Need to display seqno along with his superior number

Question

Hi friends,
I have a table adm_menus
It's DDL is
  CREATE TABLE "ADM_MENUS"
   (     "MENU_ID" NUMBER,
     "MENU_NAME" VARCHAR2(60 BYTE),
     "PARENT_MENU_ID" NUMBER,
     "SEQ_NO" NUMBER,
"DISP_SEQ_NO" VARCHAR2(250 BYTE),
     "MENU_ACTION_TYPE" VARCHAR2(60 BYTE),
     "MENU_ACTION" VARCHAR2(2000 BYTE),
     "MENU_PARAMETER" VARCHAR2(2000 BYTE),
     "INACTIVE_DATE" DATE,
     "CREATED_BY" NUMBER(15,0),
     "CREATION_DATE" DATE,
     "LAST_UPDATED_BY" NUMBER(15,0),
     "LAST_UPDATE_DATE" DATE
   )DML is
Insert into ADM_MENUS (MENU_ID,MENU_NAME,PARENT_MENU_ID,SEQ_NO,DISP_SEQ_NO,MENU_ACTION_TYPE,MENU_ACTION,MENU_PARAMETER,INACTIVE_DATE,CREATED_BY,CREATION_DATE,LAST_UPDATED_BY,LAST_UPDATE_DATE)
values (19,'TRANSACTION',null,10,'10',null,null,null,to_date('12-10-11','DD-MM-RR'),-1,to_date('12-10-11','DD-MM-RR'),-1,to_date('12-10-11','DD-MM-RR'));
Insert into ADM_MENUS (MENU_ID,MENU_NAME,PARENT_MENU_ID,SEQ_NO,DISP_SEQ_NO,MENU_ACTION_TYPE,MENU_ACTION,MENU_PARAMETER,INACTIVE_DATE,CREATED_BY,CREATION_DATE,LAST_UPDATED_BY,LAST_UPDATE_DATE)
values (18,'TRANSACTION',19,10,'10',null,null,null,to_date('12-10-11','DD-MM-RR'),-1,to_date('12-10-11','DD-MM-RR'),-1,to_date('12-10-11','DD-MM-RR'));
Insert into ADM_MENUS (MENU_ID,MENU_NAME,PARENT_MENU_ID,SEQ_NO,DISP_SEQ_NO,MENU_ACTION_TYPE,MENU_ACTION,MENU_PARAMETER,INACTIVE_DATE,CREATED_BY,CREATION_DATE,LAST_UPDATED_BY,LAST_UPDATE_DATE)
values (20,'Report1',18,30,'3010',null,null,null,to_date('12-10-11','DD-MM-RR'),-1,to_date('12-10-11','DD-MM-RR'),-1,to_date('12-10-11','DD-MM-RR'));My scenario in the sense is i need to display the results for the disp_seq_no column like
Since from the above DML statement i have three rows, For my explanation im taking four columns
menu_id------->parent_menu_id-------------->seq_no------------>Disp_seq_no
19                 null                      10                
18                 19                        10                
20                 18                        30For the above rows i need to display the rows for the column disp_seq_no as
For the first row from the above result the parent_menu_id is null(so, in my case he is the parent and there is no any superior to him, so his disp_seq_no has to be '010'(i.e his seq_no with *'0' infront of it*.)
For the second and third row i need like
menu_id------->parent_menu_id------------->seq_no------------>Disp_seq_no
19                 null                      10                010
18                 19                        10                010010 
20                 18                        30                010030For the second row, he has the parent menu id as '19', so i need his disp_seq_no like (his parents seq_no and his own Seq_no(but i need '0' infront of each and every seq number)) like
010010
For the third row, he has the parent menu id as '18', so the disp_seq_no has to be 010030
How i can able to achieve it friends.
Brgds,
Mini

Answer 1

/* Formatted on 10/12/2011 9:57:19 AM (QP5 v5.149.1003.31008) */
WITH ADM_MENUS
        AS (SELECT 19 menu_id, NULL parent_menu_id, 10 seq_no FROM DUAL
            UNION
            SELECT 18, 19, 10 FROM DUAL
            UNION
            SELECT 20, 18, 30 FROM DUAL)
    SELECT menu_id,
           parent_menu_id,
           seq_no,
           CASE CONNECT_BY_ISLEAF
              WHEN 0
              THEN
                 REPLACE (SYS_CONNECT_BY_PATH (seq_no, ','), ',', '0')
              ELSE
                 SUBSTR (REPLACE (SYS_CONNECT_BY_PATH (seq_no, ','), ',', '0'),
                         LENGTH (SYS_CONNECT_BY_PATH (seq_no, ',')) - 5)
           END
              disp_seq_no
      FROM ADM_MENUS
START WITH parent_menu_id IS NULL
CONNECT BY PRIOR menu_id = parent_menu_id
19          10     010
18     19     10     010010
20     18     30     010030