Not well-formed error in firefox in implementing ajax--pls help

Question

hi techies,
I'm trying to implement ajax in firefox and i'm getting not well-formed error in error console
heres part of code
var xmlHttp;
function create(){
if(window.ActiveXObject){
xmlHttp=window.ActiveXObject("Microsoft.XMLHTTP");
else if(window.XMLHttpRequest){
xmlHttp=window.XMLHttpRequest();
else{
xmlHttp=new ActiveXObject("Msxml2.XMLHTTP");
function getEmployeeDetails(){
frm = document.forms[0];
empid = frm.elements["empid"].value;
url="empdetails.jsp?empid=" + empid;
xmlHttp.open("GET" ,url, true);
xmlHttp.onreadystatechange=doUpdate;
xmlHttp.send(null);
function doUpdate(){
if(xmlHttp.readyState==4 && xmlHttp.status == 200){
var root = xmlHttp.responseXML.documentElement;
----so on
jsp Page is
<%@ page import="java.sql.*" contentType="text/xml" %>
<%
String empid=request.getParameter("empid");
Class.forName("oracle.jdbc.driver.OracleDriver");
Connection con=DriverManager.getConnection("jdbc:odbc:vmouli","hr","hr");
Statement st=con.createStatement();
ResultSet rs=st.executeQuery("select first_name,salary from employees where employee_id=" + empid);
if(rs.next()){
out.println("<employee><name>");out.println(rs.getString(1));
out.println("</name><salary>");out.println(rs.getString(2));
out.println("</salary></employee>");
else{
out.println("<error>Employee ID not found</error>");
rs.close();
st.close();
con.close();
%>
Firefox error console is saying not well-formed and is pointing to starting of my jsp page
can anyone help plzzz

Answer 1

As BalusC said - run the JSP producing the xml.
Save that xml to a file - INCLUDING any white space - because thats what you actually get.
Open that xml file in your browser - it should tell you at that point if your xml is well formed.
AS BalusC said this is better done in a servlet - especially since you're just doing out.println.
JSPs add extra whitespace and carriage returns. While that won't necessarily break XML, it can cause problems with the first few characters.