ORA-22950: cannot Order Objects without MAP or ORDER method (line 15)

Question

Hi
I have created a function
create type att_con.ind_field_value as object (s_owner varchar2(50), s_table varchar2(50), s_field varchar2(50));
create type att_con.ind_field_value_table as table of att_con.ind_field_value;
create or replace function fn_find_field_entries
(s_entry IN varchar2)
return ind_field_value_table
IS
found_count integer;
t_return ind_field_value_table := ind_field_value_table();
begin
for cur in (select owner, table_name, column_name
from all_tab_columns
where owner 'SYS'
and owner 'SYSTEM')
loop
execute immediate
'select count(' || cur.column_name || ') from ' || cur.owner || '.' || cur.table_name || ' where ' || cur.column_name || ' = ' || s_entry
into found_count;
if found_count 0 then
t_return.extend;
t_return(t_return.last) := (cur.owner, cur.table_name, cur.column_name);
end if;
end loop;
return t_return;
end;
and i am getting the above error when i try and run it with
select * from table(att_con.fn_find_field_entries('NDUNNE'))
anyone know what this error might mean?
thanks in advance

Answer 1

22950, 00000, "cannot ORDER objects without MAP or ORDER method"
// *Cause:  an object type must have a MAP or ORDER method defined for
//          all comparisons other than equality and inequality comparisons.
// *Action: Define a MAP or ORDER method for the object type
//