One Row into multiple Column

Question

CREATE TABLE #ids (empid VARCHAR(200))
INSERT INTO #ids SELECT '100,200,300,400'
INSERT INTO #ids SELECT '1100,1200,1300,1400'
I am trying to get output following format
ID_1    ID_2   ID_3  ID_4
100     200    300   400
1000    1200   1300  1400
Each row in EmpId column will have only max. four values
Thanks
V

Answer 1

One more method:
CREATE TABLE #ids (empid VARCHAR(200))
INSERT INTO #ids SELECT '100,200,300,400'
INSERT INTO #ids SELECT '1100,1200,1300,1400'
select * from #ids
;WITH
L0 AS(SELECT 1 AS c UNION ALL SELECT 1),
L1 AS(SELECT 1 AS c FROM L0 AS A, L0 AS B),
L2 AS(SELECT 1 AS c FROM L1 AS A, L1 AS B),
L3 AS(SELECT 1 AS c FROM L2 AS A, L2 AS B),
Numbers AS(SELECT ROW_NUMBER() OVER(ORDER BY c) AS n FROM L3)
SELECT [1] AS Column1, [2] AS Column2, [3] AS Column3, [4] AS Column4
FROM
(SELECT rn,
ROW_NUMBER() OVER (PARTITION by rn ORDER BY nums.n) AS PositionInList,
LTRIM(RTRIM(SUBSTRING(valueTable.empid, nums.n,
charindex(N',', valueTable.empid + N',', nums.n) - nums.n))) AS [Value]
FROM Numbers AS nums INNER JOIN (Select row_number()over (Order by (Select NULL)) rn , Empid From #ids) AS valueTable ON nums.n <= CONVERT(int, LEN(valueTable.empid))
AND SUBSTRING(N',' + valueTable.empid, n, 1) = N',') AS SourceTable
PIVOT
MAX([VALUE]) FOR PositionInList IN ([1], [2], [3], [4])
) AS Table2
drop table #ids