For example, on UNIX systems, the vmstat and iostat utilities are
    good choices.
    Will give this information soon.
    29. Are there any other significant applications running on this
    system? Are you using Berkeley DB outside of Berkeley DB XML?
    Please describe the application?
    No to the first two questions.
    The web application is an online review of test questions. The users
    login and then review the items one by one. The relational database
    holds the data in xml. During application load, the application
    retrieves the xml and then saves it to bdb. While the user
    is making changes to the data in the application, it writes those
    changes to bdb. Finally when the user hits the SAVE button, the data
    gets saved to the relational database. We also have an automatic save
    every two minues, which saves bdb xml data and saves it to relational
    database.
    Thanks,
    Madhav
    [email protected]

    Could it be that you simply do not have set up indexes to support your query? If so, you could do some basic testing using the dbxml shell:
    milu@colinux:~/xpg > dbxml -h ~/dbenv
    Joined existing environment
    dbxml> setverbose 7 2
    dbxml> open tv.dbxml
    dbxml> listIndexes
    dbxml> query     { collection()[//@date-tip]/*[@chID = ('ard','zdf')] (: example :) }
    dbxml> queryplan { collection()[//@date-tip]/*[@chID = ('ard','zdf')] (: example :) }Verbosity will make the engine display some (rather cryptic) information on index usage. I can't remember where the output is explained; my feeling is that "V(...)" means the index is being used (which is good), but that observation may not be accurate. Note that some details in the setVerbose command could differ, as I'm using 2.4.16 while you're using 2.4.13.
    Also, take a look at the query plan. You can post it here and some people will be able to diagnose it.
    Michael Ludwig

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