Number datatype
Hi
Assume I have 5 digits 2 numbers (as below). I notice that they do not occupy the same space.(First one consumes more storage.)
What is the reason for this?
99999
10000
Edited by: Pascal Nouma on Aug 15, 2009 6:42 PM
Justin Cave wrote:
Oracle, like all programs, stores numbers in binary. It takes more binary bits to store larger numbers than smaller numbers even if they have the same number of decimal digits.Actually, NUMBER datatype is not stored in binary - [Understanding Oracle NUMBER Datatype|https://metalink2.oracle.com/metalink/plsql/f?p=130:14:7587170171678335381::::p14_database_id,p14_docid,p14_show_header,p14_show_help,p14_black_frame,p14_font:NOT,1007641.6,1,1,1,helvetica]. And yes, 99999 and 10000 do not occupy same number of bytes:
SQL> select dump(99999) from dual;
DUMP(99999)
Typ=2 Len=4: 195,10,100,100
SQL> select dump(10000) from dual;
DUMP(10000)
Typ=2 Len=2: 195,2Reason is 10000 is exact value of POWER(100,2). As soon as we, for example, add or subtract 1 space occupied will increase:
SQL> select dump(10001) from dual;
DUMP(10001)
Typ=2 Len=4: 195,2,1,2
SQL> select dump(9999) from dual;
DUMP(9999)
Typ=2 Len=3: 194,100,100
SQL> As you can see, number with more decimal digits can occupy less space.
SY.
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Hi
Is there a side effect for using "number" datatype for "date" column?
If so, what is the disadvantage?
Many thanksHi,
Ora_83 wrote:
Hi
Is there a side effect for using "number" datatype for "date" column?
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http://mamohiuddin.blogspot.com/2007/03/practical-approach-to-understand-oracle.html
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Hi All,
I have modified a column, which is of number datatype.
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Please suggest..
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Thnx in advance..
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Hi all,
Recently i came across one of the most wierd situation across my whole Oracle experience of almost 3 Yrs. I created a table TESTAB (using Oracle 9i) as
NUMBER_F NUMBER
NUMBER_PS NUMBER(5,2)
VARCHAR_F VARCHAR2(10)
CHAR_F CHAR(10)
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NUMBER_F NUMBER_PS VARCHAR_F CHAR_F
1 3.34
23 34.34
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123.23 99.34 Asim Ahmed
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Asim Ahmed.This feature is called 'implicit conversion'
http://download-west.oracle.com/docs/cd/B10501_01/appdev.920/a96624/03_types.htm#3435 -
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How to update precision value in number datatype
hello all
i hava a database containing data in that there is a table which contan a number datatype
that is number(10)
the table contain large amount of data
now i need the precision value 2
that is number(10,2)
how i can update is
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so please suggest the solution
thanks in advanceThe number of columsn has nothing to do with it. The number of rows has nothing to do with it.
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07:02:43 > create table t3 as select * from all_objects;
Table created.
Elapsed: 00:00:06.22
07:04:08 > desc t3
Name Null? Type
OWNER NOT NULL VARCHAR2(30)
OBJECT_NAME NOT NULL VARCHAR2(30)
SUBOBJECT_NAME VARCHAR2(30)
OBJECT_ID NOT NULL NUMBER
DATA_OBJECT_ID NUMBER
OBJECT_TYPE VARCHAR2(19)
CREATED NOT NULL DATE
LAST_DDL_TIME NOT NULL DATE
TIMESTAMP VARCHAR2(19)
STATUS VARCHAR2(7)
TEMPORARY VARCHAR2(1)
GENERATED VARCHAR2(1)
SECONDARY VARCHAR2(1)
NAMESPACE NOT NULL NUMBER
EDITION_NAME VARCHAR2(30)
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alter table t3 modify (data_object_id number(10))
ERROR at line 1:
ORA-01440: column to be modified must be empty to decrease precision or scale
Elapsed: 00:00:00.98
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07:09:06 2 from t3;
COUNT(*) MIN(DATA_OBJECT_ID) MAX(DATA_OBJECT_ID) COUNT(DISTINCTDATA_OBJECT_ID) COUNT(DATA_OBJECT_ID)
184456 0 1526320 12225 70092
1 row selected.
Elapsed: 00:00:00.11
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Table altered.
Elapsed: 00:00:00.07
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184456 rows updated.
Elapsed: 00:00:04.49Notice that our column of interest is now entirely null, so the restriction against reducing its scale or precision will not longer impact us.
07:11:00 >
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COUNT(*) MIN(DATA_OBJECT_ID) MAX(DATA_OBJECT_ID) COUNT(DISTINCTDATA_OBJECT_ID) COUNT(DATA_OBJECT_ID)
184456 0 0
1 row selected.
Elapsed: 00:00:00.04
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07:12:33 > /
Table altered.
Elapsed: 00:00:00.07
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184456 rows updated.
Elapsed: 00:00:04.01
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COUNT(*) MIN(DATA_OBJECT_ID) MAX(DATA_OBJECT_ID) COUNT(DISTINCTDATA_OBJECT_ID) COUNT(DATA_OBJECT_ID)
184456 0 1526320 12225 70092
1 row selected.
Elapsed: 00:00:00.09
07:14:49 > alter table t3 drop column temp_data_object_id;
Table altered.
Elapsed: 00:00:02.40
07:15:11 > desc t3
Name Null? Type
OWNER NOT NULL VARCHAR2(30)
OBJECT_NAME NOT NULL VARCHAR2(30)
SUBOBJECT_NAME VARCHAR2(30)
OBJECT_ID NOT NULL NUMBER
DATA_OBJECT_ID NUMBER(10,2)
OBJECT_TYPE VARCHAR2(19)
CREATED NOT NULL DATE
LAST_DDL_TIME NOT NULL DATE
TIMESTAMP VARCHAR2(19)
STATUS VARCHAR2(7)
TEMPORARY VARCHAR2(1)
GENERATED VARCHAR2(1)
SECONDARY VARCHAR2(1)
NAMESPACE NOT NULL NUMBER
EDITION_NAME VARCHAR2(30)
07:15:15 > -
How do i check number datatype with precision is 6
Hello,
If a variable is declared as number datatype with precision 6.
Foe testing purpose ,i want to check which value is having precision >6
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In my case everyday a nightly job is executed to execute the stored procs
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Looking forward for the response -
dear friends,
in the number datatype we specify precision and scale
limit of precision is 1-38 & scale is -64 to 127 if i m right
so i wll like 2 know when & how -ve scale value is used for data design
also plz tell me how 2 declare col if expected values 2 b entered in it r like 0.0000078 etc.
waiting for reply
thanking you
ganeshPerhaps the following will help
SQL> create table test1 (
2 a number(5,0),
3 b number(5,1),
4 c number(5,2),
5 d number(5,-1),
6 e number(5,-2)
7 );
Table created.
SQL> insert into test1 values (1.234, 1.234, 1.234, 1.234, 1.234);
1 row created.
SQL> insert into test1 values (12.34, 12.34, 12.34, 12.34, 12.34);
1 row created.
SQL> insert into test1 values (123.4, 123.4, 123.4, 123.4, 123.4);
1 row created.
SQL> insert into test1 values (.1234, .1234, .1234, .1234, .1234);
1 row created.
SQL> insert into test1 values (.01234, .01234, .01234, .01234, .01234);
1 row created.
SQL> select * from test1
2 ;
A B C D E
1 1.2 1.23 0 0
12 12.3 12.34 10 0
123 123.4 123.4 120 100
0 .1 .12 0 0
0 0 .01 0 0
SQL> -
Wht is max lenght of number datatype
Hi all,
Can any one tell me wht is the max lenght of number datatype in oracle
9i and 10g
Regards,William, this is amazing! Is is a bug?
SQL> CREATE TABLE TEST3
2 AS SELECT 1E45 BGN FROM DUAL
3 /
Table created.
SQL> SET NUMW 50
SQL> INSERT INTO TEST3 VALUES(1E39);
1 row created.
SQL> INSERT INTO TEST3 VALUES(1E50); <--"How it is taken the value more than the precision..."
1 row created.
SQL> INSERT INTO TEST3 VALUES(1E48);
1 row created.
SQL> SELECT * FROM TEST3;
BGN
1000000000000000000000000000000000000000000000
1000000000000000000000000000000000000000
1.00000000000000000000000000000000000000000000E+50
1000000000000000000000000000000000000000000000000
SQL> SELECT DATA_PRECISION, DATA_SCALE FROM USER_TAB_COLS
2 WHERE TABLE_NAME='TEST3'
3 AND COLUMN_NAME='BGN';
DATA_PRECISION
DATA_SCALE
"Why these values are not shown ??" -
How to format a number datatype
I had a report which uses a text field. In that text field included is a placeholder column that represents a datatype of number as &<CP_CAPITAL_BALANCE>. When I run it displays as:
Capital Balance of 3423548.00 as of ...
It should be formated into 3,423,548.00
Thanks,
WarrenHi,
you can choose your desired number format by setting the "Format Mask" property of you text field (e.g. NNNGNNNGNNNGNN0D00).
N = not mandatory digit
0 = mandatory digit (in this way you always have two decimal digits)
G = group separator
D = decimal separator
Hope this helps you
Bye
Raffy -
Largest number of digits for NUMBER datatype?
What is the largest length of a NUMBER that Oracle will "support"?
The documentation says the following:
Datatype Limits indicates:
"Can be represented to full 38-digit precision"
NUMBER Data Types indicates:
"Oracle guarantees the portability of numbers with precision of up to 20 base-100 digits, which is equivalent to 39 or 40 decimal digits depending on the position of the decimal point."
I realize if I define a column as simply NUMBER, I can insert numbers with a size up to 126 digits. However, Oracle seems to only maintain the first 40 digits IN MOST cases. The most number of digits it seems to allow is 40 before it starts to replace with 0's.
With numbers that have more than 40 digits, Oracle will sometimes replace any numbers after the 38th digit with a 0 and other times will replace with 0 after the 39th or 40th digit.
Therefore, what is the most number of digits we can have confidence in Oracle storing safely?
This was the code I used for testing this process.
create table max_num (num number);
declare
l_x number;
begin
for x in 1..200
loop
l_x := x;
insert into max_num values (rpad(1, x, 1));
end loop;
exception
when others then
dbms_output.put_line('STOP: '||l_x);
dbms_output.put_line(sqlerrm);
end;
select num, length(replace(num, 0)) from max_num;Hi,
user109389 wrote:
What is the largest length of a NUMBER that Oracle will "support"?
The documentation says the following:
Datatype Limits indicates:
"Can be represented to full 38-digit precision"
NUMBER Data Types indicates:
"Oracle guarantees the portability of numbers with precision of up to 20 base-100 digits, which is equivalent to 39 or 40 decimal digits depending on the position of the decimal point."
I realize if I define a column as simply NUMBER, I can insert numbers with a size up to 126 digits. However, Oracle seems to only maintain the first 40 digits IN MOST cases. The most number of digits it seems to allow is 40 before it starts to replace with 0's.
With numbers that have more than 40 digits, Oracle will sometimes replace any numbers after the 38th digit with a 0 and other times will replace with 0 after the 39th or 40th digit.
Therefore, what is the most number of digits we can have confidence in Oracle storing safely?...
If the documentation says 38, then I'll say 38, too.
If you put in a number greater than or equal to 1E39, then Oracle may round it to 38 significant digits; that is, the last digits you entered may get turned to 0's, or rounded up.
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