Need to remove duplicate rows from a table
Hi Gurus ,
I am using oracle 11.2.0.3 .
SQL> desc osstage.S_EVT_ACT_X;
Name Null? Type
ROW_ID NOT NULL VARCHAR2(15 CHAR)
LAST_UPD NOT NULL DATE
PAR_ROW_ID NOT NULL VARCHAR2(15 CHAR)
ATTRIB_17 NUMBER(22,7)
ATTRIB_26 DATE
ATTRIB_02 VARCHAR2(100 CHAR)
PROCESS_TIMESTAMP TIMESTAMP(6);
now when i give the below command it gives the error as someone has disabled the constraint accidently .
alter table s_evt_act_x enable constraint S_EVT_ACT_X_P1;
Error starting at line 3 in command:
alter table s_evt_act_x enable constraint S_EVT_ACT_X_P1
Error report:
SQL Error: ORA-02437: cannot validate (OSSTAGE.S_EVT_ACT_X_P1) - primary key violated
02437. 00000 - "cannot validate (%s.%s) - primary key violated"
*Cause: attempted to validate a primary key with duplicate values or null
values.
*Action: remove the duplicates and null values before enabling a primary
key.
Can you please guide me with this issue .
Please refer
Script: Deleting Duplicate Rows from a Table (Doc ID 31413.1)
How to Find or Delete Duplicate Rows in a Table (Doc ID 1004425.6)
Similar Messages
-
First attempt to remove duplicate rows from a table...
I have seen many people asking for a way to remove duplicate rows from data. I made up a fairly simple script. It adds a column to the table with the cell selected in it, and adds the concatenation of the data to the left into that new column. then it reads that into a list, and walks through that list to find any that are listed twice. Any that are it marks for DELETE.
It then walks through to find each one marked for delete and removes them (you must go from bottom to top to do this, otherwise your row markings for delete don't match up to the original rows anymore). Last is to delete the column we added.
tell application "Numbers"
activate
tell document 1
-- DETERMINE THE CURRENT SHEET
set currentsheetindex to 0
repeat with i from 1 to the count of sheets
tell sheet i
set x to the count of (tables whose selection range is not missing value)
end tell
if x is not 0 then
set the currentsheetindex to i
exit repeat
end if
end repeat
if the currentsheetindex is 0 then error "No sheet has a selected table."
-- GET THE TABLE WITH CELLS
tell sheet currentsheetindex
set the current_table to the first table whose selection range is not missing value
end tell
end tell
log current_table
tell current_table
set list1 to {}
add column after column (count of columns)
set z to (count of columns)
repeat with j from 1 to (count of rows)
set m to ""
repeat with i from 1 to (z - 1)
set m to m & value of (cell i of row j)
end repeat
set value of cell z of row j to m
end repeat
set MyRange to value of every cell of column z
repeat with i from 1 to (count of items of MyRange)
set n to item i of MyRange
if n is in list1 then
set end of list1 to "Delete"
else
set end of list1 to n
end if
end repeat
repeat with i from (count of items of list1) to 1 by -1
set n to item i of list1
if n = "Delete" then remove row i
end repeat
remove column z
end tell
end tell
Let me know how it works for y'all, it worked good on my machine, but I know localization is causing errors sometimes when I post things.
Thanks,
Jason
Message was edited by: jaxjasonHi jason
I hope that with the added comments it will be clear.
Ask if something is always opaque.
set {current_Range, current_table, current_Sheet, current_Doc} to my getSelection()
tell application "Numbers09"
tell document current_Doc to tell sheet current_Sheet to tell table current_table
set list1 to {}
add column after column (count of columns)
set z to (count of columns)
repeat with j from 1 to (count of rows)
set m to ""
tell row j
repeat with i from 1 to (z - 1)
set m to m & value of cell i
end repeat
set value of cell z to m
end tell
end repeat
set theRange to value of every cell of column z
repeat with i from (count of items of theRange) to 1 by -1
(* As I scan the table backwards (starting from the bottom row),
I may remove a row immediately when I discover that it is a duplicate *)
set n to item i of theRange
if n is in list1 then
remove row i
else
set end of list1 to n
end if
end repeat
remove column z
end tell
end tell
--=====
on getSelection()
local _, theRange, theTable, theSheet, theDoc, errMsg, errNum
tell application "Numbers09" to tell document 1
set theSheet to ""
repeat with i from 1 to the count of sheets
tell sheet i
set x to the count of tables
if x > 0 then
repeat with y from 1 to x
(* Open a trap to catch the selection range.
The structure of this item
«class
can't be coerced as text.
So, when the instruction (selection range of table y) as text
receive 'missing value' it behaves correctly and the lup continue.
But, when it receive THE true selection range, it generates an error
whose message is errMsg and number is errNum.
We grab them just after the on error instruction *)
try
(selection range of table y) as text
on error errMsg number errNum (*
As we reached THE selection range, we are here.
We grab the errMsg here. In French it looks like:
"Impossible de transformer «class
The handler cuts it in pieces using quots as delimiters.
item 1 (_) "Impossible de transformer «class » "
item 2 (theRange) "A2:M25"
item 3 (_) " of «class NmTb» "
item 4 (theTable) "Tableau 1"
item 5 (_) " of «class NmSh» "
item 6 (theSheet) "Feuille 1"
item 7 (_) " of document "
item 8 (theDoc) "Sans titre"
item 9 ( I drop it ) " of application "
item 10 ( I drop it ) "Numbers"
item 11 (I drop it ) " en type string."
I grab these items in the list
{_, theRange, _, theTable, _, theSheet, _, theDoc}
Yes, underscore is a valid name of variable.
I often uses it when I want to drop something.
An alternate way would be to code:
set ll to my decoupe(errMsg, quote)
set theRange to item 2 of ll
set theTable to item 4 of ll
set theSheet to item 8 of ll
set theDoc to item 10 of ll
it works exactly the same but it's not so elegant.
set {_, theRange, _, theTable, _, theSheet, _, theDoc} to my decoupe(errMsg, quote)
exit repeat (*
as we grabbed the interesting datas, we exit the lup indexed by y.*)
end try
end repeat -- y
if theSheet > "" then exit repeat (*
If we are here after grabbing the datas, theSheet is not "" so we exit the lup indexed by i *)
end if
end tell -- sheet
end repeat -- i
(* We may arrive here with two kinds of results.
if we grabbed a selection, theSheet is something like "Feuille 1"
if we didn't grabbed a selection, theSheet is the "" defined on entry
and we generate an error which is not trapped so it stops the program *)
if theSheet = "" then error "No sheet has a selected table."
end tell -- document
(* Now, we send to the caller the interesting datas :
theRange "A2:M25"
theTable "Tableau 1"
theSheet "Feuille 1"
theDoc "Sans titre" *)
return {theRange, theTable, theSheet, theDoc}
end getSelection
--=====
on decoupe(t, d)
local l
set AppleScript's text item delimiters to d (*
Cut the text t in pieces using d as delimiter *)
set l to text items of t
set AppleScript's text item delimiters to "" (*
Resets the delimiters to the standard value. *)
(* Send the list to the caller *)
return l
end decoupe
--=====
Have fun
And if it's not clear enough, you may ask for more explanations.
Yvan KOENIG (from FRANCE mardi 27 janvier 2009 21:49:19) -
Need to remove duplicate rows from distinct query
Hello,
I have the following query:
SELECT tiab.abnr abnr, tiab.namn namn, (CAST(tiab.GATUNR||' '||tiab.gata AS VARCHAR2(254))) ADR, tiab.boxpnr boxpnr, tiab.boxort boxort,
(CAST(tiab.RIKTNRDISPLAY AS VARCHAR2(254))) RIKTNR, (CAST(tiab.TELNRDISPLAY AS VARCHAR2(254))) TELNR,
DECODE((select count(tior.tigilopnr) from tis.tior where abnr = tiab.abnr and inplnr IN (3797886)),0 ,NULL , 1, tior.tigilopnr, 'N/A') tigilopnr
FROM tis.tiab
JOIN tis.tior on tiab.abnr = tior.abnr
WHERE tior.inplnr IN (3797886)
ORDER BY tiab.ABNR )
ORDER BY abnr;
It returns the following:
14684940 Pizza Station Inc The Lafayette 26170 St Marys 304 684-2411
15123161 Chris Test 554 Easy St n 43333 Columbus 614 555-5555
15123162 Chris Test2 5556 Easy St 43333 Columbus 614 555-5151 2553304 --> keep this one
15123162 Chris Test2 5556 Easy St 43333 Columbus 614 555-5151 -- not show this
I have tried several different things as well as looking through the forums but have not found anything that will only give me unique records based only on the first column. This query works fine as long as there
are not 2 records returned with column1 being identical.
Final results should look like this:
14684940 Pizza Station Inc The Lafayette 26170 St Marys 304 684-2411
15123161 Chris Test 554 Easy St n 43333 Columbus 614 555-5555
15123162 Chris Test2 5556 Easy St 43333 Columbus 614 555-5151 2553304
Thanks in advance for the assistance.Hello,
Try:
SELECT abnr, namn, ADR, boxpnr, boxort,RIKTNR, TELNR,tigilopnr
FROM (
SELECT tiab.abnr abnr, tiab.namn namn, (CAST(tiab.GATUNR||' '||tiab.gata AS VARCHAR2(254))) ADR, tiab.boxpnr boxpnr, tiab.boxort boxort,
(CAST(tiab.RIKTNRDISPLAY AS VARCHAR2(254))) RIKTNR, (CAST(tiab.TELNRDISPLAY AS VARCHAR2(254))) TELNR,
DECODE((select count(tior.tigilopnr) from tis.tior where abnr = tiab.abnr and inplnr IN (3797886)),0 ,NULL , 1, tior.tigilopnr, 'N/A') tigilopnr,
ROW_NUMBER () OVER (PARTITION BY tiab.abnr ORDER BY (CAST(tiab.TELNRDISPLAY AS VARCHAR2(254))) NULLS LAST) row_num
FROM tis.tiab
JOIN tis.tior on tiab.abnr = tior.abnr
WHERE tior.inplnr IN (3797886))
WHERE row_num <= 1
ORDER BY abnr;Or, with your current query:
SELECT abnr, namn, ADR, boxpnr, boxort,RIKTNR, TELNR,tigilopnr
FROM (
SELECT distinct tiab.abnr abnr, tiab.namn namn, (CAST(tiab.GATUNR||' '||tiab.gata AS VARCHAR2(254))) ADR, tiab.boxpnr boxpnr, tiab.boxort boxort,
(CAST(tiab.RIKTNRDISPLAY AS VARCHAR2(254))) RIKTNR, (CAST(tiab.TELNRDISPLAY AS VARCHAR2(254))) TELNR,
DECODE((select count(tior.tigilopnr) from tis.tior where abnr = tiab.abnr and inplnr IN (3797886)),0 ,NULL , 1, tior.tigilopnr, 'N/A') tigilopnr,
ROW_NUMBER () OVER (PARTITION BY tiab.abnr ORDER BY (CAST(tiab.TELNRDISPLAY AS VARCHAR2(254))) NULLS LAST) row_num
FROM tis.tiab
JOIN tis.tior on tiab.abnr = tior.abnr
WHERE tior.inplnr IN (3797886))
WHERE row_num <= 1
ORDER BY abnr; -
Remove a row from multiple tables
Hello,
I have a form that has what appears to be one table. Since I needed 30 columns (29 of them are single character fields) I had to use 2 table objects. Then I needed the ability to add and remove rows. Adding a row at the end is easy enough. Deleting a specific row is the problem. At the moment, I added a third table which has a header row and a item body row. the body row is a button with the intention of removing that entire row from the large table. This means it needs to remove the row from all 3 tables.
My structure is:
form1
(Some other flowed subform that doesn't matter for us)
SubformPersonnel (a flowed subform)
SubformHeader (a positioned subform)
TextOverallHeader (text to label the oeverall 3 tables)
ButtonAddRow (adds a row to the end of all 3 tables)
SubformPersonnelTable (a positioned subform)
ContractorTableRemove (a table with 1 column for the Remove button)
HeaderRow (A hidden row to align the table with the other 2)
Item (A row with the Remove button)CellRemoveButton (the cell with the remove button and associated JavaScript)
ContractorTableLeft (a table with the left 15 printed columns)
HeaderRow
Contractor (A row of data to be removed when CellButton above is clicked)
ContractorTableRight (a table with the right 15 printed columns)
HeaderRow
Contractor (A row of data to be removed when CellButton above is clicked)
(Some other flowed subforms that I am not worried about at the moment)
The 3 tables are aligned so the headers all line up, with no spaces between them. The body rows then line up and this looks like one large table. From left to right, they are:
ContractorTableRemove, ContractorTableLeft, ContractorTableRight
So Item and Contractor rows are added when ButtonAddRow is clicked in the overall header. The intial count is set to 8 for each table, so I get 8 rows at startup. The minimum count is set to 1 for each. I know that each row of each table has the same index number because I filled those into a cell in each table durig the cell's initialize. This line, in the CellRemoveButton's click event deletes that cell's row in that table:
this.parent.parent._Item.removeInstance(this.parent.index);
I have tried all sorts of ways to delete the same row (using same index #) in the other 2 tables: ContractorTableLeft and ContractorTableRight, but don't seem to be getting the correct syntax correct. I have tried hard coding the references, using .parent as shown below, and also tried using an index of 1 just to try deleting a row with no results.
this.parent.parent.parent.ContractorTableLeft._Contractor.removeInstance(this.parent.inde x);
Can someone get me the correct syntax here?
I have seen examples of putting a hidden delete button on each table and clicking that, but I am concerned that it will get in the way of the tables on either side of the table it is in. I reeally want to just reference the row and remove it so I can avoid any problems these additional delete problems may cause.
I have copied the form to https://acrobat.com/#d=7M8R50rEHf4AaVXppwyKLwThank you, Niall. Much appreciated!
The Delete button was more to make sure one could delete these outside a button in the actual row and I see I had the index wrong such that I was deleting the second row and not the first. I had toyed with using this as a hidden button if I could pass the index to the event's function.
I had not thought of adding the reference to each row as a variable. It seems to work very well.
For future reference to others, here is the code from the cellRemoveButton click event:
// Declare some variables
var i = this.parent.index;
var oContractorLeft = ContractorTableLeft.Contractor;
var oContractorRight = ContractorTableRight.Contractor;
// Remove this row by accessing its index within the set of 'Item' row instances of the parent table
_Item.removeInstance(i);
// Since this table is actually 3 tables, we need to remove the other two table's instances as well.
// Their index should be the same, so we just need to get their names correct.
oContractorLeft.instanceManager.removeInstance(i);
oContractorRight.instanceManager.removeInstance(i);
// removing the row doesn't trigger calculations in tables in the form's current target (fixed in later versions of Acrobat)
// force calculations to fire so the ItemIndex field's value is updated according to the remaining row's indexes
// see http://forms.stefcameron.com/2006/05/20/add-recalculate/
xfa.form.recalculate(1);
Again, thank you!
Karl -
Removing duplicate rows from SELECT
Hi, I was wondering if there was any way to remove duplicate rows from a select statement.
My table looks like this:
CREATE TABLE CUS_ID_TO_PC_ID (
CUSTOMER_ID VARCHAR2 (10) NOT NULL,
PC_ID VARCHAR2 (25) NOT NULL,
PASSWORD VARCHAR2 (25) NOT NULL,
REG_DATE DATE,
PRODUCT_DESC VARCHAR2 (25),
EXPIRE_DATE DATE,
SERIAL_NBR VARCHAR2 (12),
LDAP_USER VARCHAR2 (200),
COMMENTS VARCHAR2 (2000),
PC_ID_5_4 VARCHAR2 (25),
PC_ID_6_0 VARCHAR2 (25),
PASSWORD_5_4 VARCHAR2 (25),
PASSWORD_6_0 VARCHAR2 (25),
PC_ID_6_1 VARCHAR2 (25),
PASSWORD_6_1 VARCHAR2 (25),
OPERATING_SYSTEM VARCHAR2 (20),
STATUS VARCHAR2 (1)
Basically, I want to retrieve all columns from the table but remove all duplicate variations of
the pc_id/serial_nbr combinations.
For example, given this data:
PC_ID SERIAL_NBR CUSTOMER_NO
1234567 AAA C345
1234567 AAA C567
3333333 BBB C456
only the 1st and 3rd rows would be returned.
Any ideas?Try something like this:
select * from your_table yt
where rowid in (select max(rowid)
from your_tabel yt2
where yt2.pc_id = yt.pc_id
and yt2.serial_nbr = yt.serial_nbr); -
I have two tables MEMBER_ADRESS and MEMBER_ORDER. The MEMBER_ADRESS has duplicate rows in it based on MEMBER_ID and MATCH_VALUE. These duplicate ADDRESS_IDs were used in MEMBER_ORDER. I need to remove the duplicates from MEMBER_ADRESS making sure I keep the one with PRIMARY_FLAG = ‘Y’ and update MEMBER_ORDER.ADDRESS_ID to the MEMBER_ADRESS.ADDRESS_ID that I kept.
I am on 11gR1
Thanks for the help.
CREATE TABLE MEMBER_ADRESS
ADDRESS_ID NUMBER,
MEMBER_ID NUMBER,
ADDRESS_1 VARCHAR2(30 BYTE),
ADDRESS_2 VARCHAR2(30 BYTE),
CITY VARCHAR2(25 BYTE),
STATE VARCHAR2(2 BYTE),
ZIPCODE VARCHAR2(10 BYTE),
CREATION_DATE DATE,
LAST_UPDATE_DATE DATE,
PRIMARY_FLAG CHAR(1 BYTE),
ADDITIONAL_COMPANY_INFO VARCHAR2(40 BYTE),
MATCH_VALUE NUMBER(38) GENERATED ALWAYS AS (TO_NUMBER( REGEXP_REPLACE ("ADDITIONAL_COMPANY_INFO"||"ADDRESS_1"||"ADDRESS_2"||"CITY"||"STATE"||"ZIPCODE",'[^[:digit:]]')))
Insert into MEMBER_ADRESS
(ADDRESS_ID, MEMBER_ID, ADDRESS_1, ZIPCODE, CREATION_DATE, LAST_UPDATE_DATE, PRIMARY_FLAG, MATCH_VALUE)
Values
(200, 30, '11 Hourse Rd.',
'58754', TO_DATE('08/11/2011 10:56:25', 'MM/DD/YYYY HH24:MI:SS'), TO_DATE('08/12/2011 10:34:10', 'MM/DD/YYYY HH24:MI:SS'), 'Y', 1158754);
Insert into MEMBER_ADRESS
(ADDRESS_ID, MEMBER_ID, ADDRESS_1, ZIPCODE, CREATION_DATE, LAST_UPDATE_DATE, PRIMARY_FLAG, MATCH_VALUE)
Values
(230, 12, '101 Banks St',
'58487', TO_DATE('08/11/2011 10:56:25', 'MM/DD/YYYY HH24:MI:SS'), TO_DATE('08/12/2011 10:35:42', 'MM/DD/YYYY HH24:MI:SS'), 'N', 10158487);
Insert into MEMBER_ADRESS
(ADDRESS_ID, MEMBER_ID, ADDRESS_1, ZIPCODE, CREATION_DATE, LAST_UPDATE_DATE, PRIMARY_FLAG, MATCH_VALUE)
Values
(232, 12, '101 Banks Street',
'58487', TO_DATE('08/11/2011 10:56:25', 'MM/DD/YYYY HH24:MI:SS'), TO_DATE('08/12/2011 10:41:15', 'MM/DD/YYYY HH24:MI:SS'), 'N', 10158487);
Insert into MEMBER_ADRESS
(ADDRESS_ID, MEMBER_ID, ADDRESS_1, ZIPCODE, CREATION_DATE, LAST_UPDATE_DATE, PRIMARY_FLAG, MATCH_VALUE)
Values
(228, 12, '101 Banks St.',
'58487', TO_DATE('08/11/2011 10:56:25', 'MM/DD/YYYY HH24:MI:SS'), TO_DATE('08/12/2011 10:38:19', 'MM/DD/YYYY HH24:MI:SS'), 'N', 10158487);
Insert into MEMBER_ADRESS
(ADDRESS_ID, MEMBER_ID, ADDRESS_1, ZIPCODE, CREATION_DATE, LAST_UPDATE_DATE, PRIMARY_FLAG, MATCH_VALUE)
Values
(221, 25, '881 Green Road',
'58887', TO_DATE('08/11/2011 10:56:25', 'MM/DD/YYYY HH24:MI:SS'), TO_DATE('08/12/2011 10:34:18', 'MM/DD/YYYY HH24:MI:SS'), 'Y', 88158887);
Insert into MEMBER_ADRESS
(ADDRESS_ID, MEMBER_ID, ADDRESS_1, ZIPCODE, CREATION_DATE, LAST_UPDATE_DATE, PRIMARY_FLAG, MATCH_VALUE)
Values
(278, 28, '2811 Brown St.',
'58224', TO_DATE('08/11/2011 10:56:25', 'MM/DD/YYYY HH24:MI:SS'), TO_DATE('08/12/2011 10:36:11', 'MM/DD/YYYY HH24:MI:SS'), 'N', 281158224);
Insert into MEMBER_ADRESS
(ADDRESS_ID, MEMBER_ID, ADDRESS_1, ZIPCODE, CREATION_DATE, LAST_UPDATE_DATE, PRIMARY_FLAG, MATCH_VALUE)
Values
(280, 28, '2811 Brown Street',
'58224', TO_DATE('08/11/2011 10:56:25', 'MM/DD/YYYY HH24:MI:SS'), TO_DATE('08/12/2011 10:45:00', 'MM/DD/YYYY HH24:MI:SS'), 'Y', 281158224);
Insert into MEMBER_ADRESS
(ADDRESS_ID, MEMBER_ID, ADDRESS_1, ADDRESS_2, ZIPCODE, CREATION_DATE, LAST_UPDATE_DATE, PRIMARY_FLAG, MATCH_VALUE)
Values
(300, 12, '3421 West North Street', 'x',
'58488', TO_DATE('08/11/2011 10:56:25', 'MM/DD/YYYY HH24:MI:SS'), TO_DATE('08/12/2011 10:42:04', 'MM/DD/YYYY HH24:MI:SS'), 'Y', 342158488);
COMMIT;
CREATE TABLE MEMBER_ORDER
ORDER_ID NUMBER,
ADDRESS_ID NUMBER,
MEMBER_ID NUMBER
Insert into MEMBER_ORDER
(ORDER_ID, ADDRESS_ID, MEMBER_ID)
Values
(3, 200, 30);
Insert into MEMBER_ORDER
(ORDER_ID, ADDRESS_ID, MEMBER_ID)
Values
(4, 230, 12);
Insert into MEMBER_ORDER
(ORDER_ID, ADDRESS_ID, MEMBER_ID)
Values
(5, 228, 12);
Insert into MEMBER_ORDER
(ORDER_ID, ADDRESS_ID, MEMBER_ID)
Values
(6, 278, 28);
Insert into MEMBER_ORDER
(ORDER_ID, ADDRESS_ID, MEMBER_ID)
Values
(8, 278, 28);
Insert into MEMBER_ORDER
(ORDER_ID, ADDRESS_ID, MEMBER_ID)
Values
(10, 230, 12);
COMMIT;Hi John;
Sorry I missed your post. Yes sorry about the flag. Please take a look as these before and after sets. I hope this helps. I should have posted this in the begining.
MEMBER_ORDER (BEFORE)
ORDER_ID ADDRESS_ID MEMEBER_ID
4 228 12
10 230 12
5 230 12
11 232 12
12 300 12
8 278 28
6 278 28
3 200 30
MEMBER_ORDER (AFTER)
ORDER_ID ADDRESS_ID MEMEBER_ID
4 232 12
10 232 12
5 232 12
11 232 12
12 300 12
8 280 28
6 280 28
3 200 30
MEMBER_ADDRESS (BEFORE)
ADDRESS_ID MEMBER_ID ADDRESS_1 CREATION_DATE LAST_UPDATE_DATE PRIMARY_FLAG MATCH_VALUE
228 12 101 Banks St. 8/11/2000 10:56:25 AM 8/12/2005 10:38:19 AM N 10158487
230 12 101 Banks St 8/11/2000 10:56:25 AM 8/12/2006 10:35:42 AM N 10158487
232 12 101 Banks Street 8/11/2000 10:56:25 AM 8/12/2007 10:41:15 AM N 10158487
300 12 3421 West North Street 8/11/2000 10:56:25 AM 8/12/2011 10:42:04 AM Y 342158488
221 25 881 Green Road 8/11/2000 10:56:25 AM 8/12/2011 10:34:18 AM Y 88158887
278 28 2811 Brown St. 8/11/2000 10:56:25 AM 8/12/2006 10:36:11 AM N 281158224
280 28 2811 Brown Street 8/11/2000 10:56:25 AM 8/12/2011 10:45:00 AM Y 281158224
200 30 11 Hourse Rd. 8/11/2000 10:56:25 AM 8/12/2005 10:34:10 AM Y 1158754
MEMBER_ADDRESS (AFTER)
ADDRESS_ID MEMBER_ID ADDRESS_1 CREATION_DATE LAST_UPDATE_DATE PRIMARY_FLAG MATCH_VALUE
232 12 101 Banks Street 8/11/2000 10:56:25 AM 8/12/2007 10:41:15 AM N 10158487
300 12 3421 West North Street 8/11/2000 10:56:25 AM 8/12/2011 10:42:04 AM Y 342158488
221 25 881 Green Road 8/11/2000 10:56:25 AM 8/12/2011 10:34:18 AM Y 88158887
280 28 2811 Brown Street 8/11/2000 10:56:25 AM 8/12/2011 10:45:00 AM Y 281158224
200 30 11 Hourse Rd. 8/11/2000 10:56:25 AM 8/12/2005 10:34:10 AM Y 1158754 -
Removing Duplicate Rows from resultSet
I have a query pulling data from 5 tables in 12 columns. I have rows where all of the data is duplicated with the exception of one date column. How would I go about deleting rows that are duplicates with the exception of this one column? I still need to pull the date from the date column with the Max(date).
i.e.
Bob Smith 1 2 3 4 12-Jul-2006
Bob Smith 1 2 3 4 02-Aug-2006
Bob Smith 1 2 3 4 21-Jan-2006
Form this resultset I only want one row
Thanks.this example might be of help.
SQL> select * from employees;
YEAR EM NAME PO
2001 02 Scott 91
2001 02 Scott 01
2001 02 Scott 07
2001 03 Tom 81
2001 03 Tom 84
2001 03 Tom 87
6 rows selected.
SQL> select year, empcode, name, position,
2 row_number() over (partition by year, empcode, name
3 order by year, empcode, name, position) as rn
4 from employees;
YEAR EM NAME PO RN
2001 02 Scott 01 1
2001 02 Scott 07 2
2001 02 Scott 91 3
2001 03 Tom 81 1
2001 03 Tom 84 2
2001 03 Tom 87 3
6 rows selected.
SQL> Select year, empcode, name, position
2 From (Select year, empcode, name, position,
3 row_number() over (partition by year, empcode, name
4 order by year, empcode, name, position) as rn
5 From employees) emp
6 Where rn = 1;
YEAR EM NAME PO
2001 02 Scott 01
2001 03 Tom 81
SQL> Delete From employees
2 Where rowid in (Select emp.rid
3 From (Select year, empcode, name, position,
4 rowid as rid,
5 row_number() over (partition by year, empcode, name
6 order by year, empcode, name, position) as rn
7 From employees) emp
8 Where emp.rn > 1);
4 rows deleted.
SQL> select * from employees;
YEAR EM NAME PO
2001 02 Scott 01
2001 03 Tom 81
SQL> if you can post a sample create tables and data it will help us provide you a some solutions. -
How to remove empty row from rfc table output.
Hello,
I am using adaptive rfc and printing table output. The table rows start from 2nd row, the first row being empty. How can I remove the empty first row.
Here is what I tried.
wdContext.nodeDataSource().nodeTableOutput().moveNext();
and
wdContext.nodeDataSource().nodeTableOutput().moveTo(1);
Neither of them worked. Any clue is appreciated.
SrinivasIWDNodeElement first = wdContext.nodeDataSource().nodeTableOutput().getElementAt(0);
wdContext.nodeDataSource().nodeTableOutput().removeElement(first);
Armin -
How to delete the duplicate rows from the table
Hi,
I have 2 tbales namely component, component_audit
For each record in component table there are multiple entries in component_audit table.
I need to keep the first record and delete the others from the component_audit table
say for example
select a.component_id,a.dt_ti_stamp,a.component_name,a.column_before,b.comments from component_audit a,component b where a.component_id=b.component_id
( on the above result set only I shold apply the actual delete query )
PLease help me in this regards.
Thanks.delete from component_audit a where dt_ti_stamp not in (select
min(b.dt_ti_stamp)
from
component_audit b
where
a.component_id = b.component_id) -
Remove Duplicate Rows from Left Outer Join
Hi All,
I am new to Oracle..I have two tables as follow:
TableA(EmpID, Empname)
TableB(EmpID, DeptID, DeptName). A employee can work in multiple dept.
table A has 1 row as EmpID 1 and TableB has two rows for EmpID 1.
I have a search page which takes dept ID as parameter and return employee name...Dept ID is not mandatory feld for Search. If DeptID is passed it should return the employee who belongs to that Dept otherwise it should return 1 employee..
Now I have used as follow:
:IN_DEPTID is passed as parameter
Select EmpName from TableA Left Join tableB on a.EmpID = B.EmpID
WHERE
CASE WHEN :IN_DEPTID IS NULL
IN_DEPTID IS NULL
ELSE|
DEPTID = :IN_DEPTID
Now problem is when Dept ID is passed it correctly returns a row but if no deptid is passed it returns 2 rows but i want ony one row as there is only one employee.
Please help;
Edited by: user10239708 on 10 Sep, 2008 12:24 AM
Edited by: user10239708 on 10 Sep, 2008 12:28 AMTry this
Select
from
tableA a
where
(exists (select 1 from tableB b where a.empid = b.empid and deptid = :IN_DEPTID )
or
:IN_DEPTID is null) you database design is not good you should keep the emp, department mapping in different table.
Regards
Singh -
Identifying and reporting Duplicate rows from table
I want to fetch all the duplicate row from the table and need to report all of it.
I am trying to run the below query but and not getting the expected output. Please help me.
Query
SELECT * FROM ADDT_RPT_REQ A WHERE
TRIM(A.EMAIL_ADDR) IN
(SELECT TRIM(EMAIL_ADDR) FROM ADDT_RPT_REQ B
WHERE TRIM(B.EMAIL_ADDR) = TRIM(A.EMAIL_ADDR)
AND A.ph_num IN
(SELECT PH_NUM FROM ADDT_RPT_REQ B
WHERE TRIM(A.PH_NUM ) = TRIM(B.PH_NUM)
There are in all 7 columns in the table where id is Unique Id.
The expected output is something like.
FST_NAME LAST_NAME EMAIL_ADDR WORK_PH_NUM ROW_ID LAST_UPD BU_ID
VALERIE HALL [email protected] 7819370177 2-21N-4312 31-AUG-04 0-R9NH
VALERIE HALL [email protected] 7819373737 2-21N-4327 29-JAN-04 0-R9NH
VALERIE HALL [email protected] 6034272034 2-21N-4309 04-APR-03 0-R9NH
VALERIE HALL [email protected] 7819373737 2-21N-4317 04-APR-03 0-R9NH
VALERIE HALL [email protected] 8563748820 2-21N-4329 31-AUG-04 0-R9NH
VALERIE HALL [email protected] 7819373737 2-21N-4319 04-APR-03 0-R9NH
VALERIE HALL [email protected] 7819373737 2-21N-4326 04-APR-03 0-R9NH
VALERIE HALL [email protected] 7819373737 2-21N-4324 04-APR-03 0-R9NH
VALERIE HALL [email protected] 8604237395 2-21N-4330 31-AUG-04 0-R9NH
VALERIE HALL [email protected] 7819373731 2-21N-4314 31-AUG-04 0-R9NH
VALERIE HALLORAN [email protected] 6194771101 2-21N-4331 31-OCT-05 0-R9NH
VALERIE HALL [email protected] 7819373737 2-21N-4316 04-APR-03 0-R9NH
VALERIE HALL [email protected] 7819373737 2-21N-4321 04-APR-03 0-R9NH
VALERIE HALL [email protected] 7819373737 7-1W4N-293 15-MAY-04 0-R9NH
VALERIE HALL [email protected] 2032341604 2-21N-4307 31-AUG-04 0-R9NH
VALERIE HALL [email protected] 7819373737 2-21N-4325 04-APR-03 0-R9NH
VALERIE HALL [email protected] 7819373737 2-21N-4315 29-JAN-03 0-R9NH
VALERIE HALL [email protected] 7819373737 7-1W4N-291 15-MAY-04 0-R9NH
VALERIE HALLORAN [email protected] 6194771101 2-21N-4332 31-OCT-05 0-R9NH
VALERIE HALL [email protected] 6038885349 2-21N-4310 31-AUG-04 0-R9NH
VALERIE HALL [email protected] 7819373737324 2-21N-4328 31-AUG-04 0-R9NH
VALERIE HALL [email protected] 7819370177324 2-21N-4313 31-AUG-04 0-R9NHHi again!
Try that:
SELECT rowid, fst_name, last_name, email_addr, work_ph_num, row_id, last_upd, bu_id
FROM ADDT_RPT_REQ A
WHERE rowid > (SELECT MIN(rowid)
FROM ADDT_RPT_REQ B
WHERE B.fst_name = A.fst_name
AND B.last_name = A.last_name
AND B.email_addr = A.email_addr
AND B.work_ph_num = A.work_ph_num
AND B.row_id = A.row_id
AND B.last_upd = A.last_upd
AND B.bu_id = A.bu_id);This query should show you all duplicate rows. Use the rowid and DELETE to get rid of these rows.
DELETE FROM addt_rpt_req A
WHERE rowid IN (SELECT rowid
FROM (SELECT rowid, row_number() OVER (PARTITION BY fst_name, last_name, email_addr, work_ph_num, row_id, last_upd, bu_id
ORDER BY row_id) dup
FROM addt_rpt_req)
WHERE dup > 1);Yours sincerely
Florian W.
Edited by: Florian W. on 17.06.2009 14:17 -
Deleting Rows From A Table After Running a Report
I've created a report that inserts rows into a table on the asp page then calls a BI Publisher report to display the data. After running the report in BI Publisher I need to delete the rows from the table that had just been inserted. How is the best way to go about this in BI Publisher?
The best way I know of would be to use an "afterReport trigger".
An afterReport trigger fires after the XML output has been generated.
Thanks,
Bipuser -
Trick to remove duplicate entries from tables ?
hi.
i have 53tables which are having duplicate entries and names of all 53 tables r listed in top_t table ?
can any1 provide me solution to show and if possible ask for remove of those duplicates entries from each table if required ?
daily i am removing duplicates manually ....its too tedious now !
can any1 help me out ?Well, I suppose if the duplication is such that
SELECT DISTINCT * FROM tablename;gives you the required result, then you could have a procedure that made a copy of the table, deleted/truncated the original, then inserted the distinct values back into it.
In 10g you could even use flashback to avoid the temp copy - but it also means you can't use TRUNCATE so whether it's any more efficient I'm not sure. But just for fun and since it's urgent:
CREATE OR REPLACE PROCEDURE dedupe_table
( p_table_name user_tables.table_name%TYPE )
IS
k_start_timestamp TIMESTAMP := SYSTIMESTAMP;
BEGIN
SAVEPOINT start_of_dedupe;
BEGIN
EXECUTE IMMEDIATE 'DELETE ' || p_table_name;
EXCEPTION
WHEN OTHERS THEN
ROLLBACK TO start_of_dedupe;
RAISE_APPLICATION_ERROR
( -20000
, 'Error deleting ' || UPPER(p_table_name) ||
CHR(10) || DBMS_UTILITY.FORMAT_ERROR_BACKTRACE
, TRUE );
END;
BEGIN
EXECUTE IMMEDIATE
'INSERT INTO ' || p_table_name ||
' SELECT DISTINCT * FROM ' || p_table_name || ' AS OF TIMESTAMP :b1'
USING k_start_timestamp;
EXCEPTION
WHEN OTHERS THEN
ROLLBACK TO start_of_dedupe;
RAISE_APPLICATION_ERROR
( -20000
, 'Error repopulating ' || UPPER(p_table_name) ||
CHR(10) || DBMS_UTILITY.FORMAT_ERROR_BACKTRACE
, TRUE );
END;
END dedupe_table;
SQL> select * from wr_test;
COL1 C C
1 A B
1 A B
2 C D
2 C D
4 rows selected.
SQL> BEGIN
2 dedupe_table('WR_TEST');
3 END;
4 /
PL/SQL procedure successfully completed.
SQL> select * from wr_test;
COL1 C C
1 A B
2 C D
2 rows selected.I make no claims for robustness, efficiency or human safety.
Edited by: William Robertson on Sep 24, 2009 7:12 PM -
How to update duplicate row from table
Hi,
how to update duplicate row from table?
First to find duplicate row then update duplicate row with no to that duplicate row in oracle.
can you give me suggestion on it?
Thanks in advance.
your early response is appreciated...In order to find a duplicate row, see:
http://asktom.oracle.com/pls/asktom/f?p=100:11:0::::P11_QUESTION_ID:1224636375004
(or search this forum, your question has been asked before)
In order to update it, just create and use an Oracle sequence, have it start and increment at a value that doesn't exist in your table.
If that doesn't get you going, post some CREATE TABLE + INSERT INTO statements, and the results you want from them, in other words: a complete testcase. -
i have a table A suppose it has 3 columns
id name sal
==========
1 A 100
1 A 100
2 B 200
2 B 200
2 B 200
3 C 300
I want to find duplicate rows from the above table without passing any column in to the where clause .
please help me to find out this query.maybe you should try the database forum...
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