On my i-Tunes I have shuffle songs turned off but it still shuffles. Help !!!!

On my i-Tunes I have shuffle songs turned off but it still shuffles the songs. In the controll box it shows shuffle off.Any ideas??????????????

I realize you posted this two years ago but I just encountered this same problem.  Did you ever get an answer to your question?  If so, did it work?  If it worked could you please share the idea?  it's driving me crazy.

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    1. Provide a SQL statement that displays the FIRSTNAME and LASTNAME of each customer separated by a comma. The FIRSTNAME and LASTNAME should be capitalized and concatenated together with a column alias of “Full Name”. The output should be sorted in ascending order by LASTNAME.
    SELECT FIRSTNAME||','||LASTNAME "FULL NAME"
    FROM CUSTOMERS;
    FULL NAME
    BONITA,MORALES
    RYAN,THOMPSON
    LEILA,SMITH
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    CINDY,GIRARD
    MESHIA,CRUZ
    TAMMY,GIANA
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    JORGE,PEREZ
    JAKE,LUCAS
    REESE,MCGOVERN
    WILLIAM,MCKENZIE
    NICHOLAS,NGUYEN
    JASMINE,LEE
    FULL NAME
    STEVE,SCHELL
    MICHELL,DAUM
    BECCA,NELSON
    GREG,MONTIASA
    JENNIFER,SMITH
    KENNETH,FALAH
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    2. Provide a SQL statement that displays the current date in the format MM/DD/YY.
    SELECT TO_CHAR( '10/25/06')
    FROM DUAL
    TO_CHAR(
    10/25/06
    3. Provide a SQL statement that displays the TITLE and publisher NAME of each book in the “COMPUTER” CATEGORY.
    SELECT TITLE, CATEGORY
    FROM BOOKS, PUBLISHER
    WHERE CATEGORY = 'COMPUTER'
    TITLE      CATEGORY
    DATABASE IMPLEMENTATION      COMPUTER
    HOLY GRAIL OF ORACLE      COMPUTER
    HANDCRANKED COMPUTERS      COMPUTER
    E-BUSINESS THE EASY WAY      COMPUTER
    DATABASE IMPLEMENTATION      COMPUTER
    HOLY GRAIL OF ORACLE      COMPUTER
    HANDCRANKED COMPUTERS      COMPUTER
    E-BUSINESS THE EASY WAY      COMPUTER
    DATABASE IMPLEMENTATION      COMPUTER
    HOLY GRAIL OF ORACLE      COMPUTER
    HANDCRANKED COMPUTERS      COMPUTER
    E-BUSINESS THE EASY WAY      COMPUTER
    DATABASE IMPLEMENTATION      COMPUTER
    HOLY GRAIL OF ORACLE      COMPUTER
    TITLE      CATEGORY
    HANDCRANKED COMPUTERS      COMPUTER
    E-BUSINESS THE EASY WAY      COMPUTER
    DATABASE IMPLEMENTATION      COMPUTER
    HOLY GRAIL OF ORACLE      COMPUTER
    HANDCRANKED COMPUTERS      COMPUTER
    E-BUSINESS THE EASY WAY      COMPUTER
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    4. Provide a SQL statement that displays the CUSTOMER# and LASTNAME for each customer along with the ORDER# of any order that the customer placed. The statement should include all customers including those that have not placed any orders.
    SELECT LASTNAME,ORDER#
    FROM CUSTOMERS C, ORDERS O
    WHERE C.CUSTOMER#=O.CUSTOMER#
    ORDER BY O.ORDER#
    LASTNAME      ORDER#
    GIRARD      1000
    LUCAS      1001
    MCGOVERN      1002
    MORALES      1003
    FALAH      1004
    MONTIASA      1005
    SMITH      1006
    GIANA      1007
    PIERSON      1008
    GIRARD      1009
    SMITH      1010
    LUCAS      1011
    NELSON      1012
    LEE      1013
    LASTNAME      ORDER#
    GIANA      1014
    FALAH      1015
    SMITH      1016
    SCHELL      1017
    MORALES      1018
    MONTIASA      1019
    JONES      1020
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    5. Provide a SQL statement that displays the total QUANTITY of books ordered.
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    FROM ORDERS NATURAL JOIN ORDERITEMS NATURAL JOIN CUSTOMERS
    HAVING SUM(QUANTITY)=ALL
    (SELECT MAX(SUM(QUANTITY))
    FROM ORDERS NATURAL JOIN ORDERITEMS GROUP BY CUSTOMER#)
    GROUP BY CUSTOMER#, FIRSTNAME, LASTNAME;
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    1007      TAMMY      GIANA
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    GROUP BY TITLE
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    BODYBUILD IN 10 MINUTES A DAY      18.75
    BUILDING A CAR WITH TOOTHPICKS      37.8
    COOKING WITH MUSHROOMS      12.5
    DATABASE IMPLEMENTATION      31.4
    E-BUSINESS THE EASY WAY      37.9
    HANDCRANKED COMPUTERS      21.8
    HOLY GRAIL OF ORACLE      47.25
    HOW TO GET FASTER PIZZA      17.85
    HOW TO MANAGE THE MANAGER      15.4
    PAINLESS CHILD-REARING      48
    REVENGE OF MICKEY      14.2
    SHORTEST POEMS      21.85
    THE WOK WAY TO COOK      19
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    FROM BOOKS
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    BODYBUILD IN 10 MINUTES A DAY      FITNESS
    REVENGE OF MICKEY      FAMILY LIFE
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    DATABASE IMPLEMENTATION      COMPUTER
    COOKING WITH MUSHROOMS      COOKING
    HOLY GRAIL OF ORACLE      COMPUTER
    HANDCRANKED COMPUTERS      COMPUTER
    E-BUSINESS THE EASY WAY      COMPUTER
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    THE WOK WAY TO COOK      COOKING
    BIG BEAR AND LITTLE DOVE      CHILDREN
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    3. Provide a SQL statement that displays the TITLE and publisher NAME of each book in the “COMPUTER” CATEGORY.
    TITLE CATEGORY
    DATABASE IMPLEMENTATION COMPUTER
    HOLY GRAIL OF ORACLE COMPUTER
    HANDCRANKED COMPUTERS COMPUTER
    E-BUSINESS THE EASY WAY COMPUTER
    DATABASE IMPLEMENTATION COMPUTER
    HOLY GRAIL OF ORACLE COMPUTER
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    E-BUSINESS THE EASY WAY COMPUTER
    DATABASE IMPLEMENTATION COMPUTER
    HOLY GRAIL OF ORACLE COMPUTER
    HANDCRANKED COMPUTERS COMPUTER
    E-BUSINESS THE EASY WAY COMPUTER
    DATABASE IMPLEMENTATION COMPUTER
    HOLY GRAIL OF ORACLE COMPUTER
    TITLE CATEGORY
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    E-BUSINESS THE EASY WAY COMPUTER
    DATABASE IMPLEMENTATION COMPUTER
    HOLY GRAIL OF ORACLE COMPUTER
    HANDCRANKED COMPUTERS COMPUTER
    E-BUSINESS THE EASY WAY COMPUTER
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    Result is wrong - you have a catrtesian product between books and publisher i.e. each book is repeated for each publisher. You need to join books to publisher and you need to select the publisher name
    4. Provide a SQL statement that displays the CUSTOMER# and LASTNAME for each customer along with the ORDER# of any order that the customer placed. The statement should include all customers including those that have not placed any orders.
    SELECT LASTNAME,ORDER#
    FROM CUSTOMERS C, ORDERS O
    WHERE C.CUSTOMER#=O.CUSTOMER#
    ORDER BY O.ORDER#This is wrong, you need to use an outer join between customers and orders to satisfy the requirement:
    The statement should include all customers including those that have not placed any orders.
    5. Provide a SQL statement that displays the total QUANTITY of books ordered.
    SELECT CUSTOMER#, FIRSTNAME, LASTNAME
    FROM ORDERS NATURAL JOIN ORDERITEMS NATURAL JOIN CUSTOMERS
    HAVING SUM(QUANTITY)=ALL
    (SELECT MAX(SUM(QUANTITY))
    FROM ORDERS NATURAL JOIN ORDERITEMS GROUP BY CUSTOMER#)
    GROUP BY CUSTOMER#, FIRSTNAME, LASTNAME;
    CUSTOMER# FIRSTNAME LASTNAME
    1007 TAMMY GIANA
    I can't see a quantity here and you should avoid NATURAL JOINs like the plague:
    SELECT CUSTOMER#, FIRSTNAME, LASTNAME, SUM(QUANTITY)
    I'm not exactly sure what you're attempting with the
    HAVING SUM(QUANTITY)=ALL
    (SELECT MAX(SUM(QUANTITY))
    FROM ORDERS NATURAL JOIN ORDERITEMS GROUP BY CUSTOMER#)
    GROUP BY CUSTOMER#, FIRSTNAME, LASTNAME;bit.
    6. Provide a SQL statement that displays the TITLE of all books that COST more than the average cost of all books.
    SELECT TITLE,AVG(COST)
    FROM BOOKS
    GROUP BY TITLEThis doesn't do what was asked, it just selects the average cost of each book - which will be exactly the same as the actual cost of each book. You need to use a sub query here.
    8. Provide a SQL statement that displays each book CATEGORY in the database. The category should only appear once in the output.
    The title does not need to be in the output here and you need to use distinct.
    HTH
    David

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    Message was edited by: stephenfromwandi

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