Odd or even number comparison?

Anyone know how to compare an incoming number and tell whether it is odd or even? How about if it is whole or fractional? Thanks
Kirk

fabb wrote:
Anyone know how to compare an incoming number and tell whether it is odd or even? How about if it is whole or fractional? Thanks
You need to be very careful applying odd/even to floating point numbers. It is only defined for intergers. Especially, if the value is a result of some computations, it could actually be 2.000000001 instead of 2.
Same with whole vs. fractional. You probably need additional code to ignore small differences from whole numbers. Where does the data come from?
ODD/EVEN: If you have an integer datatype, do a bitwise AND with "1" and check if the result is zero (even) or not (odd).
Message Edited by altenbach on 05-27-2008 09:17 AM
LabVIEW Champion . Do more with less code and in less time .
Attachments:
OddEven.png ‏3 KB

Similar Messages

Create function for ODD or EVEN(NUMBER) in pls sql

create function for ODD or EVEN(NUMBER) also
if number is odd multiply by 5
if number is even multiply by 10;

865253 wrote:
create function for ODD or EVEN(NUMBER) also
if number is odd multiply by 5
if number is even multiply by 10;
create function fn_get_no (n_in in number) return number is
o_num number;
begin
if mod(n_in,2) = 0 then
o_num := n_in*10;
else
o_num := n_in*5;
end if;
return o_num;
end;
select fn_get_no(5) odd, fn_get_no(4) even from dual;
ODD EVEN
25 40 Vivek L

Odd or even number

ok , basically how can I write a line of code which will tell me if a number is odd or even?

the test for equality with 0 should work for all numbers - the remainder of dividing a negative number by two should be 0 or -1 (I think - and the code bears this out anyway)
Lee

Function detect odd and even number

Do you know a function which can detect if a number is an odd number or other.

if ( number%2 == 1)
But a method for this? Really doubt that..
Do you know a function which can detect if a number is
an odd number or other.

How to find the largest odd number and smallest even number from an array

Hello All
I want to find out largest odd number and the smallest even number from an arry numbers? What is the best method to achieve this.
Thanks
Sravz

You need to sit down and figure out an algo on how you would do it if you had to do the same thing from a blind container perspective:
1 - collect all the items you want to look at
2 - look at an item
3 - is it odd?
4 - if it is odd then check if it is larger than previously largest number
5 - save it if it is larger
6 - return back to 2 unless no more items
7 - item is not odd so it must be even--is it smaller than previous
8 - save it if it is smaller
9 - return back to 2 unless no more items
Now you just need to know how to check if something is even or odd: to do this you will need the modulous operator--integer division.
Note: this all assumes that your needs are for integer type of numbers, otherwise there is not enough information to define an answer. For instance, if you are using floats at 0.5--it that even or odd? Do you consider an err factor when dealing with floats? etc...

MAXDOP Setting with an EVEN number will outperform ODD number. Is there anything that proves this?

Hi All,
MAXDOP Setting with an EVEN number will outperform ODD number. If any of you have any data points, please share.
NASTY RUMORS ABOUT MAXDOP

I do not think there is any relations between specifying even and odd numbers in MAXDOP... What are you trying to achieve?
http://sqlblog.com/blogs/adam_machanic/archive/2010/05/28/sql-university-parallelism-week-part-3-settings-and-options.aspx
Best Regards,Uri Dimant SQL Server MVP,
http://sqlblog.com/blogs/uri_dimant/
MS SQL optimization: MS SQL Development and Optimization
MS SQL Consulting:
Large scale of database and data cleansing
Remote DBA Services:
Improves MS SQL Database Performance
SQL Server Integration Services:
Business Intelligence

Odd even number and Boolean indicator

Hi all,
For example, I have these numbers from 0 to 112233. It will start counting from 0 and shown it on an output indicator. When it is even number (0,2 or 4,...) the Boolean indicator will become false, but when it is odd number (1,3 or,...) the Boolean indicator will become true.
I'd like to ask if it is possible to detect the values changing in output indicator when it start counting numbers from 0, and then the Boolean indicator will become false or true depending on even or odd number shown on an output indicator? How can I do that?
Thank you!

johnsold wrote:
It may not be that much faster. In the little test VI Q&R takes 581 ms for 10^8 iterations while AND takes 503 ms. That is 78 ps difference. Hardly enough time for a coffee break. Unless you drink really fast.
Yes, both are "fast enough" for all practical purpose. Even thought they are nealy identical in speed, the Q&R shows more variability in execution time (10% variability), while the AND is singificantly more stable (>1% variability).
(Make sure you disable debugging for a 10x speedup overall)
It also seems that the AND code folds better. If we change the control to a diagram constant, the AND version speeds up by a factor of two, even though no folding is shown anywhere inside the sequence structure. I have no idea what that means.
LabVIEW Champion . Do more with less code and in less time .

Check whether value in a field is odd or even

Hi folks,
I have some value in a field 'count'. I want to check if the value in that field is even or not. I need to put a IF loop saying that if the value in 'count' is even then execute the loop. How can I do this.
I appreciate the efficient method to check this. Thanks
Waiting.............

You can do something like this.
report zrich_0002 .
data: i type i value 48.
data: remainder type i.
remainder = i mod 2.
if remainder = 0.
write:/ 'This is an even number'.
else.
write:/ 'This is an odd number'.
endif.
Ooops, Abdul beat me to it.
Regards,
Rich Heilman
Message was edited by: Rich Heilman

"generate subset" in script gives error if even number

I am try to generate with a scipt using a PXI6551. In the generate subset command if it is a EVEN number such as below (gree) subset(0,17) it gives the error below (red). If it is an ODD number it works. Is this a bug, normally you would need an even number of samples to be able to generate but with the script it seems to give the error if there is an even number?
Thanks,
Brian
script myScript
   repeat 1
      Generate PRBS
   end repeat
   Generate PRBS subset(0,17) <-gives error   (0,18) does not give error
script
Error -1074115617 occurred at niHSDIO Write Script.vi
Possible reason(s):
Driver Status: (Hex 0xBFFA4BDF) DAQmx Error -200032 occurred:
Subset length specified is not valid.
Change the subset length to be longer than zero samples and a multiple of the alignment quantum.
Line Number: 5
Position in Line: 18
Subset Length: 17
Alignment Quantum: 2
Status Code: -200032
Message Edited by BrianPack on 09-29-2005 04:29 PM

Brian,
The format (x,y) means y samples starting at position X and therefore when you specify (0,17) you would still generate 17 samples but starting at position 0. Whereas when specifying (1,17) you would generate STILL 17 samples but starting at position 1. Therefore, in either case, you are still asking to generate an odd number of samples. Hope this helps.
Ayman K

Odds and evens

Hi,
How can i determine when a number is odd or even?.
Rgds,
Jose

hi,
Just divide by 2, and check the remainder.
report ztest.
data:
rem type p decimals 2,
val type i value 657.
rem = ( val mod 2 ).
if rem = 0.
write:/ 'Even'.
else.
write:/ 'Odd'.
endif.
Hope this helps !!!
Cheers
Alfred

Different margin for odd and even pages

Hi there,
I am writing a book which will be printed in 2 sided paper. Therefor I will need different margin (left and right) for the odd and even pages.
How is it possible in Pages? I am using Pages 5.2 (1860).
Thank you.
Sebastian.

Indesign & Xpress are professional DTP applications. They can layout pages in any order you can imagine with custom margins. They are also complex to learn & expensive in comparison to Pages.
There is a trial of Indesign IIRC…
https://www.adobe.com/uk/products/indesign.html
Quark also has a trial too…
http://www.quark.com
I expect there may be cheaper 'layout' software that is capable of arranging facing pages correctly (possibly from a single pages PDF export from Pages), but I just avoid apps like Pages if I need a finer level of output control.

Count if odd or even

What formula should i use to count the number of cells that are odd, or even?

Hi Jerrold,
It's like this table, with more lines...
ODD Count
A
B
C
D
F
G
H
I
K
5
5
3
6
7
8
5
13
22
12
4
3
25
6
8
19
18
21
4
2
4
12
13
20
17
3
21
8
22
2
Thanks again

Odd and even rotating pages by file name

Hi all,
Hoping someone can help me trouble shoot my script below.
The aim is to determined if the last two digits of the file name are odd or even and then rotate the file accordingly.
I have been able to get the page rotation work by it's self but it seems to do nothing at all when trying to get the last two digits of the filename and use them as the variable "pgNum".
Files will be named using the following convention....
aa-02-02.pdf
Thank you in advance for you help.
=======================================================================================
var re = /.*\/|\.pdf$/ig;
var filename = this.path.replace(re,"");;
var pgNum = filename.substring(-2);
try {
    if(pgNum % 2) {
        var crtpagerotate = this.getPageRotation({nPage:i});
        this.setPageRotations({nStart: i, nEnd: i, nRotate:(270+crtpagerotate)%360});
    else {
        var crtpagerotate = this.getPageRotation({nPage:i});
        this.setPageRotations({nStart: i, nEnd: i, nRotate:(90+crtpagerotate)%360});
catch (e)
    console.println("Batch Aborted: " + e )

Try this:
var re = /\.pdf$/i;
var filename = this.documentFilename.replace(re, "");
var pgNum = +filename.slice(-2);

Odd and Even Headers in Pages 5

I think this has been asked before, but is it possible to making different odd and even-paged headers in Pages 5? I can't figure it out.

You can take this to be the answer for most things Pages 5…
… No!
Use Pages '09 instead.
Peter

FINDING MEDIAN FOR AN ARRAY OF INTS WITH EVEN NUMBER OF VALUES

okie dokie fellas i know this has got to be easy but i hjave been sittin at my comp forever workin on projects that are due and my head isn't all there anymore...could someone please clue me in on how im supposed to write the logic to find the median of an array of integers if the array contains an even number of values...I know I have to average the 2 values on either side but i cant figure it out at all...sorry i know its dumb but thnaks to anyone who helps
package pgm3deClercqMatt;
* @author Owner
* To change the template for this generated type comment go to
* Window>Preferences>Java>Code Generation>Code and Comments
import java.sql.*;
import javax.swing.*;
import java.awt.*;
import java.util.*;
import java.text.*;
public class ExamStatistics
     public static void main(String[] args)
          DbConnection db = new DbConnection("pgm3");
          boolean moreRecords;
          String query = "SELECT * FROM pgm3Data ORDER BY ExamGrade";
          ResultSet rs = db.processQuery(query);
          int nbrGrades = 0;
          ResultSetMetaData rsmd = null;
          try
               rsmd = rs.getMetaData();
          catch(SQLException sqlex)
               JOptionPane.showMessageDialog(null, "SQLException getting ResultSet data or metadata");
               System.exit(0);
          int s[] = new int[200];
          DecimalFormat decimal = new DecimalFormat("#,##0.00");
          int n = 0, aboveNinety = 0, numberAboveNinety = 0;
          double sum = 0, avgGrade = 0, medianGrade = 0;
          try
               moreRecords = rs.next();
               if(!moreRecords)
                    JOptionPane.showMessageDialog(null, "pgm3Data Result Set is Empty.");
                    System.exit(0);
               while(moreRecords)
                    s[n] = rs.getInt(1);
                    n++;
                    moreRecords = rs.next();
               }// end of while loop
               System.out.println("n = " + n);
               System.out.println("s[0]= " + s[0]);
               System.out.println("s[n-1]= " + s[n-1]);
               //FIND AVERAGE OF ARRAY
               for(int j=0; j<n; ++j)
                    sum += s[j];
                    avgGrade = sum/n;
               //FIND NUMBER OF GRADES ABOVE OR EQUAL TO 90
               for(int j=0; j<n; ++j)
                    if(s[j]>=90)
                         numberAboveNinety++;
               //FIND MEDIAN EXAM GRADE
               for(int j=0; j<n ; ++j)
                    if(Math.abs(medianGrade - Math.floor(medianGrade))<1.e-10)
                          medianGrade = s[(j+1)/2];
                    else
                         medianGrade =    <HERE IS WHERE THE PROB IS
          }// end of try block
          catch(SQLException sqlex)
               JOptionPane.showMessageDialog(null, " SQLException getting ResultSet data or metadata");
               System.exit(0);
          String output = "";
          output = "Number of Exam Grades: " + n;
          output += "\nHighest Exam Grade: " + maxOfArray(s, n) + "\nLowest Exam Grade: " + minOfArray(s, n)
                    + "\nAverage Grade: " + decimal.format(avgGrade) + "\nNumber of exam grades above 90: "
                    + numberAboveNinety + "\nMedian Exam Grade: " + medianGrade;
          JOptionPane.showMessageDialog(null, output);
          System.exit(0);
     }// end of main
     static int maxOfArray(int z[], int n)
          int j, max = z[0];
          for(j=1; j<n; ++j)
               if(z[j]>max)
                    max = z[j];
          return max;
     static int minOfArray(int z[], int n)
          int j, min = z[0];
          for(j=1; j<n; ++j)
               if(z[j]<min)
                    min = z[j];
          return min;
}// end of ExamStatistics
class DbConnection
     //     class DbConnection creates and manages the db connection,
     //     processes queries, and returns result sets for processing
     private Connection connection = null;
     private String url="jdbc:odbc:";
     private Statement statement;
     private String username = "";
     private String password = "";
     private ResultSet rs;
     private int nbrResultSets = 0;
     //     Constructor Argument is the registered name of the database
     DbConnection(String dbName)
          try
          {// load driver to allow connection to database
               Class.forName("sun.jdbc.odbc.JdbcOdbcDriver");
               connection = DriverManager.getConnection ((url+dbName), username, password );
          catch (ClassNotFoundException cnfex)
               fatalError("ClassNotFoundException on connection attempt");
               System.exit(0);
          catch (SQLException sqlex )
               fatalError("SQLException -- Unable to Connect to db");
               System.exit(0);
     } // end of constructor
     ResultSet processQuery(String query)
     //     process a single SQL query and return the resulting data set
          rs = null;
          try
               statement = connection.createStatement();
               rs = statement.executeQuery(query);
          catch (SQLException sqlex)
               fatalError("SQLException on query or processing");
          return rs;
     void endConnection()
          try
               connection.close();
          catch (SQLException e)
               fatalError("SQLException on attempt to close connection");
     //     simple local fatal error handler
     private void fatalError(String msg)
          JOptionPane.showMessageDialog(null,msg);
          System.exit(0);
} // end of class DbConnection

sorry to anyone who thinks what i'm doing is a joke
first of all i'm a student and secondly i'm taking
java in a summer session so things don't get
explained as well as they should. And how is this our problem?
I'm doing the best
i can. The for loop was because the array that I
defined to hold 200 values was being filled by a
database with a supposed unknown number of values but
less than 200 so i waslooping through to get each
value and put it in order and the conditional
statement was supposed to test to see if the incoming
median was an integer and was in the final write-up
put into it's own boolean method returning false if
there was no median and you needed to take the
average of the next lowest and highest values. BThere's always a median. The definition I sent you tells you what it is.
But
thnak you very much to the people that actually help
on here and don't try to bash people who have put
effort into writing their code, however shitty it may
look to them. You can't control what people say about your stuff. Everyone who criticizes your work isn't making a personal attack. They're telling you something that you should be learning from. Your problem is that you can't separate yourself from your work.
No one knows absolutely everything and
people who decide to talk down on others when they
are using this forum as a last resort need to grow
up.Grow up? That's what you need to do. If you think for a moment that you'll never be criticized once you leave that ivory tower you're sadly mistaken. You need to figure out how to separate yourself from your code.
%

Odd or even number comparison?

Similar Messages

Maybe you are looking for