Opening New Window or Explorer

Question

Hi Everybody,
My scenario is like this I have one Webdynpro application which contains two Views , First View contains one Link (LinkToAction) when ever I clicks on that link Second View Should open in New Internet Explorer means new Window,
For this I have created 2 Windows which is having first/second view.
Following Code is there
      IWDWindowInfo windowInfo = (IWDWindowInfo) wdComponentAPI
           .getComponentInfo().findInWindows("SecondWindow");
           IWDWindow window = wdComponentAPI.getWindowManager().createWindow(windowInfo,true);
           window.setWindowPosition(300, 150);
           window.show();
          //     Save WindowInstance in Context
           wdContext.currentPopupElement().setWindowInstance(window);
But still its opening same Window or explorer.
I tried with this method also.
IWDWindow window = wdComponentAPI.getWindowManager()
.createModalWindow(windowInfo);
Still it is not opening New Window.
Please help me out by opening New Window.
Thanks in advance.
AW

Answer 1

Hi Adam willams,
FIRST OPTION
The sample webdynpro url is like this:
http://<hostname>:<port no>/webdynpro/dispatcher/*******/<Application Name>
In the above URL, only hostname and portnumber may change if you switch to different server. So, in the code, if we are calling any application using the URL, we need to get the hostname and portnumber dynamically so that, even if we switch to different server our URL will work.
try {
        InetAddress addr = InetAddress.getLocalHost();
        // Get IP Address
        byte[] ipAddr = addr.getAddress();
        // Get hostname
        String hostname = addr.getHostName();
    } catch (UnknownHostException e) {
store the host name and portnumber in variables and form the URL
String URL = "http://"hostname":"port"/webdynpro/dispatcher/....../<YourApplicationName>"
SECOND OPTION
Following is the way to do it
http://localhost:50000/webdynpro/dispatcher/demo.sap.com/firstapp/FirstApp?ToSecondView=yes
Here the parameter name is ToSecondView and the value for it is yes
To read this from Webdynpro use
//value will hold the value yes from the url.
String value = WDProtocolAdapter.getProtocolAdapter().getRequestObject().getParameter("ToSecondView");
Now, in the view init() write the above code.
If value contains yes then you have to navigate to view 2 immediatley. If not be in the same view only.
Suppose if you access the url directly, you will see the view1.
If you want to open view2 in the pop up window, call the URL, http://localhost:50000/webdynpro/dispatcher/demo.sap.com/firstapp/FirstApp?ToSecondView=yes.
In the opened window, it will show view2.
Regards,
VJR.