New Lines within .txt files

Hello,
I'm creating and writing text from a standalone application to a text file, however when using the "\n" command within a string in java, it is outputted as a box, not an actual new line within the text file.
Is there any way of solving this problem?
Thanks

Use a BufferedWriter and the newLine() method. It will use the appropriate newline String for the platform you are running on. In Windows this is "\r\n".

Similar Messages

Read at each new line from .txt file

Hi guys
I want to read from a file which I am saving using labview. What I am doing is reading 128 bytes fro VISA port and saving it in .txt file with new line constant. At some later time I want to read 128 bytes from that text file do some processing and display it. The "read from text file" vi has convert EOL but I am not able to configure it. Please help me..
Thanks in advance
Niladri

Hi Newbee_3,
Do 1 thing, Read the txt file & convert this into string, Then you have all the flexibility to do whatever you want.
Thanks
Kudos are always welcome if you got solution to some extent.
I need my difficulties because they are necessary to enjoy my success.
--Ranjeet

How to write new line to a File?

How to write new line to a file?
I have a string to be written to a file. the string contains "\n" in it. But why it is not showing the new line in the file.
I have tryed FileWriter class and FileOutputStream class, but none of them works?
any suggestion please...

Probably using PrintStream::println() is a portable way.
import java.io.FileOutputStream;
import java.io.PrintStream;
public class NewLine {
    public static void main(String[] args) {
     try {
         PrintStream ps = new PrintStream(new FileOutputStream("foo.txt"));
         ps.write("string".getBytes());
         ps.println();
         ps.close();
     } catch (java.io.IOException e) {
         e.printStackTrace();
}Regards,

Appending to new line in text file

I am trying to append text to a new line to a file. I set the append parameter to true and I try to output the new line character after I write the string to the file. However it is still appending the next string to the end of the first rather than in the line below. My code is below. Can someone please help me?
Thanks
public static boolean WriteToFile(String nameOfFile,
String contents)
FileWriter myFileWriter = null;
try
System.out.println("Attempting to write text to = " + nameOfFile);
myFileWriter = new FileWriter(nameOfFile,true);
myFileWriter.write(contents);
myFileWriter.write('\n');
myFileWriter.close();
return true;
catch (Exception e)
System.out.println("EXCEPTION thrown ");
return false;
}

I am trying to append text to a new line to a file.
I set the append parameter to true and I try to
o output the new line character after I write the
string to the file. However it is still appending the
next string to the end of the first rather than in
the line below. My code is below. Can someone please
help me?
Thanks
public static boolean WriteToFile(String nameOfFile,
String
String
String contents)
FileWriter myFileWriter = null;
try
System.out.println("Attempting to write
ting to write text to = " + nameOfFile);
myFileWriter = new
eWriter = new FileWriter(nameOfFile,true);
myFileWriter.write('\n');
myFileWriter.write(contents); myFileWriter.close();
return true;
catch (Exception e)
System.out.println("EXCEPTION thrown ");
return false;
try the change what i have made in bold

New lines in a file

I'm trying to find a good way to get new lines in a file, and while this works it also uses 100% CPU and is driving me nuts. At least the profiler says this is .run is using the most, and taskmanager gives it 100%. The file name changes every day.
package net.st0rm.ss.loghandlers;
import java.io.*;
import java.util.ArrayList;
import java.util.Calendar;
import java.util.Timer;
import java.util.TimerTask;
import net.st0rm.ss.Log;
import net.st0rm.ss.gamecmdhandlers.GameCommandHandler;
import net.st0rm.ss.irc.IRC;
public abstract class LogHandler {
     public static ArrayList<GameCommandHandler> gameCmdHandlers = new ArrayList<GameCommandHandler>();
     private BufferedReader reader = null;
     private File directory = null;
     private LogReadThread thread = null;
     private String thisLine = null;
     private boolean skip = true;
      * Time to wait between reads
     private Long delay = 100L;
      * Creates a new instance
      * @param directory Directory of the files used
      * @param skip Should the reader skip lines already existing?
     public LogHandler(File directory, boolean skip) {
          this.directory = directory;
          this.skip = skip;
     public String getFileName() { return ""; };
     private class LogReadThread extends Thread {
          public boolean stop = false;
          public void run() {
               Calendar c = Calendar.getInstance();
               c.set(Calendar.HOUR_OF_DAY, 23);
               c.set(Calendar.MINUTE, 59);
               c.set(Calendar.SECOND,59);
               StringBuilder sb = new StringBuilder(1000);
               new Timer("Restart Timer").schedule(
                         new TimerTask() {
                              public void run() {
                                   try {
                                        Thread.sleep(3000);
                                   } catch (InterruptedException e) {
                                        // TODO Auto-generated catch block
                                        e.printStackTrace();
                                   IRC.getInstance().msg("Restarting reader \"" + this.getClass().getSimpleName() + "\" for the new day.");
                                   LogHandler.this.restartReader();
                         ,c.getTime(), 3600000*24);
               try {
                    reader = new BufferedReader(new FileReader(directory.getAbsolutePath() + "/" + getFileName()));
                    if (skip) while ((reader.readLine()) != null);
                    while (!stop) {
                         try {
                              Thread.sleep(delay);
                         } catch (InterruptedException e) { System.out.println("Thread Interupted!"); }
                         while ((sb.append(reader.readLine())).toString() != null) { onNewLine(sb.toString()); sb.delete(0, sb.length()); }
                    reader.close();
               } catch (IOException e) {
                    Log.log(e);
      * Call to re-start the file stream
     public void restartReader() {
          if (thread != null) thread.stop = true;
          thread = new LogReadThread();
          thread.start();
      * Called when a new line is added to the file
      * @param line The line added
     public void onNewLine(String line) { }
}

I don't know what anybody can say other than "debug and profile your code".
It's weird that you have a Thread.sleep in the run method of a TimerTask. Why not just change the scheduling of the task?
This:
while ((sb.append(reader.readLine())).toString() != null) {
    onNewLine(sb.toString());
    sb.delete(0, sb.length());
}(reindented to make it easier to read) is fishy. Even when you reach the end of reader's input, I think it will just loop forever. That's because appending null to a string buffer and calling toString results in the string "null", not the value null. So that while loop will never end.
Good luck.

New line in text-files

Hallo,
this I have a problem with writing data in a text-file. How can tell LabVIEW (6.1) to begin a new line in the file?
I already tried the [carriage return] -- constant, building arrays, building spreadsheat strings from array etc.. Everything wit no success.
Can anybody of you help me?
Thanks a lot, Arno

Send an End of line character to the file. You can find an End of line constant in the string pallette.

New Line in Text File

Hi -
Im using the FileWriter and BufferedWriter classes to output text into a .txt file.
The text I am writing is taken from another text file using the FileReader and BufferedReader classes.
The text is reading from the file, and will also output to the new text file, however it won't insert a new line, it only inserts an 'unprintable' character i.e. an empty square
My code is below - its only starting out so its farily simple at the moment, just reading from one file and outputting to another.
Is there a way i can get the actual new line/carriage return inserted instead of the empty square. (im running Windows XP)
Thanks in advance
import java.io.*;
public class Pad {
private String inputPath;
private String outputPath;
/** Creates a new instance of Pad */
public Pad() {
inputPath = "C:\\OUTBOUND.TXT";
outputPath = "C:\\04'06.txt";
* @param args the command line arguments
public static void main(String[] args) {
// TODO code application logic here
System.out.println("PAD File");
//Read PAD File
Pad p = new Pad();
p.readPADFile(p.inputPath, p.outputPath);
public void readPADFile(String inputPath, String outputPath)
inputPath = this.inputPath;
outputPath = this.outputPath;
//System.out.println(inputPath);
int recordCount = 0;
String record = null;
try
FileReader fr = new FileReader(inputPath);
FileWriter fw = new FileWriter(outputPath);
BufferedReader br = new BufferedReader(fr);
BufferedWriter bw = new BufferedWriter(fw);
record = new String();
while((record = br.readLine())!=null)
recordCount++;
//System.out.println(recordCount + ": " + record);
bw.write(record + "\n");
bw.close();
br.close();
fw.close();
fr.close();
}catch(IOException e)
System.out.println("IOException Error");
e.printStackTrace();
System.out.println(e.toString());
}

I assume by using the
System.getProperty("line.separator") that this will
work independent of platform.Yes. And using bw.println() instead of bw.print() will already do it for you. So all you need to change in your program are two letters.

How to add new line to the file?

Hello,
I will like to print 2 line of string in the following format to the
file:- file.txt
String1
String2
How to print a new line after String1 so that String2 can be written after String1?
- Eugene -

Do you mean...
PrintWriter pw=new PrintWriter(new FileOutputStream("file"));
pw.println(string1);
pw.println(string2);
pw.close();
the println puts a new line after string1.

Adding line to txt file and then rename

Hello there. I am trying to create a class that will add a line to a txt file and then if the nuber of lines are greater than 5 it will rename the file.
I think I have solved it with this class.
My problem is that the file2.renameTo does not work does anyone have any suggestions why?
         public void CopyLines(String string, String location, String fileName) throws IOException {
             BufferedReader inputStream = null;
             PrintWriter outputStream = null;
               GregorianCalendar calendar = new GregorianCalendar(Locale.UK);
            boolean b=false;
             try {
                 int counter = 0;
                  File file2 = new File(location + fileName);
                  ArrayList arrays = new ArrayList();
                  if (file2.exists()){
                 inputStream =
                     new BufferedReader(new FileReader(file2));
                 String l;
                 while ((l = inputStream.readLine()) != null) {
                      arrays.add(l);
                     counter++;
                 outputStream =
                     new PrintWriter(new FileWriter(location + fileName));
                  if (!arrays.isEmpty()){
                       for(int i= 0; i<arrays.size();i++){
                          outputStream.println(arrays.get(i));
                 outputStream.println(string);
                 if (counter>5){
                      String newFileName = location + fileName + calendar.getTime().getTime();
                      b = file2.renameTo(new File(newFileName));
             } finally {
                 if (inputStream != null) {
                     inputStream.close();
                 if (outputStream != null) {
                     outputStream.close();
         }

What is ". . .does not work. . ."?

New Line in data file for sql loader

Hi all,
I have a requirement to load a data file in which some of the rows are in new line as given in following example. If i put a '\n' character in control file, then it will load only those records which have newline in them ignoring non new line ones. please have a look at control fileand provide a solution to it :-
32 grand street ~NY~NY
42 riverdrive,
apt 1B ~PL~TX
Richardson road
apt 32~ SF ~CA
As you see there are newline characters in record 2 and 3, right now my control file looks like this -
LOAD DATA
INFILE 'example.txt' "STR '\r\n'"
INTO TABLE "temp_table"
INSERT
FIELDS TERMINATED BY '~'
TRAILING NULLCOLS
(ADDRESS1,
CITY,
STATE)
If i remove "STR '\r\n'" , then the data gets loaded into different rows like the third record looks like this -
ADDRESS                         CITY                     STATE
Richardson road null null
apt 32 SF CA
Please help.

Your requirement is very unclear.
Is this your INPUT ?
--record 1
32 grand street ~NY~NY
--record 2
42 riverdrive, --"NL"
apt 1B ~PL~TX
--record 3
Richardson road --"NL"
apt 32~ SF ~CAIs this your OUTPUT?
ADDRESS      CITY STATE
32 grand street NY   NY
42 riverdrive,     null null
apt 1B          PL   TX
Richardson road null null
apt 32           SF   CAAre you using Linux or Windows platform?
You should have only one record terminator character.
*\r\n* is Windows The End of Line character (The Carriage Return + The Line Feed).
"STR '\r\n'" = "str X'0D0A'"
If there is no data after \r\n, columns will be null.
http://docs.oracle.com/cd/B28359_01/server.111/b28319/ldr_concepts.htm#i1005800

How to skip first TWO Lines of   .txt file    using XSLT Mapping

Hi Friends ,
                          I have an .txt file in has the format as
                           <TEST>
                            4564564545
                            56456444566
                            56465
                                How can i skip the first two Lines when i am writing the XSLT Mapping ?
                          That <TEST> and empty line shouldn't go the rfc .
                         How can i skip and sent to rfc using XSLT Mapping ?
Best Regards .,
V.Rangarajan

you can avoid the empty lines in your File Content Conversion by defining offset.
<i>Under Document Offset, specify the number of lines that are to be ignored at the beginning of the document.
This enables you to skip comment lines or column names during processing. If you do not make an entry, the default value is zero lines.</i>
ref: http://help.sap.com/saphelp_nw04/helpdata/en/2c/181077dd7d6b4ea6a8029b20bf7e55/content.htm
then the generated XML after FCC will not have the empty lines.

New line character in File adapter

I am having a receiver file adapter which generates files with multiple lines.
My problem is when the target file is opened in notepad there is no line break and the lines comes as continous string with small rectangle as separator.This fails the target upload program.
When I remove those small squares in notepad and hit enter and then upload it gets uploaded successfully.
Is there any way to have line break so that new line will be generated each time (the documenation says the by-default it adds new line character then why in notepad it opens like a continous string?)
Thanks in advance.
Regards
Rajeev

Hello
I know by default File Adapter value is line break. But if I open that generated file in notepad, the record does'nt appear on the new line. Instead at the end of each line there is special character added at the end of each record. When I hit enter and deletes that special character and then try to load that file it gets loaded successfully.
So my problem is how to generate the file will give record on the new line. I tried to give 'nl' as endSeparator.
How to give hexadecimal values? I tried giving '0xHH' but that gives error in File Adapter
"Error: Conversion initialization failed: Exception: java.lang.NumberFormatException: For input string: "HH"
Thanks in advance.
Regards
Rajeev

New Line in EBCDIC file created by receiver file adapter

Hi mates,
I've configured the receiver file adapter to create a file in EBCDIC format by specifyin the File encoding 'Cp037'. When the file is viewed on the AS400 system using the command DSPPFM, it appears as a continuous text instead of line-by-line. I've tried specifying 0x0D(CR), 0x0A(LF), 'nl' as the endSeparator for the record type in content conversion, but no luck. Still the file looks like a continuous text.
I learnt from the following links that the New Line character (NL or NEL) in AS400 is Unicode '0x85'.
<a href="http://bugs.sun.com/bugdatabase/view_bug.do?bug_id=4867251">OutputStreamWriter/InputSreamReader convert NEL to linefeed with Cp037 encoding</a>
<a href="http://search.cpan.org/~guido/libintl-perl-1.16/lib/Locale/RecodeData/IBM037.pm#CHARACTER_TABLE">CHARACTER TABLE</a>
But when I specify this '0x85' as the endSeparator, I get the error below as 0x85 (decimal equivalent 133) is not part of the standard ascii code i.e. basic 127 codes
<i>Conversion initialization failed: java.lang.Exception: java.lang.NumberFormatException: Value out of range. Value:"85" Radix:16</i>
Is there any way I can produce the EBCDIC file with new line as end separator for records?
I appreciate your inputs.
thx in adv
praveen

Instead of using binary mode for FTP and specifying encoding, endSeparator, I used the text mode and left the translation to the FTP server on AS400 system.
Desirably, it generated the file with right encoding and new line characters.
praveen

How to write data in differt line in .txt file

Hi all,
I am tring to write data on one file using utl_file,
the first cursor loop write data on first line of the file using
utl_file.put_line(..........................);
end the second cusor loop write the data on secion line of the same file using
utl_file.put_line(..........................);
file format we are given as .txt;
problem we are facing is when we open the file in notepad all the data is showing in one line...
same file if we open another tools like edit plus, word pad etc it showing the write formate( line by line)
Can any one help on this we need to set any setups in note pad????????????/

As others have said it sounds like an operating system difference.
If your Oracle is installed on a unix based server then the file will be written using Unix style newlines which are just Line Feed characters.
In Windows environments a newline is considered to be made of the Carriage Return/Line Feed character pair, not just the Line Feed.
Some applications such as MS Word or Wordpad can read Unix style linefeeds and interpret them as you expect as a Newline. However Notepad doesn't.
When you transfer the file from Unix to Windows, usually this is done using an FTP based mechanism. If you transfer the files using FTP Binary mode, then every byte of the file is transferred as it is on Unix, and the file will essentially be a unix file on a windows system. If, however, you transfer the files (from Unix to Windows) using FTP ASCII mode, then whenever FTP encounters a LineFeed character it will convert it to a Carriage Return/LineFeed pair of characters, so that the file will appear correctly in Notepad. Likewise if you transfer files from Windows to Unix in ASCII mode, then Carriage Return/LineFeed pairs of characters are converted to just a LineFeed character so that the file becomes Unix compatible. Note, you shouldn't transfer binary files in ASCII mode as it can corrupt them, it's only intented for text based files.

How to write new line on resource file.

Hello Everyone,
Can you please help me add new row on resource file, here is the code i have used to read my resource file.
I have no idea on how to add new line... Please help
private void btnBrowse1_Click(object sender, EventArgs e)
BrowseFile();
//versionIncrement();
if (txtInputfile.Text.Length > 0)
PathSelection = txtInputfile.Text;
oDataSet = new DataSet();
//now am reading the files fro the path that is selected
XmlReadMode omode = oDataSet.ReadXml(PathSelection);
for (int i = 0; i < oDataSet.Tables[2].Rows.Count; i++)
string comment = oDataSet.Tables["data"].Rows[i][2].ToString();
//the elements array contain all the columns filled
string[] elements = comment.Split('-'); //when it reaches the comma, it will jump to the next line
string font = elements[0]; //Font
string datestamp = elements[1]; //DateStamp
string commentVal = elements[2]; //Comment
string[] row = new string[] { oDataSet.Tables["data"].Rows[i][0].ToString(), oDataSet.Tables["data"].Rows[i][1].ToString(), font, datestamp = DateTime.Now.ToString(), commentVal };
Gridview_Input.Rows.Add(row);

Hello
Sitholimela,
>> Can you please help me add new row on resource file, here is the code i have used to read my resource file.
From your description, it seems that your resource file is a XML format file, if so, you could also have a try to use
LINQ To XML which is easy to operate the XML file to add new row to your resource file, and here is an example to show how to add a new element/row to the specific tree:
Linq to XML Add element to specific sub tree
Regards.
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New Lines within .txt files

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