Need to join paths together into a single path

I have this image which is currently composed of separate paths.
Is there a way using pathfinder, effects>pathfinder, livepaint or some other way to group all of these together so all I have is the outline of the entire object pictured below? I'm working with programmers who need the actual paths merged into one big path (preferably dropping all of the stuff in the middle, though that's not absolutely necessary) - it's not good enough just to select all the individual paths, hit group, and name that layer; paths have to be joined.
Looked like Illustrator could do this easily, but I haven't used the program that much and I'm probably missing something simple.
Thanks for any help.

I got it to work again in one case but not another.
When it works, the Expand button stops being grayed out in the pathfinder section, and upon hitting expand, a compound path is generated which has the paths I need.
EDIT --- ok, figured it out for real now.
Need to select several paths which are not yet in a group (doesn't work if they are grouped to start with)
Then Alt Click on the Unite function under Pathfinder Shape Mode
Then Expand under Pathfinder - and you're left with the compound path comprised of all the original parts (which is what I needed)
Thanks for the help.

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Need help with query joining several tables into a single return line

what i have:
tableA:
puid, task
id0, task0
id1, task1
id2, task2
tableB:
puid, seq, state
id0, 0, foo
id0, 1, bar
id0, 2, me
id1, 0, foo
id2, 0, foo
id2, 1, bar
tableC:
puid, seq, date
id0, 0, 12/21
id0, 1, 12/22
id0, 2, 12/22
id1, 0, 12/23
id2, 0, 12/22
id2, 1, 12/23
what i'd like to return:
id0, task0, 12/21, 12/22, 12/22
id1, task1, 12/23, N/A, N/A
id2, task2, 12/22, 12/23, N/A
N/A doesn't mean return the string "N/A"... it just means there was no value, so we don't need anything in this column (null?)
i can get output like below through several joins, however i was hoping to condense each "id" into a single line...
id0, task0, 12/21
id0, task0, 12/22
id0, task0, 12/23
id1, task1, 12/23
is this possible fairly easily?
Edited by: user9979830 on Mar 29, 2011 10:53 AM
Edited by: user9979830 on Mar 29, 2011 10:58 AM

Hi,
Welcome to the forum!
user9979830 wrote:
what i have:...Thanks for posting that so clearly!
Whenever you have a question, it's even better if you post CREATE TABLE and INSERT statements for your sample data, like this:
CREATE TABLE     tablea
(       puid     VARCHAR2 (5)
,     task     VARCHAR2 (5)
INSERT INTO tablea (puid, task) VALUES ('id0', 'task0');
INSERT INTO tablea (puid, task) VALUES ('id1', 'task1');
INSERT INTO tablea (puid, task) VALUES ('id2', 'task2');
CREATE TABLE     tablec
(       puid     VARCHAR2 (5)
,     seq     NUMBER (3)
,     dt     DATE          -- DATE is not a good column name
INSERT INTO tablec (puid, seq, dt) VALUES ('id0', 0, DATE '2010-12-21');
INSERT INTO tablec (puid, seq, dt) VALUES ('id0', 1, DATE '2010-12-22');
INSERT INTO tablec (puid, seq, dt) VALUES ('id0', 2, DATE '2010-12-22');
INSERT INTO tablec (puid, seq, dt) VALUES ('id1', 0, DATE '2010-12-23');
INSERT INTO tablec (puid, seq, dt) VALUES ('id2', 0, DATE '2010-12-22');
INSERT INTO tablec (puid, seq, dt) VALUES ('id2', 1, DATE '2010-12-23');This way, people can re-create the problem and test their ideas.
It doesn't look like tableb plays any role in this problem, so I didn't post it.
Explain how you get the results from that data. For example, why do you want this row in the results:
PUID TASK DT1        DT2        DT3
id0   task0 12/21/2010 12/22/2010 12/22/2010rather than, say
PUID TASK DT1        DT2        DT3
id0   task0 12/22/2010 12/21/2010 12/22/2010? Does 12/21 have to go in the first column because it is the earliest date, or is it because 12/21 is related to the lowest seq value? Or do you even care about the order, just as long as all 3 dates are shown?
Always say what version of Oracle you're uisng. The query below will work in Oracle 9 (and up), but starting in Oracle 11, the SELECT ... PIVOT feature could help you.
i can get output like below through several joins, however i was hoping to condense each "id" into a single line... Condensing the output, so that there's only one line for each puid, sounds like a job for "GROUP BY puid":
WITH     got_r_num     AS
     SELECT     puid
     ,     dt
     ,     ROW_NUMBER () OVER ( PARTITION BY puid
                               ORDER BY         seq          -- and/or dt
                       )         AS r_num
     FROM    tablec
--     WHERE     ...     -- If you need any filtering, put it here
SELECT       a.puid
,       a.task
,       MIN (CASE WHEN r.r_num = 1 THEN r.dt END)     AS dt1
,       MIN (CASE WHEN r.r_num = 2 THEN r.dt END)     AS dt2
,       MIN (CASE WHEN r.r_num = 3 THEN r.dt END)     AS dt3
,       MIN (CASE WHEN r.r_num = 4 THEN r.dt END)     AS dt4
FROM       tablea    a
JOIN       got_r_num r ON   a.puid = r.puid
GROUP BY a.puid
,            a.task
ORDER BY a.puid
;I'm guessing that you want the dates arranged by seq; that is, for each puid, the date related to the lowest seq comes first, regardless of whther that date is the earliest date for that puid or not. If that's not what you need, then change the analytic ORDER BY clause.
This does not assume that the seq values are always consecutive integers (0, 1, 2, ...) for each puid. You can skip, or even duplicate values. However, if the values are always consecutive integers, starting from 0, then you could simplify this. You won't need a sub-query at all; just use seq instead of r_num in the main query.
Here's the output I got from the query above:
PUID TASK DT1        DT2        DT3        DT4
id0   task0 12/21/2010 12/22/2010 12/22/2010
id1   task1 12/23/2010
id2   task2 12/22/2010 12/23/2010As posted, the query will display the first 4 dts for each puid.
If there are fewer than 4 dts for a puid, the query will still work. It will leave some columns NULL at the end.
If there are more than 4 dts for a puid, the query will still work. It will display the first 4, and ignore the others.
There's nothing special about the number 4; you could make it 3, or 5, or 35, but whatever number you choose, you have to hard-code that many columns into the query, and always get that many columns of output.
For various ways to deal with a variable number of pivoted coolumns, see the following thread:
PL/SQL
This question actually doesn't have anything to do with SQL*Plus; it's strictly a SQL question, and SQL questions are best posted on the "SQL and PL/SQL" forum:
PL/SQL
If you're not sure whether a question is more of a SQL question or a SQL*Plus question, then post it on the SQL forum. Many more people pay attention to that forum than to this one.

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2. If I do share it with quicktime, can i delete the original clips from iMovie, or will that also delete the new movie in quicktime?

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How does one convert a text path back into a line path in Illustrator CS 5?

The previous answer to the same question in Nov 2009 does not work for me. That was to copy and paste in front. I've tried every permutation of copy and paste; I renamed the path to path. It looks like a path when I add stroke, but it does not behave like one. I can't cut it or join it to any other path. It remembers it's text path status.
I'm running OS X 10.7.5.
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anacathena wrote:
...Holding down Option, while using the Direct Selection Tool, adds a little plus sign to the side of the tool, as there is next to the pen tool when you are in a position to add points. Is the plus sign there to let the user know the tool is in an option mode?...
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Once there is text on the path. The option-click seems a reliable solution.
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[scott w] wrote:
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(Takes you back to Illie88, don't it Jacob?)
Or even further, Steve (you may remember my being dutifully unmasked by Peter the other day).
Yep :-) but what was before Illie 88? (was there anything?)
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Need to join paths together into a single path

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