OAAM: Combining the Username and Password page?

Hi,
I am currently working on OAAM 11g. Is it possible to combine Username page and password page?
As of now first we enter the username, OAAM fingerprints the device and then displays the password page.
Also Is it possible to have only a text field for password rather than having a textpad/pinpad or anything?
Thanks,
Pradeep

Hi Pradeep,
Were you able to find a solution for this? I am trying to implement a similar login page and any information you provide will be very helpful.
Thanks,
N

Similar Messages

  • How do i send the username and password to yahoo web page through url

    how do i send the username and password to yahoo web page through url i.e as Query string so that my account in yahoo will open...

    If you don't mind using a library, then download and use the Apache HttpClient library. It takes care of all these details for you.

  • For the 1st time I am trying to send an iPhoto by email but get an error message "combinations of username and password not recognised" I use the same details to log on to my Sky Mail (yahoo mail ) account . Any ideas?

    For the 1st time I am trying to send an iphoto by e-mail but get the error message " combination of username and password not recognised  by the server" I use Sky Mail ( yahoo mail) and input the same username and password that I access Sky Mail - have retried many times. Predictably the Sky help desk have no idea. Can anyone help please?

    I regret that you're having trouble setting up your email, corbad! You're on the right track with your incoming email address. You might also try incoming.verizon.net or incoming.yahoo.verizon.net as possible alternatives, and 995 as the port number. Please let me know how that goes!
    DionM_VZW
    Follow us on Twitter www.twitter.com/vzwsupport

  • HT1695 I am trying to connect to my uni wifi, and when i click on the wifi, it directs me to a log in page. However, the two boxes to enter the username and password do not appear. Can anyone help me with this???

    I am trying to connect to my uni wifi, and when i click on the wifi, it directs me to a log in page. However, the two boxes to enter the username and password do not appear. Can anyone help me with this???

    You didn't say what you have already tried, but if you haven't already done so, power-cycle your router (unplug it for 15 seconds then plug it back in), then on your phone go to Settings>General>Reset and tap Reset Network Settings, then try joining your wifi again.

  • Sharing via email says the server did not recognize the username and password  combination

    I am trying to share photos in iPhoto via email (gmail) and it says the server does not recognize the username password combination. I have deleted the email account rebooted iMac and re-entered the gmail account info and I get the same message. I have confirmed the username and password are correct.

    LarryHN I guess I should have clarified that. I did try it that way and I am able to email pictures with mail set as the email client. When I change it to iPhoto as the email client is when I get this message. I have the same setup on my Macbook and it works great for emailing pictures from iPhoto. Although I can send them through email client, I prefer doing it through iPhoto.

  • What is the username and password for the web page on the hp deskjet 2540 printer?

    I need to administer my Deskjet 2540 through my web browser, but do not know the username and password. When it says log in it says 'The server http://[ip adress] requires a pasword. The server says: admin.' I have tryed to use admin as the usermane and no password but it does not work. Is there a way to reset the pasword?
    Thanks

    Hello there @Aokvilla , Welcome to the Forums!
    For the issue you are having, I would recommend trying a different web browser for starters, and if that doesn't help, follow the instructions below from another post with a resolved solution. If those steps don't help, the problem could be your router.
    HP printer requires a username and password by @pcwizard 
    Good luck!
    R a i n b o w 7000I work on behalf of HP
    Click the “Kudos Thumbs Up" at the bottom of this post to say
    “Thanks” for helping!
    Click “Accept as Solution” if you feel my post solved your issue, it will help others find the solution!

  • What is the username and password for the airport extreme router

    I just switched from a wired router to an airport extreme and im trying to access the router information by typing in my router into the search bar of safari, when I used my old router the username and password was admin, admin. but this isnt the case with the airport extreme, does anyone know what the username and password combination is for airport extreme?

    Unlike routers from most other manufacturers, Apple's Airport devices cannot be configured using a web browser pointed to the IP address of the Base Station. Any manual configuration of the Airport Base Station must be done using the Airport Admin Utility provided by Apple.
    FYI, when using the Airport Admin Utility the default password for the Airport Base Station is the word "public".

  • Dynamically pass the username and password to report server to invoke reports

    Hi
    The scenario is as follows:-
    9iAS is installed under - Windows 2000 (web server and report Server 6i) and everything works fine.
    We have developed a page using pl/sql cartrige (oracle 8i), from that a report is invoked with some parameters. However, the userid and password is stored under keymap file (cgicmd.dat).
    Is there anyway to pass dynamically the username and password to report server in order to invoke the report.?
    Can any one advise?
    null

    Check out
    http://serverfault.com/questions/371907/can-you-pass-user-pass-for-http-basic-authentication-in-url-parameters
    Kind regards,
    Margriet Bruggeman
    Lois & Clark IT Services
    web site: http://www.loisandclark.eu
    blog: http://www.sharepointdragons.com

  • How can i clear the usernames and passwords history from all login websites?

    how can i clear the usernames and passwords in the log in history of the websites? example when i want to login to my facebook i always type first letter of my e-mail and it comes with the passwords because before i put remember my password, and in other websites so, i just need to delete all this login history and it's not working from the clear everything !!! :S any idea please !! thanks in advance :)

    See:
    http://kb.mozillazine.org/Deleting_autocomplete_entries
    http://kb.mozillazine.org/Password_Manager

  • How to catch exception while validating the username and password in hbm

    Hi,
    I do want to set the username and password dynamically in hibernate.cfg.xml
    Here below is my configuration file.
    {code<hibernate-configuration> 
    <session-factory> 
           <property name="hibernate.bytecode.use_reflection_optimizer">false</property> 
           <property name="hibernate.connection.driver_class">oracle.jdbc.driver.OracleDriver</property> 
           <property name="hibernate.connection.pool_size">10</property> 
           <property name="show_sql">true</property> 
           <property name="hibernate.dialect">org.hibernate.dialect.OracleDialect</property> 
           <property name="hibernate.hbm2ddl.auto">update</property> 
           <property name="current_session_context_class">thread</property> 
           <property name="show_sql">true</property> 
         </session-factory> 
    </hibernate-configuration>{code}
    Also im getting that session factory object like the below code.
    public class Sessions {        private static SessionFactory sessionFactory;      private static Configuration configuration = new Configuration();        static {          try {              String userName = GuigenserviceImpl.userName;              String password = GuigenserviceImpl.password;              String hostName = GuigenserviceImpl.hostName;              String portNo = GuigenserviceImpl.portNo;              String sId = GuigenserviceImpl.sId;                  configuration                      .setProperty("hibernate.connection.username", userName);              configuration                      .setProperty("hibernate.connection.password", password);              configuration.setProperty("hibernate.connection.url",                      "jdbc:oracle:thin:@" + hostName + ":" + portNo + ":" + sId);                try {              configuration.configure("/hibernate.cfg.xml");              sessionFactory = configuration.buildSessionFactory();              GuigenserviceImpl.strAccpted = "true";              }              catch (Exception e) {                    e.printStackTrace();                  GuigenserviceImpl.strAccpted = "false";              }            }          catch (HibernateException hibernateException) {              GuigenserviceImpl.strAccpted = "false";              hibernateException.printStackTrace();          }          catch (Throwable ex) {                GuigenserviceImpl.strAccpted = "false";              ex.printStackTrace();              throw new ExceptionInInitializerError(ex);          }      }          public static SessionFactory getSessionFactory() {          return sessionFactory;      } 
    So, in this above scenario, suppose if im giving the wrong password means exception should be caught and the string variable "GuigenserviceImpl.strAccpted" should be assigned to false.
    But im getting the SQL Exception only in console like wrong username and password. And finally i couldn't able to catch the exception in Sessions class, static block.
    Anyone can help me in catching that SQL Exception in my Sessions class and i need to handle that SQL Exception in my class.
    Im getting this following exception message in my console.
      INFO: configuring from resource: /hibernate.cfg.xml  Apr 6, 2009 2:47:00 PM org.hibernate.cfg.Configuration getConfigurationInputStream  INFO: Configuration resource: /hibernate.cfg.xml  Apr 6, 2009 2:47:00 PM org.hibernate.cfg.Configuration doConfigure  INFO: Configured SessionFactory: null  Apr 6, 2009 2:47:00 PM org.hibernate.connection.DriverManagerConnectionProvider configure  INFO: Using Hibernate built-in connection pool (not for production use!)  Apr 6, 2009 2:47:00 PM org.hibernate.connection.DriverManagerConnectionProvider configure  INFO: Hibernate connection pool size: 10  Apr 6, 2009 2:47:00 PM org.hibernate.connection.DriverManagerConnectionProvider configure  INFO: autocommit mode: false  Apr 6, 2009 2:47:00 PM org.hibernate.connection.DriverManagerConnectionProvider configure  INFO: using driver: oracle.jdbc.driver.OracleDriver at URL: jdbc:oracle:thin:@192.168.1.12:1521:orcl  Apr 6, 2009 2:47:00 PM org.hibernate.connection.DriverManagerConnectionProvider configure  INFO: connection properties: {user=scott, password=****}  Apr 6, 2009 2:47:01 PM org.hibernate.cfg.SettingsFactory buildSettings  WARNING: Could not obtain connection metadata  java.sql.SQLException: ORA-01017: invalid username/password; logon denied        at oracle.jdbc.driver.SQLStateMapping.newSQLException(SQLStateMapping.java:70)      at oracle.jdbc.driver.DatabaseError.newSQLException(DatabaseError.java:131)      at oracle.jdbc.driver.DatabaseError.throwSqlException(DatabaseError.java:204)      at oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:455)      at oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:406)      at oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:399)      at oracle.jdbc.driver.T4CTTIoauthenticate.receiveOauth(T4CTTIoauthenticate.java:799)      at oracle.jdbc.driver.T4CConnection.logon(T4CConnection.java:368)      at oracle.jdbc.driver.PhysicalConnection.<init>(PhysicalConnection.java:508)      at oracle.jdbc.driver.T4CConnection.<init>(T4CConnection.java:203)      at oracle.jdbc.driver.T4CDriverExtension.getConnection(T4CDriverExtension.java:33)      at oracle.jdbc.driver.OracleDriver.connect(OracleDriver.java:510)      at java.sql.DriverManager.getConnection(DriverManager.java:525)      at java.sql.DriverManager.getConnection(DriverManager.java:140)      at org.hibernate.connection.DriverManagerConnectionProvider.getConnection(DriverManagerConnectionProvider.java:110)      at org.hibernate.cfg.SettingsFactory.buildSettings(SettingsFactory.java:84)      at org.hibernate.cfg.Configuration.buildSettings(Configuration.java:2073)      at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1298)      at com.beyon.ezygui.server.Sessions.<clinit>(Sessions.java:39)      at com.beyon.ezygui.server.GuigenserviceImpl.testRPC(GuigenserviceImpl.java:322)      at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)      at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)      at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) 
    Thanks in advance.
    Thanks & Regards,
    Kothandaraman N.

    Hi,
    Myself hardcoded that username and password checking like the below code.
    String name = loginData.get("userName").toString();
              String pswd = loginData.get("pswd").toString();
              String hstName = loginData.get("hName").toString();
              String prtNo = loginData.get("portNo").toString();
              String sid = loginData.get("sId").toString();
              SessionFactory sessionFactory = null;
              try {
                   if (name.trim().equals(userName) && pswd.trim().equals(password)
                             && hstName.trim().equals(hostName)
                             && prtNo.trim().equals(portNo) && sid.trim().equals(sId)) {
                        sessionFactory = Sessions.getSessionFactory();
                        strAccpted = "true";
                   } else {
                        strAccpted = "false";
              } catch (Exception e) {
                   e.printStackTrace();
                   strAccpted = "false";
              }I have my own values in string objects, then comparing that values with the values from login form. If both values are matching, then i will do configurations in hibernate.
    ResourceBundle resourceBundle = ResourceBundle
                   .getBundle("com.beyon.ezygui.server.Queries");
         public static final String connection_url = resourceBundle
                   .getString("connection.url");
         public static final String userName = resourceBundle.getString("userName");
         public static final String password = resourceBundle.getString("password");
         public static final String hostName = resourceBundle.getString("hostName");
         public static final String portNo = resourceBundle.getString("portNo");
         public static final String sId = resourceBundle.getString("sId");The above are the String objects i'm checking for the match with values from login form.
    Thanks & Regards,
    Kothandaraman N.

  • Can't get FaceTime to work...any suggestions...it just keeps me in this loop of asking to sign in, then verifying, then asking to sign in again. I know the username and password are correct.

    Can't get face time to work. Know the username and password are right. Asks me to sign in...verifying... And then goes back to sign in...

    One thing that worked for me:
    launched Message app which uses the same backend as Facetime. If it launches, click on the video. May display a Error Dialog. Call AppleCare and give them the number displayed. This will give them the needed info to check your AppleID account for the messaging servers
    For some reason FaceTime did not display this error, yet once I gave the Support person the number it was fixed in just a minute.
    YMMV

  • Dear Apple I buy a refurbish iPhone 5s the IMEI ******* and ICCID ******** and i restored the device when i restored its locked to iCloud and i don't know the username and password i hope to help me about the problem asap.  Best regard

    Dear Apple
    I buy a refurbish iPhone 5s the IMEI ******** and ICCID ********** and i restored the device when i restored its locked to iCloud and i don't know the username and password i hope to help me about the problem asap.
    Best regard
    <Edited by Host>

    This is a user forum. You aren't talking to Apple here.
    Return your iPhone for a refund. There is no way to remove the Activation Lock. Apple won't get involved.
    <Edited by Host>

  • Pass the username and password in URL to auto log in the application from SharePoint List

    how to Pass the  username and password in URL to auto log in the application from SharePoint List  
    I have a link  in my SharePoint list  when user try to open the link its asking username and password .i want to put username and password in URL to auto log in into that external URL from sharepoint
    please help me it is possible

    Check out
    http://serverfault.com/questions/371907/can-you-pass-user-pass-for-http-basic-authentication-in-url-parameters
    Kind regards,
    Margriet Bruggeman
    Lois & Clark IT Services
    web site: http://www.loisandclark.eu
    blog: http://www.sharepointdragons.com

  • Getting the Username and password Of Enterprise Portal in WebDynPro

    Hi Friends,
              I have developed one webdynpro application to read the excel sheet from KM Repository. i have used URL to open the connection to that excel file and to get the Inputstream.
              While opening the connection to the excel, I've hardcoded the username and password. I need to get the username and password of the user who login into the Enterprise portal and runs that application. then  i need to pass that username and password along with URL of the Excel sheet.
              Could you people find the solution and replied to me. I am waiting for your bright answer.
    Thanks and Regards,
    Sandeep Kumar Bonam.

    A very standard question in this forum.
    Refer this :
    Re: How to get User Id in Web dynpro application
    Regards,
    Subramanian V.

  • While entering the username and password in OEM, it is showing error : java.lang.ClassNotFoundException: _database._instance._sitemap._sitemap

    After starting OEM and entering the username and password , it is showing error : java.lang.ClassNotFoundException: _database._instance._sitemap._sitemap

    >
    Your reply might be useful, but it is still not a suitable answer for my question. >You might try reading it again, because you've absolutely missed the point.
    >
    I am familiar with NetBeans, because I have built many websites by this tool before, I don't want to change to other IDEs, ..>Nobody suggested 'another IDE'.
    Oh, and your 'hurry' is none of my business or concern. But if you are in such a gosh-darn hurry, it might be useful to read replies carefully - otherwise you might end up wasting a great deal of time.

Maybe you are looking for

  • How do i check how many times ive acticated CC

    hi i bought adobe cc and downloaded it onto my laptop but then i got some problems saying that it was only the trial, so i installed it on my brothers laptop aswell so i could use it on that. now  i am thinking of buying another laptop but i want to

  • I get this error when trying to create a ringtone - iTunes could not connec

    I get this error when trying to create a ringtone: "iTunes could not connect to the iTunes Store - an unknown error occurred (11556)" But I CAN connect - if I click on the iTunes Store, it connects right away. I want to make a ringtone from a song th

  • How to go to new jsp from servlet.

    In the results page, if a button is clicked, i go to servlet, then come back to display data from database in another page. It works fine but the problem is that I wnat to open up a new browser and display the target page there and not the results pa

  • Taking very long time to pick the file from internal deliviery channel fold

    Hi B2B gurus, For one of our trading partner we are testing an AS2 connectivity, so we are sending a 850 po's through internal deliviery channel(create a folder in-house), but while placing the 850 in a internal folder, its taking very long time to p

  • Add row in manually created tabular form

    Hi, I have created a manual tabular form in one of my pages, as I need 2 tabular forms. In my manual tabular form i have used collection, so while adding a row into it, the whole page get submitted. Do some have any idea how to add a row without refr